Ngày tải lên :
12/03/2013, 15:28
...
1
2
V
V
=
2
1
P
P
→ V
2
=
2
1
P
P
. V
1
=
1
10
. 10 = 100 (l)
→ W = -(nRT).ln
2
1
P
P
= -10. 10 .ln 10 = 230,259 (l.at)
→ W = 230,259 .101 ,33 .10
-3
= 23,332 (kJ)
Q = - W = -23,332 (kJ)
b) ... thì:
o
HCtungS
H
10
4
,/,
∆
= 3. E
C- C
+ 10. E
C- H
= 3.(- 327,7) + 10( -412,75) = -5 110, 6 (kJ/mol)
* (5) 4C
(k)
+ 10 H
(k)
→ C
4
H
10
(k)
o
HCtungS
H
10
4
,/,
∆
= -5 110, 6 (kJ/mol)
Lấy ... + 1,17 .10
-3
T]
= - 32,1 + 31,541 .10
-3
T
=∆
o
H
100 0
o
H
298
∆
+
dTC
P
,
100 0
298
∫
∆
=
o
H
298
∆
+
dTT )10. 541,311,32(
100 0
298
3
∫
−
+−
=
o
H
298
∆
+
)
2
10. 541,311,32(
2
100 0
298
3
T
T
∫
−
+−
=...