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... Phys B ( 20< /b> 0< /b> 8) 93: 47 54< /b> DOI 10.< /b> 100< /b> 7/s 003< /b> 40-< /b> 008< /b> -3178 -0 < /b> Numerical analysis of thespectral < /b> response < /b> of an NSOM measurement E.C Kinzel · X Xu Received: 29< /b> June 20< /b> 0< /b> 8 / Published online: 30 < /b> August 20< /b> 0< /b> 8 ... bowties using a probe with r = 75 < /b> nm with aluminum films E.X Jin, X Xu, J Microscopy 22< /b> 9, 50 /b> 3 51< /b> 1 ( 20< /b> 0< /b> 8) L Wang, X Xu, Appl Phys Lett 90,< /b> 26< /b> 11 05< /b> < /b> ( 20< /b> 0< /b> 7) H Bethe, Phys Rev 66, 163–1 82 < /b> (1944) X Jin, ... the presence of an NSOM probe for < /b> a bowtie sample with a = b = 1 50 /b> nm It can be seen that the field is disturbed by the probe and very little of the energy propagates into the probe To calculate...
... trade@cup.cam.ac.uk (outside North America) ≈ Wss N−1 55< /b> 5 13.4 Power Spectrum Estimation Using the FFT square window Welch window amplitude Hann window 0 < /b> 50 /b> 100< /b> 1 50 /b> bin number 20< /b> 0< /b> 2 < /b> 50 /b> Figure 13.4.1 Window functions ... case, the equations for < /b> the periodogram estimator (13.4.4–13.4 .5)< /b> become N−1 Dk ≡ cj wj e2πijk/N k = 0,< /b> , N − (13.4.9) j =0 < /b> P (0)< /b> = P (f0 ) = |D0 | Wss 2 < /b> |Dk | + |DN−k | Wss P (fc ) = P (fN /2 < /b> ) ... data at < /b> the same sampling rate, or else by resampling the same stretch of data with a faster sampling rate), then how much more accurate the estimates Pk become? The unpleasant answer is that...
... number records number records (76) (44) (13 .2%< /b> ) (22< /b> .7%) Between 11 and 20< /b> %< /b> 10 < /b> (22< /b> .7%) (13 .2%< /b> ) (22< /b> .7%) Between 21< /b> and 30%< /b> (13.6%) (7.9%) (13.6%) Between 31 and 50 /b> % 11 ( 25< /b> %< /b> ) (14 .5%< /b> ) ( 25< /b> %< /b> ) Greater ... ( 10 < /b> .5%< /b> ) % of total % of total number records number records (76) (64) ( 10 < /b> .5%< /b> ) ( 12 < /b> .5%< /b> ) Moderate improvement 23< /b> ( 30.< /b> 3%) ( 30.< /b> 3%) ( 35.< /b> 9%) Significant improvement 27< /b> ( 35.< /b> 5%) ( 35.< /b> 5%) ( 42.< /b> 2%) Unable ... notification process: Member States notifying a body must include information on the evaluation of competence of that body Other Member States have the possibility to object to the notification within...
... supported by grants from the National Natural Science Foundation of China (NSFC, 20< /b> 9< /b> 0 3 02 /b> 1, 607< /b> 25< /b> 1< /b> 01< /b> , 8 100< /b> 14 12)< /b> and the National Basic Research Program of China ( 20< /b> 1< /b> 1CB93 3 50 /b> 3) This work also belongs ... time The morphological images of 50 /b> and 100< /b> Hz induced assembly were shown in Additional file (Figure S2) The fibrous assemblies remain able to form Thus, the assembly mechanism lies in the attractive ... the frequency of alternating magnetic field was 20< /b> < /b> Hz, the visible fibrous assemblies nearly disappeared (Figure 2g) Theperiod < /b> of 20< /b> -< /b> Hz field was 50 /b> ms which has been analogous to the relaxation...
... u2 − ω2h 2 < /b> u2 − ω2h 1+ 2+< /b> 2+< /b> 2+< /b> ω1h − u2 1h ≤ u2 − ω1h 2 < /b> ≤ u1 − ω1h 1+ πh u − πh u 2h 1 1 + u2 − u2h 1 1 u2 − ω2h + u1 − ω1h + u2 − u2h , 2 < /b> ω2h − u2 ≤ u2 − ω2h + πh u2 − πh u2 2h 1h 2 < /b> 22 < /b> u1 − ... u1h ≤ u2 − ω2h + u1 − u1h 2 < /b> 1 u2 − ω1h + u1 − ω2h + u1 − ω1h + u0 − u0 2 < /b> 2h (3.7) Obstacle problem So u2 − u2 1h 1≤ p p =1 u2 − u2 2h 1 p u1 − ω1h p u2 ≤ 1+ p − ω2h + p =0 < /b> p p =0 < /b> p u2 − ω2h (3.8) ... u2 − ω2h , (3.6) p u1 p =1 p − ω1h For < /b> n = 2,< /b> using the discrete version of Remark 2.< /b> 3, we have u2 − u2 1h ≤ u2 − ω1h 1+ ≤ u2 − ω1h 1 1 + u2 − u2h ≤ u2 − u2 2 < /b> 2h ≤ ≤ ≤ u2 − ω1h u2 − ω2h 2 < /b> u2...
... day in 20< /b> 0< /b> 2 < /b> to 60 < /b> billion in 20< /b> 0< /b> 6 Giga Information reported that spam-mail increased fourfold during 78 MAXIMUM < /b> PERFORMANCE 20< /b> 0< /b> 1 2,< /b> with some 20< /b> 6< /b> billion junk emails circulating in cyberspace ... traffic on the Internet, up from about per cent in 20< /b> 0< /b> 0 and 40 < /b> per cent in 20< /b> 0< /b> 2 < /b> (Ellis, 20< /b> 0< /b> 3) According to analysts IDC, the total number of emails sent daily will have doubled, from about 30 < /b> billion ... has been estimated that two-thirds of visits to family doctors in the USA, the UK and Australia are attributable to stress-related illnesses (Robbins et al., 20< /b> 0< /b> 1: 27< /b> 6) Third, there has also been...
... yield, the weighted means of the estimates in the literature are 0.< /b> 26< /b> for < /b> first lactation, 0.< /b> 20< /b> < /b> for < /b> second lactation and 0.< /b> 17 for < /b> third lactation (Maijala and Hannah, 1974) In the first data set, ... smaller than for < /b> the third lactation (0.< /b> 22< /b> ) All genetic correlations were higher than 0.< /b> 89 The correlation between the first and third lactations was smaller than the others, which except for < /b> useful ... transformation, the information matrix I of the original data was obtained as it can be showed that: where D is the (6 x 6) matrix whose element (i,j) is (where 0c ) is the vector of (transformed)...
... vectorial continued < /b> fraction 2.< /b> 17 diverges and ρ U2k −1 −1 · V2k − U2k · V2k ρ p2N 2k −1 · q2N 2k − p2N 2k −1 · q2N 2k ≥ exp ∞ ρ ck > k 2.< /b> 21 So, ρ s2N 2k − s2N 2k ≥ exp ∞ ρ ck > 0,< /b> ∀k ≥ 2.< /b> 22 < /b> k This ... series n 0 < /b> ρ b2 p n 0 < /b> ρ b2 p · ρ b2 p follows that the series n 0 < /b> ρ b2 p · ρ b2 p converges too Therefore, from Lemma 2.< /b> 8 above, there exists a positive integer N ≥ such that for < /b> k k ≥ 1, the quantity ... θk−1 · θk , k q2N 2k −1 · θk , · θk , 1, 2,< /b> , q2N 2k b2 N c2k−1 2k · b2 N 2.< /b> 19 · θk−1 · θk , 2k e 0 < /b> Then, Uk Vk Uk−1 · ck Vk−1 · ck Uk 2 < /b> , 2.< /b> 20< /b> < /b> ∀k ≥ Vk 2 < /b> , This lemma is proved by the same argument...
... contradiction with the earlier assumption that γ > D This proves the theorem for < /b> D ≥ the electronic journal of combinatorics 14 ( 20< /b> 0< /b> 7), #R38 For < /b> D = 2,< /b> looking at < /b> the square of the adjacency matrix of ... 2< /b> , then we are done Suppose then that n < 2< /b> Then the vertex s has at < /b> least two neighbours at < /b> distance from the vertex w We deduce that 2 < /b> xs ≤ ( 2 < /b> − 2)< /b> xs + 2xw which implies 2 < /b> ≤ ∆ − + ≤ 2 < /b> ... http://arxiv.org/abs/math.CO /06< /b> 05< /b> 2 /b> 94 [3] Z Bo, The changes in indices of modified graphs, Linear Algebra and its Applications, 356< /b> ( 20< /b> 0< /b> 2)< /b> , 95< /b> 101< /b> [4] S M Cioab˘ and D A Gregory, Large matchings from eigenvalues,...