bai tap vat ly hay lop 9

... Pmax = 400W. ZC GSTT GROUP | 17 Bên giản đồ véc tơ, ta có: 22y 90 30 5 60V x = 90 – y = 30V 2 2 2 2U 90 x 90 30 60 2V Lưu ý: Nếu cần tính UR khi đó thì ta có: RU v 2.x.y 2.60.30 ... Z 12 9 21 Hệ số công suất của đoạn mạch AM 1AMR 2 3 2cosZ21 7 Câu 30: Tương tự trên, có thể giả sử: Z = 40Ω, ZL = 41Ω. Khi đó: 22CZ 41 40 9 C L CR 2.Z . Z Z 2 .9. 41 9 24 ... 22L3UI 3(A)R 9Z 2222LLL2222LLR 9ZR 9Z13 R 3ZRZ33 R Z      Khi roto quay với tốc độ 2n (vòng/phút) thì L1 L2RZ 2Z3 Chú ý: Khi thay đổi tốc độ...

... 212.B. 674.C. 733.D. 132.HD: Chọn C 733/cos 9 73)(3;31/ 9 1 9 1 9& apos;'coscos; 9 1' ;9& apos ;9 22212ZRRZZRZRZRZRCLZZZZZZZZZZZZZZCLCLCLCLCLLCLCLCCCLLCâu ... là00C? Lấy nhiệt dung riêng của nước C=4200J/(kg.K).A. 4 ,95 .105kg.B. 1 ,95 .105kg.C. 3 ,95 .105kg.D. 2 ,95 .105kg.ChọnA.-Dựavàoptthấy1hạtLitổnghợpraHetỏanănglượng15,1MeV.-Trong1gLicóN=8,604.1022hạtnhân.-Nănglượngtỏarakhitổnghợphết1gLilà:W=15,1.8,604.1022.1,6.10-13=2,078.1011J.-Nănglượngtrêncóthểđunsôi ... Wm 494 951, 292 5 kgc 100 0 Câu 141:Choprôtôncóđộngnăng2,5PK MeVbắnpháhạtnhân73Liđứngyên.Biết1,0073pm u,7,0142Lim u,4,0015Xm u,21 93 1,5 /u...

... cm có phương trình dao động tổng hợp là x = 9cos(ωt + φ). Để biên độ A2 có giá trị cực đại thì A1 có giá trị: A. 183cm B. 7cm C. 153cm D. 9 3Christmas Câu 2: Một vật dao động điều ... nhiêu lần URmax? A. 38 B. 83 C. 423 D. 342 Câu 9: Cho mạch điện xoay chiều như hình vẽ. Điện dung C có giá trị thay đổi được và cuộn dây thuần cảm. Điều chỉnh giá trị của C thì ... thẳng đều với vận tốc vmax ở trên. Xét CLLX có vật m (vận tốc cực đại không thay đổi): GSTT GROUP | 29     ...

... thị: X là đại lượng g Vậy : g= 9, 869m/s2 22 2=Xππ X= 1 L R = 0 12 2=Xπ X= 9. 8 696 04401 L R = 0 GV:Đoàn Văn Lượng - ĐT: 091 5718188 - 090 6848238 Trang 16 Email: doanvluong@yahoo.com ... quả là: 447,213 59 ∠∠∠∠ - 63, 43 49 . Bấm : 4 (bấm chia 4 : xem bên dưới) + Bước 3: Tìm ZNB :NBNBuZi= . Nhập máy : 4 kết quả: 447, 213 59 63, 43 49 4∠−= 50-100i ... ra: 224=lgTπ Thế số: 2224. .12= =gππ = 9, 869m/s2 Vậy gia tốc trọng trường tại nơi có con lắc đơn dao động g = = 9, 869m/s2 -Với máy FX570ES: Bấm: MODE 1 Ta có :...

... 233 .99 04T h = 2 29. 9737, a = 4.0015.1u = 1.66.10−27 = 93 1, 5MeV/C2A. 5, 27m B. 2, 37m C. 1, 27m D. 1, 07mHướng DẫnK1+ K2= 14, 15882 29, 97 37.K1− 4, 0015.K2= 0=⇒ KHe= 13, 92 MEV ... 102dB B. 107dB C. 98 dB D. 89dBHướng DẫnCứ 1m giảm5100vậy còn 95 P100Sau 6 m còn lại là ( 95 100)6P I =P4π.d2 L = 10.lgP0(0, 96 )24π.d2.I0= 102dB1 49 Hai điểm A, B cùng ... atp=a2tt+ a2ht=0, 12+ 0, 098 92= 0, 14 94 Một con lắc đơn có chiều dài 0, 99 2m, quả cầu nhỏ 25(g). Cho nó dao động tại nơi có giatốc trọng trường 9, 8m/s2 với biên độ góc 40, trong...

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... nêncó tách hay chập không tác dụng gì đến dòng ⇒ Mạng mớitương đương với mạng đã cho; ta có mạch điện có dạng như hình (b)- RCD = 32R- RADCB = 32R + 2R = 38R. 9 Trường THPT ... )S dC Ck d x d xεπ= =− −+ Năng lượng: 112 2/2 2/2 2q q xWC dC= =; 22/2 9 2qWC=; 332 2/2 2/( )2 2q q d xWC dC−= = +Tổng năng lượng của hệ lúc sau : ... chạy C đến vị trí mà RBC = 1Ω thì đèn tối nhất. Tính điện trở toàn phần biến trở RAB. b) Thay RAB = 12Ω rồi di chuyển con chạy C đến giữa (trung điểm AB) rồi đóng K. Tìm số chỉ của ampe...

... )a L h m⇒ = − = − =Vì v1 = 3v2 => S1 = 3S2 hay a + x = 2 2h x+2 2 2 2 2 2( ) 9( ) 8 2ax+9h 0a x h x x a⇔ + = + ⇔ − − = thay s vào ta có:ố8x2-10015-6.502 = 0 ph ng trình ... ộ ớ ờnên 12vr vuông góc v i ớ23vr. do đó: v13 = 2 22 212 2310 5 5 51, 24( / ) 9 9 9 v v m s   + = + = =      Bài I. 13: M t gi t m a r i đ c 100m trong giây cu ... đi đ c trong giây th 5 là:ả ườ ậ ượ ứ 2 25 5 4 0 0 01 1 9 5 .5 (4 .4 )2 2 2s s s v a v a v a= − = + − + = +V => a =5 02( ) 9 s v− =V0,2m/s2 . Qu ng đ ngả ườ v t đi đ c sau 10s là:...

... 199 9-ĐHSPTN), Đào Quang Thành - Tích cực hoá hoạt động học tập vật lý của học sinh PTTH miền núi trên cơ sở tổ chức, định hướng, rèn kỹ năng giải bài tập vật lý( luận văn thạc sĩ - Năm 199 7-ĐHSPTN), ... Hiện nay toàn bộ cấp THPT đã hoàn thành việc thay sách giáo khoa, sách giáo khoa mới có nội dung bài tập và cách thức kiểm tra, đánh giá HS có nhiều thay đổi. Vì thế GV gặp không ít khó khăn trong ... trạng dạy học vật lý, bài tập vật lý ở trƣờng trung học phổ thông miền núi hiện nay 39 1.3.1. Bài tập vật lý 39 1.3.2. Thực trạng dạy học vật lý và BTVL ở các trƣờng THPT miền núi 45 Số hóa...

... 199 9-ĐHSPTN), Đào Qu ang Th ành - Tích cực hoá hoạt động học tập vật lý của học sinh PTTH miền núi trên cơ sở tổ chức, định hướng, rèn kỹ năng giải bài tập vật lý( luận văn thạc sĩ - Năm 199 7-ĐHSPTN), ... v ật lý , bài tập v ật lý ở trƣờng trung h ọc ph ổ th ông m iền núi hi ện n ay 39 1.3.1. B ài tập v ật lý 39 1 .3 .2 . T h ự c t r ạ n g d ạ y h ọ c v ậ t l ý v à B T VL ở c á c t r ƣ ờ n ... K ết qu ả củ a các l ần ki ểm tra 138 KẾT LUẬ N CH ƢƠNG III 148 KẾT LUẬ N CH UNG 1 49 KẾT LUẬ N CH UNG 1 49 TÀ I LIỆU THA M KHẢ O 151 Phụ lụ c 1: PH IẾU PH ỎNG VẤ N GV VẬT L Ý 154 Phụ lụ c...