C. Xiclopropa n; D Xiclobutan ,'
KHAiyG VIET
Cfiu 49. Cho 0,92(g) hon hdp gom C2H2 va C H 3 C H O tac dung vCfa du v d i dung dich
A g 2 0 / N H 3 thu du-dc 5,64(g) hon hdp r^n. % khdl lUdng cua C2H2 va C H 3 O H Ian l U d t l a : t ^^•;;i.:4,rVị-tri, * < •;;,):?•',
Ạ 4 0 % v a 6 0 % WMd-^'-XOf^'i^iJ 1 B . 28,26% va 71,74% C. 60% va 40% D . 25,73% va 74,27%
Cfiu 50. O x i hda 6(g) ancol đn chúc X thu dUdc 8,4(g) hon hdp gom andehit Y , ancol dir va H2Ọ Hi$u suat phan iJng vk CTPT cua andehit Y Ih:
Ạ 80% va H C H O B . 80% va C H 3 C H O
C. 85% va H C H O .v;;,^ị«:..,V'' D. 85% va C H 3 C H O -•'•'^') •:''^^'^ •
Cfiu 51. Hidrat hda axetilen thu diTdc hon hdp A gom 2 chát hffu cd, ti khoi hdi cua A so v d i H2 la 20,2. H i f u suat phan iJng hidrat hda axetilen la:
Ạ 70% B . 75% C. 80% D . 85%
Cfiu 52. Hidrat hda 3,36 l i t C2H2 (dktc) thu diTdc hon hdp A (hieu suat phan iJng 60%). Cho hon hdp san pham A tac dung het v d i dung dich Ag20/NH3 dif thu difdc m(g) chat ran. Gia tri cua m la: ; ' i n í.D r i
Ạ 19,44 . ' i " B . 33,84 =^.!;!JV C. 14,4 •,j:';=u D . 48,24
Cfiu 53. Hon hdp A gom 2 andehit no đn chuTc. Hidro hda hokn toan 0,2 mol A , lay san pham B dem dot chay hoan toan thu dUdc 12,6(g) H2Ọ N e u dot 0,1 m o l A thi the tich C O 2 (dktc) thu di/dc la:
A . 11,2 l i t B . 5,6 lit C. 4,48 l i t D . 7,84 l i t
'' HUdm D A N G I A I \; „„., •
Cfiu 1. Cho Cu(OH)2 vao ca 3 chat tren ' * ' ^ " ' '
- . , , v , , , , . ^ , , -.mt !/rfj T . ) 1 •
Neu dun nong thi propanal phan Úng tao ra ket tua do gach
C H 3 C H 2 C H O + 2Cu(OH)2 C H 3 C H 2 C O O H + CuiOi + 2 H 2 O '
r,,:- (dogach) ''ir;;-^
Glixerol tdc dung v d i C u( 0 H ) 2 tao dung djch phỉc m^u xanh lam
Cfiu 2. Cho hon hdp phan itng v d i NaHS03, xuaft hi^n ket tua hidrosunfit. Sau do axit hda, thu dÚdc andehit.
"•ị>„.ti C H 3 —C H O H • ; ji^iy; '5.'; '(;•')!,? :v C H 3 —C — H + N a H S O j p,, S O j N a C H 3 —C H + H C 1 ^ C H 3 —C H + S O 2 +NaCl + H j O O H
an dgng va phuong ph^p giai H6a hpc 11 HOu CO - 05 Xuan Hang
=> Chon Ạ
&u 3. Cic dong phan tham gia phan iJng trang gifdng 1^: :' . '•i;i,-\':r.;;y
CH3CH2CH2CH2CH=0 • CH3CH2CH(CH3)CH=0 C H 3 C H( C H 3) C H 2 C H= 0 « • CH3C(CH3)2CH=0 C H 3 C H( C H 3) C H 2 C H= 0 « • CH3C(CH3)2CH=0 =>Chon B .
740.3,792 ' " . . v . . , . , . , . . .
&u 4. So mol N O 2 = — ^ = 0,15 mol MvSt .f .^^H
0,082(27 + 273) , .^f-W.., .
Goi cong thiJc cua andehit mach hcl la R(CHO),.. PhiTdng trinh phan ifng nhiT sau: R ( C H O ) , + 2zAgN03 + SzNHj + zHjO — ^ R(COONH4),,
ămol) ..,..,.;.,„-.,..,.„;. + 2 Z N H 4 N O 3 + 2zAg . • ; : i v-l/í^-v h
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Ag + 2HNO3 -> AgN03 + N O 2 + H 2 O » A i R n . i H .SZ s.;
^ ''^ '"^ ^''iihni ^!.v• 0,015 mol ..^•iM'í^M^'fM óO => az = 0,075 mol • >.-rM.mfik';íf'ixMff,^^^^^
Mat khac: ăR + 29z) = 4,2 => aR + 29az = 4,2 ! M ^-h^^lJ
aR = 2,025=> R = 27z . M i w . ., ^ M i i J . t^,» u i t M'i^^'ff^yS^mtru A ':^d 'iAíMí'Ki
Khi z = 1 => R = 27: C H 2= C H -
Khi z = 2 R = 54 (loai) do R + 2.29 = 28.4 (loai)
Vay andehit la C H 2= C H - C H O , ( 1 <;!',;,n
-> Chon D. •? ,
:au 5. C T D G : C3H5O => C T N : ( C 3 H , 0 ) „ C T P T : C 3„ H 5 n O „ . , , • ,
^ C T C T thu gpn: C2„H4n(CHO)n
Do andehit no, mach hd nen: 4n + n = 2n.2 + 2 => n = 2
^ C h o n c . • ' ---^nm
:au 6. HCHO + 4 AgN03 + 6 NH3 + 2H2O (NH4)2C03 + 4NH4NO3 + Ag
(Y)
(NH4)2C03 + 2NaOH ^ Na2C03 + 2NH3t + 2H2O : • Ivi; ?
(NH4)2C03 + 2HC1 2 N H 4 C I + C O 2 T + H 2 O ^^^^ ''^'H '^^^
=> Chon C . >:' ' i •• '
' 3 u 7 . T a thay khi thiTc hi§n phan iJng hidro hoa hoan toan thi so nguyen tijf C van bao toan, nghia la dot ancol thi khoi lUdng (hay so mol) C O 2 van b^ng khoi liTdng (hay so mol) C O 2 cua andehit ban daụ
Tir nhanh (1) cua sd do la thay n^o, = '^HJO
0 36 " ' , !.
nen m r n - , = - ^ — . 4 4 = 0,88gam • 1
^ " 2 18 ^ t">H/. . i , h *,»
Chon B . , • " , .;. r'. ..1' • '
C&u 8. CAc ban dCfng qud quan tSm dén hi^u suaft hidro h6a, bdi nguyen tiir C difdc
b^o tôn, nen khi dot chdy thi mcoj thu dUdc sau khi hidro h6a van bkng mcô thu difdc khi dót ch^y andehit ban daụ
Do đ: m c o 2 = - 7 7 ^ - 4 4 = l,32g . , , 1 O
=:>ChonB. '
Cfiu 9. Goi cong thiJc cua andehit mach hd la R(CHO),.. PhiTdng trinh phan uTng nhÚ sau: •, • ; • . • v.". 'r, •
R ( C H O ) , + 2zAgN03 + 3zNH3 + ZH2O — ^ R( C O O N H 4 ) , , a mol +2zNH4N03 + 2 z A g ( l )
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if J b'is\:i:yịii:' Tit phi/dng trinh (1) ta thay: 2az = 0,2
Mat khdc: ăR + 29z) = 5fi:^K = 27z Khi z = 1 thi R = 27. X m C H 2= C H - C H 0
=>ChonD. , , ., ,. , fciJ)v,!Hjij; J fit!'? virf; i J
Cfiu 10. ChuoiphSn tfng nhiTsau: ' , , , , , ^ , " ^ , C , H 3 C H = C H j ^"-^'"^ ) Q H , C H O H - C H , * ,
+CuO . C f i H s C O - C H ^ ° ? > Q H s C O - C H , B r Chon Ạ
Cfiu 11. Goi cong thiJc chung cho 2 ankanal 1^ C j j H j n O
Phi/dng trinh phan iJng chay nhif sau:
CnHzifO + O2 -> n C O 2 + n H 2 O ' a a n (mol) C O 2 + C a ( 0 H)2 C a C 0 3 + H 2 O ^ . an a n =0,25 (mol) (1) M a t k h i c : ( 1 4 n + 16)a = 5,l , (2) L a f y ( 2 ) . : ( l ) : o n =2,5
Vaiy ankanal can llm Ik etanal v^ propanal
=> Chon B .
I I j
Cfiu 12. So mol CuO phan iJng = so mol O = so mol ankanol. ^ =:> K L P T ankanol = 4,6 : 0,1 = 46 ankanol m C2H5OH => Chon B .
Cfiu 13. X a t s d d o sau: . |
C H = C H C H 3 C H O 2Ag 0,0025 0,005 mol
% th^ tich C2H2 = " ' " " ^ ^ .100% = 40% ' '5*;^'
^,0; 0,00625,..;,, ^^^o,.... á./: /•