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PHATHUYTiNHIfCH cue HOATOONGCUAHOC SINH I N G OUII DAY i G BAI lAP VA IHKG HANH Vi KIIU MANG (UN HHC 111 TS TRAN DOAN VINH* Trong chuang trinh Tin hoc 11, hpc sinh (HS) da bit dau lam quen vdi ngdn ng[.]
PHATHUYTiNHIfCH cue HOATOONGCUAHOC SINH I N G OUII DAY i G BAI lAP VA IHKG HANH Vi KIIU MANG (UN HHC 111 TS TRAN D O A N VINH* T rong chuang trinh Tin hoc 11, hpc sinh (HS) da bit dau lam quen vdi ngdn ngu lap trinh PascaLOaylamdtngdn ngi? lap trinh bac cao, ddi hdlHS phai ti/giie, ddc lap suy nghT; die biet, can tich cue hoat dpng, hoin cic yeu eau dit phan bii tap va thuc hanh Vi'n de dit la lam thenao de phat huy dupe tinh tieh cue boat ddng cua HS thdng qua day hpe bii tip v i thue hanh? Cich thuc tie'n hanh nhu the nao? Bai vie't nhim giai quye't phan nio vi'n de dupe dit d tren Nhirng hoat dong pho' bien day hpc mon Tin hoc Nhi?ng hoatddng hpe tip phd'bien eua HS day hpc tin hpc ndi ehung va bai tap va thue hanh ndi rieng thudng gdm: - Nhan biet cic di'u bleu die trung cua mdt bai toin (BT); - Xic djnh thdng tin vao hay eac di? lieu eho tmdc va thdng tin cua BT; - Tim thuat toin dung din, phu hpp vdi tung BT;-Xiy dung cau tnJc di? lieu phu hop de bie'u dlln thdng tin qua eau tnjc di?lieu dd; - Bleu diin thuat toin bing eac loal ngdn ngukhac nhau;-Dinh glimdeddphdctap eua thuat toan; - Tim thuat toin khac tdi uu ban thuat toin ban dau Nhu viy, moi boat dpng hpe tap se tUPng ung vdi mdt mue tieu day hpc nhi't djnh Do dd,HS can thuc hien mdt chudi boat dpng theo mdt trinh tu hop li mdi cd the' hoan dupe nhiem vu hpc tap Giao vien (GV) can giup HS nim dupe muc dich, nhiem vu hpe tip va xic dinh dupe cae boat ddng hpc tap cu the Khi dd, HS mdi cd the phat huy tinh dupe tinh tu giic, tich cue, chd ddng va sang tao hpe tip hpe Bii tip vi thue hinh 3ve kie'u mang nhim phat huy tinh tieh cue boat dpng hpc tap cda HS: sr.'Tao mang/4 gdm n(n< /00)sd nguyen, mdi sded gii trj tuyet dd'i khdng vupt qua 300 Tinh td'ng eic phan td cda mang la bdi sd cda mdt sd nguyen duang/f eho tnrdc 1}Haytim hieu vaehayttiuehuang trinh sau day: program Suml; uses crt; const nmax=100; tspe MyArray = array [ nmax] of integer; var A: MyArray; s, n, i, k: integer; Begin c l r s c r ; randomize; write(*Nhap n = ' ) ; readln(n); (Tao ngau nhien mang gom n so nguyen} for i:=l taa » Ati) := randoiti(300)randatiOOO); for i:=l to n write(A[i] :5); (in mang vua tao) writeln; write (^Nhap k = ^ ) ; readln(k); s:=0; for i:= to n if A[i] mod k = then s:= s+ A[i]; , writeln( "Tong can tinh la: \ s ) ; readln end Chu y: Ham chuan random(n) cho gia trj la sd nguyen ngiu nhien khoang tiif Ode'n n • 1, edn thutuera/7dor77/zekhditaocachesinhsdngiu nhien 2) Hay dua eae eau lenh sau diy vao nhifng vj tri can thie't nhim sda ddi chuang trinh cau 1)de cd dupe chupng trinh dua sdcac sdduong va sd cae sdam mang Phan tich no! dung kien thixc, hoat dpng day hoc bai tap va thuc hanh ve kieu mang posi, neg:integer; Nhirng kie'n thdc HS can dat duqc day hpe posi:= 0; neg:= 0; if A[i]>0 then posi:= posi -i- bai Bai tap vi thi/e hinh (Tin hoc 11, tr 63) ve kieu else if A[i] Save asde ghi chuong trinh sang mdt tep khac, vi du, vdi ten bt_1b.doc Tie'p dd, eic ciu lenh: (ki2-1/2014) Hoatddng cua GV:Den tdng miy cua HS, kiem tra viee chen doan chuang trinh, thuc hien chuang trinh cda cae em G V ed su hd trp can thie't Hoatddng ciia HS:Bqc lap lam viee, cd the thao luan nhdm Hoatddngcua GI/.-Chay chuong trinh len man chie'u, nhap sdphantucda mang, vidu:/7=/0thi ket qua cda chuong trinh s i nhu hinh Hinh Ket qua chuang trinh in so cac so duong, so cac so am mang A GVthuyittrinh:yd\ketquanhuahinh3,ngud\su dung nhieu rat khd nhin tha'y sdcac sdduong va sd eac sd i m Bdi vay, chung ta can dua vao lenh In ddng chu thich: writeln('So cac so duong la:", posi:4); writelnCSo cac so am la : ", neg:4); Hoatddng cda GV:Ch'\eu chuong trinh len, vda chen them hai cau lenh in ddng chu thich vda giai thich Tie'p theo, G V yeu cau HS thue hien viec chen Tap chi Gido due so 326 55 them hai ddng lenh in man hinh Khi dd, chuang trinh in sd cac sd duang va sd cic sd am mang A la: program Sumlb2; uses crt; const nmax=100; type Myarray= array [1 .Nmax] of integer; var A: MyArray; 11, i: integer; posi, neg: integer; Begin clrscr; randomize; write ("Nhap n='); readln(n); (Tao ngau nhien mang gcxn n so nguyen) for i:=l to A[i] :=random(300)random(300); for i:=l to n write (A[i] ;5); (in mang vua tao) writeln; posi:=0; neg:=0; for i:= to n if A[il>0 then posi:= posi + else if A[i]Ii>i; •IIMIIIft 4hap n= SS -249 54 186 41 -177 -131 -6B 47 2B3 224 -46 -134 -114 -38 -124 184 -186 72 -98 23 U -9 -146 -167 51 252 >o CIC so duong k : 24 So cac CO oil l a : 26 Bdi dirong nang lire giai toan (Tiep theo trang 53) ^M Tai lieu tham khao NguySn Tien Tai (chu bien) - NguySn Httu Hoan Giao trinh sd' hoc dao tao giao vi^n trung hoc co' sd NXB Gido dMC,H 1998 NguySn Vu Thanh So hoc, chuySn de b6i duong Hinh Ket qua chuang trinh in sdcac so duang, so cac chuySn toan NXB Cd Mau, 1993 so am mang A NguySn Van VTnh 23 chuySn di giai 1001 bai Hoatddngcua WS.'Kiem tra lai chuang trinh cua toan sa cap NXB Gido due Viet Nam, H 20II minh lan cudi, luu lai chuong trinh Hoatddng cua G K'G iai thich y nghTa eua eac cau SUMMARY lenh, qua irinh boat dpng eua ehupng trinh de HS Fostering capacity to arithmetic Is always the conhieu hPn rd muc dich cua BT dit cern of teachers' colleges, it Is more necessary than *** for training systems Secondary school teachers Therefore, in the process of teaching arithmetic if Jhdng qua day hpc phan bai tap va thuc hanh there is reasonable measures to build the capacity phan kieu mang mdt chieu, ngoai viec ren iuyen kT for solving arithmetic, the student will contribute to nang thue hanh tin hpc ndi ehung va kTning lap trinh improving the quality of teacher training in the curtren ngdn nguPaseal ndi rieng eho HS, ehung ta cdn rent period This article is brought out elements of arithmetic capacity to propose four measures and ren luyen va nang cao eho eac em kT ning ddc lap fostering this capacity efSclentiy and feasibility in phan tich BT, kT ning hie'u, sua, djch va thuc biin arithmetic teaching In pedagogical schools today -83 -141 52 H 68 293 -28 242 21 -141 -87 -166 -16 -212 -286 -43 75 13B 223 22 9! 28 -11 -233 56 Tap chi Gido due so 326 (ki2-1/2014) ... sdphantucda mang, vidu:/7=/0thi ket qua cda chuong trinh s i nhu hinh Hinh Ket qua chuang trinh in so cac so duong, so cac so am mang A GVthuyittrinh:yd\ketquanhuahinh3,ngud\su dung nhieu rat... Hoc tot tin lipc 11 NXB Bai hpc qudc gia TP Hd Chi Minh, 2007 Tran Doan Vinh "Ren luySn kT nang thuc hanh cho hoc sinh thOng qua day hpc "Bai tap va thirc hanh 1" a tin hoc 11" Tap chi Gido due,... 1998 NguySn Vu Thanh So hoc, chuySn de b6i duong Hinh Ket qua chuang trinh in sdcac so duang, so cac chuySn toan NXB Cd Mau, 1993 so am mang A NguySn Van VTnh 23 chuySn di giai 1001 bai Hoatddngcua