... T B NG T NG T l : 150 T L SCALE S B NV DRAWING No As indicated T NG S BN V DWG.TOTAL 110-2010/ KT-1-05 142 CN H AX3 AX4 AX5 AX6 AX7 AX8 CN H C3 CN H C3 CN H AX2 C2 CN H C2 CN H C1 CN ... B NG CH TIÊU DI N TÍCH XYD NG Di n tích khu ñ t 4298.1 m² KHO NG LÙI Di n tích xyd ng c ng trình Di n tích xanh AX1 AX2 AX3 AX4 AX5 AX6 AX7 T ng h m AX8 T ng cao 4400 RANH Đ T 9000 ... QU N LÝ K THU T TECHNICAL MANAGER KS NGUY N THÀNH HI U V DRAWN BY DDArchitects Co.,Ltd DDAchitects WC N PC P.NG C1 P.KHÁCH B I CN H P.Đ M 750 WC NAM H P.KHÁCH 58m2 W 4a < /b> P KINH DOANH P.KHÁCH C N...
... underline key words -Work individually - Speak aloud the new words and elicit their meaning - Guess what topic you will listen today - Work individually - Read all statements to understand and underline ... Grammar: should or shouldnt and conditional type II-Skill : - Writing and practicing skill B. PROCEDUCE: I-Settlement: - Greeting the class & checking students attendance II-Checking: - Talking ... their answers -Feedback and give correct answers: -Expected answer: 1.three- quarters 2.mysterious 3.modern 4.discoveries 5.biodiversity 6.huge 7.plants and animals 8.closely connected POST READING...
... 22 + = Du "=" xy x = y = Vy, minP = ữ + x xy II PHN T CHN Theo chng trỡnh chun C u VI .a:< /b> 1) C i xng vi A < /b> qua ng thng d ị C( 3; 1) B, D ẻ d AB = AD = ị B( 2; 1), D( 6; 5) ợ r r a < /b> ^ n r r r ... VS ABC = a < /b> ù 27 10 ù VS ABC SA SB 3 ị VS PQCD = VS PQC + VS PCD = a < /b> 27 VS.PCD SP 2 ù = = ị VS PCD = VS ACD = a < /b> ùV ợ S ACD SA C u V: Ta c : x > 0, y > 0, x + y = ị < xy Ê x + y P= ỗ y 22 ... 10 = ở ùcos (d , D) = ợ uuu r uuu r 2) Ly B ẻ (d1 ), C ẻ (d2 ) T : AB = k AC ị k = ị B l trung im ca on thng AC Ta c th tớnh c B( 2; 1; 1), C( 3; 4; 1) C u VII .b: Tim cn xi n (D) : y = x + m T...
... ca MB ã VMDPQ VMCNB = MD MP MQ 1 = = ị VDPQCNB = VMCNB MC MN MB 6 ã Vỡ D l trung im ca MC nnd ( M ,(CNB)) = 2d (D ,(CNB)) ị VMCNB = 2VDCNB = VDCSB = VS ABCD ị VDPQCNB = VSABNPQ 7 VS ABCD ... xy x = y = z = II PHN T CHN Theo chng trỡnh chun C u VI .a:< /b> 1) (C) c tõm I(1; 2), bn kớnh R = Vỡ cc tip tuyn AB, AC vuụng g cnn ABIC l hỡnh vuụng c cnh bng ị IA = Gi s A(< /b> x; x m) ẻ d IA2 ... phi c x1 , x1 , x2 (x1 , x1 l honh ca A,< /b> 2 B) ị x1 , x2 l cc nghim ca phng trỡnh: ( x - x1 )( x - x2 ) = x - x2 x - x1 x + x1 x2 = (2) ỡ x2 = ỡ x1 = ù 19 ù ù x2 = Kt lun: d: y = x1 = ù x x...
... hỡnh lp phng thnh hai a < /b> din: KMCAND v KBB C MAA DN t V1 = VKMCAND, V2 = VKBB C MAA DN ED.SD ADN = a3< /b> 7 29 EK EM EC a < /b> = = ị V1 = VKMCAND = VEAND = a3< /b> = a3< /b> , V2 = Vhlp V1 = 8 36 36 EA EN ... Theo chng trỡnh n ng cao C u VI .b: 1) V CH ^ AB, IK ^ AB AB = ị CH = 2SD ABC AB = ịIK = 1 Gi s I (a;< /b> 3a < /b> 8) ẻ d CH = a < /b> = Phng trỡnh AB: x - y - = d ( I , AB) = IK - a < /b> = ị I(2; 2) hoc I(1; ... Hng dn: I PHN CHUNG C u I: 2) Hai im c nh A(< /b> 1; 0), B( 1; 0) Ta c : y = x + mx ộ ờm = - 2 ãCc tip tuyn ti A < /b> v B vuụng g c vi y (1) .y (-1) = -1 (4 + 2m ) = ờm = - 2 y = - x - x ộ x =...
... suy ra: + + + + a+< /b> bb +c c +a < /b> a +7 b +7 c +7 ng thc xy v ch a < /b> = b = c = II PHN T CHN Theo chng trỡnh chun C u VI .a:< /b> 1) Gi A1< /b> , A2< /b> ln lt l im i xng ca A < /b> qua BBÂ, CCÂ ị A1< /b> , A2< /b> ẻ BC C u V: p dng bt ... Phng trỡnh ng thng d: y = -16 ùz = 32 ợ C u VII .a:< /b> Phn thc a < /b> = 88, phn o b = 59 Theo chng trỡnh n ng cao C u VI .b: 1) Chỳ ý: d1 ^ d2 v DABC vuụng cn ti A < /b> nnA < /b> c ch u d1 , d2 ị A < /b> l giao im ca ... + cb + cc + a < /b> a + b + 2c c + a < /b> a + b 2a+< /b> b+ c 2 Mt kh c: = 2a < /b> + b + c + - 4a < /b> - 2b - 2c 2a < /b> + b + c 2a < /b> + b2 + c + a < /b> + 2 (a < /b> - 1) + (b - 1) + (c - 1) 2 Tng t: ; 2b + c + a < /b> b + 2c + a < /b> + bc +...
... (A< /b> MCN) v (ABCD), P l trung im ca CD ị NP ^ (ABCD) SDMCN = S a2< /b> a2< /b> 6 , SDMCP = ị cos j = D MCP = 4 SDMCN xy z 1 + + = v xyz = x + y + z2 xy + yz + zx ị + + Ê yz xz xy xy z 1 ã Chỳ ý: Vi a,< /b> b ... + C2 nxn (1) 2n (1 - x )2 n = C2 n - C2 nx + C2 nx - C2 nx + C2 nx - + C2 nxn (2) (1 + x )2 n + (1 - x )2 n 2 2n Ly o hm v ta c: 2C2 nx + 4C2 nx + + nC2 nxn -1 = n ộ(1 + x )2 n ... C u IV: A< /b> MCN l hỡnh thoi ị MN ^ A< /b> C, DBÂMN cn ti B ị MN ^ B O ị MN ^ (A< /b> B C) ãV MAÂ BC 1 a < /b> a3 a3< /b> = MO.SD A< /b> BC = ịV ÂÂ = 2VMAÂ BC = a.< /b> a = BA < /b> MCN 3 2 ã Gi j l g c gia hai mt phng (A< /b> MCN)...
... Vi a,< /b> b > 0, ta c : Du "=" xy x = y = z = 1005 Vy MinP = 670 II PHN T CHN Theo chng trỡnh chun C u VI .a:< /b> 1) Gi s: AB: xy + = , AC: x + y 21 = Suy ra: A(< /b> 0; 3) BO ^ AC ị BO: x - y = ị B( 4; ... Hng dn: I PHN CHUNG x = C u I: 2) Phng trỡnh honh giao im ca d v (Cm): x + x + mx = (1) x + 3x + m = (2) ỡ ùm < (*) Khi ú: xD + xE = -3; xD xE = m ùm ợ (2) c nghim ph n bit, kh c ' ' yD ... AB = d (A,< /b> (P)) 2a < /b> - a < /b> + = a < /b> a < /b> = ị A(< /b> 3; 0; 0) 3 C u VII .a:< /b> Gi s s tho l: a1< /b> a2 a3< /b> a4 a5< /b> ị B Trn S Tựng a+< /b> 3 ã Nu a1< /b> = thỡ c : A7< /b> = 840 (s) 3 ã Nu a2< /b> = thỡ c : C6 A6< /b> = 720 (s) ã Nu a3< /b> = thỡ c :...
... SDB 6 2c + a < /b> V a < /b> a2 bc AD a < /b> M ASDB = ị VASDB = VCSDB = = VCSDB DC 2c 2c 12 2c + a < /b> ổ a2< /b> bc + abc2 abc Vy: VSABC = VASDB + VCSDB = ỗ ữ= 12 ố 2c + a < /b> ứ 12 C u V: t a < /b> = log2 x , b = log2 y , c ... + a)< /b> 2 = a2< /b> c + a2< /b> c - a2< /b> c ( 2c + a)< /b> 2 = 3a < /b> c ( 2c + a)< /b> 2 ị SD = ac 2c + a < /b> abc uuu uur r ã = SD.SB = 2c + a < /b> = ị sin ã = Mt kh c, cos SDB SDB SD.SB ac 3 b 2c + a < /b> 1 abc VSDBC = SC.SSDB = SC.SD.SB.sin ... D cho: DS ^ SC (D thuc on AC) ị ã = 30 ASD uur uur uuu r uuu 2cSA + aSC r a < /b> uuur AD S ASD AS.SD.sin 30 a < /b> Ta c : ị DA = DC ị SD = = = = 2c 2c + a < /b> CD SCSD 2c CS.SD uur uur uuu uur ổ 2cSA + aSC...
... - y )2 dy = -1 117p C u IV: Gi N = BM ầ AC ị N l trng tõm ca DABD K NK // SA (K ẻ SC) K KI // SO (I ẻ AC) ị KI ^ (ABCD) Vy VK BCDM = KI SBCDM KI CK CK CN = (1), DKNC ~ DSAC ị = (2) SO CS CS CA ... KI CN CO + ON CO + CO 2 a < /b> T (1) v (2) ị = = = = ị KI = SO = SO CA 2CO 2CO 3 a < /b> 3 Ta c : DADC u ị CM ^ AD v CM = ị SBCDM = ( DM + BC ).CM = a < /b> 2 Ta c : DSOC ~ DKIC ị Trn S Tựng a3< /b> KI SBCDM = x 3x2 ... v ng cnh l: 2.5! (s) ị S cc s tho y u cu bi to n l: 6! 2.5! = 480 (s) Theo chng trỡnh n ng cao C u VI .b: 1) Ta cA < /b> = AD ầ AM ị A(< /b> 9; 2) Gi C l im i xng ca C qua AD ị C ẻ AB x -9 y+ 2 = x...
... = C1 0 + 2C1 0 = 672 Theo chng trỡnh n ng cao C u VI .b: 1) (C) c tõm I(3; 4) ỡ AB = AC ã Ta c : ị AI l ng trung trc ca BC DABC vuụng cn ti A < /b> nn AI cng l ph n gi c ca ã BAC ợIB = IC Do ú AB ... x + cos x )3 (sin x + cos x ) dx = dx p 12 2ũ 2ổ pử cos ỗ x - ữ ố 4ứ dx p ổ pử2 = tan ỗ x - ữ = Vy: I = ố ứ0 1 a < /b> a2 a3< /b> C u IV: Vỡ ABB A< /b> l hỡnh b nh hnh nn ta c : VC ABB ' = VC AB ' A < /b> ' ... b ị x + (2 - y) 2 + x + ( y + 2)2 x + 16 = x + r r Suy ra: P x + + x - Du "=" xy a,< /b> bc ng hng hay y = Mt kh c, ỏp dng BT Bunhiacụpxki ta c : ( + x ) Ê (3 + 1)(4 + x ) ị x + + x Du "=" xy...
... cos2 x. dx = A < /b> B p x. dx = ũ cos4 x. cos x dx = x. dx = Vy I = p p 2 ũ (1 - sin x ) d (sin x ) = 15 p p ũ (1 + cos x ).dx = 20 p 15 C u IV: Gi E l trung im ca AB ị BC = a < /b> Trong tam gi c BIC, k ng ... ng cao IF, ta c : IF = Ta c : SBIC = S ABCD - SABI - SCDI 2SBIC BC = 3a < /b> 3a < /b> T gi thit ị SI ^ (ABCD) ị ã = 60 ị SI = IF.tan 60 = SFI ị Th tớch chúp S.ABCD: Trn S Tựng 1 3a < /b> 15 V = SI SABCD = 3a < /b> ... Hng dn: I PHN CHUNG C u I: 2) Gi ( x0 ; y0 ) l to ca tip im Tam gi c OAB cn ti O nn tip tuyn song song vi mt hai ng thng y = x hoc y = - x ị y ( x0 ) = -1 ộ x = -1 ( y0 = 1) = ị (2 x0 ...
... lun: < m < 10 C u IV: Gi O l giao im AC v BD ị SO ^ ( ABCD ) Ta c : SO = S ABCD = a < /b> ị VS ABCD = SA2 - OA2 = a < /b> - 2a < /b> a = a < /b> Gi M, N l trung im AB v CD v I l tõm ng tr n ni tip tam gi c SMN Ta chng ... chng minh I c ch u cc mt ca hỡnh chúp 2a < /b> 2 S DSMN = pr ị r = 4 (a < /b> + a < /b> 3) C u V: t t = xy Ta c : xy + = V xy + = = a < /b> ( - 1) (( x + y ) (( x - y ) 2 ) - xy -4 xy ị xy - ) + xy xy ị xy Ê ( x ... Hng dn: I PHN CHUNG ( ( ) )( ) C u I: 2) PTTT D ca (C) ti im M0 x0 ; y0 l D : y = x - x0 + x - x0 + x0 - x0 + xD qua O x0 = 0, x0 = ị Cc tip tuyn cn tỡm: y = x , y = C u II: 1) PT ( sin x...
... giao im ca PT vi AD TD DD ' = = TC MC TD AP QD DP CP = = ị AT P DP ị = = = M: TC AC QA AT CA VA.PQN AP AQ 1 N n: = = = ị VA.PQN = VABCD VA.CDN AC AD 5 10 V DDÂ // BC, ta c : DDÂ=BM ị V: VC ... VC PMN CP CM 1 = = = ị VABMNP = VABCD VC ABN CA CB 4 (1) (2) V 20 ABCD 13 Kt lun: T s th tớch cn tỡm l hoc 13 C u V: p dng BT C -si ta c : 18 x + 12 (1) Du bng xy x = x 2 Tng t: 1 8y + ... ứ y" = x = ( m - ) 5m ( m - ) ổ - m ử3 im un U nm tr n th hm s y = x thỡ + =ỗ ữ m=5 27 ố ứ C u VII .b: Ta c : AB = BC = CA = ị DABC u Do ú tõm I ca ng tr n ngoi tip DABC l trng tõm 3 ca n ...
... x DC In / x Relay Analog modules Input x Analog In x AC In 16 x DC In x Relays x AC Out x Relay x DC In / x DC Out x DC In / x Relay 16 x DC In / 16 x DC Out 16 x DC In / 16 x Relay x Thermocouple ... product can only function correctly and safely if it is transported, stored, set up, and installed correctly, and operated and maintained as recommended Trademarks SIMATIC!, SIMATIC HMI! and SIMATIC ... related equipment Install and operate all equipment according to all applicable national and local standards Contact your local authorities to determine which codes and standards apply to your...
... ^ ( A < /b> ' BC ) ị AH = 1 a < /b> = + ị AA ' = Mt kh c: 2 AH A'< /b> A < /b> AM 3a < /b> Kt lun: VABC A < /b> ' B ' C ' = 16 a2< /b> ab ab C u V: Ta c : =aa=aab (1) a < /b> +b a+< /b> b 2 ab b2 c2 bbc (2), cca (3) b+ cc +a < /b> a2 b2 c2 Cng (1), ... 16 x - 36 > x < -18 hay < x 2 So sỏnh vi iu kin Kt lun: Nghim ca BPT l < x < ỡ ỡu = ln x ùdu = dx 2) t Suy : I = ũ ln x dx = x ln x - ũ 2dx = x ln x - x + C ịớ x ợdv = dx ùv = x ợ xyC u ... (3), ta c : + + + ab + bc + ca a < /b> + b + ca < /b> +b b +c c +a < /b> Tng t: ( II PHN T CHN Theo chng trỡnh chun Trn S Tựng ) C u VI .a:< /b> 1) iu kin: < x < ( ) BPT log 2 x + x > log ( - x ) x + x > ( - x ) x +...
... i tuyn c Ngụ Thu Thu, khụng c V Mnh Cng S c ch chn nam khụng c V Mnh Cng l C6 S c ch chn ncn li l C9 Suy s c ch chn trng hp ny l C6 C9 = 540 (c ch) Vy s c ch chn i tuyn b ng bn Quc gia l: ... - yB ) v xB - yB - = ( ) uuu r ( H l trc tõm ca tam gi c ABC nn CH ^ AB ; CH = -5 + xB ; yB , AB = xB + 3; yB - uuur uuu r x - y = x = x = ù CH AB = BBBB ù( xB - 5)( xB + ) + ( yB ... trung im ca AC nnC ỗ ; ữ ố3 3ứ Vỡ BC i qua C v song song vi dnn BC c phng trỡnh: y = x +2 x + y + = ù ỡ x = -4 BH ầ BC = B : ớ ị B ( -4;1) xy = +2 y = ù ợ 2) Do ABCD l hỡnh thang cn nờn...
... 2 (a < /b> + b + c ) + 4(ab + bc + ca) - 8abc ị ab + bc + ca Ê + 9abc ị ab + bc + ca - 2abc Ê + abc 1+ 27 = Mt kh ca < /b> + b + c 3 abc ị abc Ê Do ú: ab + bc + ca - abc Ê 27 27 Du "=" xy a < /b> = b = c = ... (BDMN) Gi H l giao ca PQ v AC Suy AH l ng cao ca hỡnh chúp A.< /b> BDMN Tớnh c AH = PQ = 3a < /b> a 15 a < /b> 3a2< /b> 15 , MN = ị SBDMN = Suy ra: VA.BDMN = S BDMN AH = 16 16 C u V: ãC ch 1: Ta c ab + bc + ca ... 2) Ta c : AB = (2; 2; -2), AC = (0; 2; 2) Suy phng trỡnh mt phng trung trc ca AB, AC l: x + y - z - = 0, y + z - = uuu uuur r r Vect phỏp tuyn ca mp(ABC) l n = ộ AB, AC ự = (8; -4; 4) Suy (ABC):...
... gi c ABD, BCD, SBD l cc tam gi ccn bng v cy BD chung nn OA = OC = OS Do ú DASC vuụng ti S 1 Ta c : VS ABCD = 2VS ABC = BO.SA.SC = ax AB2 - OA2 = ax a2< /b> Do ú: VS ABCD = a2< /b> + x = ax 3a2< /b> - x ... x ) = ũ f ( x )dx = ũ ln( x + 1 )d ( x + 1) + ũ xdx - ũ d ln( x + 1) 2 1 = ln ( x + 1) + x - ln( x + 1) + C 2 C u IV: Do B v Dc ch u S, A,< /b> Cnn BD ^ (SAC) Gi O l tõm ca y ABCD Cc tam gi c ... trỡnh mt phng (SMN): nx + my + mnz - mn = n + m - mn - m .n - mn Ta c : d (A,< /b> (SMN)) = = = =1 n - mn + m + m2 n2 - 2mn + m n (d) ct (C ) ti im ph n bit A,< /b> Bd ( I , d ) < R Suy (SMN) tip xc mt cu...