pt luong giac trong cac de thi dai hoc tu 20022010

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PHƯƠNG TRÌNH LƯỢNG GIÁC TRONG CÁC ĐỀ THI ĐH-CĐ VÀ DỰ BỊ ĐH TỪ 2002-2010

02:Tìm nghiệm thuộc khoảng (0;2 ) cña PT:5  3

 



  



cos3x sin3x

sinx cos2x

1 2sin2x B02: GPT: sin 3x cos 4x sin 5x cos 6x.2  2  2  2

D02: Tìm nghiệm thuộc [0;14] PT: cos3 4cos 3cosx x x 4 DB1: Tìm m pt có nghiệm thuộc[0;/2]:

2 sin x cos  4xcos 4x2 sin 2x m 0 DB2: GPT: sin4 cos4 1cot 2 1

5sin 2 2 8sin 2

x x x

x x



 

DB3: GPT:  

2

2 sin 2x sin 3x 4

tan x 1 4

cos x 

 

DB4: GPT: tan x cos x cos x sin x tan x tan2 x

 

     

 

DB5: Cho PT: 2sin x cos x a sin x 2cos x

 



  (2) (a lµ tham sè).

a) GPT (2) a=1/3 b) Tìm a để PT (2) có nghiệm. DB6: GPT: sin x

2 8cos x

C§-A02: GPT 4sin 2x 6sin x 3cos 2x2 cos x

  

 A03: GPT: cot x cos 2x sin x2 1sin 2x

1 tan x

   



B03: GPT: cot x tan x sin 2x sin 2x

  

D03: GPT sin2 x tan x cos2 x 2



 

  

 

 

DB1: GPT: cos 2x cos x tan x 1   2 DB2: GPT: 3cos 4x 8cos x 2cos x 0    DB3: GPT:  

x 2 cos x 2sin

2 1. 2cos x



 

    

  



DB4: GPT cos x cos x 12   2 sin x   sin x cos x



 



DB5: GPT cot x tan x 2cos 4x sin 2x

 

C§03: GPT: 3cos x 1  sin x cos2x sin x sin x 1   B04: GPT 5 sin x 2 3 sin x tan x.   D04: GPT 2cos x 2sin x cos x sin 2x sin x.    

C§04: GPT: cos3x 2cos 2x 2sin x sin 2x   C§SPHP-04: GPT: cos x cos x cos x

3

  

     

    

     

     

C§-04: GPT: cos x sin x cos 2x 2cos x sin x cos x 12      C§-04: GPT: sin 4x.sin 2x sin 9x.sin 3x cos x 

C§-A-05: GPT: cos 3x cos 2x cos x 0.2   B-05: GPT 1 sin x cos x sin 2x cos 2x 0    

D-05: GPT: cos x sin x cos x4 sin 3x

4

 

   

        

   

A-05: GPT: cos23x.cos2x-cos2x = 0 A-06: GPT: 2 sin cos6 -sin cos 0

2-2sin

x x x x

x





B-06: GPT: cot sin tan tan

x

x x  x 

 

D-06: GPT: cos3x+cos2x-cosx-1=0

2

A07: GPT: (1 sin ) cos (1 cos ) sin sin 2

B07: GPT: 2sin sin sin

D07: GPT: sin cos cos

2

x x x x x

x x x

x x

x

    

  

 

  

 

 

A08: GPT

1 1 7

4sin .

3

sin 4

sin 2

x x

x

 

  



 

 

   

 

 

B08: GPT sin3x 3 cos3xsin cosx 2x 3 sin2xcos x D08: GPT 2 sin (1 cos ) sin 2x  x  x 1 cos x

A09: GPT (1 2sin ) cos 3

(1 2sin )(1 sinx)

x x

x





  .

B09: GPT sinx cos sin 2x x 3 os3c x 2( os4c x sin ).3x

   

D09: GPT 3 os5c x 2sin cos 2x x sinx 0. CĐ09: GPT (1 2sin ) cosx x 1 sinx cos x

   

A10: GPT (1 sinx os2 )sin 4 1 cos

1 t anx 2

c x x

x



 

    

  



B10: GPT (sin 2x c os2 ) cosx x2 cos 2x s inx 0.

D10: GPT sin 2x c os2x3sinx cosx1 0.

CĐ10: GPT 4cos5 os3 2(8sin 1) cos 5.

2 2

x x