hướng dẫn giải các dạng toán lớp 6

... Khoảng cách hai dây A 3 ,6 m B 36 m C 36 cm D 3 ,6 cm Giải - Chọn đáp án D - Ta có: Câu 10: Có dịng điện thẳng song song I1, I2 I3 mặt phẳng, cho I1 = 20 A, I2 = 15 A, I3 = 25 A Khoảng cách I1, ... lớn 4.10 -6 N B lực đẩy có độ lớn 4.10 -6 N C lực hút có độ lớn 2.10 -6 N D lực đẩy có độ lớn 2.10 -6 N Trang | Vững vàng tảng, Khai sáng tương lai Giải - Chọn đáp án A - Dòng điện hai dây dẫn có ... 2.10−7.2,5.0, = = 4.10? ?6 ( N ) r 0,1 Câu 4: Hai dây dẫn thẳng, dài song song đặt khơng khí Dịng điện chạy hai dây có cường độ A Lực từ tác dụng lên mét chiều dài có độ lớn 10 -6 N Khoảng cách hai dây A

Ngày tải lên: 11/04/2023, 19:36

... Px xLx EJ P x −−=−−= 3 6 3 6 )0,( 2 32 v Góc xoay dầm tính theo công thức ⎟ ⎟ ⎠ ⎞ ⎜ ⎜ ⎝ ⎛ ∂ ∂ − ∂ ∂ = y u x xy v 2 1 θ , mang dạng sau: ()()() 222222 3 36 6 3 36 6 3 36 62 1 yxLx EJ P yxLx EJ ... định các đại lượng giãn dài lò xo cùng các lực trong các lò xo s1 = 0,3328 (P/k); s2 = 0,3529 (P/k); s3 = 0, 166 4 (P/k) (h) F1 = 0,3328P; F2 = 0,5294P; F3 = 0,3328P (i) Giải các bài tốn dạng ... 0 góc xoay sẽ là: () 2 36 6 )0,( xLx EJ P x xy −−= θ Biến dạng trong dầm tính theo: () () yxL EJ P y yxL EJ P x u yx −−= ∂ ∂ =−= ∂ ∂ = υ εε v ; ()() 03 36 6 3 36 6 2222 =−−+−−− = ∂ ∂ + ∂ ∂

Ngày tải lên: 27/06/2014, 09:20

... thường lúng túng việc tìm cách giải toán Vậy làm cách để giải tốt toán dao động tắt dần lắc lò xo lắc đơn vấn đề mà luôn trăn trở, bổ sung, đúc rút kinh nghiệm cho đứng lớp Xuất phát từ thực trạng ... gặp giải toàn dao động tắt dần lắc đơn lắc lị xo, cơng thức giáo viên hướng dẫn để học sinh tự chứng minh để tạo niềm tin vào công thức, từ em nhớ để vận dụng giải tập nhanh hiệu Hướng dẫn giải ... thiện kĩ giải nhanh toán dao động tắt dần nên mạnh dạn áp dụng đề tài : “ HƯỚNG DẪN GIẢI NHANH MỘT SỐ BÀI TẬP DAO ĐỘNG TẮT DẦN CỦA CON LẮC LÒ XO VÀ CON LẮC ĐƠN, CHƯƠNG DAO ĐỘNG CƠ, MƠN VẬT LÍ LỚP

Ngày tải lên: 18/04/2015, 08:56

... 19,84s; b) T2 = 19,87s; c) Giảm lợng l = l l ' = 0, 26m = 26cm Bài 3.3: Con lắc đơn dao động bé mặt đất có nhiệt độ 300C Đa lên độ cao h = 0 ,64 km chu kì dao động bé không thay đổi Biết hệ số nở ... khảo sát lớp 12A1 -31- TI SKKN Nguyn Quc Tin giỏi Số học sinh Hc sinh t tỡm Khá Trung bình Yếu SL % SL % SL % SL % 20 11 44 24 12 32 13 52 16 0 tũi gii (25) ADPP (25) + Kết khảo sát lớp 12A7 ... s n di ca dõy treo kim loi (K-1) Gia tc trng trng - Gia tc trng trng mc nc bin: g = GM R2 G = 6, 67.10-11N.m2/kg2: Hng s hp dn M: Khi lng ca trỏi t R: Bỏn kớnh trỏi t - Gia tc trng trng cao

Ngày tải lên: 25/10/2017, 22:38

... v = 10 m/s A 164 N B 1 86 N C 254 N D 2 16 N Giải Chọn D Tại điểm cao vịng xiếc có lực tác dụng lên xe trọng lực phản lực vịng xiếc Ta có: (9)Bài 13: Một xe có khối lượng 160 0 kg chuyển ... đường tròn ? Giải Khi đá ở đỉnh đường trịn trọng lực lực căng dây đóng vai trị lực hướng tâm: Fht = P + T → T = Fht - P (4)Bài 6: Một vật chuyển động tròn tác dụng lực hướng tâm F Nếu ... 10 m/s2 bán kính Trái Đất 64 00 km Tốc độ dài chu kì chuyển động vệ tinh A 7300 m/s ; 4,3 giờ B 7300 m/s ; 3,3 giờ C 60 00 m/s ; 3,3 giờ D 60 00 m/s ; 4,3 giờ Giải Chọn C Gia tốc rơi

Ngày tải lên: 18/04/2021, 20:50

... Thiên Đức – ductt111.wordpress.com V2011 HƯỚNG DẪN GIẢI BÀI TẬP ĐỊNH HƯỚNG TUẦN 1-2-3 DẠNG TOÁN: BÀI TOÁN ĐIỆN TÍCH ĐIỂM Nhận xét: - Đặc điểm dễ nhận dạng loại toán xuất điện tích điểm đề  cần nắm ... đến vị trí B: A = q(VA – VB) o Hướng điện trường gây điện tích điểm: +: hướng ra, -: hướng - Một số dạng tập điển hình: o Xác định đại lượng bản: F, E, V, q, A o Bài toán kết hợp động lực học: dây ... VD) DẠNG TỐN: ỨNG DỤNG TÍCH PHÂN Nhận xét: - Đặc điểm toán phải sử dụng phương pháp tính tích phân để xác định cường độ điện trường, lực điện, điện đại lượng suy từ đại lượng - Để giải toán dạng

Ngày tải lên: 29/04/2021, 15:54

... 4.1.8 ăn áp dụng trách nhiệm vật chất 62 4.1.9 Mức bồi thường cách th c bồi thường 63 4.2 Tình hướng dẫn giải tình 63 Chƣơng TÌNH HUỐNG VỀ TRANH CHẤP AO ĐỘNG VÀ GIẢI QUYẾT TRANH CHẤP AO ĐỘNG 89 5.1 ... cần giải quyết; kỹ n ng lập luận giải tình huống; kỹ n ng đặt câu hỏi làm sáng tỏ vấn đề liên quan đến giải tình huống… Người học cần trang bị kỹ n ng cách thấu đáo từ có cách giải tình cách ... bị kiến thức l luận th c ti n th ng qua cách tiếp cận tình uốn sách hướng dẫn ? ?Hướng dẫn giải tình học phần Luật Lao động” đư c x y d ng để làm r định hướng chung nghiên cứu tình huống, đ c trưng

Ngày tải lên: 25/01/2022, 16:20

... bị kiến thức l luận th c ti n th ng qua cách tiếp cận tình uốn sách hướng dẫn ? ?Hướng dẫn giải tình học phần Luật Lao động” đư c x y d ng để làm r định hướng chung nghiên cứu tình huống, đ c trưng ... cần giải quyết; kỹ n ng lập luận giải tình huống; kỹ n ng đặt câu hỏi làm sáng tỏ vấn đề liên quan đến giải tình huống… Người học cần trang bị kỹ n ng cách thấu đáo từ có cách giải tình cách ... pháp luật để giải tình Việc định hướng tra cứu v n ản pháp luật giải tình giữ vai trị quan trọng để giải tình cách rõ ràng pháp luật đ ng thời chìa khóa để xác định vấn đề hướng cần giải Tuy nhiên

Ngày tải lên: 24/02/2023, 13:33

... GV: Trần Thiên Đức - http://ductt111.wordpress.com V2011 HƯỚNG DẪN GIẢI BÀI T P ĐỊNH HƯỚNG TUẦN - CÁC DẠNG TOÁN KHE YOUNG CƠ BẢN DẠNG 1: NGUỒN S DỊCH CHUYỂN Hình 1.1 Hệ khe Young – nguồn S ... tối trùng nằm cách khoảng 6i1 = 0.3cm BÀI 1.25 Xét hệ vân tròn Newton Xác định bề dày lớp khơng khí ta quan sát thấy vân sáng biết ánh sáng tới có bước sóng  = 0 .6? ??m Tóm tắt:  = 0 .6? ??m Xác định ... vàng Cho biết bước sóng ánh sáng vàng 0 .6? ??m Chiết suất n = 1.33 Tóm tắt:  = 450  = 0 .6? ??m n = 1.33 Xác định dmin Nhận xét: Đây toán giao thoa mỏng  bước để giải tốn là: B1: Xét hiệu quang lộ hai

Ngày tải lên: 27/03/2023, 13:34

... ductt111.wordpress.com V2011 HƯỚNG DẪN GIẢI BÀI TẬP ĐỊNH HƯỚNG TUẦN 1-2-3 DẠNG TOÁN: BÀI TOÁN ĐIỆN TÍCH ĐIỂM 1. Nhận xét: - Đặc điểm rất dễ nhận dạng của loại bài toán này là sự xuất hiện của các điện tích ... vậy ta thấy các bài toán đều đi qua bài toán trung gian điện trường  bài toán xác điện điện trường gây bởi vật thể đóng vai trò rất quan trọng 2 Hướng giải: ... của khoảng cách giữa hai ... q(V A – V B ) o Hướng của điện trường gây bởi điện tích điểm: +: hướng ra, -: hướng về - Một số dạng bài tập điển hình: o Xác định các đại lượng cơ bản: F, E, V, q, A o Bài toán kết hợp động

Ngày tải lên: 06/02/2014, 09:55

... Do đó Δf ≥ 0, nên M1(0, -1) là điểm cực đại, giá trị cực đại f(0, -1) = 1/e HƯỚNG DẪN GIẢI BÀI TẬP HỌC PHẦN GIẢI TÍCH 2 Ơn Ngũ Minh Xét hồn tồn tương tự, ta nhận được các điểm cịn lại cũng là các điểm cực đại với cùng một giá trị cực đại là 1/e 2.7.2 Các giá trị lớn nhất và nhỏ nhất của hàm hai biến ... , ∙ 〈 , , 〉 √ ℎ →− ⟩ v véc tơ HƯỚNG DẪN GIẢI BÀI TẬP HỌC PHẦN GIẢI TÍCH 2 Ơn Ngũ Minh Ví dụ 1 Cho ( , ) = , = ⟨−1,1⟩ Tính đạo hàm theo hướng u f điểm (1, -1) Lời giải fx = 2xy, fy = x2 Tại điểm (1, -1) ta có fx = -2, fy = 1 ... Ví dụ 2 → (x, y) → (0, 0) Lời giải Cách 1 Đặt t = y/x, ta có f = - Khi t → 0: f → 0 - Khi t → 1: f → 1/2 ( ) = khi (x, y) → (0, 0) HƯỚNG DẪN GIẢI BÀI TẬP HỌC PHẦN GIẢI TÍCH 2 Ơn Ngũ Minh Vậy khơng tồn tại giới hạn của

Ngày tải lên: 26/09/2016, 20:21

... liệu, đề thi file word môn Toán? ?? Hướng dẫn giải số tập số phức mức độ vận dụng cao Rồi gửi đến số điện thoại Sau nhận tin nhắn tiến hành liên lạc lại để hỗ trợ hướng dẫn GDSGDSGDSGFSDFGDSGSDGSDGDS ... giá trị z   + z  π 5π 7π 11π π 2π 4π 5π  x= ; ; ; ; ; ; ;  ? ?6 6 3 3   Vậy có số phức thoả điều kiện đề cho Hướng dẫn giải số tập số phức mức độ vận dụng cao Bài 19: Cho số phức z thoả ... y )2 Chú ý: Với x, y số thực ta có: x + y ≥ Dấu “=” xảy x = y  Cách 2:  z − − 4i = z − 2i ⇔ y = − x  z = x +y ≥ 2 = Hướng dẫn giải số tập số phức mức độ vận dụng cao  z = x + y = x + (4 −

Ngày tải lên: 24/10/2017, 07:52

... Hướng dẫn giải số tập số phức mức độ vận dụng cao Bài 1: Cho số phức z thoả mãn z = Gọi M m giá trị lớn giá trị nhỏ biểu thức P = z + + z − z + Tính giá trị M.n 13  Cách 1: A B ... thi – tài liệu file word Hướng dẫn giải số tập số phức mức độ vận dụng cao  P = 33 2  Thay vào f ( x) ta được: ( 0, P − 1, − 3) + (0,1P + 1,7 − 4) − = ⇔   P = 13  Cách 2:  z − − 4i = ⇔ ( ... A z = B z = C z = D z =  Cách 1:  z + i + = z − 2i ⇔ x − y =  x2 + y2 ≥ ( x − y)2 = 2 http://dethithpt.com – Website chuyên đề thi – tài liệu file word Hướng dẫn giải số tập số phức mức độ

Ngày tải lên: 02/05/2018, 14:23

... phương trình |6 − 3i + iz| = |2z − − 9i| thỏa mãn z1 − z = A 31 B 56 | Giá trị lớn z1 + z2 C D D LỜI GIẢI VÀ ĐÁP ÁN GIẢI BÀI TẬP Ta có    z − 2  +  3i = z − 13  z  + 13 Đáp án A GIẢI BÀI TẬP ... MB = 10 − 7a 10 − 4a Do  AB =  ? ?6  10 − 7a   16 a 7 Ta có  10 − 4a  25a − 80a + 100 ( 5a − 8) + 36 MA + MB = a +  = =  9   2 Do − 2 36 34 112 96  5a −    (5a − 8)2  Suy 7 ... MB  nên z   z  = m 12 96 + 36 340 121 = z  =M • MA + MB  49 49 49 Vậy M + m = 60 49 Đáp án C 13 http://dethithpt.com – Website chuyên đề thi – tài liệu file word GIẢI BÀI TẬP 21 Gọi điểm

Ngày tải lên: 14/06/2018, 15:26

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Ngày tải lên: 05/03/2014, 13:20

... CÔNG HOA SEN Giải hệ phương trình:        22 x y y x 6 x y y x 20 Giải Điều kiện: x  0; y  0 (*) Đặt u =   x 0,v y 0 Hướng dẫn giải CDBT từ các ĐTQG Toán học – 111 ...                      22 x1 1 x 8 65 8 x 0 1x 65 16 x 16 x 1 x 16x 64  Vấn đề 3: HỆ PHƯƠNG TRÌNH A. PHƯƠNG PHÁP GIẢI Dạng 1:          1 1 1 2 2 2 2 1 2 1 ... 0 A B A B Hướng dẫn giải CDBT từ các ĐTQG Toán học – 101 Bài 8: ĐỀ DỰ BỊ 2 - ĐẠI HỌC KHỐI D NĂM 20 06 Giải phương trình: x + 2 7x = 2       2 x 1 x 8x 7 1 (x  ) Giải Điều...

Ngày tải lên: 02/06/2014, 20:01

... 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Ngày tải lên: 02/06/2014, 20:02

... như sau:  Lớp A có 2 học sinh, các lớp B, C mỗi lớp có 1 học sinh. Số cách chọn là:  2 1 1 5 4 3 C .C .C 120  Lớp B có 2 học sinh, các lớp C, A mỗi lớp có 1 học sinh. Số cách chọn là: ... 90  Lớp C có 2 học sinh, các lớp A, B mỗi lớp có 1 học sinh. Số cách chọn là:  1 1 2 543 C .C .C 60 Số cách chọn 4 học sinh mà mỗi lớp có ít nhất một học sinh là: 120 + 90 + 60 = 270. ... Giải Ta có:    22 n n n n 2P 6A P A 12 (n  , n  2) n! n! 2.n! 6. n! 12 (n 2)! (n 2)! n! n! (6 n!) 2 (6 n!) 0 (6 n!) 2 0 (n 2)! (n 2)!                   6...

Ngày tải lên: 02/06/2014, 20:03

...  1; y), N(x + 1; y). Do OM + ON  MN neân Hướng dẫn giải CDBT từ các ĐTQG Toán học – 184  Chuyên đề 6: BẤT ĐẲNG THỨC A. PHƯƠNG PHÁP GIẢI I. Một số ghi nhớ:  a 2  0 , (a  b) 2 ...                 3 3 3 1 u 1 v 3 1 u 1 v u v 5 u v Hướng dẫn giải CDBT từ các ĐTQG Toán học – 1 86 Cách 3: Ta có: yz x y z 1 xx P y y z z 2x 3y y z z x 2 3 1 x x x x  ... lại có: 34 6 33 5  neân minP = 34 33 . Hướng dẫn giải CDBT từ các ĐTQG Toán học – 192  Khi x = 0, y = 1 thì  1 p 4 laø GTNN  Khi x = 1, y = 0 thì  1 p 4 là GTLN Cách 2: ...

Ngày tải lên: 02/06/2014, 20:04