... Hz)t ), jmax 6.34 107 m s 13. 12: a) From Eq (13. 19), A v0 ω v0 k m 0.98 m b) Equation (13. 18) is indeterminant, but from Eq (13. 14), , and from Eq (13. 17), sin 0, so ... the same as Eq (13. 19) b) At time t 0, Eq (13. 21) becomes 2 k 2 kA mv0 kx0 v0 kx0 , 2 2 ω2 2 where m kω (Eq (13. 10)) has been used Dividing by k gives Eq (13. 19) 13. 22: a) vmax ... From Eq (13. 4), ax ( 450 N/m)(kg) m) 13. 5 m/s2 (0.500 e) From Eq (13. 31), E (450 N/m)(0.040 m) 0.36 J 13. 25: a) amax ω2 A (2f ) A 2(0.85 Hz) (18.0 102 m) 5 .13 m/s vmax...