chuyên đề giải toán hình học lớp 5

Ngày tải lên: 26/10/2012, 14:26

Ngày tải lên: 13/12/2013, 13:20

... THAM KHẢO: CÁC BÀI TOÁN CỰC TRỊ CỦA HÌNH HỌC GIẢI TÍCH TRONG KHÔNG GIAN Ý tưởng cho các bài toán tìm GTLN ,GTNN nói chung cũng như các bài toán GTLN ,GTNN của hình học giải tích trong không ... BÀI TOÁN CỰC TRỊ (tham khảo thêm) H À N Ộ I 2 / 2 0 1 3 4 B. CÁC DẠNG TOÁN VÀ PHƯƠNG PHÁP GIẢI I. BÀI TOÁN 1: BÀI TOÁN TÌM ðIỂM CÁC BÀI TOÁN MẪU Trước khi làm các bài tập trong Chuyên ... c = = ⇒ = và 15 d = − ⇒ mp (P): 4 2 7 15 0 x y z + + − = +) Với 0 b = chọn 2 3 a c = ⇒ = và 5 d = − ⇒ mp (P): 2 3 5 0 x z + − = Chú ý: Với số liệu ñặc biệt của bài toán trên các...

Ngày tải lên: 13/01/2014, 17:16

... hình chóp đều 1. Hình chóp tam giác đều S. ABC Dấu hiệu: Đáy là tam giác đều cạnh a, đường cao vuông góc với đáy từ đó ta thiết lập hệ tọa độ như sau Cách chọn: Chọn hệ trục tọa độ như hình ... Oxy    4. Đáy là hình vuông ABCD (thiết lập tương tự như hình thoi hoặc hình chữ nhật) Bài tập giải mẫu: Bài 1: (ĐH – D 2007) Cho hình chóp S.ABCD có đáy là hình thang   0 90 ABC ... tại B có: 2 2 2 2 2 2 4 5 5 AC AB BC a a a AC a        Dựng ( ), BH AC H AC   ta có: 2 2 5 5 AB a a AH AC a    2 2 2 2 1 1 1 5 4 BH AB BC a    2 5 a BH  Dựng hệ trục tọa...

Ngày tải lên: 29/04/2014, 08:38

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...

Ngày tải lên: 26/06/2014, 23:20

Ngày tải lên: 27/07/2014, 16:32

... vectơ : =[ n JJG a J JG NB J JJG , ] = (− 15; −11; 17) Phöông trình (P) laø: − 15( x–1) – 11(y+2) + 17(z+1) = 0 ⇔ 15x + 11y – 17z – 10 = 0 b) A( 5, 0, 5) ; B (12, 0, 10) ⇒ = (0, −10, 0) OA,OB ⎡ ⎣ JJJG ... Vấn đề 5 KHOẢNG CÁCH Bài toán 1 : Tính khoảng cách từ điểm M(x 0 , y 0 , z 0 ) đến mặt phẳng α : Ax + By + Cz + D = 0 ắ Phương pháp : dM Ax By Cz D ABC (,)α= +++ ++ 000 222 Bài toán ... và song song với (D). Khi đó (Δ) chính là giao tuyến của α và β. Vấn đề 3 HÌNH CHIẾU Bài toán 1 : Tìm hình chiếu vuông góc H của điểm A treõn ủửụứng thaỳng (d) ắ Phửụng phaựp : ...

Ngày tải lên: 08/08/2014, 09:22

... =1 c) ABCE laø hình thang có đáy AB và E nằm trên Ox. ⇔ E y = 0 CE ⎧ ⎪ ⎨ ΑΒ ⎪ ⎩ JJJG JJJG // ⇔ E EE y = 0 x - 4 y - 2 = 0 - 2 3 + 1 ⎧ ⎪ ⎨ ⎪ ⎩ ⇔ hay E (5, 0) E E y = 0 x = 5 ⎧ ⎨ ⎩ d) H ... điểm E để ABCE là hình thang có một cạnh đáy là AB và E nằm trên Ox. d) Tìm tọa độ trực tâm H, trọng tâm G và tâm I đường tròn ngoại tiếp ABC. Δ e) Chứng tỏ H, G, I thẳng hàng. Giải a) D là điểm ... ⇔ BABA CACA x - x y - y x - x y - y = 0 . Với việc tìm góc của hai vectơ ta có: - Góc hình học tạo bởi hai vectơ a G , b G được suy từ công thức: cos( n a, b G G ) = 11 22 ab + ab a.b G G ...

Ngày tải lên: 08/08/2014, 09:22

Ngày tải lên: 08/08/2014, 09:22

Ngày tải lên: 08/08/2014, 09:22

Ngày tải lên: 08/08/2014, 09:22

Ngày tải lên: 07/11/2014, 22:50

Ngày tải lên: 23/12/2013, 16:58

Ngày tải lên: 14/08/2014, 09:52

Ngày tải lên: 21/08/2014, 14:27

Ngày tải lên: 29/10/2014, 19:28

... diện (P) cần tìm. VẤN ĐỀ 7: GIẢI BÀI TOÁN HÌNH HỌC KHÔNG GIAN BẰNG PHƯƠNG PHÁP TỌA ĐỘ TRONG KHÔNG GIAN Việc sử dụng phương pháp tọa độ trong không gian giải các bài toán hình học không gian là một ... (d’) VẤN ĐỀ 3: HÌNH CHIẾU 1. Tìm hình chiếu vuông góc của 1 điểm M trờn mt mt phng )( ã Vit phng trỡnh ng thng d i qua M v vuụng gúc vi )( ã Gi H là hình chiếu của M trên )( α )( α ∩=⇒ dH 8 Chuyên ... trên SA ứng với trục Oz.  Với hình chóp có đáy là hình thoi tâm O ta thường thiết lập hệ trục tọa độ dựa trên AC và BD ứng với trục Ox và trục Oy. 12 Chuyên đề: Phương pháp tọa độ trong không...

Ngày tải lên: 17/08/2013, 08:07

... c. Lớp 12 chuyên Lý - Năm học 2011-2012 - Sĩ số : 35 học sinh. - Giáo viên dạy : Thầy giáo Nguyễn Hoàng Cương - Học sinh trong lớp có trình độ học tập môn Toán tương đối đồng đều. Đa số học ... a. Lớp 10A2 - Năm học 2011-2012 - Sĩ số : 45 học sinh. - Giáo viên dạy : Cô giáo Nguyễn Phương Hạnh - Học sinh trong lớp có trình độ học tập môn Toán tương đối đồng đều. Đa số học sinh đều ... 2.2.3.2. Một số bài toán hình học phẳng giải bằng phương pháp vectơ và tọa độ *) Dạng 1: bài toán hình giải tích thuần tuý (chứa đựng sẳn các yếu tố về hình giải tích) Bài toán 1 a. Công thức...

Ngày tải lên: 09/02/2014, 14:58

...    BD là phân giác góc   . 8 .5.      III. CÁC BỔ ĐỀ VỀ ĐƯỜNG TRÒN 1.  ...           ABOC là hình vuông        . ...                     5.   ...

Ngày tải lên: 23/06/2014, 22:38