... Trang 3BÀI TẬP ƠN TẬPHÌNHHỌC CUỐI CHƯƠNG I LỚP10NÂNG CAO Câu 15 : Cho ar= (1 ; 2) và br= (3 ; 4). Vec tơ mur= 2ar+3br có toạ độ là a) mur=( 10 ; 12 ) b) mur=( 11 ; 16 ) c) ... uuur. Bài 2 :Cho bốn điểm A, B, C, D. Gọi I, J lần lượt là trung điểm của AB và CD.GV : TRẦN THANH HỒNG – THPT NGUYỄN TRÂN Trang 2BÀI TẬP ÔN TẬPHÌNHHỌC CUỐI CHƯƠNG I LỚP10NÂNG CAO b) Tam ... BÀITẬP ÔN TẬPHÌNHHỌC CUỐI CHƯƠNG I LỚP10NÂNG CAO a) Chứng minh: AC BD AD BC IJ2+ = + =uuur uuur uuur uuur uur.b)...
... BÀITẬP HÓA LỚP10CHƯƠNG 4 NÂNGCAO Bài 1. cân bằng các phản ứng hóa học sau bằng phương pháp thăng bằng electron , cho biết chất ... NaNO3 + NaOH → NH3 + NaAlO2 +………. Bài 6. cho 12 ,6g hỗn hợp Mg và Al theo tỉ lệ mol 3:2 tác dụng với dung dịch axit H2SO4 đặc , nóng vừa đủ thu được 0 ,15 mol sản phẩm có lưu huỳnh . XÁc ... Cu(NO3)2 + H2SO4 + N2O + H2Ol) FeSO4 + Cl2 + H2SO4 → Fe2(SO4)3 + HCl Bài 3. cân bằng các phản ứng oxi hóa khử sau dưới dạng phân tử và ion thu gọn , chỉ rõ chất oxi...
... có:BC2=DB2+CD2=(BO+OD)2+CD2==BO2+2.OB.OD+OD2+CD2. (1) Mà OB=R.∆AOC cân ở O có OAC=30o. Hình 20CIKJFIAK= MỘT TRĂM BÀITẬPHÌNHHỌCLỚP 9. Phần 1: 50 bàitập cơ bản. 1 -Xét hai ∆EKO và EHO.Do ... AC=CB=90o.Ta lại có: Hình 19 2 Lời nói đầu:Trong quá trình ôn thi tốt nghiệp cho học sinh lớp 9,chúng ta đều nhận thấy học sinh rất ngại chứng minh hình học. Cũng do học sinh còn yếu kiến ... NQ//PM⇒MNQP là hình thang có PN=MQ⇒MNQP là thang cân.Dễ dàng C/m thang cân nội tiếp.TÍnh SMNQP=SMIP+SMNI+SNIQ+SPIQ=2 1 SAMIP+2 1 SMDNI+2 1 SNIQC+2 1 SPIQB=2 1 SABCD=2 1 a2.5/C/m...
... BÀI TẬP10 0 ) Tính giá trị biểu thức A = Cos 200 + cos 800+ cos 10 0 0+ cos1600 101 ) Tính giá trị biểu thức: 00 300 450 600 900 Sin 0 2 1 22 23 1 Cos 1 ... 22 2 1 0 tan 0 33 1 3 Cot 3 1 33 0 CHUN ĐỀ BÀITẬPHÌNHHỌCLỚP10 ( có sử dụng tài liệu từ các nguồn khác). BIÊN SOẠN : TRẦN MAI SANG 2 I - CÁC BÀITẬP LIÊN ... 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913 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ĐỀ BÀITẬPHÌNHHỌCLỚP10 ( có sử dụng tài liệu từ các nguồn khác). BIÊN SOẠN : TRẦN MAI SANG 7 BÀI TẬP 69)...
... LƯỢNG VIỆC ÔN TẬP TỔNG KẾT MÔN HÓA HỌC LỚP 10CHƯƠNG TRÌNH NÂNGCAO Ở TRƯỜNG TRUNG HỌC PHỔ THÔNG Chuyên ngành: Lý luận và phương pháp dạy học môn Hóa học Mã số : 60 .14 .10 ... (20%) 19 (47,5%) 9 (22,5%) 4 (10 % ) Thí nghiệm do HS tự làm 6 (15 %) 19 (47,5%) 12 (30%) 3 (7,5%) Phim thí nghiệm hóa học 4 (10 % ) 13 (32,5%) 7 (17 ,5%) 16 (40%) Đồ dùng dạy học trực quan (hình ... xác, khoa học trong công việc. 2 .1. 3. Cấu trúc và nội dung Bảng 2 .1. Cấu trúc và nội dung chương 5, 6,7 SGK hóa họclớp10 chương trình nângcao CHƯƠNG 5: NHÓM HALOGEN 13 tiết:...
... tượng. 1. 5. Nội dung, PPDH phần hóa học ñại cương lớp10 (chương trình nâng cao) 1. 5 .1. Chương 1: “Nguyên tử” 1. 5 .1. 1. Vị trí Chương “Nguyên tử” là chương ñầu tiên trong sách giáo khoa Hóa học ... hợp với nó, nhằm nângcao ñời sống của mình mà vẫn bảo vệ ñược môi trường. 1. 5 .1. 3. Cấu trúc nội dung chương Hình 1. 2. Sơ ñồ cấu trúc chương 1- Hóa học1 0 (chương trình nâng cao) Có thể phân ... Dreamwear 25 1. 4.2. Phần mềm MS Access 2000 26 1. 4.3. Phần mềm Visual Studio .NET 26 1. 5. Nội dung, PPDH phần hóa học ñại cương lớp10 (chương trình nâng cao) 28 1. 5 .1. Chương 1: “Nguyên...
... mà C 1 + B2 + BMC = 18 00 => I 1 + I2 + BMC = 18 00 hay PIQ + PMQ = 18 00 mà đây là hai góc đối => tứ giác PMQI nội tiếp => Q 1 = I 1 mà I 1 = C 1 => Q 1 = C 1 => ... C 1 ( nội tiếp cùng chắn cung IM). Mà B 1 = C 1 ( = 1/ 2 sđ ẳBM) => I 1 = H 1 (2).Từ (1) và (2) => MKI MIH => MI MKMH MI= => MI2 = MH.MK4. Theo trên ta có I 1 = C 1 ; ... 1 2HM.JK ; SHAC = 1 2HC.AC 1 ⇒ SHAC : S HJM = 1 HC.ACHM.JK mà MH 1 MC 3=⇒HC HM+MC MC 11 3 4HM HM HM= = + = + =; 1 AC2JK=(JK// AC 1 ⇒ SHAC : S HJM = 8 Bài 75: Cho điểm...