[r]
(1)TRTJONG MARIE CIjzuE Hd NOi, ngdy 17 th6ng ndm2012
Dt THI TUYfN srNH L6? 6 NAM HQC 2012-2013 MON TOAN
Thdi gian ldm bdi 90 Phirt
Cirr I (J didm ):
a) Tinh g;i t i
"ac bi6u thirc sau bdng c6ch hqp lli:
A: 0,36x350+ 1,2x20x3+9x4x4,5 ;
": #i##
b) Trung binh cQng cira ba s6 ld SO thf nhAt nho hon t6ng cua trai sO la
15 56 thri hal uang m6inua s6 thri ba Tim m6i s6' CAu2 (2di€m):
B4n Mai doc mQt cu6n s6ch tlong ngdy Ngdy dAu dqc ]
'O fung cira cu6n
s6ch vd th€m trang Ngiry thu hai Aoc
I so trang cita cudn s6ch vir th6m 4 trang
Tlnh xem cu6n s6ch ddy bao nhi6u trang, bi6t rang sd trang ngdy thu ba Mai dgc
cluoc chi Uine I s5 t,'ang Mai doc ngiry cliu
4-CAu3(2di€m): .! :
MOt phons hqp x6p dugc nhi6u ntrAt ta t S .b0 ben gh6' CO hai lo4i bdn gh6: io4i tn,,i
"r,a1 rigoi [uq" +
nguoi vd loai thiL hai ng6i dugc ngudi D6 c6 83 nguoi du hqp thi ph6i xtlgbao nhrcu bQ rn6i to4i? (ccich xdp phai ddm bdo cilng c6 ch6 ng6i vd kh6ng c6 ch6 n.do
tr6ng)-CAu4(3di2m).
Cho hinh thang ABCD c6 c16y AB = 2cm, ddy CD g6p d6i d6y AB vd diQn tich
Ua"g f S.;r 11eo aii d6y AB ue pniu B m6t do4n BE cho BE edp ba len AB fVOi n v6i C vd ndi C v6i E
a) Tinh chidu cao cia hinh thang ABCD
b) Tinh tli s6 c6c chi6u cao h4 tt E vd til D xudng AC cua tam gi6c ACE vd tam gi6c ACD
c) Ggi O 1d di6m chinh giira cira AC N6i E voi O cit BC t4i M Tinh ti s6 dien
tich c0a hai tarn gi:ic OMC vd ACE'
Ciu 5 (Kh6ng b,it buqc, ndu ldm dung sd th€ml di€m vt'rq't khung)
C6 th6 ch<2n 71 s6 c6c sd tr,r nhi6n til I cl6n 100 cho tdng cua chfng
bang t0ng c6c s5 cdn l4i kh6ng?
TUYTN SINH LdP 6 NAM HOC2012-2013
HUoNG uAN cnAm vroiv roAN
C6Lu I G didm)
a) (l,7sd).
A: 0,36 x 350 + 3,6 x 20 + 36 x 4,5
: 3,6 x 35 + 3,6 x 20 + 3,6 x 45
:3,6 x (35+20+45)
:3,6 x 100=360
1234x 567 - 667 _1234x(566 + t) * 667
567 +1234x566 567 +1234x566 1234x 566+1234x1 - 667
567 +1234x566
_1234 \ 566 + (1234 - 667) _ mq " 566 + SCt _,
567 +1234x566 567 +1234x566 b) (r,25d)
'l6ng cua ba s6 ld 21x3763. 56 thir nhdt lit (et-ts)J=z+
T6ng cria sO thu hai va sti ttrrl bald; 63-24=39
SO tful trai ldrl : (t + z) = t3
56 thir ba ld r3x2 =26
i
C6,u2(2 did@ l
Xem s5 trang cfia cu5n s6ch ld I don vi quy udc
Ngdy thir ba Mai As r -l-1 = I (cu6n s6ch) vd bcvt rli : + = (trang)
3)J
Ngdy thfr ba Mai dec it hontngdy thfr nhAt lir : + - 10 (trang) Ngdy thir nhdt Vtai dqc 10 : (4-3)x = 40 trang
56 trang cira cu5n s6ch ld: (to-:)><r =1 I i(trang) i
Ciu 3 (2 di€m) i
- 56bO bangh6phdi lon hon l6 (vi l6x5=80, 80<83) vdnhi6unhdt ld 18 bQ,
suy s5 bQ bdn gn6lr fl tr{4c t t. THl C6 17 b0 bdn gh6,
- Gii sir ch 17 bQ d€u ld loai ch6 Khi d6 c6 n , q = 6a (ch6 ng6i).
Nhuvfythitium6t 83-68=15(ch5) (0'25d)
- Cf bst mOt b0 ch5 vdthay viro d6 rnQt b0 ch5 thi th6m dugc s-+=t(ch6).
B=
(0,2sd) (0,2sd) (0,25d) (0,2sd) (0,2sd) (0,2sd) (0,25d) (0,25d) (0,2sd) (0,25d) (0,25d) (0,25d)
(0,5d) (0,5d) (0,5d) (0,5d)
(0,sd)
(0,25d) (0,25d) 56 lAn thay (hay chinh ta st5 b9 ch5) 1d 15 : I = 15
(2)$,
ffi ffi
ffi
ffi
ffi
iJs
i,#il
il
TH2 C6 18 bQ bdn gh€
- GiA sri c6 l8 b0 ddu li loai ch5 Khi d6 c6 tax+ = zz(ch6 ng6i) Nhu viy thii5u m6t $-72=l I (ch6)
- Cf bdt I bQ ch6 vd thay vdo d6 rnQt bQ chd thi th6m duqc s - 4 = I (ch6)
S,5 lAn thay (hay chinh ld sO bO ch6) le 1: I = 1l
- s6 oO ch6 ld t8-l r = Ciu 4 (3di6m)
Vd hinh (0,25d)
.h
d6i chi6u cao hz tu D xu6ng AC tfc liL i=2
c) ( l,5d)
Serc = 3Seecvi d6y BE = 3AB vd chung chidu cao ru C xu6ng AE Ndi e vOi M Tucrng tV ta c6i Sssy : 3SaBv
',
* Sesc - SssNa : 3(Sesc - SesM) = SrurEc : 3$erurc (0,5d)
Ta c6 : S6y6: Sorvn : j So"" (t) vi ddy CO : AO :
] ac ua chung chidu cao ar M xu6ng AC Tuong ta c6 Sos6 = Se6a
(0,25d) (0,25d) (0;2sd)
(0,5d)
(0,25d)
= Sorc - Sorvlc = SoEa - So1aa hay Sys6 = SplBa (0,sd)
= S,rce= SMEa * SNa6c,* Ser,,1c:3S1y6 + 3S4*.+ Snvc = TSays hay Sot.:i Sr,ce (2) (0'2sd)
Tt(l)vd(2),+s6ys= # to.u =#=+ (0,25d)
CAru (Vwqt khung, Idiiim) ,
Day si5 ig nhi€n ttl ei5n I 00 c6 I 00 sii fOng cia chirng ld (l + I 00)x 00 : = 5050
(0,2sd) T6ngcriaTl s6trongcdcsOd6ldnhonho{cbingt6ng: l+2+3+ +71 (0,25d)
l+2+3+ +71=(t+Zt)x71:2=2555 @'25d)
Vi 2ss6 > 2525 = ]
" soso ndn kh6ng th6 chqn dugc 7l sii nhu ydu cAu eA Uai
(0,25d)
2
DC a) (0,sd)
2xl8 2x 18 - t -, \
Chidu cao hinh thane ld -= = = o(cm)
2+2x2 6
b) (o,7sd) i
aACE vd AACD c6 d6y AE = 2CD (AE = AB+3AB =aAB,CD =2AB)
vd chidu cao h4 tir A-xu5ng CD bdng chi6u cao h4 tir C xu6ng AE (d1u bdng chi€u cao hinh thang ABCD)
n€nSace=2xSasp (0,sd)