Tích phân đầy đủ chọn lọc

333 BÀI TOÁN TÍCH PHÂN LUYỆN THI ĐẠI HỌC 1/ Cho hàm số : f(x)= x.sinx+x 2 . Tìm nguyên hàm của hàm số g(x)= x.cosx biết rằng nguyên hàm này triệt tiêu khi x=k π 2/Định m để hàm số: F(x) = mx 3 +(3m+2)x 2 -4x+3 là một nguyên hàm của hàm số: f(x) = 3x 2 +10x-4. 3/Tìm họ nguyên hàm của hàm số: f(x)= cos 3 x.sin8x. TÍNH : 4/I = 4 2 6 (2cotg x 5)dx π π + ∫ 5/ I = ∫ 2 0 π sin 2 x.cos 2 xdx 6/I = ∫ 3 0 π (2cos 2 x-3sin 2 x)dx 7/ I = 2 2 sin( x) 4 dx sin( x) 4 π −π π − π + ∫ 8 / I = ∫ − 3 6 π π (tgx-cotgx) 2 dx 9/I = dxxxnsix )cos(2cos 44 2 0 + ∫ π 10/ I = 3 2 0 4sin x dx 1 cosx π + ∫ 11/ I = 1 3 2 0 x 1 x dx− ∫ 12/I = 1 5 2 0 x 1 x dx+ ∫ 13/I = 1 0 x dx 2x 1+ ∫ 14/I = 3 2 4 3tg x dx π π ∫ 15/ I = 2 3 0 sin x dx π ∫ 16/I = 2 0 1 cos x dx 1 cosx π − + ∫ 17/I = 2 4 0 sin x dx π ∫ 18/I = ∫ 4 6 π π cotg2x dx 19/ I = ∫ + 4 0 2 2 cos π x e tgx 20/ I = 4 4 0 cos x dx π ∫ 21/ I = ∫ 2 4 4 sin 1 π π x dx 22/ I = ∫ 4 0 6 cos 1 π x dx 23*/ I = 3 3 2 3 sin x sin x cot gx dx sin x π π − ∫ 24/I = ∫ 3 4 22 2 cos 2 sin 1 π π xx dx 25/I = 2 2 sin x 4 e sin 2x dx π π ∫ 26/I = 1 2 2 3 1 dx x 4 x− ∫ 27/I = 4 2 2 1 dx x 16 x− ∫ 28*/I = 6 2 2 3 1 dx x x 9− ∫ 29/I = 2 2 2 1 x 4 x dx − − ∫ 30/I = 2 2 3 0 x (x 4) dx+ ∫ 31/I = 2 4 4 3 3 x 4 dx x − ∫ 32*/I = 2 2 2 2 x 1 dx x x 1 − − + + ∫ 33/I = ln 2 x 0 e 1dx− ∫ 34/I = x 1 x 0 e dx e 1 − − + ∫ 35/I = e 2 1 ln x dx x(ln x 1)+ ∫ 36/I = 7 3 3 0 x 1 dx 3x 1 + + ∫ 37/I = 2 3 2 0 (x 3) x 6x 8 dx− − + ∫ 38/I = e 1 sin(ln x) dx x ∫ 39/I = 1 3 4 5 0 x (x 1) dx− ∫ 40/I = 1 2 3 0 (1 2x)(1 3x 3x ) dx+ + + ∫ 41/I = 3 2 2 6 tg x cot g x 2dx π π + − ∫ 42/I = x ln3 x 3 0 e dx (e 1)+ ∫ 43/I = 0 2x 3 1 x(e x 1)dx − + + ∫ 44/I = 2 6 3 5 0 1 cos x sin x.cos xdx π − ∫ 45*/I = 2 3 2 5 1 dx x x 4+ ∫ 46/I = 4 0 x dx 1 cos2x π + ∫ 47/I = 2x ln5 x ln 2 e dx e 1− ∫ 48/I = 2 1 0 x dx (x 1) x 1+ + ∫ 49/ I = 2 3 0 cos xdx π ∫ 50/I = 1 x 0 1 dx e 4+ ∫ 51/I = 2 x 1 1 dx 1 e − − ∫ 52/I = 2x 2 x 0 e dx e 1+ ∫ 53*/I = 3 0 1 dx cos x π ∫ 54/I = 2x 1 x 0 e dx e 1 − − + ∫ 55/I = ln3 x 0 1 dx e 1+ ∫ 56/I = 2 3 1 1 dx x 1 x+ ∫ 57/I = 1 2 3 0 (1 x ) dx− ∫ 58*/I = 1 2x 0 1 dx e 3+ ∫ 59/I = 9 3 1 x. 1 xdx− ∫ 60/I = 2 3 0 x 1 dx 3x 2 + + ∫ 61*/I = 6 0 x sin dx 2 π ∫ 62**/I = 1 2 0 ln(1 x) dx x 1 + + ∫ 63/I = 2 e 1 x 1 .ln xdx x + ∫ 64*/I = 2 2 0 4 x dx+ ∫ 65/I = e 2 1 (ln x) dx ∫ 66/I = 1 0 1 dx 3 2x− ∫ 67/I = 2 5 0 sin xdx π ∫ 68/I = 4 2 6 1 dx sin x cotgx π π ∫ 69/I = 3 2 e 1 ln x 2 ln x dx x + ∫ 70/I = 2 0 sin x.sin 2x.sin3xdx π ∫ 71/I = 2 4 4 0 cos2x(sin x cos x)dx π + ∫ 72*/I = 2 3 3 0 ( cos x sin x)dx π − ∫ 73/I = 7 3 8 4 2 x dx 1 x 2x+ − ∫ 74*/I = 2 0 4cos x 3sin x 1 dx 4sin x 3cos x 5 π − + + + ∫ 75*/I = 2 0 x dx 2 x 2 x+ + − ∫ 76/I = 3 3 2 0 x . 1 x dx+ ∫ 77/I = 2 0 sin x dx sin x cosx π + ∫ 78/I = e 1 cos(ln x)dx π ∫ 79/I = 2 1 x dx 1 x 1+ − ∫ 80/I = e 1 1 3ln x ln x dx x + ∫ 81/I = 3 2 2 ln(x x)dx− ∫ 82/I = 2 2 1 x ln(x 1)dx+ ∫ 83/I = 1 2 0 1 dx 4 x− ∫ 84/I = 3 2 6 ln(sin x) dx cos x π π ∫ 85*/I = 2 2 0 ln( 1 x x)dx+ − ∫ 86*/I = 3 2 2 1 dx x 1− ∫ 87/I = 6 2 0 x.sin xcos xdx π ∫ 88/I = 2x 2 0 e sin xdx π ∫ 89/I = 2 2 1 1 x ln(1 )dx x + ∫ 90/I = e 2 1 e ln x dx (x 1)+ ∫ 91/I = 1 2 0 1 x x.ln dx 1 x + − ∫ 92/I = 2 t 1 ln x dx I 2 x   ⇒ <  ÷   ∫ 93/I = 3 0 sin x.ln(cosx)dx π ∫ 94/I = 2 e 2 1 cos (ln x)dx π ∫ 95/I = 2 e e ln x dx x ∫ 96/I = 2 e 1 ln x dx ln x ∫ 97/I = 3 2 3 1 dx x 3+ ∫ 98/I = 2 4 0 sin xdx π ∫ 99/I = 2 1 cos(ln x)dx ∫ 100/I = 3 8 1 x 1 dx x + ∫ 101/I = 3 3 2 1 x dx x 16− ∫ 102/I = 3 4 4 sin 2x dx π π ∫ 103*/I = 2 x 1 2 0 x e dx (x 2)+ ∫ 104*/I = 4 1 x 1 x dx 1 2 − + ∫ 105/I = 2 4 0 xsin xdx π ∫ 106/I = 2 4 0 x cos xdx π ∫ 107/I = 1 0 2x 9 dx x 3 + + ∫ 108/I = 4 2 1 1 dx x (x 1)+ ∫ 109/I = 1 3 0 4x dx (x 1)+ ∫ 110/I = 6 2 0 cos x dx 6 5sin x sin x π − + ∫ 111*/I = 2 e 2 e 1 1 ( )dx ln x ln x − ∫ 112/I = 3 2 4 x 4 dx − − ∫ 113/I = 2 3 2 1 x 2x x 2 dx − − − + ∫ 114/I = 3 4 4 cos2x 1dx π π + ∫ 115/I = 0 cosx sin xdx π ∫ 116/I = 2 0 1 sin xdx π + ∫ 117/I = 0 1 sin xdx π − ∫ 118/I = 1 3 2 1 ln(x x 1) dx −   + +     ∫ 119*/I = 2 0 xsin x dx 1 cos x π + ∫ 120*/I = 1 2 x 1 1 dx (x 1)(4 1) − + + ∫ 121/I = 1 2 0 3 dx x 4x 5− − ∫ 122/I = 2 2 1 5 dx x 6x 9− + ∫ 123/I = 1 2 5 1 dx 2x 8x 26 − + + ∫ 124*/I = 0 2 2 sin 2x dx (2 sin x) −π + ∫ 125/I = 1 2 0 x 3 dx (x 1)(x 3x 2) − + + + ∫ 126/I = 2 2 sin x 3 0 e .sin x cos xdx π ∫ 127/I = 3 4 2 2 5 0 sin x dx (tg x 1) .cos x π + ∫ 128/I = 3 2 2 3 1 dx sin x 9cos x π π − + ∫ 129/I = 2 2 cosx 1 dx cos x 2 π π − − + ∫ 130/I = 2 0 1 sin x dx 1 3cos x π + + ∫ 131/I = 2 0 cos x dx sin x cosx 1 π + + ∫ 132/I = 1 3 3 1 dx x 4 (x 4) − + + + ∫ 133/I = 6 4 x 4 1 . dx x 2 x 2 − + + ∫ 134/I = 0 2 1 1 dx x 2x 9 − + + ∫ 135/I = 2 2 1 4x x 5 dx − − + ∫ 136/I = 2 2 2 2x 5 dx x 4x 13 − − + + ∫ 137/I = 2x 2 0 e sin xdx π ∫ 138/I = 2 x 1 2 0 x e dx (x 2)+ ∫ 139/I = e 1 (1 x)ln x dx+ ∫ 140/I = e 1 x(2 ln x)dx− ∫ 141/I = 4 0 1 dx cos x π ∫ 142*/I = 4 3 0 1 dx cos x π ∫ 143/I = 2 1 3 x 0 x e dx ∫ 144/I = 2 4 0 sin 2x dx 1 cos x π + ∫ 145/I = 3 4 1 dx sin 2x π π ∫ 146/I = 4 2 1 1 dx x (x 1)+ ∫ 147/I = 3 3 0 sin x dx cos x π ∫ 148/I = 1 0 x 1 xdx− ∫ 149/I = 3 2 1 1 dx 4x x− ∫ 150/I = 1 x 0 1 dx 3 e+ ∫ 151/I = 0 xsin xdx π ∫ 152/I = 1 0 cos x dx ∫ 153/I = 1 0 sin x dx ∫ 154/I = e 2 1 x ln xdx ∫ 155/I = 1 e 2 1 ln xdx ∫ 156/I = 1 4 2 0 1 dx (x 4x 3)+ + ∫ 157/I = 3 3 2 0 sin x dx (sin x 3) π + ∫ 158/I = 3 3 6 4sin x dx 1 cos x π π − ∫ 159/I = 3 2 6 1 dx cos x.sin x π π ∫ 160/I = 3 0 sin x.tgxdx π ∫ 161/I = 1 4x 2x 2 2x 0 3e e dx 1 e + + ∫ 162/I = 4 2 7 1 dx x 9 x+ ∫ 163/I = 2 x 2 0 e sin xdx π ∫ 164/I = 4 2 4 4 0 cos x dx cos x sin x π + ∫ 165/I = 1 0 3 dx x 9 x+ − ∫ 166/I = 2 2 0 x cos xdx π ∫ 167/I = 2 4 0 xsin x dx π ∫ 168/I = 2 4 0 x cos x dx π ∫ 169/I = 2 0 x cos x sin x dx π ∫ 170/I = 2 e 2 e 1 1 ( )dx ln x ln x − ∫ 171/I = 2 2 1 (x x)ln x dx+ ∫ 172/I = 2 2 1 1 x ln(1 )dx x + ∫ 173/I = 2 3 cos x.ln(1 cos x)dx π π − ∫ 174/ 2 2 sin x 3 0 e sin x cos xdx π ∫ 175/I= 2 4 0 sin 2x dx 1 sin x π + ∫ 176/I = 5 3 ( x 2 x 2 )dx − + − − ∫ 177/I = 4 1 2 dx x 5 4 − + + ∫ 178/I = 2 1 x dx x 2 2 x+ + − ∫ 179/I = 2008 2 2008 2008 0 sin x dx sin x cos x π + ∫ 180/I = 2 0 sin x.ln(1 cos x)dx π + ∫ 181/I = 2 2 0 cos x.cos4x dx π ∫ 182/I = 1 2x x 0 1 dx e e+ ∫ 183/I = 1 0 1 dx x 1 x+ + ∫ 184/I = 2 6 1 sin 2x cos2x dx cos x sin x π π + + + ∫ 185/I = 4 x 1 e dx ∫ 186/I = 2 5 1 ln x dx x ∫ 187/I = e 2 1 e ln x dx (x 1)+ ∫ 188/I = 1 2 0 1 x x ln dx 1 x + − ∫ 189/I = 4 2 1 1 dx x (x 1)+ ∫ 190/I 4 1 6 0 1 x dx 1 x + + ∫ 191/I= e 1 e ln x dx ∫ 192/I = 2 2 1 x 1 ( ) dx x 2 − − + ∫ 193/I = 4 2 0 x.tg x dx π ∫ 194/I = 2 2 1 ln(1 x) dx x + ∫ 195/I = 2 0 sin 2x dx 1 cosx π + ∫ 196/I = 2 3 2 1 x 1 dx x + ∫ 197/I = 3 4 2 0 sin x dx cos x π ∫ 198/I = e 2 1 e ln x dx (x 1)+ ∫ 199/I = 2 1 2 0 x dx 4 x− ∫ 200/I = 6 2 0 x cos x sin x dx π ∫ 201/I = 4 3x 0 e sin 4xdx π ∫ 202/I = 2 4 0 sin 2x dx 1 cos x π + ∫ 203/I = 2 2 1 5 dx x 6x 9− + ∫ 204/I = 2 1 0 x 3x 2 dx x 3 + + + ∫ 205/I = 1 2 0 ln(1 x) dx x 1 + + ∫ 206/I = 1 15 8 0 x 1 x dx+ ∫ 207/I = x 1 x x 0 e dx e e − + ∫ 208/I = 2 sin x 0 (e cos x)cos x dx π + ∫ 209/I = 2 0 sin 2x.cos x dx 1 cosx π + ∫ 210/I = 2 0 sin 2x sin x dx 1 3cos x π + + ∫ 211/I = 2 4 0 1 2sin x dx 1 sin 2x π − + ∫ 212/I = 5 3 3 2 0 x 2x dx x 1 + + ∫ 213/I = 3 2 4 tgx dx cos x 1 cos x π π + ∫ 214/I = x 2 1 2x 0 (1 e ) dx 1 e + + ∫ 215/I = 3 2 3 0 x (1 x) dx− ∫ 216/I = 3 2 2 0 sin x.cos x dx cos x 1 π + ∫ 217/I = 1 2 2 0 4x 1 dx x 3x 2 − − + ∫ 218*/I = 2 0 xsin x.cos xdx π ∫ 219/I = 2 0 cos x dx cos2x 7 π + ∫ 220/I = 4 2 1 1 dx x (x 1)+ ∫ 221/I = 2 2 3 0 sin 2x(1 sin x) dx π + ∫ 222/I = 4 2 7 1 dx x x 9+ ∫ 223/I = 3 4 0 xsin xcos xdx π ∫ 224/I = 2 3 2 cos x cosx cos xdx π π − − ∫ 225*/I = 1 2 1 ln( x a x)dx − + + ∫ 226/I = 2 x 0 1 sin x dx (1 cos x)e π − + ∫ 227/I = 2 3 2 cos x cosx cos xdx π π − − ∫ 228/I = 1 2 0 x dx 4 x− ∫ 229/I = 1 4 2 2 0 x dx x 1− ∫ 230/I = 2 2 2 2 0 x dx 1 x− ∫ 231/I = 2 2 4 1 1 x dx 1 x − + ∫ 232/I = 3 7 3 2 0 x dx 1 x+ ∫ 233/I = x ln 2 x 0 1 e dx 1 e − + ∫ 234/I = 1 0 x 1 x dx− ∫ 235/I = 1 2 0 x 1dx+ ∫ 236/I = 2 3 0 x 1 dx 3x 2 + + ∫ 237/I = 2 3 2 2 0 x dx 1 x− ∫ 238/I = 2 3 2 2 0 x dx 1 x− ∫ 239/I = 2 1 2 2 2 1 x dx x − ∫ 240/I = 2 1 2 0 x dx 4 x− ∫ 241/I = 4 2 1 1 dx (1 x)x+ ∫ 242/I = 2 0 sin x dx x π ∫ 243/I = 2 0 sin3x dx cos x 1 π + ∫ 244/I = 2 3 3 0 (cos x sin x)dx π + ∫ 245/I = 2 3 0 x 1 dx x 1 + + ∫ 246/I = 1 2 2x 0 (1 x) .e dx+ ∫ 247/I = 2 2 0 cosx dx cos x 1 π + ∫ 248/I = 7 3 3 0 x 1 dx 3x 1 + + ∫ 249/I = 2 0 sin 2x sin x dx cos3x 1 π + + ∫ 250/I = 4 2 2 0 sin 2x dx sin x 2cos x π + ∫ 251/I = 2 2 2 3 1 dx x x 1− ∫ 252/I = 1 5 3 6 0 x (1 x ) dx− ∫ 253/I = 2 0 sin x dx 1 sin x π + ∫ 254/I = 2 0 cos x dx 7 cos2x π + ∫ 255/I = 2 3 0 x 1 dx 3x 2 + + ∫ 256*/I = 3 4 cos x sin x dx 3 sin 2x π π + + ∫ 257*/I = 2 x 0 1 sin x e dx 1 cosx π + + ∫ 258/I = 1 2 3 0 (1 x ) dx− ∫ 259*/I = 5 2 5 1 1 x dx x(1 x ) − + ∫ 260/I = 3 2 0 cos x dx 1 sin x π − ∫ 261/I = 3 6 0 sin x sin x dx cos2x π + ∫ 262/I = 2 3 1 dx sin x 1 cos x π π + ∫ 263/I = 3 6 2 1 1 dx x (1 x )+ ∫ 264*/I = 2 1 2 0 x ln(x 1 x ) dx 1 x + + + ∫ 265/I = 4 2 1 (x 1) ln x dx− ∫ 266/I = 3 2 0 x ln(x 1)dx+ ∫ 267/I = 3 2 2 1 3x dx x 2x 1+ + ∫ 268/I = 1 3 2 0 4x 1 dx x 2x x 2 − + + + ∫ 269/I = 1 2 2 1 2 1 dx (3 2x) 5 12x 4x − + + + ∫ 270/I = 1 0 1 dx x 1 x+ + ∫ 271/I = 2 0 cos x dx 2 cos2x π + ∫ 272/I = 3 4 4 tg xdx π π ∫ 273/I = 4 2 0 x.tg xdx π ∫ 274/I= 2 2 2 0 1 dx (4 x )+ ∫ 275/I = 2 1 3 0 3x dx x 2+ ∫ 276/I = 2 3 6 0 sin x dx cos x π ∫ 277/I = 1 1 x 3 a e dx x ∫ 278/I = 3 1 2 3 0 x dx (x 1)+ ∫ 279/I = 1 3 0 3 dx x 1+ ∫ 280*/I = 4 1 6 0 x 1 dx x 1 + + ∫ 281/I = 1 3 0 x dx (2x 1)+ ∫ 282/I = 3 7 3 2 0 x dx 1 x+ ∫ 283/I = 2 0 cos x dx cos x 1 π + ∫ 284/I = 2 0 cos x dx 2 cos x π − ∫ 285/I = 2 0 sin x dx sin x 2 π + ∫ 286/I = 3 2 0 cos x dx cos x 1 π + ∫ 287/I = 2 2 0 sin x dx cos x 3 π + ∫ 288/I = 2 2 0 sin x cos x(1 cos x) dx π + ∫ 289/I = 4 4 4 0 sin x cos x dx sin x cosx 1 π − + + ∫ 290/I = 4 4 4 0 sin x cos x dx sin x cosx 1 π − + + ∫ 291/I = 2 0 sin x cos x cos x dx sin x 2 π + + ∫ 292/I = 3 2 1 2 0 x 2x 10x 1 dx x 2x 9 + + + + + ∫ 293/I = 7 2 1 dx 2 x 1+ + ∫ 294/I = 3 2 2 1 2 1 dx x 1 x− ∫ 295/I = 2 2 2 3 1 dx x x 1− ∫ 296*/I = 2 3 1 1 dx x 1 x+ ∫ 297/I = 3 1 2 0 x dx x 1 x+ + ∫ 298/I = 1 2 1 1 dx 1 x 1 x − + + + ∫ 299/I = 3 4 6 1 dx sin x cos x π π ∫ 300/I = 2 0 1 dx 2cos x sin x 3 π + + ∫ 301/I = 2 4 cos x sin x dx 3 sin 2x π π + + ∫ 302/I = 2 3 3 0 (cos x sin x)dx π + ∫ 303/I = 2 5 4 0 cos xsin xdx π ∫ 304/I = 2 4 4 0 cos2x(sin x cos x)dx π + ∫ 305/I = 2 0 1 dx 2 sin x π + ∫ 306*/I = 2 0 sin x dx cos x sin x π + ∫ 307/I = 4 2 4 4 0 sin x dx cos x sin x π + ∫ 308*/I = 2 2 0 tgx dx 1 ln (cosx) π − ∫ 309*/I = 2 0 sin x dx cos x sin x π + ∫ 310*/I = 1 x 2 1 1 dx (e 1)(x 1) − + + ∫ 311*/I = 3 2 4 2 0 cos x dx cos 3cos x 3 π − + ∫ 312*/Tìm x> 0 sao cho 2 t x 2 0 t e dt 1 (t 2) = + ∫ 313/I = 4 3 0 tg x dx π ∫ 314*/I = 4 5 0 tg x dx π ∫ 315/I = 4 3 6 cotg x dx π π ∫ 316/I = 3 4 4 tg x dx π π ∫ 317*/I = 4 0 1 dx 2 tgx π + ∫ 318*/I = 1 2x 1 1 dx 3 e − + ∫ 319*/I = 2 x sin x dx 3 1 π −π + ∫ 320/I = 2 0 1 dx 2 cos x π − ∫ 321*/I = 1 3x 1 0 e dx + ∫ 322*/I = 2 1 2 0 x dx x 4+ ∫ 323/I = 2 2 3 cos x dx (1 cosx) π π − ∫ 324/I = 5 2 0 sin x dx cos x 1 π + ∫ 325/I = 3 2 6 cos2x dx 1 cos 2x π π − ∫ 326*/I = 4 2 0 t gx 1 ( ) dx tgx 1 π − + ∫ 327*/I = 1 3 1 2 x dx x 1+ ∫ 328*/I = 3 3 2 4 1 x x dx x − ∫ 329/I = x ln3 x x 0 e dx (e 1) e 1+ − ∫ 330/I = 1 4 e 2 1 e 1 dx x cos (ln x 1) π − + ∫ 331*/I = 4 0 ln(1 tgx)dx π + ∫ 332*/I = 3 2 4 tan x dx cos x cos x 1 π π + ∫ 333*/I = 1 2 0 3x 6x 1dx− + + ∫ . . 333 BÀI TOÁN TÍCH PHÂN LUYỆN THI ĐẠI HỌC 1/ Cho hàm số : f(x)= x.sinx+x 2 . Tìm nguyên hàm của hàm số g(x)=