Ngày tải lên :
24/07/2015, 00:40
... õu 5 ,88 98 = (1) (2) 117,6 x5 100 = 5 ,88 gam = 0,06 mol Khụi lng H2SO4 sau hoa tan phõn lai cua viờn bi: mH SO = 117,6 x 100 = 4,704 gam 4,704 = 0,0 48 mol 98 T (2) ta co: nH SO = 0,06 - 0,0 48 = ... 0,18mol x ( 1) + y = 0, 18 y x ( M + 17 ) y ữ+ ( 2M + M '+ 32 ) = 8, 12 ( ) 2 Mx + M ' y = 13 ( 3) x x y ( ) M My + 17 17 y + My + M ' + 16 y = 8, 12 2 y x x M + M ' ữ+ 17 y = 8, 12 ... = 8, 12 2 x ( Mx + M ' y ) + 17 y = 8, 12 2 x 17 y = 1, 62 17 x y = 3, 24 ( 4) ( 1) x + y = 0,36 18 x = 3, x = 0, ; y = 0, 08 im b) (3) => 0,2M + 0,08M = 13 => 2,5M + M = 162,5 ( M