continued mapped maximum considered earthquake spectral response acceleration 5 percent damped at 1 sec period s1 for site class b for the conterminous united states
... calculated by the transforming the fields calculated at < /b> the boundaries of the simulation using the free-space Green’s function [10< /b> ] A signature of the farfield is that the E field is orthogonal to the ... analysis of thespectral < /b> response < /b> of an NSOM measurement 51 /b> Fig Far-field patterns for < /b> PEC bowtie aperture, a = b = 15< /b> 0< /b> nm, (a) below the cutoff wavelength, λ = 50< /b> 0 nm, (b) above the cutoff wavelength: ... that the field is disturbed by the probe and very little of the energy propagates into the probe To calculate an NSOM signal, the Poynting vector is integrated over the signal plane of the probe...
... N 1 < /b> 55< /b> 5 13< /b> .4 Power Spectrum Estimation Using the FFT square window Welch window amplitude Hann window 0 50< /b> 10< /b> 0 15< /b> 0< /b> bin number 200 250< /b> Figure 13< /b> .4 .1 < /b> Window functions commonly used in FFT power spectral < /b> ... 1 < /b> (13< /b> .4 .5)< /b> where fk is defined only for < /b> the zero and positive frequencies fk ≡ k k = 2fc N∆ N k = 0, 1,< /b> , N (13< /b> .4.6) By Parseval’s theorem, equation (12< /b> .1.< /b> 10), we see immediately that equation ... that the periodogram estimates not become more accurate at < /b> all! In fact, the variance of the periodogram estimate at < /b> a frequency fk is always equal to the square of its expectation value at < /b> that...
... number records number records (76) (44) (13< /b> .2%) (22.7%) Between 11< /b> and 20% 10< /b> (22.7%) (13< /b> .2%) (22.7%) Between 21 < /b> and 30% (13< /b> .6%) (7.9%) (13< /b> .6%) Between 31 < /b> and 50< /b> % 11< /b> ( 25%< /b> ) (14< /b> .5%< /b> ) ( 25%< /b> ) Greater ... notified bodies groups NB had conflict of interest 33 (43.4%) (43.4%) 12< /b> ( 15< /b> .< /b> 8%) ( 15< /b> .< /b> 8%) 16< /b> ( 21.< /b> 1%) ( 21.< /b> 1%) (11< /b> .8%) (11< /b> .8%) Lower quality of service performed by subcontractor or subsidiary of NB Other ... Member States notifying a body must include information on the evaluation of competence of that body Other Member States have the possibility to object to the notification within a certain period...
... reanalyzed the Rakai data, determining that the data did not allow for < /b> a clean estimate of per-act transmission probability but only for < /b> a per-time -period < /b> transmission probability Both Eaton et al [11< /b> ] ... Edited by: Jewell NP, Dietz KF, Farewell VT Boston: Birkhauser; 19< /b> 92 :14< /b> 3- 15< /b> 5< /b> Watts CH, May RM: The influence of concurrent partnerships on the dynamics of HIV/AIDS Math Biosci 19< /b> 92, 10< /b> 8:89 -10< /b> 4 Altmann ... used these estimates as well, the former exclusively, and the latter for < /b> their fourth model In the Hollingsworth framework, there is no explicit estimate for < /b> the number of coital acts per time period;< /b> ...
... (molar ratio is 1:< /b> 2) until the pH reached 13< /b> Then, the reaction continued < /b> for < /b> h to obtain the black colloidal particles (Fe 3O4) Then, the air was pumped into the reaction system under the 95< /b> C water ... time and the Figure Schematic illustration of assembly mechanism based on the field periods and the colloidal relaxation time If the relaxation time is above theperiod < /b> of field, the assembly can ... among the nanoparticles In this case, the relaxation time should be calculated based on the size of isolated nanoparticle rather than that of nanoparticulate cluster The relaxation time of 11< /b> -nm...
... clones 10< /b> 07, 10< /b> 19: 4.0+ 5.< /b> 6- 5.< /b> 6+ 4.0-; clone 10< /b> 11:< /b> 4.0+ 5.< /b> 6- 4.0- 5.< /b> 6+ (sorted from low to high, underlined treatments are not significantly different at < /b> P Theresponse < /b> of the conductance for < /b> ... differences between the treatments Similar results (not shown here) were obtained for < /b> top shoot growth of clones 10< /b> 11 < /b> and 10< /b> 19, the latter showing lower final lengths (A 11< /b> 2 -13< /b> 6 mm), lower b- values (b ... mm, b 5.< /b> 7-6.9, k 0 .13< /b> -0. 15< /b> < /b> d-! The point of inflexion, where half of the final length was reached, was on d 44-48 ( b/ k) = Absolute growth rates were also very similar as can be deduced from the...
... measured at < /b> 25< /b> C in their culture medium (Bligny and Douce, 19< /b> 76) Results cates that the rate of Effect of sucrose starvation on the rate of consumption by sycamore cells For < /b> 24 h the respiration rate ... (Roby et aL, 19< /b> 87) This was attributable to the fact that such a rapid synthesis of cell metabolites transiently consumed high levels of ATP rate of consumption by sycamore cells attributable ... survive for < /b> a long time after the synthesis or the supply organic carbon has been terminated of References ap Rees T (19< /b> 85)< /b> The organization of glycolysis and the oxidative pentose phosphate pathway...
... lactations are very similar The heritabilities for < /b> the first and third lactations may, at < /b> least for < /b> yields, be treated as equal The slight decrease of the heritability for < /b> the second lactation ... Madrid, pp 54< /b> 1 < /b> -56< /b> 3 Meyer K (19< /b> 83a) Maximum < /b> likelihood procedures for < /b> estimating genetic parameters for < /b> later lactations of dairy cattle J Dairy Sci 66, 19< /b> 88 -19< /b> 97 Meyer K (19< /b> 8 3b) Scope for < /b> evaluating ... lactations For < /b> milk yield, the weighted means of the estimates in the literature are 0.26 for < /b> first lactation, 0.20 for < /b> second lactation and 0 .17< /b> for < /b> third lactation (Maijala and Hannah, 19< /b> 74)...
... relation 1 < /b> .5 < /b> above, we have q0 e, q1 b1 , 2. 25 < /b> 1 < /b> 1 < /b> 1 < /b> 1 < /b> b1 and ρ q1 · q0 ρ b1 ≤ 1/< /b> 2 < then, q1 1 < /b> 1 < /b> Now, suppose that for < /b> n ≥ 2, qn 1 < /b> exists and ρ qn 1 < /b> · qn−2 < Then, from recurrence relation ... ρ b c 1 < /b> ≤ Proof Since σ b1 < /b> · c ⊂ B 0, , we have ρ b1 < /b> · c < So the element b c is invertible in A Its inverse is b c 1 < /b> b1 < /b> e 1 < /b> b1 < /b> · c ∞ b1 < /b> · 1 < /b> n b1 < /b> · c n 2.23 n So, ρ b c 1 < /b> ∞ ≤ ρ b1 < /b> ... bn · Km 1 < /b> , 1 < /b> 1 < /b> ≤ ρ an · bn · ρ bn · ρ Km · ρ sm 1 < /b> Since from 2.33 ρ bn · sm 1 < /b> n sm 1 < /b> 1 1< /b> ρ 1 < /b> bn n · sm ≤ 1/< /b> 2 < 2, 1 < /b> and ρ bn ≤ 1/< /b> 2 n − sm 1 < /b> · ρ Km 1 < /b> 2.36 < 1/< /b> 2, then, using Lemma 2 .11< /b> ,...