Ngày tải lên :
04/07/2014, 06:23
... Proof t +1+ h t+h ˜h ˜h ˜h Pr It +1 = i, αt +1 = a | I1 , αt , , 1 t +1+ h t +1+ h t+h h h h , αt , , 1 Pr It +1 = i | I1 , αt , , 1 ˜ ˜ ˜h ˜h = Pr αt +1 = a | I1 ˜ t +1+ h h t h , 1 Ψ (i, αt ... starts in state S1 = This requires that 1 assign probability to state The initial state probability is ˜h 1+ h P1 ((R1 , I1 , 1 ) = (n, i, α)) = ˜h ˜ 1+ h Q(I1 = i) n = 1, α(n) = 1 (n) ˜ otherwise ... + α (1 − pi (t)) = (1 − α)pj (t), j = i pi (t + 1) pj (t + 1) If a(t) = and the critic says “failure”, then pi (t + 1) pj (t + 1) (1 − β)pi (t) β + (1 − β)pj (t), m 1 = = j = i, where < α < 1, ...