... solved for a, b and e in terms off. The solution is, therefore, b=l-f a=-l-f e=O ( 1 .3 5d) (1 .35 e) (1 .35 f) Substituting these values in Eqn (1 .33 ), (1 .36 ) 22 Aerodynamics for Engineering ... 520 522 522 525 527 527 527 533 533 534 535 535 535 538 539 539 539 54 1 54 1 542 549 549 550 550 551 552 554 558 56 1 5 63 567 569 572 574 Index 577 Basic ... velocity potential 3. 1.2 The equipotential 3. 1 .3 Standard flows in terms of 11, and q5 3. 3.1 3. 3.2 Line (point) vortex Velocity components in terms of q5 3. 2 Laplace’s equation 3. 3 Two-dimensional...