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LUYỆN THI ĐẠI HỌC MÔN VẬTLÝ Email: Jackie9x.spb@gmail.com 1 HỆ THỐNG LÝ THUYẾT VÀ CÁCDẠNGBÀITẬPVẬTLÝ10 * Tóm tắt lý thuyết * Công thức tính nhanh * Cácdạngbàitập và phƣơng pháp ... 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... lực. B. CÁCDẠNGBÀITẬP1. Cân bằng của vật chịu tác dụng của các lực không song song * Công thức Điều kiện cân bằng của vật chịu tác dụng của các lực không song song: 1 F+2F+...
... Trường THPT Đại an Bàitậpvậtlý10 nâng caoCHƯƠNG I : ĐỘNG HỌC CHẤT DIỂM Bài 1. Hai thành phố A,B cách nhau 40km. Cùng một lúc xe thứ I qua A với vận tốc 10 km/h, xe thứ 2 qua B với ... RƠI TỰ DO Bài 3. 5b. Thời gian cần thiết để vật đi hết 1m đầu và 1m cuối của độ cao h. ( 0,45s; 0,05s ) 10 . Một vật rơi tự do trong thời gian 10 s. Hãy tính thời gian vật rơi trong 10 m đầu ... thời gian vật rơi trong 10 m cuối cùng? Lấy g = 10 m/s2 ( Đs. 1, 41s; 0,1s ) 11 .Một vật rơi tự do, trong giây cuối cùng rơi được một đoạn bằng ¾ toàn bộ độ cao.Tính thời gian của vật và độ...
... 2002cos23= - 10 0 2 (V). 5. Ta có: u 1 = 220 = 2202cos (10 0 πt 1 + 6) cos (10 0 πt 1 + 6) = 22 = cos(4) . Vì u đang tăng nên ta nhận nghiệm (-) 10 0 πt 1 + 6 = - 4 t 1 = ... 2) (V). 9. Ta có: e = - N’= 15 0 .10 0 22 .10 sin (10 0 t - 4) = 300cos (10 0 t - 34) (V). 2. Tìm một số đại lƣợng trên các loại đoạn mạch xoay chiều * Các công thức: Cảm kháng, dung ... SÁNG KIẾN KINH NGHIỆM Năm học 2 011 – 2 012 I. Đánh giá, xếp loại của HĐKH trường THPT Nguyễn Văn Linh 1. Tên đề tài: PHƯƠNG PHÁP GIẢI CÁCDẠNGBÀITẬPVẬTLÝ 12 PHẦN DÒNG ĐIỆN XOAY CHIỀU....
... 3,55 .10 10 hạt. B). 3,40 .10 10 hạt. C). 3,75 .10 10 hạt. D).3,70 .10 10 hạt.Giải- Số hạt nhân ngun tử có trong 1 gam 226Ra là : N0 = 212 3 10 . 6646, 210 . 022,6.226 1 .==ANAm hạt .- Suy ... theo đơn vị Jun làA. 6,7 .10 -13 J B. 6,7 .10 -15 J C. 6,7 .10 -17 J D. 6,7 .10 -19 JTóm tắt: Giải;000 ,12 umC= C12 3 He;0 015 ,4 um=α Năng lượng phá vở một hạt C12 thành 3 hạt He 9Suy ... Al27 13 là bao nhiêu ?A. 13 . B. 14 . C. 27. D. 40. 9.4 Các nuclôn trong hạt nhân nguyên tử Na23 11 gồmA. 11 prôtôn. B. 11 prôtôn và 12 nơtrôn.C. 12 nơtrôn. D. 12 prôtôn và 11 nơtrôn. 29Bài...
... lắc sau va chạm. Áp dụng đsauWkA=22 1 Phương Uyên CÁCDẠNGBÀITẬPVẬTLÝ 12 1 CÁCDẠNGBÀITẬPVẬTLÝ 12 Chuyên đề 1: Hạt nhân nguyên tử Dạng 1: Tính năng lượng phản ứng A + B → C + ... giác vì dòng điện lớn)Phương Uyên CÁCDẠNGBÀITẬPVẬTLÝ 12 10 Phương Uyên CÁCDẠNGBÀITẬPVẬTLÝ 12 3+ Tìm A = 222ωvx+(hay từ cơ năng E = 22 1 kA) + Tìm ω= mk(con lắc lò ... H = 11 1222 1 2coscosϕϕsIUIUPP=+ Nếu điện trở thuần các cuộn dây nhỏ thì 2 1 2 1 NNee=2 1 2 1 NNEE=⇒+ Nếu các cuộn dây có điện trở thuần : 1 exem như nguồn thu 11 11 riue−=...
... khi vật cân bằng ta có mg.sinα = k.0l∆+ E = 222222 1 2 1 2 1 2 1 AmkAkxmvEEtđω==+=+Hữu Nghĩa CÁCDẠNGBÀITẬPVẬTLÝ 12 Website: xomcodon.tk 1 CÁCDẠNGBÀITẬPVẬTLÝ 12 Chuyên đề 1: ... H = 11 1222 1 2coscosϕϕsIUIUPP=+ Nếu điện trở thuần các cuộn dây nhỏ thì 2 1 2 1 NNee=2 1 2 1 NNEE=⇒+ Nếu các cuộn dây có điện trở thuần : 1 exem như nguồn thu 11 11 riue−= ... Nghĩa CÁCDẠNGBÀITẬPVẬTLÝ 12 Website: xomcodon.tk 7 -Hai đầu cố định: l = k2λ, k bó , k bụng , (k +1) nút - Một đầu tự do : l = 2)2 1 (λ+k , k bó, (k +1) nút , ( k +1) bụng - Vật...
... thì: 2 1 2 1 NNee=2 1 2 1 NNEE=⇒- Nếu các cuộn dây có điện trở thuần: 1 e xem như nguồn thu: 11 11 riue−= ,2exem như nguồn phát: 2222riue+=. Vậy: 2 1 222 11 12 1 NNriuriuee=+−= ... chu kì 1: 1 2 1 ax 1 1 1 1, :2T mBmg hay mglhEE Eα= = = + Cơ năng chu kì 2: 222 ax 2 1 2 1 , :2T mBmg hay mglEhE Eα= = =- Độ giảm cơ năng sau 1 chu kì: 2 2 1 2 1 ( )2Emglα ... lập : 1 22222=+ωAvAx ⇒ v = 22xA−ω và: A = 222ωvx+- Lực kéo về: 5 CÁCDẠNGBÀITẬPVẬTLÝ 12 Chuyên đ 1 : Động lực học vật rắn Các công thức cơ bản cần nhớ: 1. Tốc...
... 12 :L nt L 12 12 L L LZ Z Z L L L + 12 1 2 1 2 12 12 1 2 1 2 11111 1/ / :LLLL L L L LZZLLL L Z LZ Z Z Z Z L L L L L + 12 12 12 1 2 1 2 11 ... lƠm nh sau: + đ222đW = n W 11 ( 1) 1 22W = W + W 1 2ttAkA n kx xkAn + đ2 2 2 222đW = n W 11 1 1 1 2 2( 1) 2 2( 1) W = W + W2ttkkA mv kA v ... vi ngun 1: 12 1 2ddk . Suy ra: 1 122d d k đim M dao đng ngc pha vi ngun 1: 12 1 (2 1) ddk . Suy ra: 1 12(2 1) d d k...
... - I 1 .R 1 + I4.R4 = - 10 . 3 + 6.4 = - 6 (V)UNQ = UNB + UBQ = I 1 .R3 - I4.R6 = 10 . 1 - 6.4 = -14 (V)UPN = UPB + UBN = I4.(R5 + R6) + I 1 .R3 = 6.(2+4) - 10 . 1 = ... giải cácbàitập nâng cao phần điện học là thiết thực và hiệu quả. Kết quả cụ thể, năm học này (10 1 1- 2 012 ), tôi đã tham gia dạy bồi dưỡng các đội tuyển và đã cho các em giải nhiều cácdạngbài ... thời gian cácdạngbàitậpVậtlý là điều cần thiết đối với giáo viên Vật lý để hướng dẫn cho học sinh. Hơn nữa, trong phần điện học, cácdạng bài tập nâng cao thường “khó” hơn so với các phần...