C. b anot xayra sir oxi hoa: Cu > C u^^+2e
10. Dien philn c6 mang ngan 500ml dungdj ch chiia h6n hop gom CuCU 0, 1M va
N a C l 0 , 5 M (dien circ t r o , hieu suat dien phan 100%) v6\g d o d o n g dien 5 A
t r o n g 3 8 6 0 giaỵ D u n g djch thu dirge sau dien phan eo k h a nang hoa tan m gam A l . G i a trj Ion nhat cua m la
A . 5,40. B. 1,35. C. 2,70. D. 4,05.
Huong dan gidi
T h e o bai ra: n c c , , = 0,5. 0.1 = 0,05 ( m o l ) .
n^aci = 0,5. 0,5 = 0,25 ( m o l ) .
D e khir het i o n C u " * t h l thcji gian dien phan can:
(Cu-* + 2e > C u i , day la qua t r i n h khir xay ra dau tien)
mc„.n.F 0,05.64.2.96500 to, = = — = 1930 ( g i a y ) < 3 8 6 0 ( g i a y ) . A . I 64.5 => T h o i g i a n d i e n phan H , 0 ( d catot) la 3 8 6 0 - 1930 = 1930 ( g i a y ) . 2 H , 0 + 2e > 2 0 H " + H , t c - I t 5.1930 , ^ ,^ i \ S u y r a : noH = = = 0,1 ( m o l ) n.F 1.96500
Phuorng t r i n h hoa hoc hoa tan A l t r o n g d u n g d j c h t h u dirge: A l + O H - i - 3 H : 0 > | A l ( O H ) J + | H . 0,1 < - 0 , l ( m o l )
V a y m = m^i = 0 , 1 . 27 = 2,70 ( g a m ) . D a p a n diing la C .
1 1 . D i e n phan d u n g d j c h g o m 7,45 g a m K C I va 28,2 g a m C u ( N O , ) , (dien cue tro, m a n g ngan xop) den k h i k h o i l u g n g d u n g d j c h g i a m d i 10,75 g a m t h i ngirng m a n g ngan xop) den k h i k h o i l u g n g d u n g d j c h g i a m d i 10,75 g a m t h i ngirng dien phan (gia thiet lirgng nirdrc bay h o i k h o n g dang ke). Tat ea cac chát tan t r o n g d u n g d j c h sau dien phan la
A . K N O , va K O H . B. K N O „ K C I va K O H . C. KNO3 va C u ( N O j ) , . D . K N O „ H N O , va C u ( N 0 j ) 3 . C. KNO3 va C u ( N O j ) , . D . K N O „ H N O , va C u ( N 0 j ) 3 .
Huong dan gidi
T h e o bai ra: ^^^Q\1 m o l => n _ —0,1 m o l
"cu(N03)2 = 0 , 1 5 ( m o l ) = > n ^ . ^ 2 ^ = 0 , 1 5 m o l
V i mjd g i a m = 10,75(g) < m c , ^ + m ^ , = 13,15(g)
=>Cu^^ chua bj d i c n phan het, do do trong d u n g djch sau dien phan c6 C U(N 0 3 ) ^ .
K h i C r bj dien phan het t h i : ' ' " '
m c , ^ t + " V u i = 0 , 0 5 . 7 1 + 0,05.64 = 6 , 7 5 ( g ) < 1 0 , 7 5 ( g ) ,
: r > C r bj d i e n phan het va H , 0 da bj o x i hoa (V anot: , , "'^ " H , 0 - > 2 H " + - 0 , + 2 e
2 -
V a y t r o n g d u n g d j c h co: K \ * , C u " ^ , N O , ti'rc la co cac chat tan: K N 0 , , H N 0 „ C u ( N 0 3 ) , .
D a p a n diing la 1). 12. D i e n phan 20()ml d u n g d j c h li6n hgji g o m N a C I 0 , 5 M va C u ( N O , ) : 0 , 7 5 M (dicn
cue t r o , CO m a n g ngan) den k h i k h o i lirgng d u n g d j c h g i a m 1 1,65 g a m t h i dirng
laị D u n g d j c h tini dirge sau d i c n phan ehira cac chat tan la
A . N a C I va C u ( N O , ) : B. N a N O , , H N O , va C i i ( N O , ) :
C . N a N O , va C u ( N O , ) : D. N a N O , , N a C I va C u ( N O , ) :
Huong dan gidi
T h e o b a i r a : n j ^ j . ^ i - " 0 , 2 . 0 , 5 - 0 , 1 ( m o l ) " c u , N < ) , ) 2 = 0 - 2 - 0 ' 7 5 = 0 , 1 5 ( m o l ) Phirong t r i n h d i c n phan: -TrU(5c t i e n : C u ' ^ + 2 C r ^ ' l i ^ C u i + C I , t 0 , 0 5 < - 0 , l > 0 , 0 5 - > 0 , 0 5 ^^-^'-^ = > m , , = 0,05. 64 + 0,05. 7 I = 6,75 (gam) .Oi:.: . - T i e p l h c o : C u ^ ' + H , O ^ ^ C u i + 2 H' + | o , T 0,1 > 0,1 - > 0,05 md.,„a , „ = 0 , 1 . 6 4 + ( ) , 0 5 . 3 2 = 8 ( g a m ) V I m , , , , „ „ + m , , , „ ,„„ = 6,75 + 8 = 14,75g (> 11,65 g a m ) ^ Q r * chua b, dien phan het ( C f da bj d i c n plnui het). ... V a y d u n g d j c h t h u dugc chua chat tan: C u ( N O , ) , ; H N O , ; N a N O ,
, D a p a n diing la 15.
an loai vii phifcfng phcip gidi Bl Hon hoc 12 — Cii Thanh Toan
Dang 9: Bai tap dien phan h6n hop C U S O 4 + NaCl