ADECH02 SOLUTION PROB4 1

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ADECH02 SOLUTION PROB4 1

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HANOI UNIVERSITY OF MINING AND GEOLOGY ADVANCED PROGRAM IN CHEMICAL ENGINEERING Subject : ADECH02- Petroleum Refining SOLUTION PROB 4.1 Dai Duong Van K4 – 2017 100,000 BPD ( API = 36) - Light vacuum gas oil ( 650-850°F) Heavy vacuum gas oil (850-1050°F) Vacuum residue ( 1050+°F) We must calculate the mass flow rate and the sulphur content ( lb/hr) TBP(°R) = {( ln −𝐿𝑉% API = -0.0004 𝑉% + + } 𝑉% − Light vacuum gas oil ( 650-850°F) cut (4.1) 𝑉% + (4.2) IBP = 650 °F = 343.33°C = 1109.67°R EBP= 850°F= 454.44°C= 1309.67°R Substituting in eq ( 4.1) to get LV% at IBP and EBP : Cut vol % = 42.30 - 39.09=3.21% Cut mid volume = 40.695 Substituting the cut mid volume in eq (4.2) to get API= 38.18, we get SG = 0.834 Cut volume = 0.0321(100,000)= 3210 BPD Cut amount = 3210(SG)(14.60)=3210(0.834)(14.60)=39,086.244 lb/h Calculate of sulphur content : M= 42.965[exp(2.097× M= 355.55 lb/lb mol − 𝑏 − 𝑏 𝐺+ = + − × + − 𝑏 𝐺 ] = 𝑏 𝐺 I=2.266× n= + 𝐼 −𝐼 / − exp = 1.466 − × 𝑏 + 𝐺− 𝑖 m= M(n – 1.475) = -3.19995 = − × − 𝑑 𝑏 𝐺 𝑏 𝐺− = = since M> 200 sulphur wt% = -58.02+ 38.463 𝑖 − + sulphur amount = 0.01083(39,086.244) = 423.3 lb/h 𝐺 = 𝑤𝑡% Heavy vacuum gas oil (850-1050°F) cut IBP = 850 °F = 454.44°C = 1309.67°R EBP= 1050°F= 565.56°C= 1509.67°R Substituting in eq ( 4.1) to get LV% at IBP and EBP : Cut vol % = 44.91 – 42.30=2.61% Cut mid volume = 43.605 Substituting the cut mid volume in eq (4.2) to get API= 37.25, we get SG = 0.839 Cut volume = 0.0261(100,000)= 2610 BPD Cut amount = 2610(SG)(14.60)=2610(0.839)(14.60)=31,971 lb/h Calculate of sulphur content : M= 42.965[exp(2.097× − 𝑏 − 𝑏 M= 534.86 lb/lb mol I=2.266× n= + 𝐼 −𝐼 / − exp = 1.469 × − 𝑏 𝐺+ = + + 𝐺− − − × 𝑏 + × − 𝐺 ] 𝑏 𝐺 = 𝑏 𝐺 𝑏 𝐺− = 𝑖 m= M(n – 1.475) = -3.21 = − 𝑑 = since M> 200 sulphur wt% = -58.02+ 38.463 𝑖 − + sulphur amount = 0.01214(31,971) = 388.13 lb/h 𝐺 = 𝑤𝑡% Vacuum residue ( 1050+°F) cut Cut vol % = 100– 44.91=55.09% Cut mid volume = 72.455 Substituting the cut mid volume in eq (4.2) to get API= 16.45, we get SG = 0.956 Cut volume = 0.5509(100,000)= 55,090BPD Cut amount = 55,090(SG)(14.60)=55,090(0.956)(14.60)=768,924 lb/h ... (4.2) to get API= 37.25, we get SG = 0.839 Cut volume = 0.02 61( 100,000)= 2 610 BPD Cut amount = 2 610 (SG) (14 .60)=2 610 (0.839) (14 .60)= 31, 9 71 lb/h Calculate of sulphur content : M= 42.965[exp(2.097×... gas oil (850 -10 50°F) cut IBP = 850 °F = 454.44°C = 13 09.67°R EBP= 10 50°F= 565.56°C= 15 09.67°R Substituting in eq ( 4 .1) to get LV% at IBP and EBP : Cut vol % = 44. 91 – 42.30=2. 61% Cut mid volume... exp = 1. 469 × −

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