+ Br2 -Br + H B r ' - P h a n iJng c o n g m d v o n g : + H2 C H 3- C H 2 - C H 2- C H 3 4 « I M ' n m y 1*11 ' - Phan ifng o x i hoa (phan iJng c h a y ) :
C4HS + 6 O 2 4 C O 2 + 4 H 2 O .
Bai 2. N g i r d i ta thiTc h i ? n p h a n iJng n o m p t liTdng m e t a n tao ra C O 2 v a H 2 O , v d i m o t
the t i c h k h o n g k h i viifa d u trong b i n h thep k i n , sau p h a n iJng diTa v e n h i e t d o ban d a u ( h d i niTdc ngifng t u v a a p suat h d i nufdc k h o n g d a n g k e ) . HSy xac d i n h % the Úch cac k h i t r o n g b i n h sau p h a n ufng. T i m t i le a p suat tnfdc v a sau p h a n iJng ?
... ^G«ir'--.>
, .. Phifdng t r i n h p h a n iJng ' ' • aif;} iMn l i s i j l T"'} .1 liSi
CH4 + 2O2 > C O 2 + 2H2O „ :âm.ihh
x m o l 2 x m o l x m o l 2x m o l
;H.; J a CO tnA3c p h a n ufng :, -jij) \ ^itiMss. :><;t$ i M nM n f e i g i*>lj T j J
* T o n g so m o l k h i trirdc p h a n iJng : , • .i;t;:i^i*#feiiigi>|i::^^^^^^^
•r . . n i = ncH4 +no2 + n N 2 = x + 2x + 8x = l l x ^.^^^^i^,^ (j^n'WD '& A A .
(trong k h o n g k h i t i le the tich O2 va N2 ^ 1 : 4 => UQ^ = 2X = > n^^^ = 8x) '^-l
* T o n g so m o l k h i sau p h a n iJng : n^ = TIQQ^ + nN2 = x + 8x = 9 x ( m o l ) V a y % the t i c h cac k h i sau p h a n iJng :
%Vco2 = ^ - 1 0 0 % = 1 1 , 1 1 % ^ % V N2 = 8 8 , 8 9 % T i 1^ a p suat trifdc v a sau p h a n uTng :
Ps " s
n , 1 I x 11 Uiifihilii^HO ifi! O i i f e f TiT') i = n
9x 9 • ,hr::m>^^tf<}',0: K^H^i::)iMm*i^>iVUOx.W'
Bai 3. D o t c h d y h o a n toan 4 0 0 m l m g t ankan A t h u difdc 8 0 0 m l k h i C O 2 (cung d i e u
k i $ n ) . T i m c o n g thuTc phan tuT cua A . V i e t cong thiJc cau tao A ' " ""
Gidi D a t C T T Q cua a n k a n A l a C„H2„+2- PhUdng t r i n h p h a n iJng : CnH2n+2 + T O i - > n C 0 2 + ( n + O H j O , < T a c6 t i 1$ : 4 0 0 m l 1 8 0 0 m l =>n = 2 4 0 0 8 0 0
V a y C T P T cua A l a C2H6. C o n g thifc cau tao cua A : C H 3- C H 1
titl't m w liiHy
i I '
p^i 4. A n k a n Y m a c h k h o n g p h a n n h a n h c6 c o n g thuTc đn g i d n n h a t l a C2H5.
T i m c o n g thiJc p h a n tuf. V i e t c o n g thiJc c a u tao v a g o i t e n chat Y .
5) ViS't phifdng t r i n h h d a h g c cua phan Ung giQa Y v d i c l o k h i chiéu sang, c h i ro s^n p h a m c h i n h ciia p h a n u-ng. ^:>m m':'^ J ni^'y; <::K<W i f.^'- ' s^n p h a m c h i n h ciia p h a n u-ng. ^:>m m':'^ J ni^'y; <::K<W i f.^'- '
V I Y c 6 C T D G N l a C2H5 => Y cd d a n g (C2H5)„ hay CjnHsn. ,., ^ m = 2 n rn = 2 M a Y l a a n k a n : CmH2m+2 n e n ta cd : 2 m + 2 = 5n [ m = 4 , j i , , - r 'I V a y C T P T c Q a A m C4H10. "M^V-. ; ayv'' , \^;J^;J5.= '.^,JV,,;:-; C T C T c u a Y : C H 3 - C H 2 - C H 2 - C H 3 : butan ' " , PhUdng t r i n h p h a n iJng : i n < ÓM C H 3 - C H 2 - C H 2 - C H 2 C I + H C l ( s a n p h a m p h u ) ^ , C H 3 - C H 2 - C H 2 - C H 3 + CI2 - 1 ^ ^ C H 3 - C H 2- C H- C H 3 + H C l
Bai 5. D o t c h a y h o a n t o k n 5 , l g h o n h d p X g o m h a i ankan k e t i e p t h u diTdc 8 , l g
H2Ọ X a c d i n h c o n g thiJc p h a n tijf m o i ankan v a t i n h % theo k h o i liTdng m o i ankan. Dat C T T Q cua h a i a n k a n k e t i e p : C-H2-^2- PhiTdng t r i n h p h a n u-ng : ' '^'^^'^ Cn^2n.2 ^ — > n C 0 2 - . (n + l ) H 2 0 , " H 2 0 ~ = 0,45 ( m o l ) ^ T h e o p h a n iJng ta c 6 : nx = " H ^ O ~ ^ — n + 1 n + 1 ' T a c 6 : £ ^ = o 0,45(14n + 2 ) = 5. l ( n + 1) ',.!^:' i^. : n + 1 14n + 2 ' r:i>ni = 3 < n = 3 , 5 < n 2 = 4 aiiM V § y C T P T cOa h a i a n k a n : C j H g : a mol C 4 H, „ : b mol T a c d : n = ^ i i i ^ = 3,5 ^ a = b ^ ^ ^ ^ ^ ^ ^ i a + b •;. ,;„•' ,/ , „ , , Mat k h d c : 4 4 a + 58b = 5,1 a = b = 0,05 ( m o l ) ' ' ' 6 1
Phan dang vS phuong phjp giSi H6a hpc 11 HPu cd - D5 Xifln Hung
Thanh phan % khoi liTcJng moi ankan: %mc3Hg = ' ^ ^ g ^ 100% = 43,14%
=> %mc4H|o = 5 6 , 8 6 % . <^.iM .. ^f'lij' :^.v:Vri-i<:'.nf.\i
B a i 6. Dot chay h o i n tôn 3,36 l i t hon hdp k h i A gom metan etan thu dtfdc 4,48 lit khi cacbon. Cdc the tich k h i dtfdc do'd dieu ki$n tieu c h u l n . T i n h th^nh p h i n % the tich cua m o i k h i trong hSn hdp A .
Gidi , ,
Phtfdng tnnh phan tfng:
CH4 + 2O2 — ^ CO2 + 2H2O
V, V, ' ' C2H6 + - 0 2 — • 2C02 + 3H20 ' ' C2H6 + - 0 2 — • 2C02 + 3H20 V2 2V2 ^ ^ f V , + 2 V 2 = 4 , 4 8 l i t rv,= 2,24 l i t . i ' " U i <y) ,\\ Ta c6 : ^ => [ V ,+ V 2 =3,36 l i t [V2 =1,12 l i t
Thanh phan % ihi tich cdc k h i trong A : %VrH^ = 100% = 66,67%
^"'^ 3,36 :
% V c 2 H 6 =33,33%.""'-^'
B a i 7. Cho 8,8g ankan A phdn tfng v d i clo trong dieu k i ^ n dnh sdng thu dtfdc 15,7g d i n xuat mpt Ian the clọ Xic dinh cong thtfc phSn tuT ciia A dan xuS't mpt l l n t h ^ c l o . ) ' i , ' , ' 1 ' . ' •< Ft' f cUi D a t C T T Q ciia ankan A : C„H2„+2 - C„H2„+2 + CI2 C„H2„+,C1 + H C l ' < • ' • ' • ' Theo phtfdng tnnh ta c6 : — ^ — — = —M _ n = 3 , , - 14n + 36,5 14n + 2 ' ^' Vay CTPT cua A : C 3 H 8 ' ^ ' ^ C T P T d S n x u r t m 9 t l l n t h e - c l o: C 3 H, C l . ' " ' J BAI TAP N A N G C A O
B a i 1. D ^ t c h i y hoan tôn mOt mau hidrocacbon ngtfdi ta thS'y the tich hdi ntfdc sinh ra gS'p 1,2 l l n the tich k h i CO2 (do trong cilng d i ^ u k i ^ n ) . B i ^ t r^ng hidrocacbon do chi tao th^nh mOt dan xuat monoclo duy nhat. HSy xic dinh c6ng thtfc du tao cija n6. Gill D$t C T T Q cua hidrocacbon : C^Hỵ CxHy + . 4 ; a m o i T h e o d I : VH20 = 1.2VCO2 XCO2 + J H 2 O ax m o i — moi ^ = l,2ax = > y = 2,4x X 1 2 3 4 5 y 2,4 4.8 7 , 2 9,6 1 2
(loai) (loai) (loai) (loai) (nhan) V§y CTPT cua hidrocacbon la C 5 H 1 2 . i/ i S i :e <-:::.rfS ^v'h'-'fi> ^J-^^'
V i hidrocacbon chi tao thanh mOt d i n xuS't monoclo duy nhS't
C H 3 = j . C T C T i a : C H 3- C- C H 3 . = j . C T C T i a : C H 3- C- C H 3 .
C H 3 "'^
Bai 2. C6 ba ankan X , Y , Z liSn tiep nhaụ Tdng so k h o i Itfdng m o i phan ttf cua chdng m 132. Xic dinh cong thtfc phan tiJ c i a X , Y , Z.
D^t M la khoi Itfdng m o i phan tuf trung binh ciia ba ankan lien t i ^ p nhau ( C - I l j - ^ j ) -
_ — 1-12 -
T a c 6 : 14n + 2 = M = o 14n + 2 = 4 4 :
=> Ba ankan l l n Itfdt la : X : C2H6; Y : CjHg; Z : C4H,ọ , . • B i i 3. K h i 1 gam metan chdy t6a ra 55,6kJ. Can d^t bao nhifiu l i t k h i metan (dktc)
de Itfdng nhỉt sinh ra du dun 1 l i t ntfdc ( D = I g / c m ' ) ttf 25''C len 100°C. Biet r i n g mudn nang 1 gam ntfdc len 1"C cSn tieu t ^ n 4,18J gid sd nhỉt sinh ra chi dilng de l ^ m tSng nhi^t d$ ciia ntfdc.
• Gi&i •' K
Khi nang 1 gam ntfdc len T C c i n tieu ton 4,18J. . i f •
Vaiy k h i nang 1 gam ntfdc tilf 25''C len 100"C can tiSu ton m0t nhỉt Itfdng la : ( 1 0 0 - 2 5 ) x 4 , 1 8 = 313,5kJ
=> N h i e t Itfdng can tieu ton cho 1 lit ntfdc ttf 25''C len 100"C 1^ : 313,5 X 1000 = 313500J = 313,5kJ Ta l a i c6 I g CH4 chdy toa ra 55,6kJ ' ' x g? C H 4 c h a y t6ara313,5kJ , , 3 1 3 , 5 x 1 55,6 = 5,64g 5,64 S6 m o i CH4 : ncH. = -— = 0,3525 (moi) 16
Phan dgng vji phuong phap giSi H6a hpc 11 HOu c o - Pg Xuan Hung
=> Thé l i c h k h i CH4 (dktc) : V C H 4 = 0,3525 x 2 2 , 4 = 7 , 8 9 6 (Ht).
B a i 4 . H a i x i c l o a n k a n A va B d e u c6 t i k h o i h d i so v d i m e t a n b&ng 5,25. K h i m o n o c l o hoa (cd chiéu sang) t h i A cho bón san p h a m , B c h i cho m o t san p h a m d u y n h a t . X a c d i n h c o n g thiJc cafu tao ciia A va B .
M A h o a c B = 5,25 X 16 = 84 w ' : ; . o , ',
V i A hoac B la h a i x i c l o a n k a n c d khd'i li/dng m o l p h a n tuT b ^ n g n h a u
=> A va B la d o n g p h a n c u a n h a u . , D a t C T T Q cua A hoac B : C„H2n. ' * •
T a c d : 14n = 8 4 => n = 6 C T P T ciia A hoSc B Ih CfiHiz-"''' ^'"''^
K h i m o n o c l o h o a : « v.s?fc ị*30ftoin ikii nib iOm liixiui! o ^ i trf:j n o d ^ ^ ^ f o i x s i V
+ A c h o b o n san p h a m =i> C T C T cua A la H 3 C- C H- C H 3 hoac ( _ )
2\ u U ' . . . . . . , / r 3 c r
+ B c h o m 6 t san p h a m duy n h a t => C T C T cua B : 1 ^
B a i 5. K h i o x i hda hoan toan 7 m g hdp chát A thu diTdc 11,2ml k h i CO2 (dktc) v a 9 m g
H2Ọ T i k h o i h d i c u a A so v d i N2 b i n g 2,5. X a c d i n h c o n g thiJc c a u t a o c u a A néu k h i c l o hda no t h i c h i thu difdc m g t dan xuát m o n o c l o d u y nhaft. '
;'• : '•" Kd ,t!t» l i r i ^ ' i o i i j j & k j loos J^Ci -
M A = 2,5 X 28 = 7 0 ' ' ^'
m c = 1 2 . 1 1 i i = 6 ( m g ) ; m H = 2.A = i ( „ , g ) ^^UtX^^^ mii,^^
= > m o = 7 - ( 6 + 1 ) = 0 => t r o n g A k h d n g c d o x i . D a t C T T Q cua A : CJiy ^^'^^ '^^ ' f ^'^ cd t i l ? : x : y = — : - = 0 , 5 : 1 = 1:2 = > A c d d ^ n g ( C H 2 ) „ . T a c d : 14n = 7 0 = > n = 5 ^ . p ^ { M>l^iJi i^t' < mhl ' V a y C T P T cua A la CsH,,,. ' ' V i A + C I 2m O t d a n x u a t m o n o c l o duy nhat ' ' ' ^"-5 '^"^ ' ' ^ ' f ^''^ C T C T cua A l a \ _ J . • >.
B a i 6. Dót c h a y m p t hidrocacbon A v d i li/dng o x i vCfa d u . T o a n bo san p h a m chay diTdc d a n q u a b i n h diTng CaCl2 khan c d diT t h i the tich g i a m d i h d n m g t nu:ạ,Xdc d i n h cong thufc cau tao cua A ? B i e t rkng trong A cacbon c h i e m 8 0 % ve k h o i lifdng.
Gidi ••:*>!•;:; D a t C T T Q cua A : C„H2n+2-2a (n > 1, a ^ 0 ) D a t C T T Q cua A : C„H2n+2-2a (n > 1, a ^ 0 ) Phi/dng t r i n h p h a n iJng c h d y : * CnH2n+2-2a + ^ 3 n + r - a ^ 2 O2 > nC02 + (n + 1 - a)H20 ^ imAMflVOBfr
V i san p h a m chay d a n qua CaCl2 k h a n , (do C a C l j giu" H2O) n e n the t i c h g i d m la
thi tic h c u a H2Ọ
T h e o phuWng t r i n h the tich H2O > the tich CO2. j ,
T a c d : n + 1 - a > n => a < 1 => a = 0 ' ' = > C T T Q cua A : C„H2„+2 : a n k a n . i r : v v.
T h e o d e : % C = . 1 0 0 % = 8 0 % =i> n = 2 . ,^
14n + 2 ' ' • • • vay : C T P T cua A la C2H6; C T C T cua A : CH3-CH3: etan. '
B^i 7- Tilf m e t a n , ngiTdi ta c d the d i e u che H2 ( v a C O ) theo h a i c d c h sau : _ C d c h 1 : C H 4 + - O 2 " " " " ^ > C O + 2H2 ( H = 8 0 % )
_ C ^ c h 2 : CH4 + H2O ""J^"*^ > C O + 3H2 ( H = 7 5 % ) -i, ,
a) H d i each n a o t h u difdc n h i e u h i d r o hdn ?
b) N 6 u theo each thu diTdc nhieu hidro hdn t h i tiif 10* l i t CH4 (0°C; 22,4 a t m ) c d the d i e u che difdc bao n h i e u l i t H2 (dktc). d i e u che difdc bao n h i e u l i t H2 (dktc).
c) V i e t phuTdng trinh d i e u che metan tif n h o m cacbua, natri axetat, C v a H2, iH pentan.
Gidi
a ) * C d c h l : CH4 + ^ O ; ^^^.^ > C 0 + 2H2 ^ r j
1 m o l ' ' ^ j_ 2 m o l ft..«iT,;+'cR •Írt.i i,-'
" H 2 ( i ) = 2 x — = l , 6 ( m o l )100 .r:,^,^ftm^yt.''
C a c h 2 : CH4 + H 2 0 - ^ « ^ C O + 3H2 ^^.^^ ^ j . .
1 mol''"', '!'' 3 mol SA/riq b d . " " H 2 (2) = 3 ^ "iT^ = 2,25 (mol) :: 100 => C d c h 2 t h u dUdc n h i e u h i d r o h d n . +I,S;;<6 b) S6 m o l CH4 : n c H , = — = = ( m o l ) ^^ ; ''I , , • ' • ^ " ' • * " ' " 2 7 3 • ,.; r > nH2 (2) = 2 , 2 5 x 1 0 ^ ( m o l ) , , C'.-it ^ V H , = 2 , 2 5 . 1 0 ^ 2 2 . 4 = 5 0 . 4 . 1 0 5 ( l i t ) .
^) PhiTdng t r i n h phSn iJng d i e u che" m e t a n : 1 p; AI4C3+I2H2O > 4A1(0H)3 + 3CH4
Phan d?ng phmng ph^p gi^i H6a hpc 11 HOu co - D5 Xuan Hang e + 2 H 2 ^ C H 4
B a i 8 . D o t chay hoan loan 30,6g hon hdp gom hai ankan d the k h i sinh ra 92,4g C Q ^
a) Tinh tong so mol hai ankan.
b) Tinh the tich o x i can de dót chay 10,2g hon hdp tren.
c) Xac dmh cong thiJc phan tur hai ankan biét the tich hai ankan trong hon hdp bang nhau va d the k h i . 1 . t J i f , ,, . ,^<) I ' > i.'A,'^i^>% i . J. M . f t ' Giai I ' , , ) 'C„H2n+2 : a m o l ^ • , C n , H 2 m + 2 : b m o l ' D3t C T T Q hai ankan 1^ ^3n + l ^ ,IUi 1 I •» 1 Ạ^", -i a) C„H2n+2 + a mol ' Cn,H2m+2 + b m o l V 2 p n + f . 2 , O 2 > nCOz + (n+ 1)H20 H '• ^ * ^3m + P a mol na m o l O 2 > mC02 + (m + 1)H20 3m + l b mol mb mol , 1 ) 92 4 T a c 6 : na + m b = — ^ = 2,1 44 (14n + 2)a + (14m + 2)b = 30,6 » 14(na + mb) + 2(a + b) = 30,6 TCr ( I ) , (2) => a + b = 0,6 (mol) ' ' "A ^
Theo hai phUdng trinh^o mol o x i :
(1) (2) r 3 n+ n p m+ n a + I 2 J I 2 J b = 3(na + mb> + (a + b) 2 ~ . " 0 2 = •
3 x 2 1 + 0 6 ' •'^jri tytfc*fruaHr^i?^Mrs:;jil.';vilalÓ^
^ — ^ = 3,45(moI) , => S5 mol O 2 trong 10,2g hon hdp :
10 2
= 3 , 4 5 . — ^ = 1,15 (mol) =>Vo2 = 1.15.22,4 = 25,76(lft). c) V I t h ^ Uch hai ankan b^ng nhau => a = b = 0,3 m o l
T a c 6 : 0,3n + 0,3m = 2.1 => n + m = 7=> m = 7 - n (<!ik:n,m^4)
n 1 2 3 4
m 6 5 4 3
(loai) (loai)
Vay hai ankan la
C 3 H J J
Bai 9. MOt hdp chat hiJu cd X c6 % khoi luTdng cua C, H , C I Ian lUdt la 14,28%; J 19%; 84,53%. Hay ISp luan de tim cong thiJc phan tur cua X , viet cac cong thiJc cáu tao c6 the cd cua X .
Giai n. ' ' / » n : 4 < « W f! ( " . t U. 4 ^ rt . Dat C T T Q cua X : Q H y C l , " " 14,28 1,19 84,53 Ta C O t i l e : X : y : z = 12 1 35,5 = 1.19: 1 . 1 9 : 2 . 3 8 = 1 : 1 : 2 . X c6 dang (CHCl2)„ hjly C„H„Cl2„. s ^ |^;^,^^ Neu n = 1 => X : C H C I 2 (loai) Neu n = 2 X : C2H2CI4 (nh$n) H C I H H I I I I CTCT cua X : H - C - C - C l ; C l - C - C - C l I I I I CI C I CI CI
Neu m = 3 X : C3H3CI6 (loai). .,. - . r ' . f - , f n ,
Bai 10. Dot chay hôn tôn 0,384g hon hdp X gom hai ankan la d6ng d i n g ke tiep. San pham sinh ra cho vao 520ml dung dich N a O H 0,1M thu di/dc m u o i trung
, hoạ , itsx»;:ic::,.
a) Xac dinh cong thiJc phan tuf m o i ankan. :,fitdol;)Lx!vJ'.:iffi!-; ^
b) T i n h % khoi lifdng m o i ankan trong hon hdp daụ f yfcii) i * ' ' ' '
Giai ^.i,.' ,.„v,4;,,,,,\
Dat C T T Q cua hai ankan dong dang ke tiep : C- H 2 - ^ 2 fjf,,
Phifdng trinh phan iJng :
C H . ' ' 3 n + l O2 — - > n C 0 2 + (n + l) H 2 0 (1)
ts4 0ii&S q\>,ri- f! ( 0 , 0 2 6 m o l '''^"''-'^ 't^'-'
C O 2 + 2 N a O H > N a j C O j + H2O ''9<?*Auri«,J 0,026 0,052 m o l
HNaOH = 0,1 X 0,52 = 0,052 (mol)' ' ' Theo phifdng trinh ( 1 ) :
(2)
'I ( V I ' I
0 , 0 2 6 , „ 0.026 0,384 nx = — = — (mol) < ^ — = — = — = nx = — = — (mol) < ^ — = — = — =
n n 14n + 2 ni = 2;n2 = 3 (hai ankan ke tidp)
C2Hg : a m o l
n = 2,6
V$y CTPT hai ankan la
i l l
Cjii^ : b m o l
PhSn dang va phudng phdp gi^i Hoa hpc 11 HQu c d - D5 XuSn Hi/ng T a c d : n = ^ 5 ^ = 2 , 6 ^ a = - b ( I ) a + b 3 M a t k h a c : 30a + 44b = 0 3 8 4 ( I I ) a = 0,004 m o l b = 0,006 mol Giai (I), (II) ta difdc
Thanh phan % k h ^ i lUdng m o i ankan :
^^"^ 0,384 I-
=> %rnc^Hn =68,75%. <'',M'
^ B A I T A P T R A C N G H I | : M
C&u 1. D6't chdy hoan toan mot m l u hidrocacbon X ngifdi ta thay the tich hdi niTdc sinh ra gap 1,2 Ian the tich k h i cacbonic trong ciing mot dieu kỉn. Biét rang hidrocacbon do chi tao thanh mpt dan xuat monoclo duy nhS't. V a y X c6 ten la: A . 2,2-dimetylpropan B . isobutan
C. 2-metylbutan D . etan
C a u 2 . M o t xicloankan X c6 t i k h ^ i so v d i o x i bkng 2,625. B i e t k h i cho X tac dung v d i clo ngôi i n h s^ng thi chi tao di/dc dan xuaft monoclo duy nhat. V $ y A Ik c6
Ạ xiclohexan , B . metylxiclopentan
C. 1,2-dimetylxiclobutan """^ D . l , 3 - < l i m e t y l x i c l o b u t a n ' ' ' ^ ' ^ - ^ CSu 3 . Dót chay hoan tôn m6t Wdng hidrocacbon X . Hap thu t o l n bp san
pham chay vao dung dich BăOH)2 (diT) tao ra 29,55 gam ket tua, dung dich sau phan iJng c6 khoi Itfdng giam 19,35 gam so v d i dung dich Bă0H)2 ban daụ Cong thtfc phan tuT cua X la
A.C3H4. B.C2H6. C.C3H6. M D.C3H8.
„ , ,; ' " Trich de thi tuyen sinh Dai hoc khoi A ndm 2010"
CSu 4. D6't c h i y hôn t o i n 6,72 l i t (dktc) hon hdp g6m hai hidrocacbon X Y ( M Y > M x ) , thu diTdc 11,2 l i t CO2 (dktc) va 10,8 gam H2Ọ Cong thiJc cua X IS A . C2H6 B . C2H4 C. CH4 D . C2H2
" Trich de thi tuyen sinh Cao đng ndm 2010"
CSu 5. So lien k e t a (xich ma) c6 trong m o i phan tijr: etilen; axetilen; buta-l,3-dien
l a n l i f d t m , • &gfW"' •••.•vc''
Ạ 3; 5; 9 > toi r B . 5 ; 3 ; 9 C. 4; 2; 6 D . 4; 3; 6
. " Trich de thi tuyín sinh Cao đng ndm 2010"
c a u 6 . K h i crackinh hôn tôn mOt the tich ankan X thu diTdc ba the tich hon hdp Y
(cdc the tich k h i do d chng dieu k i ^ n nhỉt dO va dp suat); t i khoi cua Y so v d i H2 bkng 12. Cong thtfc phan tuf cua X la
A. C 6 H , 4 . B . C j H x . C.C4H,ọ D . C5H,2.
" Trich de thi tuyín sinh Dai hoc lihói A nam 2008"
Cflu 7- Cho iso-pentan ike dung v d i C12 theo t i 1$ so m o l 1 : 1, só san pham monoclo t ^ i da thu difcJc la \nirrM iii\-^''f ':yki!<^ij ••!'X<^}. '^.^,.1 ^.w.,)
Ạ 2. B . 3. ; C. 5. D . 4.
" Trich de thi tuyen sinh Dai hoc Ichoi A ndm 2008"
C&tt 8. Hidrocacbon mach hd X trong phan tuT chi chiJa lien ket a va c6 hai nguyen
tvl cacbon b$c ba trong mpt phan tuT. D o t cMy hoan toan 1 the tich X sinh ra 6
thi tich CO2 id cung dieu kien nhiet dp, suat). K h i cho X tac dung vdi C l j (theo ti 1# so m o l 1 : 1), so dan xuat monoclo tdi da sinh ra IS ^' '
Ạ 3. B . 4 . -•.^--••^^ C . 2 . ' D . 5 . '-^'^ ' H | | , Trich de thi tuyen sinh Dai hoc Ichoi B ndm 2008''
Cfiu 9 . Cong thiJc đn gian nhát cua mpt hidrocacbon la C n H 2 n + l - Hidrocacbon đ thuQC day dong dang cua
Ạ ankan. B . ankin. C. ankadien. D . anken.
• " Trich de thi tuyen sinh Cao đng ndm 2008"
c a u 10, D o t chay hôn toan mpt hidrocacbon X thu difdc 0,11 mol CO2 va 0,132 mol H2Ọ K h i X tac dung v d i khi clo (theo t i 1? so m o l 1:1) thu duTdc mpt san pham hOu cd duy nhat. T e n goi cua X la , ^ , . , •
Ạ 2-Metylbutan. B . etan.