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Hớng dẫn về nhà: -V nh lm li tp 6 (SBT) Ngy ging: 09 / 09 / 20 09 Tiết7: S PH THUC CA IN TR VO CHIU DI DY DN IMC TIấU: 1 Kin thc: -Nờu c in tr ca dõy dn ph thuc vo chiu di, tit din v vt liu lm dõy dn - Nờu c cỏch xỏc nh s ph thuc ca in tr vo 1 trong cỏc yu t (chiu di, tit din, vt liu lm dõy dn) 19 - Mụ t v tin hnh dcTN kim tra s ph thuc ca in tr dõy dn vo chiu di -Nờu c in tr ca cỏc dõy dn cú cựng tit... kt: in tr ca cỏc dõy dn cú cựng chiu di v c lm cựng t 1 loi vt liu thỡ t l nghch vi tit din ca dõy 2 Hng dn nh: -Tr li C6 v bi tp 8 SBT -ễn li bi ca tit 7 v tit 8 Ngy ging Tit 9: S PH THUC CA IN TR VO VT LIU LM DY DN I.MC TIấU: 1 Kin thc: -B trớ v tin hnh TN kim tra chng t rng in tr ca cỏc dõy dn cú cựng chiu di, tit din v c lm t cỏc vt liu khỏc nhau thỡ khỏc nhau -So sỏnh c mc dn in ca cỏc cht... C4in tr ca dõy ng in tr ca dõy ng l 0,087 trong mch in l rt nh, vỡ vy ngi ta thng b qua in tr ca dõy ni trong mch in *Tng kt-Hng dn v nh 1 Tng kt:- in tr sut ca vt liu cng nh thỡ vt ú dn in cng tt -in tr ca dõy dn t l thun vi chiu di ca dõy dn, t l nghch vi tit din ca dõy dn v ph thuc vo vt liu lm õy dn 2Hng dn v nh: -c phn Cú th em cha bit -Tr li cõu C5, C6 (SGK-tr.27) v lm bi tp 9 (SBT) 29 Ngy ging:... - Mc tiờu: HS nhn bit c in tr sut l gỡ? n v ca iờn tr sut - Cỏch tin hnh: II in tr sut-Cụng thc in -Yờu cu HS c mc 1 v tr li tr cõu hi: 1.in tr sut +in tr sut ca mt vt liu -in tr sut ca mt vt liu (hay 1 cht) l gỡ? (hay mt cht) cú tr s bng in +Kớ hiu ca in tr sut? tr ca mt on dõy dn hỡnh tr +n v in tr sut? c lm bng vt liu ú cú chiu -GV treo bng in tr sut ca di 1m v cú tit din l 1m 2 mt s cht 20 0... xỏc nh s ph thuc ca in gia in tr vo chiu di dõy tr dõy dn vo chiu di ca dõy ta dn thỡ phi o in tr ca dõy phi o in tr ca cỏc dõy dn c dn nh th no? lm t cựng mt loi vt liu, cú tit din nh nhau nhng chiu di khỏc nhau -Gi HS nhn xột cõu tr li ca bn, GV sa cha nu cnỏnh giỏ cho im HS V: in tr ca mt dõy dn ph thuc nh th no vo tit din dõyBi mi 3.Dạy học bài mới: Hoạt động1:NấU D ON V S PH THUC CA IN TR VO TIT... oỏn v s ph thuc ca in tr vo tit din ca dõy - Cỏch tin hnh: -Yờu cu HS vn dng kin thc I.D oỏn s ph thuc ca in tr vo v in tr tng ng trong tit din dõy dn on mch mc song song tr R R C1: R2 = ; R3 = li cõu hi C1 2 3 -T cõu hi C1D oỏn s ph C2: Trng hp hai dõy dn cú thuc ca R vo S qua cõu 2 cựng chiu di v cựng c lm t cựng mt loi vt liu, thỡ in tr ca chỳng t l nghch vi tit din dõy Kt lun: in tr ca dõy dn cú... 27 -Yờu cu HS tr li C1 I.S ph thuc ca in tr vo vt liu lm dõy dn C1: o in tr ca cỏc dõy dn cú cựng chiu di v cựng tit din nhng lm bng cỏc vt liu khỏc nhau 1.Thớ nghim -Yờu cu thc hin TN theo nhúm A Cỏc bc tớnh 1 2 V + - Dõy dn cú cỏc in tr sut khỏc nhau( ) in tr dõy dn( ) l1 = l2 = 1800m S1 = S2 = 0.07065mm 2 R1 = = 1.8m = 0.07065.106 m 2 R2 = 2.Kt lun: in tr ca dõy dn ph thuc vo vt liu lm dõy dn Gi... -Yờu cu a ra phng ỏn TN tng quỏt tit din, cht liu lm dõy dn cú th kim tra s ph thuc ca in tr vo 1 trong 3 yu t ca bn thõn dõy dn Hoạt động2: XC NH S PH THUC CA IN TR VO CHIU DI DY DN - Mc tiờu:- Hs thy c s ph thuc ca in tr vo chiu di dõy dn - dựng: 1 ngun in 3V và 1 cụng tc -1 ampe k cú GH l 1A 1 vụn k cú GH l 6V -3 in tr: S1=S2=S3 cựng loi vt liu l1 =90 0mm; l2=1800mm; l3=2700mm 21 -Cỏc in tr cú =0,3mm... cỏc on dõy dn I.Xỏc nh s ph thuc ca in tr dõy hỡnh 7.1 cho bit chỳng khỏc nhau yu dn vo mt trong nhng yu t khỏc t no? in tr ca cỏc dõy dn ny liu nhau cú nh nhau khụng? -Hỡnh 7.1: Cỏc dõy dn khỏc nhau: Yu t no cú th gõy nh hng n +Chiu di dõy tr ca dõy dn +Tit din dõy -Yờu cu tho lun nhúm ra phng +Cht liu lm dõy dn ỏn kim tra s ph thuc ca in tr dõy * Kt lun: in tr ca dõy d ph dn vo chiu di dõy dn thuc... NG DY HC 1 n nh t chc: 2 Khi ng: - Mc tiờu:- Kim tra li kin thc c, to tỡnh hung hc tp - Thi gian: 7phỳt - Cỏch tin hnh: 1 in tr ca dõy dn ph thuc vo nhng yu t no? Ph thuc nh th no? Vit cụng thc biu din s ph thuc ú 1.in tr ca dõy dn t l thun vi chiu di l ca dõy, t l nghch vi tit din S ca dõy dn v ph thuc vo vt liu lm dõy dn l Trong ú: R l in tr S ca dõy dn (); l in tr R = sut (m); l l chiu di dõy . $YL 89) K;%I$!"#' %H!M&@/%+J& $%&'(')*&+,-.,/*0,-*123 4153/('67)*8/ *9: ;;<';&=,- %:>?,-%12, @9& apos;>AB>C,DEF*1 29. =1>?/#4f' =%=1> J/*KL1 59 >1M,67)*8/ *9: ; ;<';&=,-%:>?,-%12,DEF*1 29 %12,/*G UI#;<