... x
x
x
x
x
x
x
x
x
x
x
x
x
x
x
x
x
x
x
x
x
x
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1
z
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A
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2
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1
2
3
4
5
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6
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A
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2
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a
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==
2
2
2
2
D
M
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==
22
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- Lực dọc trục:
==
22
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- Mô men do lực dọc trục gây nên:
==
2
.
22
2
DA
M
A
Phần ... x
x
x
x
x
x
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x
x
x
x
x
x
x
x
x
x
A
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2
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A
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2a
2a
2a
a
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... x
x
x
x
x
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x
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x
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1
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2
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2
2
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- Lùc híng kÝnh:
==
22
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- Lùc däc trôc:
==
22
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2
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2
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Phần ... x
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22
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x
x
x
x
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2
2
2
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22
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- Lực dọc trục:
==
22
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2
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22
2
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Phần 2: Vẽ biểu đồ mô men cho dầm...
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22
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&apos ;2
z
2
z
'1
z
1
A
B
C
x
D
x
z
1
z
'1
z
2
z
&apos ;2
D
A
B
C
x
A
B
C
z
'1
z
1
z
2
z
&apos ;2
a 2a 2a
a
a
a 2a
2a
a
2a
2a
a
a
a
a ... đơng.
5. Phơng trình 3 mô men:
( )
0
.6 .2.
2
22
1
11
22 121 01
=
+
++++
l
b
l
a
MlMllMl
Trong đó:
l
1
= l
2
=
M
0
= M
2
=
=
+
2
22
1
11
.6
l
b
l
a
Thay vào phơng trình...
... x
x
x
x
x
x
x
x
x
x
x
x
x
x
x
x
x
x
x
x
x
x
z
1
z
'1
A
B
C
z
2
z
&apos ;2
D
z
'1
z
1
A
B
C
D
z
2
z
&apos ;2
z
&apos ;2
z
2
z
'1
z
1
A
B
C
x
D
x
z
1
z
'1
z
2
z
&apos ;2
D
A
B
C
x
A
B
C
z
'1
z
1
z
2
z
&apos ;2
a 2a 2a
a
a
a 2a
2a
a
2a
2a
a
a
a
a a a 2a
2a
a
a 2a
a
a
a
1
2
3
4
5
3
Bàitập lớn
(sơ đồ10- số liệu 8)
Phần 1: Sơ ...
.6 .2.
2
22
1
11
22 121 01
=
+
++++
l
b
l
a
MlMllMl
Trong đó:
l
1
= l
2
=
M
0
= M
2
=
=
+
2
22
1
11
.6
l
b
l
a
10
9
a
2a
P
2
P
1
C
B
A
a
2t
t
A
2
T
2
T
1
... x
x
x
x
x
x
x
x
x
x
x
x
x
x
x
x
x
x
x
x
x
A
D
B
C
z
1
z
'
1
z
2
z
'
2
x
D
A
B
C
z
'
1
z
1
z
2
z
'
2
B
A
D
z
'
2
z
2
z
'
1
z
1
C
A
B
C
D
z
2
z
'
2
z
1
z
'
1
z
'
1
z
1
D
z
2
z
'
2
A
B
C
a
a
a
2a
2a
2a
2a
a
a...
...
11
.
nn
aΩ
+
22
.
nn
aΩ
=
2
1
.197.2a.
3
2
.2a +
2
1
.136.2a.
(2a+
3
1
2a) = 625 .a
2
11
.
++
Ω
nn
a
=
2
1
.143.2a.a = 143.a
2
VËy (1) <=> 12a.M
1
+ 6.(
a
a
4
. 625
2
-
-
a
a
2
.143
2
) ... = 458.2a.2a = 18 32. a
2
11
.
++
Ω
nn
a
= 52. a.a = 52. a
2
VËy: (1) <=>
12a.M
1
+ 2a.344 + 6.( -
a
a
4
.18 32
2
-
a
a
2
. 52
2
)
= 0
M
1
= 198 (Nm)
VËy : M
X
ST
= M
X
+M
1
M
2
3t
T
1=
1738N
P
2=
7640N
M
Y
2a ... (mm)
A
B
C
M
Z
M
Đ=
573Nm
M
1=
191Nm
M
2=
382Nm
573
3 82
191
(Nm)
aaa2a2a
A
B
C
P
2
T
2
M
2
M
A
P
1
T
1
M
1
3t
M
Đ
D
E
F
42
115
M
x
st
(Nm)
176
164
M
y
344
21 9
198
359
st
(Nm)
(Nm)
191
3 82
573
M
Z
Tính chuyển vị:
Ta có:
f=
2
2
2
2
)()(
Y
Z
X
Z
ff...
... P=qa
P.án 1 2 3 4 5 6 7 8 9 10
(1) EF 2EF EF EF EF 2EF EF EF EF 2EF
(2) EF EF 2EF EF EF EF EF EF EF EF
(3) 2EF 2EF EF 2EF 2EF 2EF 2EF 2EF 2EF EF
(4) 2EF 2EF 2EF EF 2EF 2EF 2EF 2EF 2EF 2EF
(5) P 2P P ... (1) (2) (3) (4) (5) (6) (7) (8)
1 EF 2EF P P a a a 3a
2 EF 2EF 2P P 2a a a a
3 EF 2EF P 2P a 2a a a
4 2EF 1EF P P a 2a a a
5 EF 2EF 2P P a a 2a a
6 EF 2EF P P 2a a a a
7 EF 2EF P 3P a a 2a a
8 ... điểm D theo P, E, F, a, α
P.án 1 2 3 4 5 6 7 8 9 10
(1) EF EF 2EF EF EF 2EF EF 2EF EF 2EF
(2) 2EF EF EF 2EF 2EF EF 2EF 2EF EF EF
(3) 2EF EF EF 2EF 2EF EF 2EF 2EF EF EF
(4) 30
0
45
0
60
0
45
0
30
0
30
0
60
0
30
0
30
0
45
0
(5...