Đặc điểm huyết động của van hai lá nhân tạo saint jude

EVALUATION OF HEMODYNAMIC CHARACTERISTICS OF THE SAINT JUDE PROSTHETIC HEART VALVE IN THE MITRAL POSITION MD MSc NGUYỄN NGỌC HOÀNG MỸ Can Tho Central General Hospital Thanks to • Mentor: MD PhD Hồ Huỳnh Quang Trí • Place of research: Heart Institute of HCM city • Place of work: Can Tho Central General Hospital Declaration of Interest • No research funding • No stocks, investments, ownership, patents RESEARCH QUESTION OBJECTIVE OF STUDY OVERVIEW METHODS RESULTS - DISCUSSION CONCLUSIONS RECOMMENDATIONS RESEARCH QUESTION Rising population with Prosthetic mitral valve (PrMV) PrMV: quite new area Normal values of hemodynamic parameters of Saint Jude valve in mitral position on Doppler Echocardiography Transthoracic echocardiogram (TTE): useful, precise, harmless OBJECTIVE OF THE STUDY Define normal values of hemodynamic parameters of the Saint Jude valve in mitral position Describe baseline clinical characteristics Define structure and hemodynamic parameters of PrMV on Doppler Echocardiography Compare difference of basic echo parameters in points of time OVERVIEW Types of Prosthetic heart valves Mechanical Prostheses Ball-cage valve Monoleaflet valve Bileaflet valve Biological protheses: Autograft valve, Homograft valve, Xenogaft valve OVERVIEW Methods to evaluate Prosthetic heart valves EOA EOA PPI = 𝑃𝐻𝑇 CE = 220 PHT LVOT 𝑑 ∗ 𝜋 ∗ VTI = ∗ VTI MV EOA GOA EOAI = EOA BSA VTI MV VTI Ratio = VTI(LVOT) LVOT RESEARCH METHODS Objective of study Criteria for sample selection • Patients with Saint Jude mitral valve replacement followed up as outpatients and in stable clinical condition Criteria for exclusion • Aortic stenosis or aortic regurgitation ≥ 2/4 • Aortic valve replacement • Coronary stenosis or CABG with mitral valve replacement (MRV) • Congenital heart defect • Unstable clinical condition: tachycardia, angina, dyspnea, fever… • Pleural effusion, pericardial effusion • PrMV complication after 02 months of observation RESEARCH METHODS Research Methods Research design 𝐶2𝑥 𝑆2 𝑛 ≥ 𝜀2 • Prospective observation with analysis C= 2,09 (degree of freedom 19 p= 0,05) Sample mean 1,85 cm2 Sample variance S2= 0,12 𝑋 and  difference 5%   = 0,09 Therefore, n ≥ 61 Data Analysis • SPSS 20.0 • Analysis of variance ANOVA, t-Test (p value