... trường + 21 EEE + 21 21EEEEE + 21 21EEEEE + 2 2 2 121 EEEEE + cos2, 21 2 2 2 121 EEEEEEE Nếu 2 cos2 121 EEEE + Lực tác dụng ... 1 2 F F F + 1 2 1 2 F F F F F + 1 2 1 2 F F F F F + 0 2 21 2 1 2 ( , ) 90F F F F F + 2 21 2 1 2 1 2 ( , ) 2 osF F F F F F F c ... ĐẠI HỌC MÔN VẬT LÝ Email: Duclongtn95@gmail.com 22 - Ngắm chừng ở vô cực: d 2 = f 2 ; d' 2 = - ; khi đó O1O 2 = f1 + f 2 . + Độ bội giác: G = 2 1ff và 21 21ffOO ...
... =R 2 Z 2 C+(ZLZC− 1) 2 =(R 2 + Z 2 L)1Z 2 C− 2. ZL1ZC+1=(R 2 + Z 2 L)x 2 − 2. ZLx +1Trong đó: x =1ZC;Tacó:a =(R 2 + Z 2 L) > 0Nên y = min khi x = −b2a=ZLR 2 + Z 2 L, ... =R 2 Z 2 L+(1−ZCZL) 2 =(R 2 + Z 2 C)1Z 2 L− 2. ZC1ZL+1=(R 2 + Z 2 C)x 2 − 2. ZCx +1Trong đó: x =1ZL; Ta có: a =(R 2 + Z 2 C) > 0Nên y = min khi x = −b2a=ZCR 2 + ... EtB1max= mgh1,hayE1=1 2 mglα 2 1Cơ năng ở chu kì 2: E 2 = EtB 2 max= mgh1,hayE 2 =1 2 mglα 2 2Độ giảm cơ năng sau 1 chu kỳ: ∆E =1 2 mgl(α 2 1− α 2 2)Th.s Trần AnhTrung33Luyện...
... 100πt - 2 = 3 t = 1 120 (s). Sau thời điểm đó 1300s, ta có: u = 20 0 2 cos(100π(1 120 +1300) - 2 ) = 20 0 2 cos 2 3= - 100 2 (V). 5. Ta có: u1 = 22 0 = 22 0 2 cos(100πt1 ... = 2 2 = cos(4) . Vì u đang tăng nên ta nhận nghiệm (-) 100πt1 + 6 = - 4 t1 = - 1 24 0s t 2 = t1 + 0,005 = 0 ,2 240s u 2 = 22 0 2 cos(100πt 2 + 6) = 22 0 ... Phương pháp giải cácdạngbàitậpVậtlý 12 – Phần dòng điện xoay chiều Trang 2 Người viết: Dương Văn Đổng – Trường THPT Nguyễn Văn Linh, Bình Thuận B - NỘI DUNG CÁC DẠNGBÀITẬP VỀ DÒNG...
... trong 1 gam 22 6Ra là : N0 = 21 2310.6646 ,21 0. 022 ,6. 22 61.==ANAm hạt .- Suy ra số hạt nhân ngun tử Ra phân rã sau 1 s là : 1086400.365.15801 21 010.70,3 21 10 .6646 ,2) 21(=−=−=∆−−TtNN ... ?A. 13. B. 14. C. 27 . D. 40. 9.4 Các nuclôn trong hạt nhân nguyên tử Na 23 11 gồmA. 11 prôtôn. B. 11 prôtôn và 12 nơtrôn.C. 12 nơtrôn. D. 12 prôtôn và 11 nơtrôn. 29 Bài 2: người ta dùng ... : 23 290Th → 20 8 82 Pb + x4 2 He + y01−β– . - Áp dụng định luật bảo toàn điện tích và số khối , ta được : ==⇔=−=⇔=−=−+=−=+46 82 68 829 0).1 (2 2 420 823 2.04yxyxxyxyx....
... =R 2 ω 2 L 2 +(1−1ω 2 CL) 2 =1C 2 L 2 1ω4+R 2 L 2 − 2 1CL1ω 2 +1Hay: y =1C 2 L 2 x 2 +R 2 L 2 − 2 1CLx +1với x =1ω 2 Ta có: a =1C 2 L 2 > 0Nên y = min khi x = −b2a= 2 CL−R 2 L 2 .L 2 C 2 2=2LC − R 2 C 2 2Vậy ... hoà.Chu kỳ: T = 2 ωhay T =2 4mkCách 2: Cơ năng:E = Eđ+ Et=1 2 mv 2 +1 2 kx 2 L=1 2 mv 2 +1 2 k(x 2 ) 2 = constĐạo hàm hai vế theo thời gian:1 2 m2vv+1 2 k42xx=0⇔ x”+k4mx ... I.ZL=UZLR 2 +(ZL− ZC) 2 =UωLR 2 +ωL−1ωC 2 =UR 2 ω 2 L 2 +1 −1ω 2 CL 2 Hay UL=const√y,đểULcực đại khi y = min.Ta có: y =R 2 ω 2 L 2 +(1−1ω 2 CL) 2 =1C 2 L 2 1ω4+R 2 L 2 −...
... giác vì dòng điện lớn)Phương Uyên CÁCDẠNGBÀITẬPVẬTLÝ 12 10 Phương Uyên CÁCDẠNGBÀITẬPVẬTLÝ 12 3+ Tìm A = 2 2 2 ωvx+(hay từ cơ năng E = 2 21kA) + Tìm ω= mk(con lắc lò ... tWtCqCqCuWđ)(cos)(cos 22 1 2 1 22 2 0 2 2ϕωϕω+=+===, tần số góc dao động của đWlà 2 ω chukì 2 T. tW = )(sin)(sin 22 1 22 2 0 2 ϕωϕω+=+=tWtCqLi, tần số góc dao động của tWlà 2 ω, chu kì 2 TTrong ... Năng lượng từ trường : 2 21LiWt= ⇒ 2 0max 2 1LIWt=+ Năng lượng điện từ : W = 2 21Cu+ 2 21Li= Cq 2 21+ 2 21Li= CQCU 2 0 2 0 2 1 2 1= 2 0 2 1LI= . Vậy =maxđWmaxtW+...
... và R 2 và có hệ thức: R1.R 2 = r 2 :Từ (1) Px. (Rx + r) 2 = U 2 . Rx Px.Rx 2 - (U 2 - 2rPx).Rx + r 2 .Px = 0 (3) = (U 2 - 2r.Px) 2 - 4Px 2 .r 2 Thay U 2 = 4r.Pcđ ... thời gian cácdạngbàitậpVậtlý là điều cần thiết đối với giáo viên Vật lý để hướng dẫn cho học sinh. Hơn nữa, trong phần điện học, cácdạng bài tập nâng cao thường “khó” hơn so với các phần ... NGHIỆMNăm học: 2011 - 20 12 I. Đánh giá xếp loại của HĐKH trường THCS Chu Văn An 1.Tên đề tài: VÀI KINH NGHIỆM GIẢI CÁCDẠNGBÀITẬPVẬT LÝNÂNG CAO THCS - PHẦN ĐIỆN HỌC 2. Họ và tên tác...
... LUYỆN THI ĐẠI HỌC MÔN VẬTLÝ Email: Jackie9x.spb@gmail.com 1 HỆ THỐNG LÝ THUYẾT VÀ CÁCDẠNGBÀITẬPVẬTLÝ 10 * Tóm tắt lý thuyết * Công thức tính nhanh * Cácdạngbàitập và phƣơng pháp ... 21 FFF; với F 2 = F1 2 + F 2 2 + 2F1F 2 cos.; F1 + F 2 ≥ F ≥ |F1 – F 2 |. Khi 1Fvà 2 F cùng phương, cùng chiều ( = 00) thì F = F1 + F 2 . 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