C. Xiclopropa n; D Xiclobutan ,'
4. Cong thd-c nguyen la (C2H30)„
Cong thu-c phan tuT c6 dang: C2„H3„0„ - -..v , ; ui
Cong thiJc cau tao cua andehit C„H2n(CH0)n t j , , , . . ,
CAii y: Songuyen tit H + So nhom chiic <2.S6 C + so H ^^^^^ ,,^„,„^ . ^,. ^ ^ ,, ,
=>2n + n < 2 . n + 2 = > n < 2
Khi n = 1: C T P T la C2H3O (loai vi khong dam bao h6a tri cua C )
n = 2: C T P T la C2H4(CHO)2
=>ChonB. ••^•''••••-.<^ , , ' • tell
C§u 15. Cong thiJc cau tao thu gon cua A la: Cx_2H6(CHO)2
T a c 6 : 6 + 2 = 2 ( x - 2 ) + 2 ^ x = 5 " . > >yd. M
Chon D.
CSu 16. Cong thitc phan tuf cua X la: C3nH6„On' * ' ^ " '"^
=> C T C T thu gon C2„H5„(CHO)„ ' " ^' T a c o : 5 n + n < 4 n + 2 = > n < 1 =>n= 1 ' * • =>Chon Ạ ^ • • rf'«->^'H<.:'H' ^ W ' , r.4> ^ H ,
C f i u l 7 . Goicongthu-ctongquatcua A l a R ( C H 0 ) „ t a c 6 :
R(CHO), + 2zAgN03 + 3zNH3 + ZH2O R(C00NH4). + 2ZNH4NO3 + 2zAg
4,4 • 7,7 R4-29Z R + 62Z „ ' ! ^ WfịtJ v>M;>fa R4-29Z R + 62Z „ ' ! ^ WfịtJ v>M;>fa R = 15z 4,4 7,7 ( I . fOk ' ' " I * n ^ , t t , « K h i z = l t h i R = 15:-CH3 =>ChgnB.
Cfiu 18. Goi cong thiJc tong qudt cua A Ih. CJiyO, ' * * • •'^ * '
6,6 , _ m c = — .12= l.Sgam , >^ ^ i 1 1 n ! a u d i M,,M 44 mH= ^ . 2 = 0,3 gam h^ụ'í,^ j , ?.( w " (n'l «)'< iaUW' ^ f ^ w K ' / 18 " m o = 2 . 9 - ( 1 . 8 + 0,3) = 0,8 gam ^ x : y : z = ^ : ^ : ^ = 0 , 1 5 : 0 , 3 0,05 = 3 . 6 : 1 " V " 12 1 16
Cong thiJc nguyen cua A m (C3H60)„ ! . / , _ ^
Cong thiJc phan tuf cua A l£l: C3„H6„0„ ' ' ^. i l U U
=> C T C T thu gon C2nH,„(CH0)„ "' ' ' " ^' ' Ta cd: 5n + n S 4n + 2 => n < 1 => n = 1 => Chon C . ' ' 302
Z&u 19. Goi cong thiJc cua andehit la R(CHO),
• Cong thu-c cua axit la R(COOH),
R + 29z „ - „ ' ' : v .:)H':;rU;L*kf3?infi • V V . '
í>!f:>::H:j k! id ar:: : •
T a c d ti 10: • = 0,7435 =>R = 29z R + 45z
I Vay R = 29: C 2 H 5 -
=> Chon C.:;.) .vvht-j Sivtif\ rt'Ó'^ ufl::;.i(n,4l 9 i'(;;bM:|:::'«<*>iií''t .i^t ,
Su20. Sđo phan iJng nhiTsau: ./irmg 1
+Br2
[>
•ChonC.
^ ; ^ ^ ' ' - ' ^ C H 2(CHO) 2
» , 2,9.44 Q.'^^i :si ::rf)!fio fii-jf* H;':s afc? sr.i^ih -Sdri:. artfi;^ (?)•>
U2 1 .M A= - ^ = 5 8 d v C ,
2,2 +• iMXn^ ^\ - Hmyjii
SomolAphanúng= ^ = 0,05mol ,1 > . ' , ,
S^moíAg'tao thanh = ^ = 0 , 2 mol l ' " ^'
108
,.;Ti le s6 mol A : s6 mol Ag = 1 :4.'y-:' ••• •-^•^ '^r.^.^^'''•",'•'•.;':"„.'
=> A cd 2 nhdm chuTc hoac A la HCHO, tuy nhien M = 58. ^'^'^ '''''''^ : V|y A la (CHO)2: andehit oxalic. « ~ ,ii sT . M
Ti 1§ so mol Ag : so mol 2 ankanal = 0,8 : 0,25 = 3,2 > 2 ' ^' t
|=> Trong hon hdp phdi cd HCHO (vi 1 mol HCHO tdc dung vdi
AgNOj/NHj dir cho 4 mol Ag) HCHO + 4AgN03 + 6NH3 + 2 H 2 O - > (NH4)2C03 + 4 N H 4 N O 3 + 4Ag
a 4a (mol) C„H2„+iCHO + 2AgN03 + 3NH3 + H2O ^ C„H2„+iCOONH4+ 2 N H 4 N O 3 + 2Ag C„H2„+iCHO + 2AgN03 + 3NH3 + H2O ^ C„H2„+iCOONH4+ 2 N H 4 N O 3 + 2Ag
;*> ' 2b(mol) cd: a + b = 0.25 ^•'•'M&^i ,1^ ,i ii^b-iim .T.; '=> Chon C . u 22. So mol Ag = = 0,8 mol 108 4a + 2b = 0,8 (2) I l l ' . I ,,.(••
Giai h^ g6m (1) va (2) ta di/dc: a = 0,15 mol v^ b = 0,1 mol Mat khac: Khói lUdng dung dich giam = khoi lifdng ket tua
- khoi liTdng 2 ankanal » Khoi lUOng hon hdp = 86,4 - 77,5 = 8.9g ' : » Khoi lUOng hon hdp = 86,4 - 77,5 = 8.9g ' :
=> 30.0.15 + (14n + 30).0.1 = 8.9 n = 1: C H 3 C H O
Cfiu 23. So mol 2 andehit < " "
2 :ịcv';'> •
Vay phai c6 1 andehit la HCHO, viet phifctng trinh l|ip h§
=> andehit c6n l ^ i la CH3CHỌ
=:>Chon B. ^ ' ' -1 ' • ' • • • ' > '
Cfiu 24. Nh6m ankyl day e l^m cho tinh axit giam, nh6m ankyl c^ng Idn thi tinh axit cang giam. . ^.
(2) c6 2 nhdm - C H 3 day e manh hdn nhdm C H 3 C H 2 C H 2 - ndn tinh axit cQa ( 5 )
manh hdn (2). => Chon B. *'
Cfiu 25. Ta c6: n N a O H = 0,3.1 = 0,3 mol ' :) / s 1 D
GoicongthiJc Chung cua axit đnchtfc la: RCOOH ' | j
RCOOH + NaOH RCOONa + H j O ' ""ll '
0,3 0,3 • VS •
A p dung dinh luat bao tôn khoi lifdng ta c6:
m a x i t + m N a O H = Hlmufft + " ^ H J O Vtfl i5
^ m m u < ? , = n i a x i i + m N a O H - mH20= 16,6 + 0,3.40 - 0,3.18 = 23,2 (g)
Cfiu 26. Ta c6: nhhaxi, = | ^ = , , 4 ' ' ^ " ' ^ ^ = 0.025 mol
^ . ( 1 3 6 , 5 + 2 7 3 ) o ; ,
273 ' t • •
1:65 , • . . . n . ; ' - gAioro ,1^.^
44
=> so nguyen ti3f C trung blnh trong hon hdp 2 axit = = - ^ ^ ^ = 1,5 iT "hh 0.025 * => trong hon hdp 2 axit phai c6 1 axit c6 I C do la axit HCOOH.
=> day dong đng ciia 2 axit la day dong d i n g axit no đn chiJc: C-H2-O2
Vdi n = 1,5 m a x i , = (14n + 32).0,025 = (14.1,5 + 32).0,025 = 1,325(g) => D a p an A .
Cfiu 27. Cdc chat 2, 3. 4 deu c6 nhdm - C H = 0 trong phan tuT, nen d i u b i oxi h6a
bdiAgNOj/NHj .^•v: •-•^^í-'^'-'-''^ ' • ' ^' U ^ v' '^^•):'><'>M-íSiky^ H + 4 A g N 0 3 + 4NH3 + 2H2O *^ (NH4)2C03 , ' t ' + 4 N H 4 N 0 3 + 4 A g 3 0 * nc02 = = 0,0375 mol H C D. H - 1 . . . . 1 ...oJ H - — C - 0 + NH4NO3 + 4Ag • i f ' ; +2NH4N03 + 2Ag => Chon B.
Cfiu 28. G o i cong thiJc cua axit no đn chiJc la CnH2n+iCOOH, viet phiTdng tfinh phan ỉng vdi NaOH tCf do tinh diTdc n = 3. Viet diTdc 2 cong thu-c cau tao
=> Chon B. V . ^ ii^/ii(fy,r,m>i0:. ;;«vr|, itii« ny&BID
Cfiu 29. n c o , = — = 0,025mol
22,4
H • '/it')
2R-COOH + M g C O j —> (R-COO)2Mg + CO2 + H2O
0,05 0,025 (mol)
0,05 (R + 45) = 2,3 0,05R + 2,25 = 2,3 < » R = 1 ,
Vay CTCT cua axit m HCOOH ^ Chon A . ' ^ '
Cfiu 30. Chu y phan ỉng giGa C H 3 C O O H vdi Cu(OH)2 xay ra theo kieu axit-bazd, chỉ khong tao CU2O nhif trong phan iJng cua andehit. J Q , ,
Cfiu 31. Gom c6 cac dong phan sau:
CH3 H CH3 C O O H
H C O O H H H
But-2-enoic axit But-2-enoic axit ^ ,
H 2 C = C C H - C O O H H 2 C = C C O O H tf'^-'- H ^ CH3 tf'^-'- H ^ CH3
But-3-enoic axit ''^ * W 3 - 2-metyl-acrylic axit
— C O O H iiciMsifHi
Xiclopropancacboxylicaxit =>ChonC. ,?• ? , t , • iwv D r H >
Cfiu 32. Goi X, y 1^ so mol cua axit acrylic v^ axit propionic trong hon hdp.
C H 3 C H 2 C O O H + N a C H j C H z C O O N a + I R Z 5 " '
2 '\hií'!íAh fi'Vị^-ri:.
Phan d;ng vi phuong ph^p giii H6a hqc 11 HCTu co - D8 Xuan Hung
CH2=CH-COOH + Na - » CH2=CH-COONa + - H , ' ^ ' '
C H 2= C H - C 0 0 H + H2 ^ CH3CH2COOH r
Theo de ra ta c6: 74x + 72y = 1 0 , 9 ( l ) v a | + ^ = 0,075 (2) 3 ,,?r} < Giai h? gom ( I ) va (2), ta diWc: x =0,05; y= 0,1 mbl ' ' ' ""' ' ' '/
So mol axit CH3CH2COOH thu diTdc sau phan ilhg = x + y = 0,15 mol ' Khoi lUdng cua axit sau phan iJng hidro hoa = 0,15.74 =11,1 gam ''''^
i=>ChonB. xkíhr^' ^'V'^^ : .flf^i^jiHâ^^ .yV'' •^'^^ Cfiu33. Difa vao phan u^ng t^ng quat: ' ; '
R - C O O H + N a - > R-COONa + ^H2^^ V ^^^^ ;vs^
" ' . ' ' • ''S 2 24''-''' ^'^^ + "^'^^'^'^
Ta thay s6 mol axit gap 2 l l n so mol H2 = 2. ^ j - ^ = 0.2 mol. v.^ T ' j T l v| '
• Mat khdc, khi hidro h6a hôn tôn thl trong san ph^m chi c6 axit propionic vdi
so mol = mol hon ban dau = 0,2 mol'"'' ^''>^*^'i ^•"*-':'-*s«'^'' •^"«-'
Vay khoi lUdng axit thu diTdc = 0,2.74 = 14,8 gam. > '''' ''"5^? '•"
: ^ C h o n C . „ . , j , . , . . . . . ' • - • :,,,M^^^lam(rth9' :Mjií
C&uM. Sđ6phantfngnhUsau: " -X.^X' J'^"^
vv,.j^,-
nCHjOH + nCHj^CH-COOH ^nCH2=CH-<;OOCH3 ^ - -CH^-^
32n(gkm) 7 2 h ( g a m f 86n (kg) OOOCH3
200 (kg)
Khói lifcJng cda C H 3 O H thiTc t e ' c i n lay l a : x = ^ O ^ ^ ^ l O O , ^ 137,8kg K h ^ i lUldng cua CH2=CH-COOH thifc t ^ m y la: , j3, , „ , „ „ v . j , , , ^
200.72n.100.100 , ; , ' = 86n.90.60 = ' ^ ' ' ' ' ' ^ • -'^^ -^''^' ^^^^^ F^-''^;|,PP^^^^^^^
n ^ C h o n D . V 4
Cfiu 35. Cho Cu(OH)2 v^o tat ca cdc mau thuf sau d6 dun n6ng ^ng nghi^m:
I Mau xulft hỉn ket tua d6 gach la CH3CHO: * l
- M a u tao dung dich mau xanh nhat la C H s C O O H , ^ ^ ^ MCX)3i,íi"''?H3
- M a u tao dung dich xanh tham 14 glixerol.
- ' M a u khong l^m tan Cu(0H)2 m C5H5OH. : ^ ;j => Chon B.
306 ./•'^.'•/'^ • •••'^
C a u 3 6 . HCOOH + CH3OH < => HCOOCH + H2O '
Ban dau: 2 mol 3 mol Phanifng: x mol x mol
Saup/iJ: 2 - x 3 - x x , \„ = 0,5 (1) X X ' [ H C 0 0 ~ ] [ H 2 0 ] V, ,Vj [HCOOHjfCHjOH] '2-- X 3 -- X V [ V )
V d i V la the tich cua hon hdp. f,>> " ^'V I ' M ' ^ I ^ ^ ^ ^ ^ ^ ^ ^ , ' \
Tir (1) ta CO phifcJng trinh: x^ + 5x - 6 =0 => x = 1. ''lipj.i^.i ^ .j)/)! • : v , ^
= > C h o n A . Ir.iM i-iiji: 'idM., i B , ' _ f-i#
I u 3 7 . . ...^ ''Zí"'' •
• Goi R(COOH), I I cong thdt cua X;' ' '4}.: f : MS
R(COOH), + z K O H R(COOK), + ZH2O hi A dr.> n^;V<«Siii ^iJi^^^ •
a az (mol) , • / •W;:; • •... • ' [az=0,01 ' ' +
[ăR + 45z)= 0.58(2) V I - P .1 ^ -
L a y ^ = > R = 13z ^ „;,r;:^
."'f|;3.£f Y iifc'Jlswp gfi^f »ỉri:( 11,06;^ J f i i ' r „.;„"
• M a t k h d c M x < 1 5 0 n e n z < 2 , 4 ^ „ . „ ,, + Khi z = 1 thl R = 13: CH loai do khong phu hdp hoa tri , '
+ K h i z = 2 thl R = 26 => X c6 cong thiJc thu ggn la C2H2(COOH)2 ' *^ '' '
> Chon B. , au 38. 1 ,«'i:5.''. n X n X (mol) , „ 'i^M^ •(14n + 32)x = 15,2 f x = 0,2 4 4 n x - 1 8 n x = 18,2 I n =3,5 • CTCT C2H5COOH C3H7COOH . Chon C.
~au 39. Do so mol CO2 = so mol niTdc nen trong phan tuT X chi c6 1 lien ket n, do đ X phai Ik axit no đn chiJc. Khi đ y = 2x + 1. ' i ' " ' '
. Chon Ạ :a.
Phan d g n g va p h u o n g phap giSi H 6 a h p c 11 HCu CO - D5 n ^ng
C a u 40. Chu y cong thiJc: , ỹ •>.-.HOOMi ' • - 1
So nguyen tuT H + so nh6mchỉc < 2. so nguycn tur C + 2 .
=> Chon D. . ,
Cau 4 1 . TO cong thỉc C^UyO,
=> Cong thuTc cua axit c6 dang: C2x-/H2y-/(COOH)^
TOdotaco: ^ ^ + - = 2 . ^ ^ + 2 ^ y = 2 x - z + 2 j j ' ^ ' ^ "
2 2 2 ,
=> Chgn B . • — ^ ^ ^ ^ C S u 42. Goi cong thiJc igng quat cua A la C, H A . " f t ' ' ' M^f^:?)^ a-ir iil V
Ta cd: % 0 = 100 - (34,61 + 3,84) = 61.55% '^•'^ ^^^mW^i^i '
^ , %C % H % 0 34,61 3,84 61,55 A n ; / * , T a c o : x : y : z = — : — : — = — : —
= 2,88 : 3,84 : 3,84 = 3 : 4 : 4 "''J ' i «' " » ' '
Vay cong thurc nguyen cua A la (C3H404)n ^'S-" • - ^'^ ' '-^ '
=:> C o the Viet C3nH4n04„ => C„H2„(COOH)2„ , •) '
Dieu kỉn ben: 2n + 2n < 2n + 2 • j M l - , , , ^ , ^ n < 1. Vay n = 1 • ' " " i i " í. -* i j i Ji '
Do do axit c6 cong thtfc la CH2(COOH)2: axit malonic , , s
::>ChonẠ
Cau 43. Goi cong thtfc tdng quat cua Y la CxHyO, , ^ , ,,
mc = l,2g; niH = 0,lg mo = 4,5-(1.2 + 0,1) = 3,2 gam
T > m c . m H . m o 1 , 2 . 0 , 1 . 3 , 2 '
T a c o : x : y : z = — : - ^ . — = - . - . - = 1 . 1 . 2
r:> Cong thiJc nguyen cua Y la (CH02)„ ^ , , ^
=^ CTPT la C„H„02n hay (COOH)„ ' ^ ' n < 2. Ket qua hdp li khi n = 2 Y la HOOC-COOH , p ! ^ / i ' , , * ,.,
= > C h o n C . , , /
I I
Cau 44. Ta c6: n^^ = — = 0,35 mol ' '
^ 108 * M ,/| . , , _ M / ( / , i , ) j
Goi cong thiJc chung cua 2 andehit la RCHỌ ' • , „ . n i ' • , ' RCHO + A g 2 0 RCOOH + 2Ag 4 (1 > . ! ! ) !
' T a c o : J l ^ = = 3,5 > 2 ^. HRk^t ^' "andehit 0,1 „V ' v., , ,
=> 1 trong 2 andehit phai Ih HCHO hay CH2Ọ - , , , , , - ,,
=i> andehit ke tiep cClng day dong dilng l i CH3CHO hay C2H4Ọ , , , ,,
D a p an Ạ /(..}'' 308 4 3 , 2 , , Cau 45. Ta c6: n^g = — — = 0 , 4 mol = M = 2 =^ X CO 1 nhom CHỌ nx 0.2
Goi cong thiJc tong quat cua X la RCHỌ O J> n a ; Mi
De cho: Mx = 16.4,25 = 68 Ci> M R + 29 = 68 => M R = 39 (C3H3 -)
" A e a4 4 ^ . h'- f-. ^
M a t k h a c : & - = - ^ = - < 2 ^ • chiJng to trong X c6 chiJa lien ket ba (C = C) dau mach.
=i> CTCT dung cua X la HC ^ C - CH2 - CHO D a p an Ạ Cau 46.
Ta c6: nH^o =T^ = ^ "^"^ ^ "02 = = 3.4 mol - Goi cong thtfc chung cua hon hcJp X la C - H - O . , , ,.
C-H-O + (X + ^ - ^ ) 0 2 XCO2 + ^ H 2 0 .'^
I m o l ( x + T - r ) ^ T
- = 3 r - 1 /t
V
Phan tuf khoi trung binh cua hon hdp X: ,;; . ^CHJi • <)liJjIS i i M x = 1 2 x + y + 16= 12.2,4 + 6 + 16 = 50,8>! , .
M 5 0 ^ - . • 4 : ' ; , • y|;V-li,..M - 4 ' ; ' |
=> D a p an D. Bit^n^Ajl <i)k:; : i u i t i i ; . ! : - gju;
C S u 4 7 . - ; • ) .5 • ! ^ " 'í*'^'- ...fV'^''
10 8
T a c d : n A g = — ^ = 0,1 mol ^ /,,„jn - + ^ 1 0 8 • '
HCHO + 2Ag20 ) CO2 + H2O + 4Ag i " ' ' " 0,025 i ' ^ - ; ' ' - ''"'WS^^^ ,-';.«0..t v,„«;n ;iis:OJ i f i ' t s ^ j ' - ' i r ' ' - i i K A i ' V ' ;
:^ C%(HCHO) = ^ : ^ ^ . 1 0 0 % = 38,07% ^ '
P h a n d g n g v S phifang ph^p gi^i Hoa hpc 1 1 HOu CO - B5
C a u 4 8 . G o i c o n g thuTc c h u n g cua 2 a n d e h i t la R C H O . v i , , .
R C H O + io2 ^ " "'^"> R C O O H
Di/a v a o p h U d n g t r i n h p h a n i l n g ta t h a y :
TU 1 m o l R C H O 1 m o l R C O O H thi kh6'i liTdng tSng 16g hay M B = M A + 16
D o d o : d B / = = ^ = - ^ = = 1 + ^ — (1) / A M A M A M A • " ' ' . . , A " , V d i M H C H O = 3 0 < M A < M C H J C H O = 4 4 the v a o ( 1 ) t , i , . , *'f ^ ^ i ^ < d < ^ = ^ b a p ' a n C . ' ' ' " ' ^ " >1 15 ^ ) 1 5, » 1 ' M i 3 C 3 u 4 9 . s.;,;. [Q = b m o l => Phifdng I r i n h p h a n l i n g : . / ; , . , , i > v . ;n
C2H2 + Ag20 3 ' ) C2Ag2 i + H2O
C H , C H O + Ag20 ^ ^ 3 ' ^ ) CH3COOH + 2 A g i T; „
T a c d : m,ha-,rin = " ^ C j A g j "^Ag = 5,64 <=> 240a + 108.2b = 5,64 ( 2 ) D a t n p j_j = a m o l ; p j ^ O = => 26a + 44b = 0,92 ( 1 )
T i r (1) v a ( 2 ) a = 0,01 v a b = 0,015 , ' i ^ -v
^ %C2H2=M1:^. 1 0 0 % = 2 8 , 2 6 % ' '^'•il.iMnr''-'^^^
=> % C H 3 C H 0 = 1 0 0 % - 2 8 , 2 6 % = 7 1 . 7 4 % =i> D a p a n B . tMíifS cikm
C&u 50. A n c o l đn chitc X - i ^ andehit Y ^ X la ancol b§c 1: RCH2OH. RCH2OH + I 0 2 ^ " ^ ' ^ ° ) R C H O f H2O
' A p d u n g d i n h l u a t b a o t o a n k h o i l i T d n g l a c d : Jll os ffjfcd
m x + nriQ = n i y + m,„,„idu + mp^ Q s i f '
« m x + mô = m h ^ „ M p = 8.4 , ''••ỉ^ 1,0 - — • -
m o j = 8,4 - m x = 8.4 - 6 = 2,4(g) => = 0,075 m o l . jt-yị*
T h e o phifdng t r i n h p h a n iJng: n,,na,i = 2. nQ^ = 2.0,075 = 0,15 m o l . 13,0
D o p h a n i l n g o x i hoa v d i h i ^ u suát phan iJng k h o n g d ^ t 1 0 0 % n e n : ,, ;;,;r)
6 ••• 'A y^^'!i^^,.ị'^^h,C., "
nx phan iJng < nx ban Jau < = > U , 1 3 < — - — ,
310
KifAKgflinrBt
=> M x < 4 0 => ancol X la CH3OH andehit Y la H C H O .
H i e u .suat p h a n iJng: H = ^ ' ' ^ - ^ ^ . 1 0 0 % = 8 0 % D a p a n A .
•1,
" C S U 51.
PhiTdng t r i n h p h a n iJng:
QH2 + H2O CH3CHO
G o i a la so" m o l C2H2 b i hidrat hoa, b la so m o l C2H2 con l a i . 44a + 26h T a c d : M A = = 20,2.2 = 40,4 => a = 4 b a + b a 4 b H i ? u suat p h a n lirng: H = . 1 0 0 % = - ^ . 1 0 0 % = 8 0 % => D a p a n C . • "^^^^ 'iavf:wm:}}^<^.^H^r..r. €m. minKmmMM 2 i,*)-^ • 3 3 6 C2H2 + H20 " g ^ ^ ^ ' " " > CH3CH0
V i hỉu suat 6 0 % nen so m o l C2H2 tham gia phan iJng = 0 , 1 5 . 6 0 % = 0 , 0 9 m o l => so m o l C2H2 chufa p h a n tfng (con dif) = 0 , 1 5 - 0 , 0 9 = 0 , 0 6 m o l
S'C T h e o phiTdng t r i n h p h a n iJng : n ^ j ^ H phan<i«g = 0 , 0 9 m o l
3 2 2 h 6 n h d p A g o m C2H2: 0 , 0 6 m o l v a CH3CHO : 0 , 0 9 m o l '