- Chodung dich NaHS03 vdo honhdp con lai thi (C2H5)20 khong phan iing di/dc tach ra c6n C 2 H 5 C H O phan itng tao ket tua, Ipc lay két tua cho tdc dung vd
Bai 1 Cho 36,2g honhd pX gom axit fomic, axit axetic va axit acrylic lam mát mau hoan toan 40g dung dich brom Mat khac de trung hda hoan tôn cClng liTdng hon
hdp X tren can dilng 300ml dung dich NaOH 2M. Tinh % khoi liTdng moi axit trong hon hdp X. ,.^•-•^•,.:^t;,ii^.•.«,;;-• j ; . , ' -
P i i S H u ^ i i y v a p h u o i i g p i i u p y i u i I K J o iiQC 1 1 HOu CO - B5 Xuan Hung
" " r . Giai
PhiWng innh phan iJng : '-^'ỉ; • »^r:x:vn> j ; : / : ; / , ; r">,>n , C H 2= C H - C O O H + Br2 > C H j - C H - C O O H (1) 0,25 mol 0,25 mol C H 2= C H - C O O H + NaOH > C H 2= C H - C O O N a + H 2 O (2) , 0.25 mol 0,25 mol H C O O H + NaOH > HCOONa + H 2 O ' ' " ( 3 ) X X mol C H j C O O H + NaOH y y mol C H j C O O N a + H 2 O 40
So mol B r 2: = — = 0,25 (mol) m^xi,acrylic = 0.25.72 = 18 (g) 160
So mol NaOH : n N a O H = 0.3.2 = 0,6 (mol) ''^^^"^ i(S-K})s:) ri'sjl,.. gftiib
=> So mol NaOH cl phan tfng (3) va (4) • "'^.^ :fmm^<^ o l v xil,, ^J<i<li
n N a O H = 0,6 - 0,25 = 0,35 = x + y ^^'"1 ' - ' " ^ ' i ' Sfstrí- Mat khdc ta c6 : 46x + 60y = 36,2 - 18 = 18,2 (g) ^ ' K K O - ) £ 46x + 60y = 18,2 x = 0,2 • "•0;\H,3) (mol) ... :K y = 0,15 T a C O phiTdng t r i n h , ^ ^ [ x + y = 0,35 niHcooH = 46.0.2 = 9.2 (g); mcHjCOOH = 60.0.15 = 9 (g)
T h^nh p h a n % khói lifdng m o i axit trong X 9.2 %m HCOOH - 36,2 X 100% = 25,41% I %nicH3COOH = r r T x 100% = 24,86% W 36,2 =>%C2H3COOH = 49,73%. ... ^ v- —H O s M f B 3 - , H p
B a i 2. Dan hdi cua 3g etanol di vao trong ong siJ nung n6ng chtfa bOt C u O dir. Lam lanh dc ngiftig tu san pham hdi di ra khoi ong siJ, diTdc chaft long Ạ Khi A phan iJng hoan toan vdi mpt liTdng duf dung dich AgNOs trong NH3 thay c6 8,lg bac kc't tuạ Tinh hi^u suat ciia qua trinh oxi hoa etanol.
" ' Gidi
C H 3 - C H 2 - O H + CuO - A C H 3 - C H O + Cu + H2O 0,0375 mol 0,0375 mol
CH3CHO + 2AgN03 + 3NH3 + H2O > CH2-COONH4 + 2 A g i + 2NH4NO3 0,0375 mol , . 0,075 mol
8,1 .r M r u.r}f,'A ,•!->;);, j^n-jtj ifpiị
So mol Ag : nAg = — = 0,075 (mol) 108
~n) .X ofi
. ,X qfvf! :nliA snó'
Khoi liTdng C 2 H 5 O H phan tfng : mc^HgOH = 46.0,0375 = 1,725 (g) Hỉu suat qud trinh oxi h6a etanol: H = -^-^ x 100% = 57,5%).
P a i 3 .
3) Cho l,97g fomalin tac dung vdi AgNOs trong NH3 diT tao ra 10,8g bac. Tinh nong dp % ciia andehit fomic trong fomalin (gia .suf trong fomalin iUdng axil fbmic khong dang ke). ( SH--.... |.f> .^.El'•0;4?4 ^'H'LNri«*(:,:i • ,
b) Tinh nong do can bang cac ion H* va CH3COO" trong dung dich C H , C O O H 0,1M va dO dien li a cua dung dich axit đ. Biet hhng so axil cua CH3COOH la