Đề thi HSG Tỉnh 2017 - 2018 đợt 2 (ngày thi 27.1.2018)

V i l t cac phuong trinh hoa hgc xay ra trong qua trinh thi nghiem va tinh ham lugng H2S trong khong khi thco ppm (so microgam chat trong 1 gam mau). Giam thi khdng giai thich gi them[r]

s d GIAO D y e VA DAO TAO ViNH LONG

D E CHINH T H t r C

K Y T H I C H Q N H Q C S I N H G I O I T H P T C A P T I N H N A M H Q C -

Khoa thi 21 thang 01 nam 2018 Mon thi: T I E N G A N H

Giam thi s o l : Giam thi so 2: (Ky vd ghi rd hq vd ten)

Ho va ten thi sinh: So bao danh:

Nam / nu: Ngay sinh: N o i sinh:

Hoc sinh trudng:

Chu v:

- Thi sinh Idm bdi true tiep tren de thi

- Thi sinh khong duac ky ten hay diing bat cu ky hieu gi de danh dau bdi thi

- Bdi thi duac viet rd rdng bang mot loai but, mot thu muc; khong duac viet bang muc , but chi hoac hai thu muc

s d GIAO DVC VA DAO T ^ O K Y THI C H Q N H Q C SINH GIOI T H P T C A P TINH ViNH LONG N A M H Q C 2017 - 2018

Khoa thi 21 thang 01 nam 2018 DE CHINH THlTC

(De thi gom c6 15 trang)

Mon thi: TIENC ANH

Thdi gian : 180 phiit (khong ke thoi gian giao de) Chuky

Ciam khao

Chfl-ky Ciam khao

Tong diem (Bang so)

Tong diem (Bang chu)

So phdch

S6 thu tic

Diem tirng phan: 1

11 Ill IV Cgng:

Hie&ng dSn thi Nghe hieu:

• 77?/ sinh c6 phitt de nghien ciht cac cdu hoi • Bai nghe gom phdn, moi phdn duoc nghe Idn • Bat ddu moi phdn deu cd thong bdo (bang tieng Anh) • Bat ddu vd ket thuc phdn thi nghe Id doan nhgc

1 LISTENINC (5 points) Part 1: Questions 1-8

You will hear a wildlife expert giving a talk to a group of bird lovers in the UK about a species called the Tawny Owl Complete the note below For questions 1-8, write ONE WORD ONLY You will hear the recording twice

T h e T a w n y O w l Most (0) common owl species in UK

Strongly nocturnal Habitat

Mainly lives in (1) , but can also be seen in urban areas, e.g parks Adaptations

• Sbort wings and (2) , for navigation

• Brown and (3) featbers, for camouflage • Large eyes (more effective tban tbose of bumans), for good nigbt vision

• Very good spatial (4) , for predicting wbere prey migbt be found • Excellent (5) , for locating prey from a percb

Diet

• Main food is small mammals • Owls In urban areas eat more (6) Survival

• Two tbirds of young owls die witbin a (7) • Owls don't disperse over long distances

• Owls seem to dislike flying over large areas of (8)

Part 2: Questions 9-17

You will hear part of a radio program in which the presenter is talking about the attractions of an area For questions to 17, fill in the missing information You will hear the recording twice

L O C A L ATTRACTIONS H A L F O R D

castle regarded as tbe (00) best - preserved castle in tbe country

L I N B U R Y I bas one of tbe best (9) in tbe country

LEWISTON I a number of (10) bappened tbere

ROCKFIELD

main attraction: tbe (11) B U C K T O N

zoo: you can save money if you buy a (12) WESTHILL

main attraction: tbe (13) STONE

castle not (14) tbe castle in Halford

L O X T O N zoo bas rare breeds and popular (15)

COUNDON

main attraction: tbe (16) T R A C E

main attraction: tbe (17)

Part 3: Questions 18-25

You will hear part of an interview on a train with two friends, Jane and Chris, chefs who both won prizes in the National Railway Chef of the Year competition For questions 18 - 25, choose the correct

answer A, B, C, or D You will hear the recording twice 18 What was Chris's attitude to the competition?

A He was worried about tbe quality of bis dishes B He was afraid time migbt be a bit of a problem C He admitted he'd been looking forward to challenge D He said conditions were similar to bis normal routine

19 Jane admitted that tbe greatest problem she faced during tbe competition was having to A work in a very small space

B be original when travelling at speed C prepare a meal so quickly

D create a meal with so little money

20 What both Chris and Jane feel is unique about their job? A tbe close contact with tbe customers

B tbe necessity to everything at tbe same time C tbe opportunity to be creative

D tbe need to be focused on tbe Job

21 What Chris and Jane feel about what they cook on board tbe train? A They approve of tbe menus created for them | B They consider themselves more adventurous tban other chefs C They would like to have more freedom of choice

D They are happy to adapt their ideas to suit tbe job

22 Chris thought being a railway chef would suit bim mainly because it would enable bim to A show bis ability to work under pressure

B use tbe skills be bad been trained for C something out of tbe ordinary D satisfy bis love of traveling

23 What is often Jane's initial reaction when things spill over? A She asks another member of staff to help her clear up B She blames tbe train driver for tbe accident

C She tells herself to keep a closer watch next time D She says nasty things to tbe other staff

24 What does Chris say caused bis worst disaster? A leaving things to burn under tbe grill B dropping tbe main cause on tbe floor C losing bis concentration when cooking D not keeping an eye on tbe oven temperature

25 How does Jane react to Chris's suggestion for tbe future? A She's determined that she'll join bim if she can B She's looking forward to a challenge of that kind C She's afraid Chris wouldn't want her company D She'd be unable to take part in that kind of activity

II LEXICO AND GRAMMAR (4 points)

Part 1: Choose the best answer (A, B, C or D) to each of the following questions and write your

answers (A, B, C, D) in the corresponding numbered boxes:

1 When Josh phoned, he sounded like he quite a shock B had had C had been having released at tbe end of next year

A on tbe verge of being B on tbe point of being C due to be A bad

2 Tbe film is

D would have D about to be 3 Most teenagers go through a rebellious

A stint B span

for a few years but they soon grow out of it C duration

4 Fred Astaire is one of my favorite dancers and I love tbe way be seems to A glide B march C skid

5 Scientists are predicting that tbe volcano migbt erupt so people have been A escaped B emigrated C exported

6 Sending out e-mails that people haven't asked for to 'spamming'

A sufficient B widespread C countless 7 To be honest, Harry bas tban you have

D phase

across tbe floor D dash

from tbe area D evacuated addresses is often known as

D multiple A been more helpful considerably

B been considerably more helpful

8 Tbe play wasn't very good but it wasn't bad either

A Medium B Mediocre C Metric

C been more considerably helpful D considerably been more helpful

, I'd say

D Mellow My daughter is having trouble adjusting to

care package

A dorm life B adult life

at college I think I am going to send her a

10 My doctor 10 days

C social life D silence once be found out that I bad a sinus infection I have to take them for A experienced terrible heartburn

B prescribed an antibiotic

C took some blood D ran some tests 11 You that film last week - it was only released yesterday

A mustn't have seen B couldn't see

12 Mrs Davies asked me to tell you that she would like A tbe orders sent

B that tbe orders sending 13 Written to be performed on a England community

A stage scenery of bare B bare of stage scenery

C didn't need to see D can't have seen

by Friday at tbe latest C tbe orders to send

D to sending tbe orders

, Thornton Wilder's play Our Town depicts life in a small New C scenery bare of stage

D stage bare of scenery

14 A l l tbe novels we have studied this year have bad a man as tbe leading character It's about time we bad a female

B antagonist

A protagonist C phenomenon D prodigy

Your answers

1 2 3 4 5 6 7

8 9 10 11 12 13 14

Part 2: For questions 15-20, write the correct form of each bracketed word in the corresponding

numbered boxes There is an example at the beginning

A newly-employed sales assistant at a DIY store was (0) unexpectedly (EXPECT) sacked after failing a computerized test, despite having performed so well that he was offered a promotion However, Mr Filer had been promoted before tbe results of tbe company's psychometric test bad come

through I Tbe ten-minute test presents (15) (APPLY) with statements including things like T

prefer to have close relationships outside work rather tban with fellow employees', and ' M y (16) (PRODUCE) is higher tban others I work with'

Unfortunately, after accepting tbe promotion, be received (17) (NOTIFY) that his efforts in tbe psychometric test bad been unsuccessful Although bis manager bad given bim assurances that there would not be a problem, he was (18) (RULE) by tbe bead office who insisted on Mr Filter's dismissal A company spokesperson insisted that their procedures were fair and ensured consistency and (19) (OBJECT),' Mr Filter was eventually escorted off tbe premises by security guards 'It is an (20) (ORDINARY) strange way to run a company,' be commented

Your answers : unexpectedly

15 16 17

18 19 20

111 READING (4 points)

Part I: For questions 1-12, read the text below and decide which answer best fits each gap Thomas Edison

On tbe nigbt of 21 October 1931, millions of Americans took part in a coast-to-coast ceremony to commemorate tbe passing of a great man Lights (1) in homes and offices from New York to California Tbe ceremony (2) tbe death of arguably tbe most important inventor of (3)

time: Thomas Alva Edison

Few inventors have (4) such an impact on everyday life, and many of his inventions played a crucial (5) in the development of modern technology One should never (6)

how revolutionary some of Edison's inventions were

In many ways, Edison is a perfect example of an inventor - that is, not just someone who (7)

up clever gadgets, but someone whose products transform tbe lives of millions He possessed tbe key characteristics that an inventor needs to (8) a success of inventions, notably sheer determination Edison famously tried thousands of materials while working on a new type of battery, reacting to failure by cheerfully (9) to bis colleagues: 'Well, (10) we know 8,000 things that don't work.' Knowing when to take no (11) of experts is also important Edison's proposal for electric lighting circuitry was (12) with total disbelief by eminent scientists, until be lit up whole streets with bis lights

1 A turned out B came off C went out D put off

2 A marked B distinguished C noted D indicated

3 A whole B full C entire D.all

4 A put B bad C.served D set

5 A effect B placed C role D.share

6 A underestimate B lower C decrease D mislead

7 A creates B.shapes C dreams D forms

8 A gain B make C achieve D.get

9 A announcing B informing C instructing D notifying 10 A by far B at least C even though D for all

11 A notice B.regard C attention D view

12 A gather B.caught C drawn D.received

Your answers here

1 2 3 4 5 6

7 8 9 10 11 12

Part ; For questions 13-20 Read the following newspaper article about an expedition and choose

the best answers (A, B, C or D) Write your answers (A, B, C, D) in the corresponding numbered boxes:

Tsunami

Tsunami is a Japanese word meaning "harbor wave" "Tsu" means harbor, while "nami" means wave In tbe past, tsunamis were sometimes referred to as "tidal wave " or "seismic sea waves" But both are misleading since tbe tidal waves are not related to tsunamis and most tsunamis are caused by earthquake-related mechanisms

Tsunami is a series of travelling ocean waves of extreme long length generated by disturbances related primarily to earthquakes occurring below or near tbe ocean floor Underwater volcanic eruptions and landslides can also generate tsunamis When these earthquakes occur beneath tbe sea, tbe water above tbe deformed area is displaced from its equilibrium position Waves are formed as tbe displaced water mass, which acts under tbe influence of gravity, tries to regain its equilibrium When large areas of tbe sea floor elevate or subside, a tsunami, which travels outward in all directions from tbe epicenter of an earthquake, can be created

other Subduction earthquakes, which are a series of violent waves, produce shaking that lasts for several minutes, and are particularly effective in generating tsunamis

On March 28, 1964, an earthquake occurred in Alaska triggering a Pacific-wide tsunami Tbe quake was accompanied by large vertical displacements over an approximate 200,000 square mile area along tbe source fault, much of this beneath Prince William Sound This vertical displacement generated a major tectonic tsunami that struck tbe southeast coast of Alaska, tbe Pacific Coast of British Columbia, and tbe west coast of tbe United States In addition to tbe tectonic tsunami, tbe violent shaking during tbe earthquake caused many large landslides and submarine slumps, which in turn produced destructive local tsunamis at many locations along tbe Alaskan coast Tbe earthquake bad a surface-wave magnitude of 8.4, an epicenter of 61.1° N , 147.5°W, and a depth of 23 km One of tbe waves reached a height of 31.7m above low tide Tbe waves destroyed two saw mills, tbe Alaska Railroad depot, and a small harbor Tbe death toll reached 106 and tbere was $84 million in damage

On December 26, 2004, another earthquake known as tbe Sumatra-Andaman earthquake occurred due to an undersea earthquake which bad an epicenter off tbe west coast of Sumatra, Indonesia Tbe earthquake triggered a series of devastating tsunamis that spread throughout tbe Indian Ocean, inundating coastal communities across South and Southeast Asia, including parts of Indonesia, Sri Lanka, India, and Thailand Tbe initial tsunami took a little over two hours to reach tbe teardrop-shaped island of Sri Lanka and additional waves continued to arrive for many hours afterward Estimates have put tbe worldwide death toll at 186,983 dead with 42,883 missing Tbe magnitude of tbe earthquake was between 9.1 and 9.3 At this magnitude, it is tbe second largest earthquake ever recorded on a seismograph Fishing villages have been wiped out and tourist resorts wrecked Sri Lanka's economy will be tbe hardest bit and Thailand's tourism industry will have to pick itself up again Tbe immediate impact on tbe Indian economy is seen as negligible, but overall South Asia's economies and markers are likely to suffer tbe most from tbe disaster i

In Hawaii, tbere are reportedly technical systems that allow countries in tbe Pacific to receive warnings well in advance of tsunamis reaching their shores In combination with well-developed infrastructure, it is likely that tbe system would have saved many lives bad it been in operation When tbe earthquake struck off Sumatra, a monitoring system could have predicted tbe possibility of an approaching tsunami caused by tbe earthquake by measuring underwater sea currents Such a system can inform tbe relevant governments in tbe area around tbe Indian Ocean, and they can then warn their people to evacuate coastal areas Currently, implementing various measures for tsunami preparedness is a priority worldwide

13 What is tbe passage mainly about? A How a tsunami is generated

B Tbe effects of tbe December 2004 tsunami

C How tsunamis work and tbe past tsunamis disasters D Tbe difference between tsunamis and earthquakes 14 In paragraph I, what can be inferred about tsunamis?

A Tbe terms used in tbe past are regarded as misnomers B Tsunamis are only caused by earthquakes

C Tbe meaning of Tsunami bas been changed over time D Tsunamis usually occur along tbe harbor

15 According to paragraph 3, bow are subduction earthquakes generated? A One slab of rock pushes below an overriding one

B Massive amounts of stored energy are released C Two plates move in opposite directions

D Waves move through solid rock and fluids

16 Which of the following is not mentioned as the causes of tsunamis in the passage?

A Tidal waves B Earthquakes C Volcanic eruptions D Landslides 17 What is implied about tidal waves in tbe passage?

A Most people mistakenly believe a tsunami is caused by a tidal wave B Most tsunamis are generated by tidal waves

C Tidal waves and gravity play an important role in generating tsunamis D Tidal waves and seismic energy combined generate tsunamis

18 Which of tbe following does tbe author not explain about tsunamis in Alaska and in Asia? A Tbe casualties C Impact on politics

B Tbe magnitude of tbe earthquake D Tbe location wbere tbe earthquake occurred 19 What is NOT expected if an earthquake occurs in Hawaii in tbe future?

A Fewer losses of lives are expected C Advance warnings are expected B Rapid evacuation is expected D Better infrastructure is expected 20 Why does tbe author mention tbe countries Sri Lanka and Thailand in tbe passage? A To illustrate that tbe countries were badly damaged by tbe earthquake in 2004 B To suggest that economic slumps have been deepened by several factors C To explain that tbe countries have better warning systems for tsunamis D To say that these countries will not be affected by tsunamis any longer

Write your answers here

13 14 15 16 17 18 19 20

Part 3: Questions 21-34 are based on the reading passage below The Future of fish

Tbe face of tbe ocean bas changed completely since tbe first commercial fishers cast their nets and books over a thousand years ago Fisheries intensified over tbe centuries, but even by tbe nineteenth century it was still felt, justifiably, that tbe plentiful resources of tbe sea were for tbe most part beyond tbe reach of fishing, and so tbere was little need to restrict fishing or create protected areas Tbe twentieth century heralded an escalation in fishing intensity that is unprecedented in tbe history of tbe oceans, and modern fishing technologies leave fish no place to bide Today, tbe only refuges from fishing are tbose we deliberately create Unhappily, tbe sea trails far behind tbe land in terms of tbe area and tbe quality of protection given

For centuries, as fishing and commerce have expanded, we have held onto tbe notion that tbe sea is different from tbe land We still view it as a place wbere people and nations should be free to come and go at will, as well as somewhere that should be free for us to explore Perhaps this is why we have been so reluctant to protect tbe sea On land, protected areas have proliferated as human populations have grown Here, compared to tbe sea, we have made greater headway in our struggle to maintain tbe richness and variety of wildlife and landscape Twelve percent of tbe world's land is now contained in protected areas, whereas tbe corresponding figure for tbe sea is but three-fifths of one percent Worse still, most marine protected areas allow some fishing to continue Areas off-limits to all exploitation cover something like one five-thousandth of tbe total area of tbe world's seas

package of reform for fisheries management They underpin and enhance all our other efforts There are limits to protection though I

Reserves can not bring back what bas died out We can never resurrect globally extinct species, and restoring locally extinct animals may require reintroductions from elsewhere, i f natural dispersal from remaining populations is insufficient We are also seeing, in cases such as northern cod in Canada, that fishing can shift marine ecosystems into different states, wbere different mixes of species prevail In many cases, these species are less desirable, since tbe prime fishing targets have gone or are much reduced in numbers, and changes may be difficult to reserve, even with a complete moratorium on fishing Tbe Mediterranean sailed by Ulysses, tbe legendary king of ancient Greece, supported abundant monk seals, loggerhead turtles and porpoises Their disappearance through bunting and overfishing bas totally restructured food webs, and recovery is likely to be much harder to achieve tban their destruction was This means that tbe sooner we act to protect marine life, tbe more certain will be our success

To some people, creating marine reserves is an admission of failure According to their logic, reserves should not be necessary if we have done our work properly in managing tbe uses we make of tbe sea Many fisheries managers are still wedded to tbe idea that one day their models will work, and politicians will listen to their advice Just give tbe approach time, and success will be theirs How much time have we got? This approach bas been tried and refined for at last 50 years Tbere have been few successes with which to feather tbe managers' cap, but growing litany of failure Tbe Common Fisheries Policy, tbe European Union's instrument for tbe management of fisheries and aquaculture, exemplifies tbe worst pitfalls: flawed models, flawed advice, watered-down recommendations from government bureaucrats and then tbe disregard of much of this device by politicians When it all went wrong, as it inevitably bad to, Europe sent its boats to other countries in order to obtain fish for far less tban they were actually worth I

We are squandering tbe wealth of oceans If we don't break out of this cycle of failure, humanity will lose a key source of protein, and much more besides Disrupting natural ecosystem processes, such as water purification, nutrient cycling, and carbon storage, could have ramifications for human life itself We can go a long way to avoiding this catastrophic mistake with simple common sense management Marine reserves lie at tbe heart of tbe reform But they will not be sufficient if they are implemented only here and tbere to shore up tbe crumbling edifice of tbe 'rational fisheries management' envisioned by scientists in tbe 1940s and 1950s They have to be placed centre stage as a fundamental underpinning for everything we in tbe oceans Reserves are a first resort, not a final resort when all else fails

Questions 21 -25

Do tbe following statements agree with tbe information given in tbe reading passage In the boxes 21-25 write

TRUE if the statement agrees with the information FALSE if the statement contradicts the information NOT GIVEN if there is no information on this

21 It is more tban a thousand years since people started to catch fish for commercial use 22 In general, open access to tbe oceans is still regarded as desirable

23 Sea fishing is now completely banned in tbe majority of protected areas 24 People should be encouraged to reduce tbe amount of fish they eat

25 Tbe re-introduction of certain mammals to tbe Mediterranean is a straightforward task

Write your answers here

21 22 23 24 25

Questions 26 -28

CIRCLE the correct answer, A, B, C or D

26 What does the writer mean with the question, "How much time have we got?" in the fifth paragraph?

A Fisheries policies are currently based on uncertain estimates B Accurate predictions will allow governments to plan properly C Fisheries managers should provide clearer information D Action to protect fish stocks is urgently needed

27 What is tbe writer's comment on tbe Common Fisheries Policy? A Measures that it advocated were hastily implemented B Officials exaggerated some of its recommendations C It was based on predictions which were inaccurate D Tbe policy makers acquired a good reputation

28 What is tbe writer's conclusion concerning tbe decline of marine resources? A Tbe means of avoiding tbe worst outcomes needs to be prioritized B Measures already taken to avoid a crisis are probably sufficient C Tbe situation is now so severe that tbere is no likely solution D It is no longer clear which measures would be most effective

Questions 29 - 34

Complete the summary using the list of words/phrases, A-J, below Write the letters (A-J) in the given

spaces. I

Measures to protect the oceans

Up till tbe twentieth century tbe world's supply of fish was sufficient for its needs It was unnecessary to introduce (29) of any kind, because large areas of tbe oceans were inaccessible However, as (30) improved, this situation changed, and in tbe middle of tbe twentieth century, policies were introduced to regulate (31)

These policies have not succeeded Today, by comparison with (32) , tbe oceans have very little legal protection

Despite tbe doubts that many officials have about tbe concept of (33) , these should be at tbe heart of any action taken These consequences of further (34) are very serious, and may even affect our continuing existence

A action B control C failure D fish catches E fishing processing F fishing techniques G large boats

H marine reserves Ithe land J the past

Part 4: You are going to read an extract from a magazine article Six paragraphs have been

removed from the extract Choose from the paragraphs A-G the one which fits each gap (35-40) There is one extra paragraph which you not need to use

How to have a conversation

Is conversation a dying art, struck down by text, email and messaging? And we really need to be taught how to talk to each other? I enrolled in a class at the School of Life, and academy of 'self-help', to find out The topic was 'How to have a conversation'

35 I

I had arrived about twenty minutes early but tbe rest of tbe class was already tbere One woman kindly invited me into her circle She was finding it bard to have meaningful relationships Technology was partly to blame: "Sometimes you feel tbe smart phone is like a third person," she said Another new acquaintance agreed and described bow immediate access to Google bad blocked off avenues of conversation with her boy friend "Before we would argue about this or that but now we just look it up on Wikipedia," she said

36 I ~ My classmates also spoke of more personal

reasons for their attendance A n IT worker in her fifties bas found that her conversations with her husband "wandered" and wanted to learn ways to become a better partner A man in bis late twenties said be wanted to have fewer rows with bis girlfriend

37 I ~ Our discussion was interrupted by tbe arrival of

our teacher, Cathy Haynes Haynes flicked to tbe first slide in her Power Point presentation and we sat attentively as she talked about bow tbe nature of conversation bad changed over tbe past 300 years

38 I

After an enjoyable ten minutes spent chatting to my classmates and discovering more about

their motives for joining tbe class, we were told to retake our seats Haynes continued her Power Point presentation, as king us to reflect on a Rene Magritte painting, a comedy sketch and a book about marriage A i l of these examples were a means to an end and to avoid stereotyping tbe other person

39 I ~ Then it was time to put some of these ideas into

practice In groups, we bad to try our ideas for unusual openings A man in bis early twenties, who joked that be bad thought of this before, suggested as a chat-up line: "Tell me something I want to know." A more challenging opener came from another group member: "If you were coming to tbe end of your life, what would you have wanted to have achieved?"

40 I ~ Despite our excellent teacher, I suspect tbe

class was too abstract to be useful Nearly three-quarters of tbe session were spent listening to theories of conversation Genuine discussions were stopped in mid-flow, with tbe class asked to return its attention to tbe presentation Tbere was a touching eagerness to share ideas but frustration grew as our time ran out What I suspect my classmates bad hoped to find was that most basic thing: human connection But I doubt tbe class bad made this any more available

A These aims seemed disappointingly unambitious to me I bad hopes of becoming a witty and intellectual conversationalist But none of my new friends shared this desire It was tbe simple act of talking and listening that my classmates sought

B Some useful advice followed on the six ways to have better conversation" These according to school, are: (1) Be curious about others (2) Take off your mask (3) Empathize with others (4) Get behind the job title (5) Use adventurous openings (6) Have courage

C Haynes went on to explain that tbe Enlightenment was tbe age of conversation, when ladies and gentlemen in English dining rooms and French salons could become famous through eloquence

alone D Then we were told to break off into pairs and answer tbe question: Which three words describe

your conversations with (1) friends, (b) family, (c) colleagues? My partner said banter, sacrifice and sporadic were tbe words be would use to describe ail three types of conversation Before I bad a chance to share my three words, it was time for a break

E Tbere was general unease about bow email, instant messaging and texting bad crept into tbe space formerly occupied by conversation "What was tbe point," asked a young man, "of asking bow someone's day was when you've been emailing them from tbe office?"

F After this enjoyable burst of role play Haynes put up a slide that said: What conversation are you not having? and then it was ail over Once tbe class structure bad been dismantled, conversation seemed to dwindle

G Tbe basics of this were first described by tbe ancient Roman writer Cicero, which can be summarized as follows: speak clearly, not interrupt, be courteous, never criticize people behind their backs, stick to subjects of general interest, not talk about yourself and, above ail, never lose your temper

IV WRITING (5 points)

Part 1: Complete tbe second sentence so that it bas a similar meaning to tbe first sentence, using tbe word given Do not change the word given You must use between three and eight words, including tbe word given

1 Tbe suggestion to increase tbe entrance fee at tbe disco came from Tony, should

It was Tony increased at tbe disco It is as yet unclear whether a new sports center is being planned or not

seen I ft are any plans for a new sports center or not

3 Tbe twins are so alike that most people find it bard to distinguish them,

difference |

The twins are so alike that not many people them Unfortunately, Katie bas decided to withdraw from tbe competition,

pull

Unfortunately, Katie bas made up tbe competition Most people are more aware of other people's faults tban they are of their own

identify

Most people are they are tbose of others

Part 2: The flow chart illustrates the consequences of deforestation Summarize the information by selecting and reporting the main features

Write your answer to the task in at least 150 words

micro-organisms feeding on waste lost

pioneer species move in, vegetation is spoilt

I

less biodiversity heavy logging

equipment compresses the soil

fewer roots hold the top soil in place

Increased risk of burning (intentional or

accidental)

plans return less moisture to air

soil becomes hard and 'baked'

top soil erodes waste wood from logging is destroyed

less rain

increased drought

You may begin with: The flow chart shows what typically occurs as a sequence of_

Part 3: Write an essay about 250 words on the following topic

Some say that because many people are living much longer, the age at which people retire from work should be raised considerably

To what extent you agree or disagree? ' Provide specific reasons and examples to support your opinion

t

(You may continue your writing on the back page if you need more space)

—HET—

s d G I A O D V C V A D A O T A O K Y T H I C H Q N H Q C S I N H G I O I T H P T C A P T I N H V I N H L O N G N A M H Q C 2017 - 2018

Khoa thi 21 thang 01 nam 2018 H i r d N G D A N C H A M M O N T I E N G A N H

T O N G D I E M : 18

1 L I S T E N I N G : (0.2 x 25 = points)

Part 1:

1 woodland/woods/forest(s) tail

3 grey/gray memory

Part 2:

9. cathedrals 10 battles

11 transport museum 12 (cheap) family ticket 13 boating lake

5 bearing birds 7 year water

14 as big as 15 Snake House 16 art gallery 17 theme park

Part 3:

18 D 19 B 20 A 21 C 22 D 23 B 24 C 25 D

Part 1:

II L E X I C O A N D G R A M M A R tO.2 x 20 = pointsl

1 B 2 C 3 D N A 5 D 6 D 7 B

8 B 9 A 10 B 11 D 12 A 13 D 14 A

Part 2:

15 applicants 16 productivity 17 notification 18 overruled 19 objectivity 20 extraordinarily

111 R E A D I N G (0.1 X 40 = points) Parti:

1 C 2 A 3 D 4 B 5 C 6 A

7 C 8 B 9 A 10 B 11 A 12 D

!

Part 2:

13 C 14 A 15 C 16 A 17 A 18 C 19 D 20 A

Part 3:

21 T 22 T 23 F 24 NG

26 D 27 C 28 A 29 B

30 F D 32.1 33 H Part 4:

25 F

34 C

35 G Part 1: (1 point)

36 E 37 A 38 D 39 B 40 F

IV WRITING (5 points)

who/that suggested that the entrance fee should be increased at the disco It was Tony

2 It remains to be seen whether there are any plans for a new sports center or not The twins are so alike that not many people can tell/see the/any difference between

them I Unfortunately, Katie has made up her mind to pull out of the competition

5 Most people are less able to identify their own faults than they are those of others

Part 2: (2 points)

- Task achievement (0.5)

(e.g requirement of the task, overview of main trends, differences or stages, purpose, highlights key features/bullet points)

- Coherence and cohesion (0.5)

(e.g logically organizes information and ideas, progression, cohesive devices) - Lexical resource (0.5)

(e.g range of vocabulary, word choice, spelling, lexical items) - Grammatical range and accuracy (0.5)

(e.g range of structures, simple and complex structures, error free sentences)

Part 3: (2 points)

- Task response (0.5)

(e.g addresses parts of tbe task, position, main ideas, supporting ideas, conclusion drawn) - Coherence and cohesion (0.5)

(e.g logically organizes information and ideas, progression, cohesive devices, central topic witbin each paragraph, referencing, paragraphing)

- Lexical resource (0.5)

(e.g range of vocabulary, word choice, spelling, uncommon lexical items, awareness of style and collocation)

- Grammatical range and accuracy (0.5)

(e.g range of structures, simple and complex structures, error free sentences)

sd GIAO D V C V A D A O T A O K Y THI CHQN H Q C SINH G i d l C A P THPT V O N G T i N H J VINH L O N G N A M H Q C 2017 - 2018

Mon thi: T O A N

Thai gian lam bai: 180 phut (khong ke thai gian giao de) Ngay thi: Sang 21/01/2018

DE CHINH THlTC

Bai (3.0 diem) Cho ham s6 y = x^ ~ f ' " ^ ^ ^2"^^ ^° ^^""^ ^^^^ ^™

tit ca gia tri thuc cua tham so m de d6 thi ( C „ ) c6 hai d i l m cue tri la ^ va cho dudng thang AB vuong goc dudng thing d :y = x

x+dx-]

Bai (3.0 diem) Giai phuong trinh 2''^^ -9.2 + 2^^^ = vdi x e R

Bai (4.0 diem) Cho hinh lang tru ABC.A'B'C bilt tam giac + C l a tam giac can, AB = BC = 3a, AC^2a. Cac mat phing (B'AB),(B'AC),(B'BC) cung tao vdi mat phing (ABC) mot goc 60°

a) Goi H la hinh chilu vuong goc cua B' tren mat phing (.4J5C) Chung minh H la tam dudng trdn noi tilp tam giac ABC

h) Tinh thi tich khdi lang tru ABC.A'B'C theo a

4sin''x-i-4cos Bai (3.0 diem) Giai phuong trinh

X

4 cos2x

- ^ =

Bai (4.0 diem) Cho x,y la hai so thuc thoa man dieu kien 2x^ + 2>'^ - xy = Tim gia tri ion nhit va gia tri nho nhit cua h i l u thuc P = (x"* + y"*) + 4x^y^

Bai (3.0 diem) Cho ABCD la hinh binh hanh tam O, d i l m I thuoc doan thdng OC (diem / khong trung vdi d i l m O va d i l m C ) Dudng thdng BI Ian lugt cit cac dudng thang CD va AD tai P, E cho BI = PE. Chung minh rdng

AD AE

SOf G I A O D V C V A D A O T A O K Y T H I C H Q N H Q C S I N H G I O I C A P T H P T V Q N G T I N H

ViNH L O N G N A M 2018

HlTOiNG D A N C H A M MON T O A N (Buoi sang)

Bai Cho ham s6 y = mx^ +-m^ c6 d6 thi (C„) (m la tham s6) Tim tkt ca gia tri thuc cua tham s6 m dk db thi (C„) c6 hai dilm cue tn la A\aB cho dudng thing AB vuong

goc dudng thang d:y = x. I

Bai Noi dung Dilm

1 3.0

Ta c6: / = -3mx => / = o

x = /w=>y =

1.0

De ham so c6 hai diem cue tri thi m^O

/ A ( ^ G i a s u ^ 0;-m^ ,B{m;0)^ AB= m, —

V / \ J

1.0

Ta CO vtpt ciia d la « = (1;-1)=>M = (1;1)

1 rw = o

Be AB Id o AB.u = 0^m—w'=0<=> ^

2 [m = ±d2 2>ffj = ± V

1.0

Bai Giai phuang trinh: 2'^' -9.2 ^ + 2^*^"^ = vdi x e M

Bai Noi dung Diem

2 3.0

Dilu kien x > 0.5

^ 2 - ^ - 2 + = 0.5

<3>

r x-d^i J 2 =

-2 o

2 ' =4

^ = - ^ = -1 (1)

^ = - ^ " ' = (2)

1.0

Giai (1) suy phuang trinh v6 nghiem 0.5

Bai Cho hinh lang tru ABC.A'B'C bilt tam giac ABC la tam giac can, AB ^ BC = 3a, AC = 2a Cac mat phing {B'AB),{B'AC),{B'BC) cung tao vdi mSt phing {ABC) mgt goc 60°

a) Goi H la hinh chilu ciia B' tren mat phing [ABC) Chiing minh H la tam ducmg

tron noi tiep tam giac ABC \

b) Tinh thi tich khii iSng Xm ABC.A'B'C _

Bai Noi dung Diem

3 4.0

B'Jw-^\y-^IA\\ / \

A

ZPf ^'

a) Ggi M, N, P lin lugt la hinh chieu ciia H tren AC, Ta CO goc giua (B'AC) va (BAC) la goc B'MH Tuong tu ta c6 B'MH = B'NH = B'PH = 60°

AB va BC

1.0

Do do AB'MH = AB'NH = SB'PH ^ HM = HN ^ HP

Vay H la tam dudng trdn noi tiep tam giac ABC 1.0 b) Theo cong thiic S^^^ = 2V2o^

Mat khac S^,, =pr^r = HM = ^ ^ = = p da

1.0

Tam giac vuong B'HM cd B'H = HM.taneo" =^.yf3 = ^ Tir dd V,,c ,.,.c = S^,c.B'H^ 2A2a\^ = 2V3a' ( dvtt)

1.0

4 sin" X + cos" (x - —) -1

Bai Giai phuong trinh ^ = cos2x

Bai Noi dung Diem

4 3.0

4sin" x + 4cos"(x-—)-l

Giai phuong trinh = 2(1) cos2x

Dilu kien: cos 2x <» x — + /t—(A: € Z)

0.5

( 7T Y

(l)c:>(l-cos2x)^+ l + cos(2x ) - l = 2cos2x

V ^

0.5

<=>(!- cos 2x)^ + (1 + sin 2x)^ -1 = cos 2x o - c o s x - s i n x = 2cos2x

o 2cos2x-sin2x =

<=> 2(cos^ X - sin^ x) - (cos x + sin x)^ = o (cos X + sin x)(cos x - sin x) =

0.5

0.5

cosx-i-sinx = cosx-3sinx = <3>

X = + A:;r

x = arctan i-A:;?r

(A:eZ) 0.5

K i t hgp vdi dilu kien phuong trinh da cho cd nghiem la x = arctan + (A: G Z) 0.5

Bai Cho x, y la hai so thuc thoa man dilu kien: 2x^ + 2y^ - xy = Tim gia tri Idn nhit va gia tri nho nhit ciia hieu thuc: P = 7(x"+y") + x V

Bai Noi dung Diem

4.0 rr ' 2 + xy „ _ 33 2 "7

Taco X +y - Suyra P = x y +-xy+—

2 - ^

1.0

1 = 2x^ + 2y^ - xy = 2(x + yf - 5xy > -5xy => xy > - - 0.5

1 = 2x^ + 2y^ - xy = 2(x - yf + 3xy >3xy=>xy<-j=>—j<xy<^ 0.5

Dat / = xy, re •5'3

o 33 7 => P = r ' + r +

-4 -4

0.5 70 18

Tim duoc maxP = — o r = —,minP = — o r = — 33 33 25

0.5 Ket luan

n 70 maxP - — <=>

33

hay

x = —

1 x = —

2 34 33 ^V33 X 34 33 ^33 hay

x = —

'=2

34 33 34 \ 3

_6_ 33 T_ 33 33 V33 -(33 hay X = —

2 ^ =

34 V33 34 33 _6_ 33 '33

minP = — o 25

1 x = —\y =

-1 x = —7=;y =

1

1.0

Bai

Cho ABCD la hinh binh hanh tam O, dilm / thuoc doan thing OC. Dudng thing BI l i n luot cit cac dudng thSng CD va AD tai P, E cho BI = PE Chung minh rang —^ i

-Noi dung | Die

m

6 3.0

A °

B C Ta dat AD - xAE^ BP = xBE

(1 ^ AI = yAC=y[AB4AD\ = yAB4yAD -<y<\

E

0.5

1 ( n

/ F = Z4 + T F = -y/15-yy4D + - T D = -yH45+ - y + - +D (1)

X I

0.5

BP = xBE^ X(bA + AE^j = -xAE + AD (2) 0.5

Tir (1) va (2) suy

[ x = y - y + - = l

I X

— <X<1 - + =

X

0.5

<=> •

\x = -''f(nhgn)

| x = ^ [logi)

0.5

AE AD -1 + V5 /7 ^

Vay + = + T= = V5 (dpcm) \

AD AE 2 - I + VS '

0.5

s d GIAO DVC V A DAO TAO KY THI CHQN HQC SINH GIOI THPT CAP TiNH

v i r m LONG ' N A M H Q C 2017-2018

Khoa thi 21 thang 01 nam 2018 Mon thi: Vat ly

Thdi gian: 180 phiit (khong ki thai gian giao de) Budi thi thir nhat: sang 21/01/2018

(DI thi cd 02 trang, gdm 05 cau) DE CHINH THirC

Cau 1: (3,50 diem)

Mot khoi hop cd khdi lugng m = 20 kg dugc keo chuyen ddng tren mat san nam ngang bdi luc F, hgp vdi phuong ngang mot gdc a He sd ma sat trugt giua vat vdi san la g Cho g = 10m/s3

1 K h i luc keo F=120N vdi gdc a =60° thi khdi hop chuyen ddng thing deu a Xac dinh va ve hinh cac luc tac dung vao khdi hop

b Tinh he sd ma sat trugt p

2 K h i gdc a =30° thi gia tdc chuyen ddng ciia vat bing bao nhieu? Cau 2: (4,00 diem)

Mot lugng Heli (p = 4) cd khdi lugng m=lg Ban dau cd nhiet dg t, =127°C va the tich la lit, dugc bidn doi qua giai doan:

- D i n g nhiet, the tich tang gip hai l i n - D i n g ap, thd tich trd v l gia tri ban diu

1 Xac dinh cac thdng sd trang thai va ve dd thi hieu dien cac qua trinh bien ddi he tga dd (p,T) Cho R = 0,082atm f/mol.dd

2 Tim nhiet dd va ap suit thip nhit qua trinh bien doi

Cau 3: (4,00 diem)

Vat sang A B dugc dat vudng gdc vdi true chinh cua mot thau kinh hoi tu L i A n h A j B i cho bdi L i la anh that, each A B 90cm va cao gip ddi A B Dat them thiu kinh phan ky Lj khoang giua A B va L i cho hai true chinh trung nhau, hai quang tam each

£ = 10cm A n h cudi cung cua A B cho bdi he thau kinh d vd cung Xac dinh tieu cu ciia L i va La

2 G i u nguyen vi tri ciia A B , doi cho hai thiu kinh L i va La Xac dinh vi tri ciia anh sau cung

Cau 4: (3,50 diem)

Cho hai dien tich d i l m qi=16|a,C va qa = -64 p C Ian lugt dat tai hai diem A va B chan khdng each 100cm Xac dinh vec ta luc dien trudng tong hgp tac dung len dien tich dilm qo=4 | i C dat tai:

1 D i l m M : A M = 60cm, B M = 40cm D i l m N : A N = 60cm, B N = 80cm

L , r

-UOTTO9N-M N

Cau 5: (5,00 diem)

Cho mach dien xoay chieu nhu hinh ben Hieu dien the xoay chieu hai d i u mach c6 b i l u thuc: UAB = Uo-coslOOTit (V),

bo qua dien tra cac day ndi Cac hieu dien the hieu dung: UAN = 300 (V), UMB = 60N/3 (V) Hieu dien thd tuc thdi UAN lech pha so vdi UMB mot goc Cugn day cd he sd txjc cam

L = - T = (H) vdi dien trd r, dien dung cua tu dien C =^-^^ (p)

1 Tinh dien trd r Vidt bidu thuc hieu dien thd tuc thdi giua hai didm A N

2 Thay ddi R ddn cdng suit tidu thu trdn no cue dai Tinh gia tri cua R luc

H i t

HQC sinh khong duac su dung tai lieu - Giam thi khong gidi thich gi them

SOf GIAO DVC VA DAO TAO VINH LONG

DE C H I N H T H V C

KY THI CHON HQC SINH GIOI THPT CAP XiNH * NAM HQC 2017-2018

Khoa thi 21 thang 01 nam 2018 Mon thi: Vat ly

Thdi gian: 180 phut (khong ke thai gian giao de) Bu6i thi thu nhat: sang 21/01/2018

H L T O N G D A N CHAM

Can 1: (3,50 diem)

Mot kh6i hop c6 khoi lugng m = 20 kg dugc keo chuyin dong tren mSt san nkm ngang bdi lire F, hgp vol phuang ngang mgt goc a He s6 ma sat trugt gida vat vdi san la p Cho g = 10 m/s^

1 Khi luc keo F=120N va goc a =60° thi khdi hop chuyen ddng thing dIu a Xac djnh va ve hinh cac luc tac dung vao khdi hop

b Tmh he so ma sat trugt p

2 Khi gdc a =30° thi gia tdc chuyin ddng ciia vat bing bao nhieu?

Hudng dan cham Die

Cau m

1 a Cac luc tac dung len vat: Luc keo F , trgng luc p , phan luc Q ciia mSt san, va luc ma sat Fn

b Theo djnh luat 11 Niu ton:

P + Q + F + Fms =ma (1) Chilu (1) theo phuang thing dung, chilu (+) hudng len:

Q + F.sina-P=0 =>Q = P - F s i n a (2)

Chieu vat theo phuong ngang, chilu duong la chieu chuyen dong F.cosa - Fms= ma => F.cosa - pQ = ma (3)

Khi luc keo F hgp vdi phuang ngang gdc 60° thi vat chuyen ddng thang deu nen a=0, thay (2) vao (3) ta dugc:

F.cosa - p(mg - F.sina) = Fcosg

p = ^7-; wO, 624 =>

m g - F s i n a

2 Khi gdc a =30° thi gia tdc ciia vat la

(2) va (3) =4 a _ F(cosa + psin g) - pmg m

^0,83 m/s'

0.25d

0,50 d 0,25 d 0,25 d 0,25 d

0,50 d 0,50d

1,00 d

Cau 2: (4,00 diem)

Mgt lugng Heli (p = 4) cd khdi lugng m=lg Ban diu cd nhiet t, =127°C va thi tich la lit, dugc biln ddi qua giai doan:

- Ding nhiet, thi tich tang gap hai Ian - Dang ap, the tich trd v l gia tri ban dau

1 Xac dinh cac thdng sd trang thai va ve thi bllu dien cac qua trinh blln doi he toa dg(p,T)

Cau Hudng dan cham Diem

1 Vedd thi

- Trang thai 1: (p, ""^^^ - 2,05 atm Vi= / , Ti = 400K)

pv, 0,50 d

- Trang thai II: (p2, ¥2= 2Vi= ^, T2 = Ti= 400K)

- Trang thai III: (ps = p2, V3= Vi= ^, T3) D6 thj nhu hinh ben

b Nhiet va ap suit thap nhat qua trinh bien doi Tren thj ta thay Pmin = P2

Xet qua trinh ding nhiet (1 )-(2) ta c6: , PiV, = P2V2 => P2 = PiV, 1 '1 _ = 1,025 atm

=>Pmin = P2= 1,025 atm Tren thj ta thay Tmin = T3 xet qua trinh ding ap (2) -(3) ta c6:

V V V T

2^ = 2±^T=llh. =200K

T Vat

0 T3 T | T .Hinh v5

T^in = T3=200K haytn3in=-73°C

Cau 3: (4,00 diem) | Vat sang AB dugc dat vuong goc voi true chinh ciia mgt thau kinh hgi tu L i Anh A i B i cho bdi Li la anh that, each AB 90cm va cao gip doi A B Dat them thiu kinh phan ky L2 khoang giua AB va Li cho hai true chinh trung nhau, hai quang tam each £ = 10cm Anh cudi cung ciia AB cho bdi he thiu kinh d vd cung

1 Xac djnh tieu cu ciia Li va L2

2 010 nguyen vj tri ciia A B , ddi cho hai thiu kinh Li va L2 Xdc djnh vj tri cua anh sau cimg

Cau Hudng dan giai Diem

1 Tieu cu ciia thau kinh Li va L2

a Khi chua dat them L2, Vat AB qua Li cho anh A i B i Khidd: d, = A , A - d , =90-d,

Mat khac: k = - i - = -^^51^ = -2 d, d, ^ d, = 30cm va d', = 60cm ct> f - _ i ^ = c m

d,+d,

b Khi dat them thiu kinh L2

0,25d 0,25d 0,50d 0,50 d

Ta cd so tao anh: A B ^ ^ A B , — ^ A , B d, d; dj dj '•2^2 Tir dilu kien bai toan ta dugc di = 30 -10 = 20cm

d , - f , - f

20-Ma dj = oo-^dj = f, = 20cm - f

rt> f2=-20cm

2 Khi d l i cho hai thau kinh cho

So tao anh ' ' ' ' d, d; d^ d^ Vdi thiu kinh L i

Ta cd di = 20 cm = fi nen di' = 00 Vdi thau kinh L2

0,25 d 0,25d

0,25d 0,25d 0,50d

0,25d

d2=dl==o 0,25d

d'2 - - -20cm 0,25d

0,25d Cau 4: (3,50 diem)

Cho hai dien tich dilm qi=16 | i C va q2 = -64 p C lin luot dat tai hai dilm A va B chan khong each 100cm Xac dinh vec to luc dien trudng ting hgp tac dung len dien tich dilm qo=4|jC dat tai:

1 Dilm M : A M = 60cm, B M = 40cm Dilm N : A N = 60cm, B N = 80cm

Cau Hudng dan cham Diem

A M Fio F20 F B

â â ã â

qi qo q2 V i M A + M B = A B vay dilm M , A, B thing hang M nim giua A B Luc dien ting hgp tac dung len qo:

F = Fio + F20

V i Fio cung hudng vdi F20 nen luc dien trudng tong hgp F cd

- Do Id-n: | F - F.o + F,o - k ^'^^ + k "^'^ - N

'° A M ' B M ' V i N A ' + N B ' = A B ' => A N A B vuong tai N

Hgp luc tac dung len qo la: Fiợ F = FiơF2o ^° ^

F = VF,O + F,', = , N / F ^ o^ X F hop vdi NB mot gdc a nhu hinh ve: /

• P • qi 01

t a n a - ' ° - , 4 r ^ > a - ° A B F20

0,50d

0,50d 0,50 d

0,50 d

0,50d

0,50d

0,5d

Cau 5: (5,00 diem)

Cho mach dien xoay chieu nhu hinh ben Hieu dien thi xoay ^ ^ L , r ^ chieu hai dau mach cd hieu thdc: U A B = Uo.sinl007rt (V), bd qua • C Z Z Z > ^ j j - « ( J ^

j dien trd cac day ndi Cac hieu dien thi hieu dung: UAN = 300 (V),

UMB = 60N/3 (V) Hieu dien thi tuc thdi UAN lech pha so vdi UMB mgt gdc — Cugn day cd he s6 tu cam L = —7= (H) vdi dien trd r, dien dung ciia tu dien C =—'• (F)

W ' 167t

1

2

Tinh dien tra r Vilt bieu thuc hieu dien the tdc thdi gida hai diem A, N

Thay doi R din cdng suit tieu thu tren no c\rc dai Tinh gia trj ciia R liic

Cau Hudng dan cham

100 160 a) Tinh r: Z, = co.L = - -Q ; = — = -r-Q

di oiC 43

1 z ,

Ta cd: (PAN + (PMB = 7i/2 Suy ra: tgcp,^, = , tu do:

R + r Zc - Z L

tg^MB

Vay : Z L (Z C - Z L ) = r.(R + r), hay: U^CUc - U J = U , ( U R + U,) (1)

Mat khac: U ^ N = (U, + U R )' + U ^ (2)

Va: U J , = U ; - ( U L - U C ) ' (3)

Uf

Tu (1), ta nit ra: ( U R + U , ) ' = - ^ ( U ^ - U j '

Thay (4) vao (2):

T2 /TT TT X2 r,2 ULfyxT XT N2 x T2 (4)

U I N = T ; r ( U c - u j ' + K = tA ( U C - u j ' + (5) u

u v U x y

.u Thay (3) vao (5), ta dugc: U ^ N =

^.x X , U L 300 Bien doi ta co: = = -7= ,

60V3 Vs

V3 100A/3 suy ra: r = Z L — = —7=- = 20Q

5 5V3

Bilu thiic UAN:

- Ta cd: uAN = UOANCOS(1 OOrit + (p^^N) •

+ Bien dd: UOAN = 300V2 (V) + Pha ban diu:

9UAN = <Pi + 9AN = 9U - + 9AN = - + (PAN Z, - Z p

Ma: tg(p = C, ^

M B

(6)

R + r

100 160 100 T u m u c l t a c : R + r = ^ ^ ^ ^ c- Z L ) , V i U ^

r 20

Suy ra: R = 80Q ' Thay vao (8), ta tinh dugc: tgcp = - 0,346 ^ (p = -19°

(7)

(8)

= ioon

Ta lai cd: tgcp^N = 100 Vay: (py = 19°+30° = 49° = —(rad)

R + r IOOV3 yji

4971

180

^ - (PAN =30"

-Biluthiic: u,,, =30oV2cos(1007rt + —) ( V ) 180

(9) (10) (11)

(12) (13)

2 Cong suat tieu thu tren R :

P R = U R =

U ' R u"

V(R + r ) ' + ( Z , - Z e ) '

R +

r ' + ( Z , - Z c ) '

R

+ 2r Theo Co si: PRmax khi R = /r' + (Z^ - Z^)^ = 40D

0,25 d

0,50d

Chii v: - N6u hoc sinh lam theo each khac diing van cho dii s6 dilm

- NIU hoc sinh lam sai don vi, hoac khdng cd don vi thi trir 0,25d nhung khdng qua 2ian/cau

sd G I A O D U G V A D A O T A O K Y T H I C H Q N H O C S I N H G I O I T H P T C A P T i N H , V i N H L O N G N A M H Q C 2017-2018

I Khoa thi 21 thang 01 nam 2018 D E C H I N H T H l T C Mon thi: H O A H Q C (BUOI S A N G )

Thdi gian: 180 phut (khdng ke thai gian giao de) D I thi C O 02 trang, g6m 06 cau

Cho: , i N a , „ C , ,3A1, , N , gO, 9F, ^ K , j^S, ^ A r , ^^Ca, jjMg, ^C, ^^Ca, ggBr, ^^Ve, ^Be Na = 23, K = 39, Ca = 40, M g = 24, Cu = 64, Fe = 56, Pb = 207, Zn = 65, A l = 27, Ba=137, A g = 108, Cr=52, M n =55, C = 12, H = 1, O = 16, CI = 35,5, S = 32, N = 14, Br= 80,1 = 127 , Be =

Do am dien: CI = 3,16; O = 3,44; N = 3,04; C = 2,55; A l = 1,61; H = 2,2; C a n 1(5,0 diim):

J l I Thuc hien phan ung hoa hoc theo so d6 sau, ghi d i l u kien (nlu co)

M n O (1)

NaClO — ^ C h

+ C l _ ( l L ^ H2SO4 H N - ^ N H N O (7) • N ,

H3PO4 - i ° U K H P O (10) ^ K H P O

1.2 Chit (X) tao tu nguyen t l (A), (B), (C) co cong thiic phan tii la A B C T6ng s6 hat co ban phan tii (X) la 82, so hat mang dien nhilu hon s6 hat khong mang dien la 22 Hieu s6 k h I i ciia (B) va (C) gap 10 l i n s6 k h I i cua (A) T6ng so k h I i cua (B) va (C) g i p 27 l i n s6 khoi ciia (A) Xac djnh s6 khdi ciia (A), (B), (C)

1.3 Can bang cac phan ling oxi hoa khii theo phuong phap thang bSng electron: a) CrjSj + Mn(N03)2 + NazCOj ^ Na2Cr04 + Na2S04 + Na2Mn04 + N O + CO2 b) FCxOy + H2SO4 ^ Fc2(S04)3 + SO2 + H2O

C a u (2,0 diem):

2.1 Neu hien tugng va v i l t phuong trinh phan ung xay dang ion cac thi nghiem sau: ' a) Cho tu tu d i n du dung dich H C l vao dung dich chua N a A l G j (hoac Na[Al(0H)4]j

b) Cho dung dich H2SO4 loang vao dung dich Fc(N03)2-I c) Cho FC3O4 tac dgng voi dung dich HFc(N03)2-I du

d) Sue CI2 den du vao dung djch Br2

2.2 Nguyen t l luu huynh tao voi flo hgp chit SFn, n co gia trj cue dai Dua vao c i u hinh electron ciia S d l tim gia tri V i l t cong thuc c i u tao, cong thiic electron ciia SFn Cac obitan nguyen tii trung tam S lai hoa kieu gi? Dang hinh hgc ciia SFn?

C a u (4,0 diem)

3.1 Co (A), (B), (C), (D), (E)

I - K h i (A) dugc dieu c h i bSng each dun nong K M n

- K h i (B) dugc dieu che bang each cho K M n tac dung voi dung dich H C l - Khf (C) thu dugc bang each dot chay hoan toan quang CuFcS2 oxi

- K h i (D) dugc d i l u c h i bSng each cho quang sit FCS2 tac dung voi dung djch H C l - K h i (E) dugc d i l u c h i h i n g each dun nong b i n Ca(0H)2 va NH4CI

a) Hay v i l t phuong trinh hoa hgc ciia cac phan ung tao cac (A), (B), (C), (D), (E)? b) Cho cac (A), (B), (D), (E) l i n luot tac dung voi timg doi mgt, truong hgp nao c6 phan ling xay ra? V i l t phuong trinh hoa hgc ciia cac phan ung va ghi ro d i l u kien (nlu c6)

3.2 Thiiy phan hoan toan 2,475 gam halogenua ciia photpho ngudi ta thu dugc b i n hgp axit (axit ciia photpho vdi so oxi hoa tuong ling va axit khdng chiia oxi ciia halogen) D I trung hoa hoan toan b i n hgp c i n dung 45 ml dung dich N a O H M X a c dinh cong thiic ciia halogenua

Cau 4(3,5 aiem):

4.1 Nho tu tu dung djch Ba(0H)2 d i n du vao dung dich hdn hgp Na2S04 va Al2(S04)3 ta c6 thi bieu dien su phu thuoc khoi lugng ket tua thco so mol Ba(0H)2 nhu sau:

K h o i lugng k i t tua (g)

X 69.9

So mol Ba(0H)2 Hay xac dinh gia tri ciia x dua tren d l thj tren, giai thich

4.2 D I xac dinh ham lugng doc H2S khong ngudi ta lam thi nghiem nhu sau: Lay 50 lit khong n h i l m H2S (D = 1,29 g/lit) cho di qua thiet bi phan tich co chua dung dich CdS04 du Sau axit hoa toan bg hon hgp thu dugc va cho tat ca luong H2S sinh hap thu het vao Ing dung 10 ml dung dich I2 0,015 M Lugng I2 du tac dung vua dii vdi 12,5 ml dung dich Na2S203 0,008 M V i l t cac phuong trinh hoa hgc xay qua trinh thi nghiem va tinh ham lugng H2S khong thco ppm (so microgam chat gam mau) Biet ppm = 10'" g Cau (3,0 diem):

5.1 Cho 18,4 gam N2O4 vao binh chan khong dung tich khong d l i 5,904 lit 0 27°C, xay phan ung: N2O4 (k) 2 N O 2 (k)

Luc can bSng ap suit binh la 1,0 atm

a) Tinh ap suit rieng p h i n m i l luc can bSng b) Tinh dg phan l i a cua N2O4 d 27°C

c) Tinh h i n g s i can b i n g Kp cua phan ung 400K chip nhan hieu ung nhiet cua phan ung khong d l i khoang nhiet khao sat va b i n g 58,04 kJ K i t qua thu dugc co phu hgp v d i nguyen ly L c Chatclicr khong? Giai thich

Gia su A H ° khong thay d l i khoang nhiet dg nghien cuu Cho phuong trinh Van't Hoff: f

R

_ L _ J _ T T 1 y

L i y N = 14; = 16; R = 8,314 J/(mol.K) = 1,987 cal/(mol.K)

5.2 Tantan (Ta) co k h I i lugng rieng la 16,7 g/cm', k i t tinh thco mang lap phuong vdi canh cua mang co sd la 3,32A

a) Trong moi co sd co bao nhieu nguyen tu Ta?

b) Tantan k i t tinh thco k i l u mang lap phuong nao? Cho Mja ^ 180,95 g/mol, cho NA=

6,023.10"

Cau (2,5 diem):

Hon hgp (X) gom Fc va mgt k i m loai M co hoa tri khong doi H o a tan hoan toan 3,3 gam (X) dung dich H C l du thu dugc 2,9568 lit d 27,3°C va latm Mat khac cung hoa tan hoan toan 3,3 gam (X) dung dich H N O 3 I M l i y du 10% thu dugc 896 ml b i n hgp ( Y ) g i m N O va N O (dktc) co ti k h I i hoi so vdi hon hgp (T) g i m N O va C2H6 la 1,35 va mgt dung djch (Z) B i l t R = 0,082

a) Xac dinh M va tinh % k h I i lugng cac k i m loai (X) b) Tinh t h i tich H N O 3 da su dung

H E T

- Thi sinh khdng dugc sii dung tai lieu Giam thi khdng giai thich gi them - Thi sinh khdng dugc su dung bang tuan hoan va bang tinh tan

s o G I A O D V C - D A O T A G T i N H V i N H L O N G

H D C K Y T H I C H O N H S G T H P T C A P T I N H N A M H Q C 2017-2018

M o n : H O A H Q C

Cau 1(5,0 diim): 1.1

Viet dung m6i phan ung dirge 0,25d x 10 = 2,5d

(1) (2) (3) (4) (5) (6) (7) (8) (9) (10) 1.2

-U MnCl2 + 2H2O + CI2 t

Mn02 + 4HC1

CI2 + 2NaOH -> N a Q + NaClO + H2O NaCI0 + 2HCl- -yNaCl + Cl^+HjO

•>2HC1 + H2SO4 y H N O j + NaHS04 CI2 + 2H2O +SO2

-NaN03(r) +

H2S04(d)-HNO3 + NH3 >-NH4N03 NH4NO3 - ^ N j O + 2H2O

Ca3(P04)2 + 3H2SO4 3CaS04i + 2H3PO4 H3PO4 +2K0H >K2HP04 +2H3O K2HPO4 +H3PO4 >2KH2P04

G o i s6 proton, natron cua A , B , C Ian lugt la Z A , ZB, ZC, N A , N B , N C Thco dft kien d l bai ta c6 he phuang trinh nhu sau

2(ZA+ Z B + Zc) + (NA+ N B + N C) = 82 2(ZA+ Z B + Zc) - (NA+ N B + N C) = 22

(ZB+ N B) - (ZC+ N C) = 10 (ZA+ N A ) (ZB+ N B) + (ZC+ N C) = 27 (ZA+ N A ) Giai he phuong trinh ta dugc

(ZA+ N A) - 2, Z B + N B = 37, Zc+ N c = 17 A A = ( Z A + N A ) =

A = Z + N = 37 Ac = Z c + N C = 17

1.3 a)

.0,25a .0,25a .0,25a

.0,25a

.0,5a

+2 +6 +6 +6 +2

Cr2S3+15 M n ( N O 3) + 20Na2CO3 > 2Na2 Cr O4 + 3Na2 S O4 +15Na2 M n O4 + 30 N O + 2OCO2 Ix

15x

Cr2S3

+6 +6 ->2Cr+ 3S + 30c +2 +5

Mn+ N +

2e-+6 +2 ->Mn+ N

0,25a .0,25a

HOA -1/7

.2y

+6 +3 +4

b) F e x O y + ( x - y ) H S >Fe2 ( ) + ( x - y ) S + ( x - y ) H

2y

( x - y )

+3

xFe >xFe +(3x-2y)e +6 +4

S+2e >-S Cau (2,0 diem):

2.1

a) Tao ket tua, roi ket tua tan

>A1(0H)3 i

A ( H) + 3H"

b) Tao khong mau, hoa nau khong 4H" + 3Fe'" + N O , -+3Fe'^+ N O + 2H2O c) Fe304 tan, tao ket tua

Fe304+ H " + r >3Fe'^+ ^ + 4H2O d) mat mau dung dich BTI

CI2+ 5Br2+ 6H2O- -+10HBrO3+ 2HC1

.0,25a .0,25a

.0,25a .0,25a .0,25a .0,25a

2.2

Cau hinh cua S: f

n n n n n n n t t

I s ' 2s' 2p^ 3s' 3p^ 3d° 0,25a

V i S C O cac obitan t r i n g a phan lop 3d nen cac c ghep doi a 3s, 3p co the nhay len phan lop 3d d l tao 6c doc than se tao v o i flo lien k i t cong hoa tri SFn la SFs V a y cac obitan cua S hop chk SF^ a trang thai lai hoa s p ' d '

V i l t C T C T , C T electron dung Hinh dang phan tu SF^. Bat dien Cau (4,0 diem)

3.1

a) A la O2; B : Ch; C: SO2; D : H2S; E : NH3 2KMn04 >K2Mn04+ MnO^ + O^

2KMn04+ 16HC1 >2HC1 + 2MnCl3 + SCl^ + SH^O

4CUFCS3+ I3O3

FeSj +

2HC1 +4CuO + 2FC2O3+ 8SO2

-+FeCl2+ H2S+ S

>CaCl2+ N H + 2H2O

2NH4CI + C a ( H)

b)

O + H S

-Hoac (5O2+4H2S >4S0, + 4H3O)

-+2S + 2H3O

.0,25a

.0,25a

.0,25a

.0,25a

.0,25 a

.0,25a

.0,25a .0,25a

0,25a

+ N H

-HoSc ( O + N H -3CI2 + H S —

3 C I + 2NH3-Hoac (3CI2 + N H

-• + N + H O

- ^ N + H O ) ->3S + 6HC1

- > N + 6HC1

HjS + N H

- T > N + N H C I ) - + N H H S

P T H H 3.2

Halogenua cua photpho co the co cong thuc PX3 hoac PX5 *Xet trirfrag hgp P X :

P X + H O > H P O + H X a a 3a

H P O + 2NaOH > Na2HP03 + H O

a 2a

H X + NaOH > N a X + H O 3a 3a

nNaOH =2a+3a= 5a=2.0,045= 0,09 mol =ga= 0,018

2 475

Mpx = 137,5 0,018

KA 137,5-31

M x = = 35,5

rr> X la CI Cong thuc PCI3

*Xet trirfrag hgp P X :

PX5 + H O > H P O + H X

b b 5b

H P O + 3NaOH > Na,?0, + 3H^0

h 3b

H X + NaOH 5b 5b

nwaOH = 3b + 5b=8b=2 0,045 = 0,09 =>b=0,01125

M „ , = 220

.0,25a

.0,25a

.0,25a

.0,25a

.0,25a

.0,25 a

.0,25a

.0,25a

.0,25a

-+ N a X + H j O

0,01125 (220-31)

= 37,8

=> khong ung v o i halogen nao => L o a i

(Neu gidi trudng hap PX5 trudc thi cho aiim mSiphuang trinh Id 0,25 a)

.0,25a

Cau 4(3,5 diem): 4.1

Khoi lirgng ket tua (g)

X 69,9

S6molBa(OH)2

SO: ,2 = a + 3b

N a S : amol A l ( S 4) : b m o r

K h i qua trinh tao lugng k i t tua khong d l i co nghia A I ( H) da tan h i t , luc k i t tua chi 69

BaS04 Hay Wgaso, = f^sor =a + 3b = = 0,3mo/ (1) o,25a

Tai d i l m bat dau lugng k i t tua khong d l i chinh la d i l m ma A1(0H)3 vua bi tan hit, liic dung mol Ba(0H)2 la 0,32 m o l hay mol O H " = 0,64 mol

A P+ H - > A l ( O H ) ^ ' 2b 8b

8Z> = 0,64

b = 0,OSmor 0,25a

0,25a Thay vao ( ) : a = 0,06 mol

V i C O qua trinh tao ket tua BaS04 va A1(0H)3 d i n g thdi nen lugng ket tiia cue dai c6 t h i xet hai trudng hgp sau:

T H I : k i t tua cue dai gom A1(0H)3 cue dai va lugng BaS04

A F" + H - > A\{OH\ I

0,16 -> 0,48 0,16 mol

L u c mol O H ' = 0,48 =>Bá^ = 0,24 mol; SỐ =a + 3b = 0,3mol B a ' V S O f ^BaSÔ

0,24 [0,3

n BaSO

0,24

= 0,24wo/ .0,25a

V a y = m^^so, +^Aimh " 07 24.233 + 0,16.78 = 68,4gaw o,25a

TH2: k i t tua cue dai g i m BaS04 cue dai va lugng A1(0H)3 B a ' " + SO4'' > BaS04

0,3 0,3 0,3

L u c nay, mol B a ' ^ = 0,3 m o l , hay mol O H ' = 0,6 mol A F" + H - > A1(0H)3

0,16 ^ , 0,16 mol

> A l ( O H ) ; A1(0H)3 + O H '

0,12 <r- (0,6-0,48)

^AKOH), =(0,16-0,12).78 = 3,12gam

.0,25a

.0,25a

V a y m^^^=m,^,o, ^^AI(OH), = , 3 + 3,12 = , g ^ w K i t tua TH2 > T H I nen lugng k i t tiia cue dai chinh la x = 73,02 gam 4.2

Phuong trinh hoa hgc:

HjS + C d ' " > CdS + H " (l) a a

CdS + H " ).Cd'" + HjS (2) a a H2S+ V >S + r + H " (3)

a a 2a J I3+ S O ' "—> r + S4O,'- (4)

0,5.10-" 10""

} n,^ = 0,01 0,015 = l,5.10"'mol n _ , _ = 0,0125 0,008 = 10""mol

S2O,

a = 1,5.lO'"*-0,5.10-* = 10-*mol

K h d i lugng khong khf: m = 1,29 50 = 64,5 gam (lO"" 34.10")

Ham lucng H2S theo ppm : -^^ = 52,7 ppm 64,5

I

Cau (3,0 diem): 5.1

a)

So mol N2O4 = 0,2 m o l

N2O4 (k) ^ 2NO2 (k) So mol ban dau 0,2

X 2x

So moi can bang 0,2-x 2x Tdng so mol luc can bang: 0,2 + x

Tac6:Pcb= ^+7;^:; = o n„, = 0,2 + x = 0,24 5,904

» X = 0,04 m o l 0 , - x „

2x „

^I'^in'Q-^^-'-4^-0,2=20%

^ p , 0

A H R

1 1 400 300

1 400 300

I^SAOO^ 58,04.10^ ^ J_ 8,314

6

« Kp,4oo-56,02 atm

Do AH > 0, can bang dich chuyin theo chilu thuan tang nhiet do, nen kit qua phu hgp .0,25a

5.2

a) The tich co so cua Ta la: V = (3,32.10''^)' = 36,6.10'"" cm A-24

Khdi lugng cua C O sd la: m = 36,6.10''*.16,7 = 611,22.10'"" g

Ggi n la sd nguyen tu Ta mgt d co sd Khdi lugng mgt nguyen tu Ta la: N-24

.0,25a

.0,25a

x-24

611,22.10'

niTa'^ g n

MTa-mTa.N= ^^^22.10 '" 5^023.1023= 180,95 n

368,14 n =>n=2

.0,25a

=180,95

.0,25a

b) V i n = nen Ta kit tinh thco kilu mang tinh thi lap phuang tam khdi 0,25a Cau (2,5 diem):

a)

* Khi hoa tan X dung dich HCl 1.2,9568

0,082(273 + 27,3) Fe + 2HC1

-= 0,12mol

M + nHCl

> FcCb+Hj n -> MCI + - H ,

2 bn 56a + Mb = 3,3

a+ ^ = 0,12

2 (1) (2)

*Khi hoa tan X dung dich H N O MNO =Mc2H6 =30-> MT=30

-> M Y =1,35.30=40,5 ny=0,04 mol

NO: xmol J30x + 44y =0,04.40,5 N2O: ymol [x + y = 0,04

Cgi O S

x = 0,01 ly = 0,03

.0,25a

.0,25a

.0,25a

0,25a

Qua trinh oxi hoa Qua trinh khur Fe

a M b

•+ Fe'" + 3e 3a M " " + ne

bn

N r + H " +3e 0,04 <- 0,03 2 N O r+ H " + 8e

+ N O +2H2O

- 0,01

N2O +5H2O

0,3 4- 0,24 <- 0,03 T a c o : 3a+ bn = 0,27 (3)

T u ( l ) , ( ) , ( ) :

'56a + M b = 3,3 a+ ^ = 0,12

2

3a + bn = 0,27 M b _ 1,62 ^ bn ~0,18

M = 9n V d i n = o M = 7( A l )

0,03.56

(1) (2)

(3)

a = 0,03 bn = 0,18 M b = 1,62

%Fe=- -.100% = 50,91% 3,3

o %A1 = 49,09%

b) n^Q^ = nH^=(0,04 + 0,3).110% = 0,374 mol 0,374

'HNO, 1 = 0,374 lit

sd GIAO D V C V A D A O T A O K Y THI C H Q N H Q C SINH GIOI T H P T C A P T i N H V i N H L O N G N A M H Q C 2017-2018

Khoa thi 21 thang 01 nam 2018 Mon thi: SINH H Q C (BUOI SANG)

Thai gian lam bdi: 180 phut (khong ke thai gian giao de) (De thi CO 03 trang, gom 09 cau)

D E CHINH THIRC

Ho vd ten thi sinh: ; So bdo danh:

Chu ky giam thi 1: ; Chit ky giam thi 2:

Cau (2,5 diem) ' a Cho cac don phan sau: glucozo; axit amin; steroit; nucleotit Trong cac don phan tren thi don phan nao can tao nen protein, don phan nao cau tao nen axit nucleic? V i to tSm, to nhen, sung trau, toe, thit ga d i u dugc cau tao tir protein nhung chung khac v l rat nhilu dac tinh? I b Hay lira chgn ngi dung cot A va ghep vdi noi dung cot B cho phu hgp, roi dien ket qua vao cot C

Cgt A CotB C g t C

1 Protein cau true Protein enzim Protein van dong Protein hoocmon

A Miosin, tubolin 1 Protein cau true

2 Protein enzim Protein van dong Protein hoocmon

B Inteferon, khang t h i Protein cau true

2 Protein enzim Protein van dong Protein hoocmon

C Albumin, cazein Protein cau true

2 Protein enzim Protein van dong

4 Protein hoocmon D Amilaza, lipaza Protein cau true

2 Protein enzim Protein van dong Protein hoocmon

E Insulin, glucagon Protein cau true

2 Protein enzim Protein van dong Protein hoocmon

F Keratin, colagen

Cau (2,0 diem)

a Phan biet ti t h i v d i lap the ve cac dac diem sau:

Dac diem Ti the Lap the

- Cau true cua mang - Co d loai te bao - Chuc nang

b Can cu vao nhung tieu chi nao ma thuyet cong sinh cho r i n g : " S u c6 mat cua ti the t l bao nhan thuc la k i t qua cong sinh cua mgt dang v i khuan hieu khf v d i t l bao"

Cau (2,5 diem) ' a Mgt nha sinh ly thuc vat t i l n hanh thi nghiem v l su trao d l i nude, ong quan sat thiy co mot chau cay hi heo la A n h / C h i hay giai thich hien tugng tren cac trudng hgp sau:

- R I bi ngap ling lau - B o n phan vdi lieu lugng cao - D I ngoai nSng gat

- De phong lanh

Cau (2,5 diem)

a Tai noi thy tinh kep chi co d thuc vat hat kin? Neu y nghia cua hien tugng thu tinh kep d thuc vat hat kin

b. C) mgt loai thuc vat hat kin, lay hat phan cua cay co kieu gen A a thu phan cho cay c6 kieu gen aa Hay xac dinh kieu gen cua phoi va ngi nhu cac hat c6 the dugc tao

Cau (3,0 diem)

\ y F r

So ben dudi mo ta ve moi quan he giua quang hgp va ho hap d thuc vat

(4) + (5)

(1) + (2) (8)

(9) a Hay d i l n cac chat cdn thiet vao nhung v i tri thilu tir (1) d i n (9) d l hoan so d l tren

b O x i dugc tao d pha nao cua qua trinh quang hgp va cd nguon g l c tu dau? V i l t phuang trinh phan ung minh hga cho qua trinh tren

Cau (2,0 diem)

a Phan biet dac diem cua phan xa khong dieu kien va phan xa co dieu kien Dac diem

•

Phan xa khong dieu kien Phan xa co dieu kien Ben vung

D i truyen Dac trung So lugng

Tra Idi kich thich Te bao than kinh

b ngudi, trdi ret, thay moi tai tim, sdn gai l c , ta voi di tim ao am mac Nhung hien tugng tren thuoc loai phan xa nao?

Cau (1,5 diem)

a Tai xung than kinh dugc truyen qua xinap chi theo mgt chieu tu mang trudc sang mang sau ma khong truyen ngugc lai?

b Chat trung gian hoa hgc co vai tro gi truyen tin qua xinap? Cau (2,0 diem)

a Cho cac nhan dinh sau:

I Tao dugc nhieu bien di lam nguyen lieu cho qua trinh chgn giong va tien hoa

s II C a the song doc lap, don le van co the tao chau V i vay, co Igi trudng hgp mat quan the thap

III Tao cac ca t h i thich nghi t i t v d i moi trudng s i n g I n dinh, ft b i l n dong, nho vay quSn the phat trien nhanh

IV Tao cac ca t h i mdi rkt da dang v l cac dac diem di truyen V i vay, sinh vat co t h i thich nghi va phat trien dieu kien moi trudng song thay doi

F f F

V Tao so lugng Idn chau giong mgt thdi gian ngan

I ' <> F r > f -k

V I Tao cac ca the mdi giong va giong ca the me ve cac dac diem di truyen V i vay, d i l u kien moi trudng song thay doi co the dan den hang loat ca the bi chet, tham chi toan bg quan the hi tieu diet

» Trong cac nhan dinh tren, nhtrng nhan dinh nao la uu diem va nhung nhan dinh nao la ban c h i cua sinh san v6 tinh? |

b Trong qua trinh t i l n hoa, dong vat chuyin tu ddi s i n g dudi nude len can se gap nhung trd ngai gi lien quan den sinh san? Nhung trd ngai da dugc khac phuc nhu the nao?

Cau (2,0 diem) ' a Cho cac v i du sau: hoa nghe tay; cay nap am V i du nao thuoc ung dong sinh trudng va v i du nao thuoc ung dong khong sinh trudng?

b Phan biet van dong khep la - xoe la d cay trinh nu bi va cham va hien tugng van dong khep la - xoe la d cay phugng

Dac diem phan biet Cay trinh nu Cay phugng

Kieu ung dong Nguyen nhan Tinh chat bieu hien Y nghia

hit

- Giam thi coi thi khdng duac gidi thich gi them - Thi sinh khdng duyc sit dung tdi lieu

SO GIAO DVC V A DAO T A O K Y THI CHQN HQC SINH GIOI CAP THPT VONG TINH VINH LONG NAM HQC 2017 - 2018

DE CHINH THtrC

Mon thi: SINH H Q C

HirOfNG DAN C H A M V A BIEU DIEM Ngay thi: 21/01/2018 (BUOI SANG) Cau T

Y NQI dung j Diem Ghi chu

1 2,5 d

- Don phan cua protein: axit amin - Don phan cua axit nucleic: nucleotit - Cac dac tinh khac cua protein la

+ Protein co cdu true da phan, voi don phan la axit amin (20 loai axit amin khac nhau) Cac protein khac ve so lugng, phan va trinh tu sap xep cac axit amin -> dac tinh khac

+ cdu true khong gian cua protein cung khac nhau: bac 1; bac 2; bac va bac Chung CO cac loai lien k i t khac d l dam bao ben cau true va trung tam

loat dong khac -> dac tinh khac

0,25 0,25 0,5 0,5 1 2,5 d

b Cot A CytB C y t C

0,25 0,25 0,25 0,25 1 2,5 d b 7

1 Protein cau true Protein enzim Protein van dong Protein hoocmon

A Miosin, tubolin 1-F 0,25

0,25 0,25 0,25 1 2,5 d b 7

1 Protein cau true Protein enzim Protein van dong Protein hoocmon

B Inteferon, khang the - D

0,25 0,25 0,25 0,25 1 2,5 d b 7

1 Protein cau true Protein enzim Protein van dong Protein hoocmon

C Albumin, casein - A

0,25 0,25 0,25 0,25 1 2,5 d b 7

1 Protein cau true Protein enzim Protein van dong

4 Protein hoocmon D amilaza, lipaza - E

0,25 0,25 0,25 0,25 1 2,5 d b 7

1 Protein cau true Protein enzim Protein van dong Protein hoocmon

E Insulin, glucagon F Keratin, collagen

0,25 0,25 0,25 0,25 2 2,0 d

Dac diem Ti the Lap the

0,25 0,25 0,5 2

2,0 d Cau true mang Mang ngoai tron nhan

Mang gdp khiic chiia nhilu enzim ho hap

Hai mang deu tron nhan

0,25 0,25 0,5 2

2,0 d

Loai te bao Co 0 tat ca cac te bao Chi CO te bao quang hgp thuc vat

0,25 0,25 0,5 2

2,0 d

Chuc nang Cung cap nang lugng cho te bao dudi dang ATP

Quang hgp (tong hgp chat huu C O tu chdt v6 co)

0,25 0,25 0,5 b + Cau tnic A D N vong tran, kich thuoc riboxom ciia ti the giong vi khuan

+ Co c h i ting hgp protein cua ti thi co nhieu dac diem giong vi khuan + Mang ti thi co cdu tao giong mang vi khuan: co h | enzim ho hap

+ Ti thi dugc hinh sir phan chia cua ti thi trudc bdng hinh thiic phan doi gilng vi khuan

0,25 0,25 0,25 0,25 3 2,5 d

a - Re bi ngap ling lau

H o hdp cua r l bi lic c h i t h i l u O2, s\r hdp thu nude giam - B o n phan v d i l i l u lugng cao

M d i trudng co ndng ion khoang cao hon dich bao, r l khd hap thu nude

- D I ngoai nang gat:

+ Nude thoat hoi qua la n h i l u hon binh thudng + Ddt t h i l u nude, khdng bu du lugng nude bi mdt - De phong lanh

Nhiet thdp, nhdt chdt nguyen sinh tang gay khd khan cho sy chuyin dich cua nude

0,5 0,5 0,5 0,5 3 2,5 d

b Nhimg cay than byi thdp va than thao co chieu cao thap, de bi tinh trang bao hoa hoi nude v a ap sudt r l dii manh d l ddy nude tu r l len la gay hien tugng l i gigt

0,5

4 2,5

- V i thu tinh d thuc vat hat kin mdi xay hien tugng

+ Nhan thu nhdt thu tinh vdi t l bao trung tao hgp tu (2n)

+ Nhan thu hai ket hgp vdi nhan ludng boi (2n) d trung tam cua tui phoi tao nhan tam bgi (3n) phat triln noi nhu

- Y nghia: Cung odp dinh duong cho su phat triln cua phoi va thdi ki dau cua ca thi mdi

0,25 0,25 0,5 - Cay CO kieu gen A a se co loai hat phan (A va a)

- Cay CO k i l u gen aa se tao loai tiii phoi a Khi thu tinh

+ hat phan ket hgp vdi noan cau -> hgp tu

Nhan thu nhdt (A) x noan cdu ( a ) ^ Hgp tu (Aa) -> phoi Nhan thu hai (A) x nhan luong bgi (aa) ngi nhu (Aaa) + hat phan ket hgp vdi noan cau -> hgp tu

Nhan thu nhdt (a) x noan cdu (a)-> Hgp tii (aa) phoi Nhan thii hai (a) x nhan ludng bgi (aa) noi nhu (aaa)

0,25 0,25 0,25 0,25 0,25 0,25 5 3,0

(3) Quang hgp; (4) O2; ( l ) N u d c ; (2)C02;

(6) Ho hdp; (7) A T P ; (9) Tdng hgp cac chat

Luu y CO thi ddi qua lai (1) - (2); (4) - (5); (8) - (9)

(5) C6H,206; (8) Van chuyen cac chat qua mang (hap thu chii dong);

2,25

- Oxi dugc tao tu pha sang ciia qua trinh quang hgp - Oxi CO nguin g l c tu qua trinh quang phan li nude - Phuong trinh phan ling

2H2O > H " + e - + O2

DL

0,25 0,25 0,25

M o i diing 0,25 6 2,0 Dac 3iem Ben vung Di truyen Dye trung So lugng

Tra Idi kich thich Te bao than kinh

Phan xa khong 3ieu kien Co

C6 Loai

Han che (it)

Tuong ling (kich thich khong dieu kien)

Tru nao, song

Phan xa co dieu kien Khong

Khon^ Ca the

Khong gidi ban (nhieu) Bat ki + kich thich co dieu kien V6 nao 0,25 0,25 0,25 0,25 0,25 0,25 - Moi tai tim, sdn gai 6c trdi ret phan xa khong dieu kien

- Di tim ao dm mac -> phan xa c6 dilu kien

V i mang sau khong co chat trung gian hoa hgc de di ve phia mang trudc va mang trudc khong co thu thi tilp nhan chdt trung gian hoa hgc

0,25 0,25 7

1,5 0,5

8 2,0

Chat trung gian hoa hoc di qua khe xinap lam thay dpi tinh tham mang sau xinap thuy phan axetincolin axetat va colin Hai chdt quay trd lai chuy xinap va dugc tai ting hgp lai axetincolin chua cac bdng xinap

- Nhan dinh uu dilm: 11; 111; V - Nhan dinh ban chi: VI

1,0

1,0 M i l diing 0,25 - Nhimg trd ngai:

+ Thu tinh ngoai khong thuc hien dugc vi thilu moi trudng nude

+ Trung de se bi kho va de bi cac tac nhan khac lam hong nhu nhiet qua cao hoac qua thdp, anh sang manh, vi sinh vat tdn cong

- Khdc phuc:

+ Thu tinh

+ De trung c6 vd hoc day hoac phoi thai phat trien co the me

0,25 0,25 0,25 0,25

9 2,0

a - V i du ung dong sinh trudng: hoa nghe tay - V i du ung dong khong sinh trudng: cay ndp dm

0,5 0,5 9

2,0

b Dac diem phan biet Cay trinh nir Cay phugng

0,25 0,25 0,25 0,25 9

2,0 b

Kieu ung dong iTng dong khdng sinh trudng

iTng dong sinh trudng 0,25 0,25 0,25 0,25 9

2,0 b

Nguyen nhan Sue truong cua nude Do hoocmon thuc vat

0,25 0,25 0,25 0,25 9

2,0 b

Tinh chat bieu hien Nhanh, khdng chu ki Cham, cd chu ki

0,25 0,25 0,25 0,25 9

2,0 b

Y nghia Giiip thich ung vdi su

thay doi cua mdi trudng

Giup thich ung vdi su thay ddi cua mdi trudng

0,25 0,25 0,25 0,25

H E T —

sd G I A O D U G V A D A O T A O K Y T H I C H Q N H Q C SINH GIOI T H P T C A P T i N H V i N H L O N G N A M H Q C 2017 - 2018

Khoa thi 21 thang 01 nam 2018 D E C H I N H THirC M o n thi: NCCT V A N

Thai gian: 180 phut (khong ke thai gian giao de)

Cau 1; (8.0 dilm)

T A M L O N G T R E T H O

Mgt phu nu don than no vua mdi chuyin nha Hang x6m cua ba la mot gia dinh ngheo vdi ngudi me gda chdng cung hai dua

Mgt hdm mat dien, ba djnh thap nen len cho sang thi c6 tieng go cua D d la cua nha hang xdm D u a be nghiem tuc hdi: I

- Con chdo di, di cho hoi, nha di cd nen khdng g?

B a ta tham nghi: " C a i gia dinh ngheo den ndi ca nen cung khdng cd sao? Tdt nhat khdng cho, cu nhu the hg se y lai mat!" N g h i roi, ba l i l n dap:

- Khdng cd!

Dung luc ba chuan bi ddng cua, dua be l i l n cudi rang r d va ndi:

- Con thira biet la nha dl khdng cd nin md! - N d i xong, dua be l i l n chia hai cay nen - Me vd sg di song mdt minh khdng cd nen nen bdo dem tang di hai cai de thdp

sang a! [ (Luge ghi theo Doc xong cdu chuyen ndy ban se hieu muc dich ciia ddi ngudi ,

I www.nguoiduatin.vn, 20/12/2016) Trinh bay suy nghi cua anh/ chi ve y nghia dugc ggi len tu each ung x u cua nhan vat ngudi phu nu don than m l u chuyen tren

Cau 2: (12.0 dilm)

Cam tudng v l Nhan dan hai doan trich Viet Bdc - T6 Hiju va Ddt Nude (trich trudng ca Mat dudng khat vong) - N g u y i n Khoa D i l m {Ngit van 12, Tap mgt, N x b Giao due 2008, trang 109-113 va trang 117-122)

H l t

sd GIAO D y e V A D A O T A O K Y THI CHQN HQC SINH GIOI THPT CAP TiNH VINH L O N G NAM HQC 2017 - 2018

Khoa thi 21 thang 01 nam 2018 j D E CHINH T H U C ^

H i r d N G D A N C H A M T H I M O N NGlT V A N (Huang ddn cham thi gom 03 trang)

Can 1; (8.0 dilm)

A Yen can chnng: T u y nghTa mau chuyen cung vdi nhan thuc, trai nghiem song, nang luc ban than, thi sinh trinh bay quan diem ve vin d l dat Bo cue sang ro, lap luan sic ben, thuylt phuc, van mach lac, khdng mSc Idi chinh ta, dung tu, ngu phap

B Yen can en the; Thi sinh co t h i trinh bay y theo nhilu hudng khac nhau, bdng nhilu each khac Dudi day la mot so ggi y tham khao cho ngi dung bai vilt:

- Gidi thilu dan dii vao vin d l

- Rut y nghTa cua mau chuyin tir each ung xir cua nhan vat ngudi phu nu don than: p h i phan thdi ich ki, nho nhen d ngudi

- Bay to suy nghT v l thdi ich ki, nho nhen:

+ M u u cau quyin Igi cho ban than —>• nhu cau chinh dang cua moi ngudi cuoc s6ng + N l u su muu cdu iy mang tinh vi ki nguy hiem, dang sg va dang hi p h i phan la nguyin nhan gay mat doan k i t (dim d i y trach nhilm, tranh phan hon qua ); la dong C O cua tgi ac (ham hai ngudi khac, lam vile bit chinh d l muu igi cho ban than ); ban than trd nIn me mugi, thieu sang suit cdng vile, tinh cam; khdng tim dugc su than, hanh phuc

+ Khdng ddng nhit giua ich k i vdi vile muu c i u quyIn igi chan chinh cho ban than -> ddng luc d l phan dau, vuon l l n ; ca nggi nhung ca nhan hilt nghT, hanh ddng vi ngudi khac

- Bai hgc cho ban than; thdng dilp cho moi ngudi C Tieu chuan cho diem;

- Diim 7.0 - 8.0: xac dinh ro van d l ban luan, y sau sic, t h i hien ro quan n i l m cua ban than Van mach lac, linh boat, giau cam xiic, lap luan sac ben, thuylt phuc Dan chung thuylt phuc C d t h i m i c mot vai sai sot rit nho

- Diim 5.0 - 6.0: xac dinh dugc v i n d l ban luan, y kha sau sic, the hien dugc quan n i l m ban than V a n kha trdi chay, co cam xuc, lap luan tuong ddi chat che Co chii y dua d i n chung, m i c mdt sd Idi nho v l d i l n dat, chinh ta, dung tu, ngu phap

- Diim 3.0 - 4.0: to h i l u v i n d l , y chung chung Han c h i v l dan chiing Lap luan ddi chd lung tung, thao tac chua vung; m i c nhilu Idi dien dat, chinh ta, dung tu, ngu phap

- Diim 1.0- 2.0: chua ham sat vao de Van y l u , y ngheo, m i c qua nhilu Idi d i l n dat, chinh ta, dung tu, ngu phap

Cau 2: (12.0 dilm)

A Yeu cau chung: Tren ca sa dinh huong cua de cung kien thuc ban than, thi sinh bay to y kien ve van de dugc neu B o cue chat che, lap luan vung vang Dan chiing chgn Igc Van mach lac, giau hinh anh, cam xiic, khong mac loi chinh ta, dung tu, ngu phap

B Yeu cau cu the: Thi sinh co t h i trinh bay y thco nhilu hudng khac nhau, b i n g nhieu each khac Dudi day la mgt s6 ggi y cho bai vilt:

1 Gi&i thieu de di vao dinh hu&ng vdn de (Cam tudng v l Nhan dan hai doan trich Viet Bdc - To H u u va Ddt Nuac - N g u y i n Khoa D i l m )

2 Cam tie&ng ve Nhan ddn hai doan trich

a) Cam tuong vi Nhan ddn dugc h i l u la nhimg suy nghT, quan n i l m , tinh cam cua ngudi viet v l Nhan dan dugc t h i hien qua sang tac van hgc T r i n trang v i l t cua cac nha van, nha tho, hinh tugng Nhan dan thudng g i n vdi bdi canh thdi dai, dac d i l m phat triln cua lich su

b) Cam tuong ve Nhan ddn hai doan trich (Thi sinh k i t hgp k i l n thuc van ban, chgn loc dan chung va cac thao tac lap luan d l lam ro v i n d l ) :

- Viet Bdc - To H i m

+ Nhan dan binh di ma nghTa tinh, thuy chung vdi each mang —* danh nhimg tinh cam sau nang, cung chia nggt se bui vdi can bd khang chien k i n i l m thiing liing, khd quin

+ Nhan dan sat canh, chung vai vdi each mang cung xong tran, chiln dau, lam nIn

r \ F f r ^

khi t h i oai hung, mang v l c h i l n thang ve vang V i l t Bac trd n i l m tin cua cudc khang chiln chdng Phap

- Ddt Nuac - N g u y i n Khoa D i l m : Nhan dan la ngudi lam dat nude la chu nhan cua dat nude

+ Bang cudc ddi, ca n i l m dau va hanh phuc, bang ve dep tam hdn, su lao ddng c i n cu —>• dcm d i n buc tranh non nude dep tuoi, k i thu '

\ r r

+ Bang su hi sinh anh dung chdng ngoai xam —>• giiJ gin bd coi cho t h i he mai sau + Bang thuc t i l n ddi sdng, bing y thiic ngudn cgi —* de lai bao gia tri vat chat va tinh than quy bau

c) So sanh cam tuong ve Nhan ddn hai doan trich

- Gidng nhau: ca hai doan trich d i u t h i hien thai tran trong, nggi ca Nhan dan, lam ro dugc vai trd quan trgng cua Nhan dan ddi vdi dit nude —>• n i m mach tu tudng chung ciia van hgc V i l t Nam 1945-1975 T u tudng i y dugc t h i hien qua nhung chat lieu dam chit dan gian (ngdn tu binh di, hinh anh g i n gui, qucn thudc, vay mugn ca dao, tuc ngu )

- Khac nhau: I + V I tu tudng:

• CJ doan trich Viet Bdc - Td Hiiu, "Nhan dan" d day la ddi tugng cu the: ngudi Viet Bac; mdi gan k i t vdi can bd khang chiln —> cuu mang, che chd, gdp phan lam nIn sue manh chiln thing cho cudc khang Phap —>• ggi nhic n i l m tri an sau sic cua each mang doi vdi V i l t B i c ndi chung

• 0 doan trich Ddt Nuac - N g u y i n Khoa D i l m , "Nhan dan" chi chung cho tit ca mgi ngudi cd cdng dung xay, bao v l q u i huong, bd coi danh thiic y thiic trach nhilm ddi vdi dat

nude cua moi ngudi ndi chung, dac biet la t h i he tre thdi i y - ngudi thu hudng qua cha ong d l lai

+ Nghe thuat: d Viet Bdc, giong d i l u thiln v l tam tinh; d Ddt Nude thi cd su hoa quyen giua giong tam tinh vdi chit trilt luan, suy tu sau l i n g tao nIn sue tac dong, cd vu manh me

3 Danh gid chung !

- M d i doan trich la mot cdng trinh nghe thuat doc dao, t h i hien ro phong each ca nhan cua mdi nha tho |

- Hai tac gia da gdp thim tieng ndi d l khing dinh vai trd to Idn cua Nhan dan ddi vdi dit nude —* tu tudng nhan van va cd gia tri bit b i l n moi thdi dai

•F f

C Tieu chuan cho diem;

- Diem 11.0 -12.0: B a i lam t h i hien tu sau sic B d cue chat che D i n chung chon loc, phan tich sau Bai lam cd net rilng hoac cd sang tao Van mach lac, giau cam xuc C d t h i m i c mdt vai Idi rit nho ve d i l n dat

- Diem 9.0 - 10.0: B a i lam t h i hien tu kha sau sac B d cue ro Chon va phan tich dan chung kha tdt; phan ddi sanh kha tdt Van trdi chay, giau cam xuc C d t h i mac mot sd Idi nho v l d i l n dat, chinh ta, dung tu, ngu phap

•? r F F /SI

- Diem 7.0 - 8.0: Bai lam t h i hien tu tuong ddi sau sac B i l t chon dan chung nhung phan tich chua sau; ndi dung so sanh so sai Van kha mach lac, cd cam xiic, m i c mot sd Idi nho v l d i l n dat, chinh ta, dung tu, ngtt phap

- Diim 5.0 - 6.0: B a i lam td h i l u d l C d cd g i n g chon d i n chung nhung chua that t i l u bilu, phan tich chua sau; cd y thiic ddi sanh nhung chua that ro y Lap luan nhilu chd Iiing tiing, m i c mdt sd Idi v l d i l n dat, chinh ta, dung tu, ngu phap

- Diem 3.0 - 4.0: B a i lam chua ro y l u cIu d l Chua bilt chon dan chiing Phan tich chung chung hoac nang v l phan tich tac pham don thuan; mac nhilu Idi d i l n dat, chinh ta, dung tu, ngu phap

- Diem 1.0 - 2.0: Bai lam ban v l ndi dung hoan toan xa d l va khdng phu hop V a n y l u , y ngheo, mac qua nhilu 161 d i l n dat, chinh ta, dung tu, ngu phap

Liru V chung:

- Giam khao can cu vao hudng ddn chdm vd van dung linh hoat vao thuc te bdi lam cua thi

sinh de cdn nhdc cho diem.

- De hudng den tinh chdt "md", gidm khao cdn chuy khuyen khich nhung bdi Idm cd net rieng cam thu, suy nghi, nhan thuc nhung vdn hgp li vd cd su sdng tao cdch trinh bay, dien dat

I

sd GIAO DUG VA DAO TAO VINH LONG

DE CHINH THlTC

KY THI CHON HOC SINH GIOI THPT CAP TINH NAM HOC 2017-2018

Khoa thi: Ngay 21/01/2018 MON: LICH Slf

Thdi gian: 180 phut (Khdng ke thai gian giao de)

Caul (2.0 diem):

Long yeu nude, quyet tam bao ve to quoc ciia toan quan, toan dan ta the hien nhu the nao qua cac cuoc khang chien chdng quan xam luge Mdng- Nguyen the ki XIII? L a hgc sinh, cac cm the hien long yeu nude va quyet tam bao ve td qudc nhu the nao?

Cau (2.0 diim): I

V i lai no cac cudc Cach mang T u san? Tai Cach mang T u san khdng the la cudc Cach mang xa hdi triet de?

Cdu (4.0 diim):

Hoan canh lich su, ndi dung va y nghTa ciia H d i nghi lap Dang Cdng san Viet Nam? Tai khang dinh Cuong ITnh chinh tri dau tien ciia Dang Cdng san Viet Nam la diing

dan,sang tao?

Cdu (3.5 diim):^

Tom tat nhimg dieu kien ve kinh te, xa hdi va tu tudng dan den su hinh va phat trien ciia phong trao yeu nude d Viet Nam sau Chien tranh the gidi thu nhat?

Khai quat cac khuynh hudng chinh tri va bieu hien ciia no phong trao dau tranh ciia nhan dan Viet N a m chdng thuc dan Phap xam luge tir cudi the ky X I X ddn dau nam 1930? Ket cue ciia cac phong trao thco nhimg khuynh hudng chinh tri tren ndi len dieu gi ?

Cdu (2.5 diim):

V i Qudc te Cdng san t i l n hanh Dai hdi VII (7-1935)? Nhimg chii truong dieu chinh chien luge each mang the gidi ciia Qudc te Cdng san tai Dai hdi tac dong thd nao den each mang Viet Nam nhimg nam 1936-1939?

Cdu (3.5 diim):

V i ndi tir thang 9.1939 den nira dau thang 8.1945 Dang Cdng san Ddng Duong da chuan bj day dii, true tiep cho thing Igi ciia Cach mang thang Tam nam 1945?

Cdu (2.5 diim):

Trinh bay hoan canh trieu tap va nhimg quyet djnh quan trgng dugc thdng qua tai H d i nghi lanta (2 -1945) Nhung quyet dinh da tac ddng nhu the nao den tinh hinh the gidi nhung nam 1945 - 1947?

— H E T —

s d G I A O D U G V A D A O T A O K Y T H I C H O N H O C S I N H G I O I T H P T C A P T I N H V I N H L O N G " N A M H O C 2017 - 2018

M O N : L I C H SU"

H i / d N G D A N C H A M

C A U N O I D U N G D I E M

C A U

(2.0 diem)

a Long yeu niro-c, quygt tam bao ve to quoc cua toau quau, toau dau ta the hieu uhir the uao qua cac cuoc khaug chieu choug quau xam luge Moug- Nguyen the ki X l l l

C A U

(2.0 diem)

-1282 nha TrIn trieu tap hoi nghi Binh Than gdm quy tdc va tudng ITnh cac cap trieu dinh

0.25

C A U

(2.0 diem)

-1285 H d i nghi Dien Hdng tao c a sd viing c h i c dd xay dung khoi doan ket nhat tri to idn cua toan dan, bien quyet tam cua trieu dinh quyet tam cua dan tdc, la mdt nhung dinh cao cua nghe thuat tap hgp luc lugng toan dan

0.25

C A U

(2.0 diem)

- L d i "Hich tudng sP' cua Iran Hung Dao da thdi bung len ngon lua cam thu, long quyet tam gidt giac cua quan dan ta

0.25

C A U

(2.0 diem)

-Kinh Thang Long ba Ian hi giac tan pha nhung vdi tinh than "sat that", thuc hien kd hoach "vuon khdng nha trdng" chu ddng ddi phd vdi moi am muu cua giac, quan dan ca nude thuc hien Idnh ciia tridu dinh da danh bai quan xam luge, bao vd vung chac ddc lap dan tdc

0.25

C A U

(2.0 diem)

-Chidn thing Bach D i n g vang ddi mai di vao lich su nhu bidu hien ciia truydn thdng ydu nude, bat khuat ciia dan tdc

0.25

C A U

(2.0 diem)

b L a hoc sinh, cac em the hien long yen nirdc va quyet tam bao ve td qudc uhu the uao? C A U

(2.0 diem)

-Hoc tap tdt, chap hanh tdt ndi quy, qui dinh nha trudng, chi'nh sach phap luat nha nude, 0.25

C A U

(2.0 diem)

-Canh giac vdi nhung luan dieu xuydn tac ciia ke thu, tidp thu cd chon loc nhung ydu td bdn ngoai,

0.25

C A U

(2.0 diem)

-Quydt tam bao vd chii quydn bidn gidi qudc gia, van hoa dan tdc, 0.25

C A U

(2.0 diem)

a.Vi lai ud cac cudc Cach maug T u sau C A U

(2.0 diem)

- Lich su xa hdi loai ngudi phat tridn khdng ngirng tu thap ddn cao qua cac hinh thai kinh te xa hdi

0,25

C A U

(2.0

diem) - Trong long chd dd phong kidn sinh quan he san xuat mdi tidn bo, dd la quan he san xuat tu ban chii nghTa ma dai dien la giai cap tu san

0,25

C A U

(2.0 diem)

- Quan he san xuat tu ban chii nghTa bj chd dd phong kidn kim ham lam sinh mau thuan xa hdi

0,25

C A U

(2.0 diem)

-Cach mang tu san nd nham giai quydt mau thuan cua quan he san xuat tu ban chii nghTa vdi chd phong kidn, dd xac lap chd tu ban chii nghTa tidn bo ban

0,5

C A U

(2.0 diem)

b.Cach maug tu sau khdug the la cudc each maug triet de v i : C A U

(2.0 diem)

-Cach mang tu san chi mang quyen Igi cho giai cap tu san chu khdng phai cho quan chiing nhan dan

0,25

C A U

(2.0 diem)

- Ban chat ciia giai cap tu san la hoc lot, ndn thuc chat each mang tu san thay thd hinh thiic bdc lot ciia phong kidn bang hinh thiic bdc lot ciia tu san ddi vdi quan chiing nhan dan

0,25

C A U

(2.0 diem)

- Cach mang tu san chi triet dd vdi muc dich va nhiem vu ciia nd, chu khdng thd la mdt cudc each mang xa hdi triet dd Trong lich su xa hdi loai ngudi, chi cd each mang vd san xda bd mgi ach ap hue, bdc lot mdi la cuoc each mang xa hdi triet de nhit

0,25

C A U

(4.0 diem)

a Hoau eauh ijch su, udi duug, y ughia cua Hdi ughj thauh lap Daug Cdug sau Viet Nam C A U

(4.0 diem)

*Hoau eauh lich su: C A U

(4.0

diem) - 1929 ba td chuc cdng san ddi va tich cue boat ddng, tuydn truydn, td chiic va lanh dao

quan chiing dau tranh

0.25

C A U

(4.0 diem)

- Ba td chuc cdng san boat ddng ridng re, tranh gianh anh hudng ciia khidn cho phong trao each mang ca nude cd nguy ca chia re Idn

0.25

C A U

(4.0 diem)

- Ydu cau cap thidt la phai thdng nhat y chi, hanh ddng ciia cac td chuc cdng san 0.25

- Nguyen A i Quoc diing trieu tap va chii tri H o i nghj hgp nhit cac to chuc cong san Viet Nam tai Cuu Long (Huang Cang,Trung Quoc) H g i nghi bat dau tu 6/1/1930

0.5

* Noi dung:

- Hgi nghi nhit tri thdng nhit cac td chuc cong san mgt dang nhat lay ten la Dang Cong san Viet N a m

0.75

- Thong qua Chinh cuong v i n tit, Sach luge v i n tit, Nguyen A i Qudc soan thao, la ban Cuong ITnh chinh tri dau tien ciia Dang

0.5

* Y ughia cua hgi ughj:

- Hgi nghi hgp nhat cac to chiic cong san cd y nghTa nhu mgt dai hgi lap Dang 0.25

- Chinh cuong v i n tit, Sach luge v i n t i t dugc xcm la Cuang ITnh chinh trj dau tien ciia Dang Tuy van tat nhung nd da vach cho each mang Viet N a m nhung van de ca ban dung dan ve dudng loi each mang Cham dut dugc tinh trang khiing hoang ve dudng loi va giai cap lanh dao, khang dinh quyen lanh dao tuyet ddi ciia giai cap cong nhan ma dgi tien phong la Dang Cong san Viet N a m

0.25

b Khaug djuh Cuong ITuh chiuh trj dau tieu cua Daug Cgug sau Viet Nam la diiug dau, saug tao vi:

- Vach dudng loi chien luge cho each mang Viet Nam phu hgp vdi xu the ciia thdi dai (do la thdi dai qua tu chii nghTa tu ban len chii nghTa xa hgi)

0.25

- Van dung sang tao chii nghTa Mac-Lenin vao hoan canh cu the ciia Viet N a m : Dd la xa hgi thuoc dia mia phong kien, ton tai hai mau thuan c a ban (mau thuan giua toan the nhan dan Viet Nam vdi thuc dan Phap va mau thuan giua ndng dan Viet N a m vdi dia chii phong kien, )

0.25

- Cuong ITnh giai quyet diing dan mdi quan he dan tdc va dan chu, dua nhiem vu dan tdc len hang dau, giai quyet diing dan mdi quan he giua each mang Viet Nam vdi each mang the gidi

0.25

- Day la Cuong ITnh giai phdng dan tdc diing dan, sang tao nhuan nhuyen ve quan diem giai cap, ti'nh dan tdc, nhan van, neu cao tu tudng ddc lap, tu do, dan chii

0.25

C A U (3.5 diem)

a.Tdm tat nhirng dieu kien ve kinh te, xa hgi va tn tnang dan den sn hinh va phat trien cua phong trao yen nnfrc d" Viet Nam san Chien tranh the gidi thn nhat C A U

(3.5 diem)

- Ve kinh te: T h u c dan Phap tien hanh chuang trinh khai thao thudc dja Ian thu hai, lam cho tinh hinh kinh te Viet N a m co bien ddi, nhung chii yeu van la mdt nen kinh te ndng nghiep lac hau va phu thudc kinh te Phap

0.25

C A U (3.5 diem)

- Ve xa hoi: S u phan hoa giai cap sau sac nhat la su phat trien ciia giai cap cdng nhan va su ddi ciia cac giai d p t u san va tidu tu san

0,25

C A U (3.5 diem)

- Ve tu tuong: C A U

(3.5 diem)

+ He tu tudng tu san anh hudng vao Viet N a m tu trudc Chien tranh the gidi thu nhit, sau chien tranh van tidp tuc dugc su dung lam vu chdng Phap

0,25 C A U

(3.5 diem)

+ T u tudng chi'nh tri vd san: Cach mang thang M u d i N g a (1917) cdng, md thdi dai mdi lich su nhan loai C h i i nghTa M a c - Ldnin trd hien thuc va dugc truydn ba rdng rai khap noi, dan ddn su ddi nhidu dang cdng san Qudc td C d n g san dugc lap (3/1919) C h i i nghTa M a c - L d n i n va nhung tu tudng each mang ciia Nguydn A i Qudc dugc truydn ba vao Viet N a m , tao mdt vu t u tudng mdi

0,25 C A U

(3.5 diem)

b.Khai quat cac khuynh huong chinh trj va bien hien cua nd phong trao dan tranh cua nhan dan Viet Nam chong thuc dan Phap tir cudi the ky X I X den dan nam 1930: C A U

(3.5 diem)

-Cudi the ky X I X : Theo khuynh hudng phong kien, bieu hien qua phong trao Can Vuong vdi nhung cudc khdi nghTa tidu bidu: B a Dinh, Bai Say, Huong K h d va cudc khdi nghTa ndng dan Ydn Thd

0,5 C A U

(3.5 diem)

-Dau thd ky X X (trudc Thd chidn thu nhit): X u l t hien khuynh hudng tu san vdi nhung boat ddng tidu bidu ciia Phan B d i Chau va Phan Chau Trinh

0,5 C A U

(3.5 diem)

-Sau Thd chidn thu nhit - d i u nam 1930, didu kidn Ijch su mdi, cd hai khuynh hudng:

+ Khuynh hu&ng ddn chii tu sdn: Bidu hien qua cac phong trao dan chu tu san 1919 - 1925, su ddi va hoat dong cua Viet N a m Qudc dan dang (1927 - 1930) N o luc cao nhat va cuoi cung la cudc khdi nghTa Ydn Bai (2/1930) bi that bai, keo thco su tan hoan toan ciia Viet Nam Qudc dan dang

0,5

+ Khuynh hu&ng v6 sdn: Bidu hien qua nhirng boat ddng each mang ciia Nguyen A i Qudc, phong trao cdng nhan, su xuat hien cac to chuc cdng san dan ddn su ddi cua Dang Cdng san Vidt N a m dau nam 1930

0,5

c.Ket cue cua cac phong trao theo nhimg khuynh hirdng chinh t r i tren noi len:Con dudng giai phong dan tdc thco cac khuynh hudng chinh tri phong kidn va dan chu t u san la khdng cdng, khdng phii hop, "Mudn cihi nuac vd gidi phong ddn toe khong cd con duong nao khdc dudng cdch mang v6 sdn"

0.5

C A U

(2.5 diem)

a.Vi Qudc te Cong san tien hanh Dai hoi VII (7-1935) C A U

(2.5 diem)

- Dau nhung nam 30 T K X X , chu nghTa phat xit xuat hien va nam quydn, chiing thi hanh chlnh sach khiing bd dan ap nhan dan, thii tidu ndn dan chii tu san d cac nude

0.25 C A U

(2.5

diem) -Vd ddi ngoai, chii nghTa phat xit da thii tidu trat tu thd gidi V e c xai - Oa sinh ton, cdng khai chdng Qudc td Cdng san, chuan hi phat ddng chidn tranh thd gidi

0.25 C A U

(2.5 diem)

-Ke thu nhan loai khdng la chii nghTa dd qudc ndi chung ma la chii nghTa phat xit, nhiem vu hang dau la chung tay ngan chan chii nghTa phat xit va chidn tranh thd gidi

0.25 C A U

(2.5 diem)

- Chinh vi vay, 7-1935 Qudc td Cdng san tridu tap Dai hdi dd nhiem vu cap thidt cho cac Dang Cdng san, giai cap cdng nhan va nhan dan lao ddng thd gidi nham tap trung mui nhon ngan chan phat xit, nguy co chidn tranh

0.25 C A U

(2.5 diem)

b Nhirng chu trirong dien chinh chien Inoc each mang the gidi cua Qudc te Cong san tai Dai hdi tac dgn^ the nao each mang Viet Nam nhirng nam 1936-1939?

C A U

(2.5 diem)

- Dua trdn Nghi quydt D a i hdi VII cua Qudc td Cdng san va can cu vao tinh hinh cu the cua each mang Vidt N a m , Dang Cdng san Ddng Duong tridu tap Hdi nghi Trung uong Dang tai Thuong Hai (Trung Qudc) vao thang 7-1936, de dudng ldi, phuong phap dau tranh phu hgp tinh hinh

0.5 C A U

(2.5 diem)

-Xac dinh ke thu trudc mat la thuc dan phan ddng Phap va tay sai, chii truong lap Mat tran Thdng nhat nhan dan phan dd Ddng Duong nham doan kdt cac luc lugng chdng thuc dan phan ddng va tay sai, chdng phat xit, chdng chidn tranh ddi tu dan chii, dan sinh, com ao hoa binh; Phuong phap dau tranh la kdt hgp cac hinh thiic cdng khai va bi mat, hgp phap va bat hgp phap

0.5 C A U

(2.5 diem)

-Dudng ldi ciia Dang dua vao 7-1936 la dung dan phii hgp thuc tien lich su, tac ddng true tidp bung nd phong trao each mang 1936-1939, de lai cho Dang nhieu bai hgc quy bau Phong trao dan chii 1936-1939 la cudc tap dugt thu hai chuan hi cho each mang thang Tam nam

1945 sau

0.5

C A U

(3,5 diem)

V i noi tir thang 9.1939 den nira dau thang 8.1945 Dang Cong san Ddng Duong da true tiep chuan bi day du cho thang loi cua each mang thang Tam nam 1945?

C A U

(3,5 diem)

a Chuyen hudng chi dao chien lirgc each mang: C A U

(3,5

diem) -Thd hien cac nghi quyet trung uong: Ian (11/1939), l l n (11/1940) va Ian (5/1941) 0.25

C A U

(3,5 diem)

- Ndi dung ciia dudng ldi each mang: C A U

(3,5 diem)

+ Dat nhiem vu giai phdng dan tdc Idn hang dSu, tam gac k h i u hieu "each mang rudng dit", dd khau hieu 'tich thu rudng dit ciia dd quoc va Vidt gian chia cho dan cay ngheo', giam td, giam tuc, chia lai rudng cdng

0.25

C A U

(3,5 diem)

+ Thanh lap Mat tran Vidt Minh de doan kdt, tap hgp cac luc lugng ydu nude KhIng djnh chuan bj khdi nghTa vu trang la nhiem vu trung tam va dd dudng dd tidn tdi khdi nghTa gianh chlnh quydn: T u khdi nghTa tiing phIn tien Idn tdng khdi nghTa

0.25

C A U

(3,5 diem)

b Chuan bj ve luc lugng each mang C A U

(3,5 diem)

lam nhiem vu tap hgp luc lugng va to chuc dau tranh, lap cac H g i cuu quoc ciia Mat tran Viet M i n h , thu hiit dong dao cac giai cap va tang lop yeu nuac tham gia

0.25

- Luc lugng vu trang:

+Thanh lap D g i Viet Nam Tuyen truyen giai phong quan (22/12/1944) 0.25

+ Thanh lap cac D g i cuu quoc, xay dung cac Dgi du kich d cac dja phuang 0.25

+ Thang 5/1945, lap U y ban quan su BIC ki de lanh dao cuoc dau tranh vu trang d Bac ki va toan quoc, thong nhat cac luc lugng vu trang Viet Nam giai phong quan

0.25

c Xay dung can cir dia each mang: X a y dung cac can c u dia va chien khu de phat trien va bao ve luc lugng each mang: BIC San-V6 Nhai, Viet BIC

0.25

d Tuyen truyen dudng loi cua Dang, to chuc va tap dot quan chiing dau tranh de tien tdi khdi nghia gianh chinh quyen thdi ca den

- Tieu bieu la cac cuoc khdi nghTa Bac Son, Nam K i (1940) Tam thang chien tranh du kich d can cu dia BIC San - V d Nhai (tu 7/1941 ddn 2/1942), cac cuoc danh don Phay K b i t , N a Ngan (12/1944), boat dong vu trang tuyen truyen kdt hgp dau tranh chi'nh tri va quan su cac luc lugng vu trang

0.25

- Dinh cao la cao trao "khang Nhat cuu nude" (tu 9/3/1945 ddn mia dau thang 8/1945) Phong trao d i u tranh vu trang va khdi nghTa tung phan lidn tidp no d nhidu dja phuang Ddn nua dau thang 8/1945, luc lugng each mang da phat tridn manh me ca nude, quan chiing each mang da san sang dung Idn khdi nghTa gianh chinh quydn thdi co ddn va cd lenh tong khdi nghTa ciia Dang

0.25

d Chuan bi bg may lanh dao tong khoi nghia

- Ngay 13/8/1945, Trung uong Dang va Vidt Minh lap tuc lap U y ban Khdi nghTa toan quoc, ban bo Quan idnh sd 1, phat Idnh Tdng khdi nghTa ca nude

0.25

- T u 14 ddn 15/8/1945, Hdi nghi toan qudc ciia Dang hgp d Tan Trao, quydt djnh phat ddng Tdng khdi nghTa ca nude, quydt dinh nhung van dd ddi ndi, ddi ngoai sau gianh dugc chinh quydn

0.25

- T u 16 ddn 17/8/1945 Dai hdi Qudc dan hgp d Tan Trao tan chii truong Tdng khdi nghTa, thdng qua 10 chinh sach ciia Vidt M i n h , c i i U y ban Dan tdc giai phdng Vidt Nam H d C h i M i n h lam Chii tich

0.25

N h d su chuan hi true tidp va day dii, ndn cd thdi co, each mang thang Tam dien rit mau le, chi 15 ngay, nhung lai cdng to Idn, gianh dugc chinh quydn ca nude va it mau

0.25

C A U (2.5 diem)

a Hoan canh Ijch su" Chidn tranh thd gidi thu hai budc vao giai doan cudi nhidu van dd quan trgng va d p bach dat trudc cac cudng quoc Ddng minh bdi canh dd, mgt hgi nghi qudc te dugc tridu tap d lanta (Lidn X d ) tu den 11 - - 1945

0,5 C A U

(2.5 diem)

b Hoi nghi da dua nhCrng quyet djnh quan C A U

(2.5 diem)

- Tidu diet tan gdc chu nghTa phat xit Due va chu nghTa quan phidt Nhat 0,25 C A U

(2.5 diem)

-Thanh lap td chuc Lidn hidp quoc 0,25

C A U (2.5 diem)

-Thoa thuan vide dong quan tai cac nude nhim giai giap quan ddi phat xit Phan chia pham vi

anh hudng d chau A u va chau A 0,5

C A U (2.5 diem)

c Tac dong: C A U

(2.5 diem)

- Nhung quydt dinh ciia H d i nghi lanta cung nhung thda thuan sau ciia ba cudng quoc trd khudn khd ciia trat tu thd gidi mdi - trat tu hai cue lanta

0,25 C A U

(2.5 diem)

- Thuc day cuoc Chidn tranh thd gidi thii hai nhanh chong di ddn kdt thiic d chau A u , chau A tidu diet tan gdc chu nghTa phat xit

0,25 C A U

(2.5 diem)

- Lidn hgp qudc ddi nhu mdt cdng cu tri trat tu thd gidi mdi 0,25 C A U

(2.5 diem)

- Vide phan chia pham vi anh hudng ciia cac cudng qudc dan ddn su hinh trat tu thd gidi cue, hai he thong ddi lap, doi dau cang thing

0,25 '.hiiz,

-sd GIAO DUG V A DAO T A O VINH L O N G

D E C H I N H THLTC

K Y THI C H Q N H Q C SINH GIOI THPT CAP T i N H N A M H Q C 2017 - 2018

Khoa thi 21 thang 01 nam 2018

Mon thi: D I A L I

Thai gian: 180 phut (khdng ke thai gian giao di)

Can (3,0 diim)^

a) Dua vao kien thuc Dja l i de phan tich cau tuc ngG d Viet Nam: "Dem thang nam chua n i m da sang, thang mudi chua cudi da tdi" V i mua cua hai ban cau trai ngugc nhau?

b) Tridu cudng xay thdi ki nao? Tai sao? Thuy tridu c6 y nghTa gi san xult va ddi song?

Caul (2,0 diim)

a) Nhung thay ddi cua loai hinh quan cu ndng thdn hien la gi? Tai co su thay do! nhu thd? b) Su phat tridn cac nganh dich vu cd anh hudng nhu thd nao ddn ddi sdng cua ngudi dan?

Cau3 (3,0 diem)

a) Phan tich hoat dong gid mua mua d nude ta

b) V i ndi sinh vat Viet Nam tieu bidu cho sinh vat ciia vung nhiet ddi am gid mua? Cau (3,0 diem)

a) Dua vao Atlat Dia 11 Viet Nam va kidn thuc da hoc, hay phan tich dac didm chd nhiet ciia tram khf hau Sa Pa

h) Trinh hay dac didm tu nhien ciia mien BIC va Ddng BIC BIC BO Tieu chi quan nhat de phan chia cac midn dja 11 tu nhien la tieu chi nao?

Cau (3,0 diim)

Dua vao Atlat Dja 11 Viet Nam va kidn thuc da hoc, hay chung minh va giai thich su phan hda phan hd dan cu d vung ddng hing

Cau (3,0 diim) ^

a) Cho hang so lieu sau:

T O N G S A N P H A M T R O N G N l / Q C (GDP) P H A N T H E O T H A N H P H A N K I N H T E

(Dan vi: nghin ti ddng)

^ Nam Thanh phan

1995 2000 2010 2013

Kinh te Nha nude 92,0 170,2 722,0 1039,7 Kinh te ngoai Nha nude 122,5 212,9 1054,0 1559,7 Kinh te cd vdn dau tu nude ngoai 14,4 58,6 381,7 984,8

Tdng so 228,9 441,7 2157,7 3584,2

nude ta giai doan 1995 - 2013

h) Dua vao Atlat Dja 11 Viet Nam va kidn thuc da hgc, hay chung minh va giai thich su phan hd hgp l i ciia cay cdng nghiep lau nSm vdi cac vung sinh thai ndng nghiep

Caul (3,0 diim)

a) V i ddng hing sdng Cuu Long c i n phai chu y ddn chuydn ddi ca cIu ndng nghiep?

h) Phan tich didu kidn tu nhidn va tai nguydn thidn nhidn dd phat tridn cay cdng nghiep cua vung Ddng Nam Bg Tai cay cao su lai phat tridn manh nhat vung Ddng Nam Bg?

HET I

- Thi sinh dugc sit dung Atlat Dia li Viet Nam (NXBGD) - Gidm thi coi thi khdng gidi thich gi thim

SC5 G l A O DUG v A D A O T A O K Y THI CHON HQC SINH GIOI VONG TINH N A M 2018 V I N H L O N G Mon: £>IA Lf

Dd thi chinh thuc H i r O f N G D A N C H A M

CAU NOI DUNG DIEM

1 3,0 diem

a

Dua vao kien thuc Dia U de phan tich can tuc ngu ciia Viet Nam: "Dim thdng nam chua ndm dd sdng, thdng mu&i chua cu&i dd toi" Vi miia cua hai bdn cdu trdi ngugc nhau?

1,5

1 3,0 diem

* Viet Nam nam d B B C :

- Tbang tbugc tbdi ki (21/3 - 23/9) B B C nga vd pbia Mat Trai nen co goc cbidu sang Ian, dien ticb dugc cbidu sang Ian ban dien ticb ticb kbudt bong t6i (mua xuan va mua ba), dai ban dem

- Tbang 10 tbugc tbdi ki (23/9- 21/3 ) B B C cbdcb xa pbia Mat Trdi nen cd goc cbidu sang nbd, dien ticb dugc cbidu sang nbo ban dien ticb ticb kbuat bong tdi (mua tbu va mua ddng), ddm dai ban

* Nguyen nban: Do true Trai Ddt ngbieng vdi mat pbSng quy dao cua Trai Dat va suot nam, true Trai Ddt kbong ddi pbuong kbong gian nen d moi tbdi ki Idn lugt bai ban cdu nban dugc lugng anb sang kbac nbau

1,0

0,5 1

3,0 diem

b Trieu cucmg xay th&i ki nao? Tgi sao? Thuy trieu co y nghia gi sdn xuat vd

ddi sdng?

1,5 1

3,0 diem

* Trong tbang: tbuy tridu Idn nbdt la vao tbdi ki trang trdn va kbong trang; nam tbuy tridu Idn nbdt vao cac xudn pbdn va tbu pbdn

* Do nbiing tbdi ki vi tri cua Mat Trang, Mat Trdi va Trai Dat nam tbang bang nen sue but cua Mat Trang va Mat Trdi len Trai ddt Idn nbdt

* Y ngbia cua tbuy tridu san xudt va ddi s6ng:

- Nbd sir len xudng cua tbuy tridu nen ngudi xua sdng d gdn sdng, gdn bien bidt each bat bai san

- Ngay ngudi biet su dung tbuy tridu dd pbuc vu cbo cong ngbidp (san xudt dien), ngu ngbidp: danb bit bai san, va ngbidn cuu kboa bgc nbu tbuy van

- d) Viet Nam: L g i dung tbuy tridu lam nen cbidn thing tren sdng Bach Dang cua Ngo Quydn trudc qudn Nam Han, cbidn thing qudn Nguyen - Mdng cua Nbd Trdn

0,5 0,5 0,5 2 2,0 didm

a Nhung thay ddi ciia logi hinh quan cu ndng thdn Men Id gi? Tgi cd su thay ddi

nhu the?

0,5

2 2,0 didm

* Qudn cu nong tbdn bien dang cd nbidu tbay ddi vd cbuc nang, cdu true va budng pbat tridn, ty Id ddn kbong lam ndng ngbidp cang tang

* Do kdt qua cua qua trinb tbi boa va cong ngbidp boa

0,25 0,25

2 2,0 didm

b Suphdt trien cdc nganh dich vu cd anh hu&ng nhu the nao den ddi sdng ciia ngu&i

ddn?

1,5 2

2,0 didm

- Nbu cdu cua ngudi, cua tung gia dinb, cong dong rdt da dang

+ Cac nganb dicb vu giup pbdn pbdi cac san pbdm vat cbdt pbuc vu nbu cdu ngudi tidu dung

F r 1 ^ x

+ Tao va pbdn pbdi cac gia tri phi vat cbdt dd dap ung nbu cdu vd cbam s6c sdc kbdc, the tbao, giai tri, van boa, giao due

- Q nbung vung ddng ddn: tac ddng ciia nganb dicb vu rdt ro Q nbiing vung tbua ddn, tac ddng cua nganb dicb vu cung rdt quan trgng, la didu kidn dd giiip nbiing vung tbua ddn kbdng bi cbim tinb trang kinh td tu cung tu cdp ma pbat trien nen kinb te san xudt bang boa

- Tao vide lam gdp pban ndng cao ddi song ngudi ddn

0,75

0,5

0,25 1

Phan tich hoat ddng gid mua mua hg & nir&c ta

3 3,0 diem

- Tir thang den thang 10, c6 hai luong gio cung huong tay nam thoi vao

- Vao dau mua ha: Klidi khf nhiet doi Bdc A n Do Duong (khdi khdng chi tuydn vinh Bcngan- TBg) di chuydn thco huong tay nam

+ Khdi di chuydn thco hudng tay nam xam nhap true tidp gay mua cho ddng bdng Nam Bd va Tay Nguyen

+ K b i vugt qua day Trudng Son va cac day nui doc bien gidi Viet- Lao, kboi kbi trd ndn kbd nong

- Vao giua va cudi mua ba: Gio Tay Nam xudt pbat tu cao ap can cbi tuyen nua cdu Nam (kboi kbdng kbi nam xicb dao- Em) boat ddng manh

+ Kbi vugt qua bien vung xicb dao, khdi kbi trd nen ndng dm thuong gdy mua Idn va keo dai cbo cac vung Nam Bd va Tdy Nguyen

+ Hoat ddng cua gio mua Tdy Nam cung dai bdi tu nbiet ddi gdy mua ca bai midn Nam, Bdc va gdy mua vao tbang cbo Trung Bd

+ Do dp thdp Bdc Bd, kboi kbi di chuydn tbeo budng ddng nam vao Bdc Bd, tao nen "gid mua Ddng Nam" vao mua ba d midn Bdc

Vi ndi sinh vat Viet Nam tieu bieu cho sinh vgt cua viing nhiet ddi dm gid mua?

* Do vi tri dia 11 ndm boan toan vung nbiet ddi nen tdng sd bon 15.000 loai tbuc vat d Viet Nam da cd gdn 10.000 loai mang ddc tinb nbiet ddi va cbi co tren 5.000 loai tbuc vat a nbiet ddi va dn ddi tren nui

* Cac loai sinh vat d Viet Nam tbd bien ro quy luat dia ddi: pbong pbu sd loai, sue sdng manh bet, ndng sudt sinh bgc cao va ban cbd sd lugng ca the

He sinh thai rung nbiet ddi gid mua la tieu bidu va pbd bidn nbdt, cbidm dien ticb Idn nbdt va dugc pbdn bo rdng kbdp tu Bdc cbo ddn vung rung tram, rung ngap man d pbia Nam

Do vi tri dia li va ddc didm kbi bau ndn cac kidu rung nbiet ddi gid mua pbdn tbanb nbidu kidu: rung rdm nbidt ddi gid mua thudng xanb quanb ndm Rung ram nbiet ddi gid mua rung la ' '

Cac be sinh thai rung nbidt ddi gid mua c6 cac qudn xa va cac loai ddng vat nbidt ddi didn binh (kbi, vugn, cac loai ddng vat dn tbit: meo rung, cac loai cbim, nbidu loai bd sat, nbidu loai cdn trung)

Dang kd la sd lugng Idn cac loai tbu: bco, cay, cao, cbdn bay, sdc bay; buou, nai, bodng, bd rung, voi, td giac, cac loai dn tbit: bd, bao, cbd s6i

4 3,0 didm

Dua vao Atlat Dia li Viet Nam vd kien thirc dd hgc, hay phdn tich dac diem che dd nhiet cua tram khi hau Sa Pa

* Nbidt dd trung binh ndm cua Sa Pa kboang 15°C (bode dudi 18°C) thdp bon so vdi trung binh cua ca nude

Nguydn nban:

- Sa Pa cbiu anb budng cua gio mua Ddng Bdc

- Nbidt dd Sa Pa cbiu anb budng cua dd cao dia binh tbeo quy luat cu Idn cao kboang 100m nbidt dd giam trung binh kboang 0,6°C Sa Pa ndm xa Xicb dao

* Nbidt dd trung binh tbang cao nbat la tbang V l l : kboang 18°C

Nguydn nban: Day la tbdi ki Mat Trdi chuydn ddng bidu kidn Idn gan Cbi tuydn Bdc ndn Sa Pa nban dugc lugng nbidt Idn

* Nbidt dd trung binh tbang thap nbdt la tbang 1: khoang 7°C

Nguydn nban: Day la tbdi gian Mat Trdi chuydn ddng bidu kidn vd Nam Ban Cau ndn lugng nbidt nban dugc giam so vdi tbdi gian trudc Ddc bidt, tbdi gian nay, Sa Pa cbiu anb budng cua gid mua Ddng Bdc

5 3,0 diem

Nguyen nhan: Do Sa Pa chiu anh hudng true tiep ciia gio mua Dong Bac nen nhiet giam ro ret thdi ki mua dong Dong thdi Sa Pa cung nam gan chi tuyen nen dp chenh goc nhap xa va thdi gian cbidu sang nam Idn bon nbidu dia pbuong kbac

(dac bidt d pbia Nam)

Trinh bay dac diem tu nhien cua mien Bac vd Dong Bac Bac Bp Tieu chi quan nhdt de phdn chia cdc mien dia litu nhien Id tieu chi nao?

* Dac diem:

- Pham vi: T u ta ngan song Hdng ddn ria pbia tay, tay nam ddng bang Bac Bd - Dia hinh

+ Ddi niii tbip la uu tbd (cao trung binh 600m) c6 nbidu mil da vdi, mil cd budng vdng cung, cac tbung lung sdng Idn va ddng bing md rdng

+ B d bidn da dang: noi tbip, phang, them luc dia ndng, noi nbieu vinb, dao, quan dao, vinb nude sau

-Khihau

+ Co mua ddng lanb nbat nude

+ Cd mua: ddng lanb, ft mua va ba ndng, mua nbidu - Song ngdi

+ Mang ludi sdng ngdi day ddc

+ Hudng vdng cung va budng tay bac- ddng nam - Sinh vat: Nbidt ddi va can nbidt ddi

- Khoang sdn: giau tban (tban da), da vdi, tbidc cbi, kem, kbi tu nhidn * Tidu cbi: su pban boa cua cbd nbidt

Dua vao Atlat Dia li Viet Nam vd kien thirc dd hoc, hdy chung minh vd giai thich su phdn hda phdn bo ddn cu & vung ddng bdng

* Mdi vung ddng bang co muc tap trung dan sd kbac nbau co su kbac nbau vd dac didm tu nhidn, kinb td - xa bdi

* Ddng bing sdng Hdng c6 mat dd dan sd cao nbit (do)

Nguydn nban: co su tbuan loi vd dia binh, dat dai, ngudn nude,., (do); lich svr kbia tbac lanb thd lau ddi, nen ndng ngbidp lua nude vdi trinb tbam canh cao, tap trung nbidu trung tam kinb td- trung tam cdng ngbidp, co sd ba tang pbat tridn,

* Dong bing sdng Cuu Long co mat dan sd kba cao nbung thap bon ddng bang sdng Hdng (dc): c6 su tbuan loi vd dia binh, dat dai, ngudn nude,., (do); licb su khai tbac lanb tbd mudn bon, trinb dp tbam canh ndng ngbidp thap bon D B S H , cac trung tam kinb td - trung tam cdng ngbidp, co sd ba tang, chua pbat tridn nbu D B S H

* Ddng bing vcn bidn Midn Trung c6 mat dan sd tbIp bon ddng bang sdng Hdng (dc): vi dia binh, dit dai, ngudn nude,., (dc) kbdng tbuan Ipi nbu bai vung trdn

Nhan xet vd gidi thich nguyen nhan cua su chuyen dich ca cdu GDP phdn theo phdn kinh te & nu&c ta giai doan 1995 - 2013

6 3,0 didm

—•— JJani

Thanh phan 1995 2000 2010 2013

Kinb td Nba nude 40,2 38,5 33,5 29,0

Kinb td ngoai Nba nude 53,5 48,2 48,8 43,5 Kinb td cd vdn dau tu nude ngoai 6,3 13,3 17,7 27,5

Tdng sd 100 100 100 100

* Nban xet:

Co cIu GDP tbeo tbanb pbin kinb td co su chuydn dicb va cbdnb Idcb tbeo budng - GDP d kbu vuc Nba nude: ty giam lidn tuc (dc)

+ GDP d khu vuc kinh te cd vdn dau tu nude ngoai: ty tang lien tuc va nhanh (dc) - GDP d khu vuc kinh td cd vdn ddu tu nude ngoai xdp xi vdi kinh te Nha nude; kinh td ngoai nha nude van chidm ty cao nhdt (dc)

(Thieu ddn chiing khong cho diem toi da) Gidi thich:

- Tac ddng cua cdng cudc Ddi mdi, chuydn dich co cau kinh td thco co chd thi trudng - Do kdt qua cua dudng ldi phat tridn ndn kinh te hang hda nhidu phdn thco dinh hudng X H C N

- X u hudng hdi nhap quoc td

0,5

b Dua vao Atlat Dia li Viet Nam vd kien thuc dd hgc, hdy chung minh vd gidi thich su

phdn bo hop licua cay cdng nghiep lau ndm v&i cdc vung sinh thdi ndng nghiep

1,5 * Do mdi vung co uu thd vd didu kidn tu nhidn va T N T N ndn se co nhung cdy trdng phu hop vdi tung vung sinh thai khac khac

* Cdy ca phd: trdng nhidu d Tdy Nguydn, Ddng Nam B d , cd ddt badan, kbi bau

ndng quanb, I * Cdy cbe: nbidu d T D - M N Bac Bd, trdn cac cao nguydn cao d Tdy Nguydn, cd ddt dai

tbfcb bgp: fcralit trdn nbieu loai da, kbi bau lanb, mat me,

(TS cd thi neu su phdn bo khdc nhung dung vdn cho diim)

0,5

0,5

0.5

7 3,0 diem

a Vl ddng bdng song Cuu Long cdn phdi chuy den chuyen doi off cdu ndng nghiep? 1,0

7 3,0 diem

* Ddng bdng sdng Cuu Long cdn pbdi chuydn ddi co cdu ndng ngbidp tbeo budng pbu bop vdi tinb binh bidn ddi kbi bau toan cdu gdy nbidu bau qua: xdm nbdp man, sat Id vcn bd, mdt ddn didn ticb ddt ndng ngbidp d vung vcn bidn,

* Giam ti d kbu vuc 1, tang ti d K V 11 va 111; dac bidt chuydn ddi co cdu cdy trdng va vat nudi pbu bgp

0,5

0,5

7 3,0 diem

b Phdn tich dieu kien tu nhien vd tdi nguyen thien nhien de phdt trien cdy cdng nghiep cua vung Ddng Nam Bd Tgi cdy cao su lgi phdt trien mgnh nhat vung Ddng Nam Bd?

2,0

7 3,0 diem

* Didu kidn tu nhidn va tai nguydn tbidn nhidn: - Tbuan lgi:

+ Ddt xam pbu sa cd, dat dd ba dan didn ticb Idn, pbdn bo trdn mat bdng rdng tbuan lgi cbo binh tbanb vung chuydn canh cdy cdng ngbidp vdi qui md Idn

+ Kbi bau: cd tinb cbdt can xicb dao gid mua vdi mua mua va kbd keo dai ndn tbfcb bgp pbat tridn cdy cdng ngbidp co ngudn gdc nbidt ddi va can xicb dao

+ Cd su pbdn mua rd rdt: mua kbd keo dai tbuan lgi cbo phoi sdy ndng san + Ngudn nude ngdm va nude mat khai tbac kba tdt dd pbuc vu tudi tidu - K b d khan:

+ Mua kbd keo dai, nude ngdm bi ba thdp ddn ddn tbidu nude ngbidm trgng cbo san xudt + Ddt bi bac mau, bi da ong boa

* Cao su la cdy pbat tridn manh nbdt: Cd nbidu tbuan lgi vd tu nhidn va kinb td- xa bdi - Didu kidn tu nhidn

+ Cdy cao su tbfcb bgp vdi ddt ba dan, ddt xam pbu sa cd: didn ticb Idn (dc) L a ban binh nguydn Idn nbat nude ndn tbuan lgi cbo vide binh tbanb vung chuydn canh cdy cao su Idn nbdt nude

+ Cdy cao su tbicb bgp nbidt dd: 22°C den 27°C, lugng mua tu 1500 - 2500mm Cdn nbidu anb sang, kbdng cbiu gid manh, kbdng cbiu bao, ndn Ddng Nam Bd rdt pbu bgp

- Didu kidn kinb td - xa bdi:

+ Ddn cu va lao ddng: ddng, c6 kinb ngbidm trdng va cbd bien cao su + Tbi trudng tidu tbu va ngoai nude tang

+ Cdng ngbidp cbd bidn cang pbat tridn + Ngudn vdn ddu tu tbuan lgi

1,0

1,0

SOf GIAO DVC V A DAO T A O K Y THI CHQN HQC SINH GIOI THPT CAP TINH VINH L O N G ' N A M H Q C 2017-2018

Khoa thi 21 thang 01 nam 2018 D E THI C H I N H THlTC Mon: T I N HQC

Thoi gian lam bai: 180 phut (kbong kd tbdi gian giao dd) Budi tbi tbu nbdt: Sang 21/01/2018

(Dd tbi c6 03 trang, gom 03 bai)

T Q N G Q U A N B U G H T H I THtTNHAT

Tdn bai File cbuong trinb File du lidu vao File kdt qua Didm Bai Da tbiic D A T H U C * D A T H U C I N P D A T H U C O U T Bai Windows WINDOWS.* WINDOWS.INP W I N D O W S O U T 7

Bai Cat binh C A T H I N H * C A T H I N H I N P C A T H I N H O U T 7

Ddu * dugc thay the bai PAS hoac CPP cua ngon ngu lap trinh dugc su dung tuong ung Id Pascal hogc C++ Hay lap trinb giai cac bai toan sau:

B A I L Da thu-c (6 didm)

Cbo sd nguydn x va day gdm n+1 sd nguydn an, an-i, a n- ,a i , ao

Yen can: Tinb gia tri cua da tbuc P(x) = anx" + an-ix""' + an-2x"'' + + aix' + ao Du- lieu: Vao tu file van ban D A T H U C I N P :

• Ddng ddu tidn chua bai sd nguydn x va n (|x| < lO', < n < 5.10* va |x"| < lO'*) • Dong tbu bai chua day sd nguydn an, ap-i, a n ,a i , ao.(|ai| < 100)

Cac sd trdn cung ddng dugc gbi each nbau bod ddu each |

Ket qua: Gbi file van ban D A T H U C O U T mdt sd nguydn nbat la gia tri P(x) tim dugc Vi du:

DATHUC.INP D A T H U C O U T -1

1-12

-2

Gidi thich:

P(-l) = l.(-lf + (-l).(-lf + 2.(-l) + = -1 -1 -2 + = -2

BAI Windows (7 didm) ' M a n hinh quang cao la mot ludi vuong kich thudc N x N , cac hang dugc danh s6 tu ddn N -1 tu tren xudng dudi, cac cot dugc danh sd t u ddn N -1 tu trai qua phai N g u d i ta m d M cua sd cho M ndi dung quang cao khac Cac ciia sd cd dang hinh chu nhat, cac canh song song v d i canh ciia man hinh va dugc danb sd tu ddn M C i i a sd thii i dugc xac dinh bdi tga dd (xi,yi) ciia d trdn trai va tga dd (Ui,Vj) ciia d dudi phai ciia ciia

sd (cac tga dd ddu la sd nguydn v a pham v i man hinh) Tai mdi thdi didm, mdt ciia sd nao cd thd dugc klcb boat, nd se dugc dua Idn trdn cung v a se che phan didn tich chung v d i cac ciia so dugc kich boat trudc do. (3 hinh bdn, man hinh quang cao cd kich thudc x 9, co ciia sd dugc md:

- C i i a sd thii nhdt dugc xac dinh hdi tga dd (0,4) va (6,7) - C i i a sd thii hai dugc xac dinh hdi tga dd (2,3) va (5,8) - C i i a sd thii dugc xac dinh hdi tga dd (5,1) va (7,6) - C i i a sd thii tu dugc xac dinh hdi tga dd (1,1) va (3,8)

Trinh tu kich hoat cac ciia sd la thii tu, thii nhat, thii hai va thii N h u vay ciia sd thii hai h i che mat d, dien tich nhin thay chi cdn 20 d

1 r CinsS

ussiiWi 1 m

Cl>B SO — m y

i C0>as6 •yW{

2

: I

Ci>a s

— 3

1 : 1 ) 1

1 1 1 J

' I

—:—1

Yeu cau: Cho tnroc N ; M cua so co cac toa tuong ung la (xi,yi), (Ui,Vi), i = 1, , , M ; trinh tu kich hoat cac cua so kj, k2, kM (kj f kj, voi i 7^ j) va s6 nguyen L Hay xac dinh dien tich S nhin thay

dugc cua cua so thu L

Du lieu: Vao tu file van ban WINDOWS.INP:

• Dong dau tien cbua ba s6 nguyen duong N , M , L (2 < N , M < 100, < L < M)

• Dong tbu i M dong tilp tbeo cbua b6n s6 nguyen Xi, yi, Ui, Vj (0 < Xi, yi, Uj, Vj < N-1) • Dong cuoi cung cbiia M so nguyen duong k i , k , k M (1 < kj < M)

Cac so tren cung dong dugc gbi each nbau bdi ddu each

Ket qua: Gbi file van ban WINDOWS.OUT mgt s6 nguyen nbdt la dien ticb S nbin tbay dugc cua cua so tbu L

Vi du: WINDOWS.INP WINDOWS.OUT

9 4

0

1

BAI cat hiuh (7 didm)

Cbo A ia ludi vudng gdm m ddng va n cot Cac ddng ciia ludi dugc danb s6 tu ddn m, tu trdn xudng dudi Cac cot cua ludi dugc danb sd tu ddn n, tu trai sang pbai n i m trdn giao cua ddng i va cot j cua ludi ggi la (i, j) Tai moi (i, j) cua ludi c6 cbua mot s6 nguydn kbdng am aij

Vua qua, gid hoc dn luydn cbo ky tbi bgc sinb gidi Tin hoc d p tinb, Hoang dugc co giao giao cbo giai quydt bai toan sau day trdn ludi A da ndu:

Cbo mot binb cbu nbat (trong ludi A ) dugc xac djnb bdi trdn trai la (x,y) va dudi pbai la (u,v), can dua cbdnb Idcb nbd nbat sd cac cbdnb Idcb giua bai tdng cac sd bai binb cbd nbat tbu dugc bing vide cIt ngang binb cbu nbat da cbo doc tbeo dudng ke cua ludi Gia tbidt (x,y) va (u,v) la bai kbac nbau trdn ludi

Yeu cau: Ban bay giup Hoang giai quydt bai toan ma cd giao dat Du lieu: Vao tu file van ban CATHINH.INP:

• Ddng dau tidn cbua bai so nguydn duong m, n (m, n < 1000);

• Trong m ddng tidp tbeo, ddng tbu i cbua n sd nguydn kbdng am aii, a i , a i n (0 < ajj < 10°); • Dong cudi cung cbiia bdn sd nguydn duong x, y, u, v (1 < x < u < m, < y < v < n)

Cac s6 trdn cung ddng dugc gbi each nbau bdi d i u each

Ket qua: Gbi file van ban C A T H I N H O U T kdt qua bai toan ma Hoang dugc cd giao giai quyet Vi du:

CATHINH.INP CATHINH.OUT

3

0 1 1 1 1 1

Giai thich vi du:

Ndu cat ngang H C N (1,1), (3,2) doc thco dudng ludi thu nhdt: GTII

11 1 l | l

taco chdnhlech: - =3;

Ndu cit ngang H C N (1,1), (3,2) doc thco dudng ludi thu hai: OTll

j _ l 1 l | l

ta CO chdnh lech: - = 1; Rang buoc:

- Cd 30% sd test ung vdi 30% s6 didm cua bai cd m, n < 10

- Co 40% so test kbac ung vdi 40% sd didm cua bai co m, n < 100 - Cd 30% so test ung vdi 30% so didm cdn lai cua bai cd m, n < 1000

H E T -• 77?/ sinh khong dugc sir dung tdi lieu

• Cdn bo coi thi khdng gidi thich gi them

Ho tdn tbi sinb: S6 bao danb:

SCf G I A O D V C V A D A O T A O K Y T H I C H Q N H Q C S I N H G I O I T H P T C A P T I N H

V I N H L O N G N A M H Q C 2017-2018 D E T H I C H I N H T H V C Mon thi: TIN H Q C

Bu6i thi thii nhdt: Sang 21/01/2018 I

HirOfNG D A N C H A M T H I (Bdn hu&ng ddn ndy gom 07 trang)

I HiroTig dan chung

1) Ndu thi sinh lam bai khong theo each neu dap an nhimg dung thi T chdm thi trao doi, thong nhat thang diem va van cho du so diem tung phan nhu huong dan quy dinh;

2) Vide chi tiet hoa (neu c6) thang didm huong dan chdm phai dam bao khong lam sai lech hudng dan cham va phai dugc thong nhat thuc hien To cham thi

II Dap an va thang diem

B A I D A P A N D I E M

Bail Tinh gia trj cua P(x) bang luge Homer:

Chia P(x) cho (x - XQ), T a co: P(x) = (x - Xo).Q(x) + r

6,0

^ P ( x o ) = r

=> De tinh gia tri cua da thuc tai XQ, ta di tinh r, r dugc tim bdng luoc dd Homer

Test D A T H U C I N P D A T H U C O U T

1 -

6 M d i

Test -1

1 - 1 - 1 -

-6 0.5

didm

3 - -

67 -1

- 2 - 1 -3

-11 5

100 100 100 100 100 100

100 -2

10 -3 -10

178

7 File dathuc07.inp File dathuc07.out

8 File dathucOS.inp File dathuc08.out

9 File dathuc09.inp File dathuc09.out

10 File dathuc 10.inp File dathuc 10.out 11 File dathuc 11.inp File dathuc 11 out 12 File dathuc 12.inp File dathuc 12.out

Bail Theo trinh tu kich boat, kbi klcb boat den cua so tbu k ta gan nhan cac d thudc cua sd gia tri hang k

Dd tinh didn tich nhin thay cua cua sd thu L , ta dem sd cac d co gia tri

7,0

bang L cua s6 iy

Test W I N D O W S I N P W I N D O W S O U T

1 18 M o i

0 Test

2 0.5

5 d i l m

1

2

0 3 0 3 0 3

1

3 20

0 1

4 9

0 1

5 20

0 5 1 4

6 2

0 5 1 4

7 File windows07.inp File windows07.out

8 File windows08.inp File windowsOS.out

9 File windows09.inp File windows09.out

10 File windows 10.inp File windows 10.out 11 File windows 11.inp File windows Tout 12 File windows 12.inp File windows 12.out 13 File windows 13.inp File windows 13.out 14 File windows 14.inp File windows 14.out

Bdi 7,0

Test C A T H I N H I N P C A T H I N H O U T

1 3 M o i

0 1 Test

1 1 0,5

1 1 diem

1 3

2 0 1 1

1 1 1 11 1 1 2 3

3

0 1 1 10 1 1 11 1 1 1

4

0 1 0 1 0 1 0 1 1

5 5

0 1 1 0 1 0 1 0 1 1

1 2

6 5

0 1 ; 0 1

1 1 1 0 1 1

1 5

7 File cathinh07.inp File cathinh07.out File cathinhOS.inp File cathinhOS.out File cathinh09.inp File cathinh09.out 10 File cathinhlO.inp File cathinhlO.out 11 File cathinh 11 inp File cathinh 11 out 12 File cathinh 12.inp File cathinh 12.out 13 File cathinh 13.inp File cathinh 13.out 14 File cathinhl4.inp File cathinhM.out Code tham khao:

B a i l const

fi = 'Dathuc inp'; fo = 'Dathuc.out'; M a x N = 50000;

var

Heso: array[0 MaxN] o f longint; Homer: array[O MaxN] o f int64; N , x : Longint;

procedure nhap; var i : Longint; begin

Readln(x,N);

For i:=N downto Read(Heso[i]); end;

//

procedure xuli; var i : longint; begin

for i:=N downto

i f i=N then Homer[i] := Heso[i]

else Horner[i] := x*Homer[i+l]+Heso[i]; Write(Horner[0]);

end; //

{function luythua(x,k:longint): int64; var i : longint; L T : int64;

begin

ifk=Othen exit(l); i f k = l then exit(x); L T := x;

for i:=2 to k L T := L T * x ; exit(LT);

end;

procedure xuli;

var i : longint; P: int64; begin

P:=0;

for i:=0 to N P := P + Heso[i]*luythua(x,i); write(P);

end;} // B E G I N

assign(Input,fi); reset(Input);

assign(Output,fo); rewrite(Output); Nhap;

xuli;

Close(Input);

Close(Output); E N D

Bai const

fi = 'Windows.inp'; fo = 'Windows.out';

M a x N = 100; M a x M = 100; var

x,y,u,v : array [1 MaxN] o f Longint;

ManHinh: arTay[O MaxN-l,O MaxN-l] o f Longint; TrinhTu: a r r a y [ l M a x M ] o f longint;

N , M , L : Longint; procedure nhap; var i : Longint; begin

Readln(N,M,L);

For i:=l to M Readln(x[i],y[i],u[i],v[i]); ! For i:=l to M Read(TrinhTu[i]);

end; //

procedure Gannhan(k;:Longint); var i,j:Longint;

begin

For i:=x[k] to u[k]

For j:=y[k] to v[k] ManHinh[i,j] := k; end;

//

procedure xuli; var i : longint; begin

for i:=l to M Gannhan(TrinhTu[i]); end;

//

Procedure Xuat; var S,i,j: Longint; Begin

S : - ;

For i:=x[L] to u[L] Forj:=y[L] to v[L]

i f (ManHinh[iJ] = L ) then inc(S); write(S);

End; B E G I N

assign(Input,fi); reset(Input);

I

assign(Output,fo); rewrite(Output); Nhap;

X u l i ; Xuat; Close(Input); Close(Output); E N D

Bai

const m a x N = 1000;

v a r a : array [1 MaxN, L m a x N ] o f longint; sum: array[0 maxN,0 maxN] o f int64; m,n,x,y,u,v: longint;

D_min: int64; procedure chuanbi; var i,j: longint; begin

for i:=l to m // tao mang sum

for j : = l to n sum[i,j] := a[i,j] + sum[i-l,j] + sum[i,j-l] - s u m [ i - l , j - l ] ; end;

//

procedure xuli(x,y,u,v:longint);

var i , j , L , H , M i d : longint; s,sl,s2: int64; begin

D _ m i n := 2000000000000; L:=x; H:=u;

s := (sum[H,v] - sum[H,y-l]) - (sum[x-l,v] - s u m [ x - l , y - l ] ) ; s i :=0; s2 :=0;

while (L<=H) // cat hinh theo dong begin

M i d := (L+H) div 2;

s i := (sum[Mid,v] - sum[Mid,y-l]) - (sum[x-l,v] - s u m [ x - l , y - l ] ) ; s2 := s - s i ;

i f sl=s2 then begin D _ m i n := s i - s2; writeln(D_min); exit end; i f abs(sl-s2) < D then D _ m i n := abs(sl-s2);

i f s l < s t h e n L := M i d + e l s e H : = M i d - ;

end;

writeln(D_min); end;

//

procedure nhap; var i,j: longint;

begin

readln(m,n); for i:=l to m

begin

for j : = l to n read(a[i,j]); readln;

end; chuanbi;

readln(x,y,u,v); xuli(x,y,u,v); end;

//

begin

assign(input,'cathinh.inp'); reset(input); assign(output,'cathinh.out'); rewrite(output); nhap;

close(input); close(output); end

H E T

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