!"#$ %$&'(' )*+,-. / 01$2344!.+$546+ 78 25 16 9− + 98 3( 12 5) 5( 3 5)− + + !0:#$; 1 1 x 2 C ( ) x 2 x 2 x − = + − + ,<=>?@>AB/ )*+,-. / 0CDE"FG$2H6+ 3x y 10 2x y 0 − = + = !0CD!$6+!I44J"E"FG$2H0K$H4LJ$4M4+< N( O$P4Q+R=G4Q+2K( O$01RES4H4LJ$-M0 )*+N,-. / 0T$3 6U%8>V-W+-. ,@X/0H E6U<4!Y$ 6U -T!Y%34!YZ>?[\H6[ !0J"!D$232T<]-T$3 6U%8>V$2^E$2_4$;-K`>%0 )*+B,-. / )$ 479)<+$a7P-F47P$+K49)09Y$98b4 < )8(4 0cd<+M4<=79P<+M4<=7)P$+K479P$+K4 7)0 01-KR70 !0)5 70798707) 40)5 $549)KeY"-F$2f0 )*+&,-. / 2^-F$2f$* `g%-. 7<9646U-4+h79 i0eY"$+%Y$a7<94j$+$a0 016U-M47`9<M4790 !0cd-FZ19`)0)5 7)''`0 $`k,Z4+%^/ %$l'l' "#$,ZZ.$-Q/ )*+0,P-. / 0:#$;!.+$5478 20 5 2 8− + 0 !01$234m!.+$54 25 49 B 0,01 16 9 = × × )*+0,P-. / ) 6U%8>V<%8X>nN0 0\]44-T$34m 6U%$2^4o K$E$2_4$;-K0 !0H $;-K-. 4m-T$3 6U$2^0 )*+N0,NP-. / )"FG$2H>VX(>n 8,/ 0p4-344E6UP!P44m"FG$2H,/0 !0\=$234m $H"FG$2H,/4ME 0 40CD"FG$2H,/Z 8ql0 )*+B0,NP-. / 2^r-F$2f$* `-FZ1798:g%-. )<-. s6 4444+7)P)sPs9L4+!I+0\]s<+M4<=79$aP ;c-. 4m44e7)<sPt-. 4m9)<s0 0)5 M47s)!IM4)cs0 !0C;)>eY"$+%Y4mr-F$2f$2^$a)P)>4j$c$au0)5 $ 4)tu$ 4-Q+0 4019c$v:0 $`k,4+%^/ %$l'l' &"#$,ZZ.$-Q/ )*+0,P-. / )5 6U8BVnNVnVXVZ"D6U41 "FG0 )*+0,P-. / CDE"FG$2H 2 2 x xy y 19 x xy y 1 + + = − + = − )*+N0,P-. / )"FG$2H>VX, nN/>n 8, $ 6U/0 0)5 2I"FG$2H+4ME <= ; 0 !0C;> P> E 4m"FG$2H0H !.+$54 2 2 1 2 T x x= + 4M $23hg$0 )*+B0,P-. / )$ 479)-Q+PKeY"$2-F$2f,`/02^4+h9)g%-. 02^e7g%-. s64s890 0)5 2I$ 49s-Q+0 !0)5 2I789n)0 )*+&0,P-. / )-F$2f,`@:/$2^-M4M!-. 7P9P)"*!E$0C;$2w4$* $ 479)0 479)"D4M-Q+ZEH 7n9)=g$[1$23= g$-M$v:0 $`k,Z4+%^/ "#$,ZZ.$-Q/ )*+0,P-. / w4E"O"S 0 1 80 20 45 5 4 + − + !0 x x x 1 x x 1 − − + − )*+0,P-. / )E"FG$2H mx y 5 x y 1 − = + = ,/ 0CDE"FG$2H,/<= 8&0 !0\=$234m $HE"FG$2H,/4ME R+%g$P<E [ )*+N0,NP-. / )"FG$2H>Vn,B n/>n, XB/8P<= $ 6U0 0CD"FG$2H<= 8 !0)5 2I"FG$2H+4ME "*!E$<= ; 0 40H "FG$2H4M44E > P> $h x,> X> /V8(& )*+B0,NP-. / ) K$-. !g$ZyI $2^r-F$2f$* `-FZ179, Z47<9/02^r z$"{!7945r-F$2fPZdeY"$+%Y7> 4j$e9$a0*4M474j$r-F$2f$at<4j$e9$au@e 9t4j$7>$a<4j$7$ac0 0)5 tuc$54KeY"0 !0)5 7V8090 40)5 $ 497u4*0 |Ck`s})~•`€` •)BX& •‚ƒ)„ `k,c…C)†/ "#$,ZZ.$ -Q/ 90,P-. /CD"FG$2HPE"FG$2H 0>VXl>n8 !0>VX, 2 n/>n 2 8 40> B Xb>Vn8 R0 3x 2y 4 4x 3y 5 − = − = 90,P&-. / 0\]-T$3,/4m 6U%8>V<-F${,‡/%8>nN$2^4o z$ "{$;-K !0H $;-K44-. 4m,/<,‡/!I"O"$10 9N0,P&-. /:#$;44!.+$546+ 078 5 5 3 5 5 5 2 3 5 5 1 + − + + + − !098 x 1 2 6 ( ) : (1 ) x 3 x x 3 x x 3 x + − + + + + ,<=>?/ 9B0,P&-. /)"FG$2H>VX >X8 ,/P<= $ 6U 0)5 "FG$2H,/+4ME "*!E$$2Rg+0 !0C;> P> 44E 4m"FG$2H,/01$234m8 2 2 1 1 2 2 1 2 x x 1 x x 1 x x + − + − − 9&0,NP&-. / )$ 4;79),79ˆ7)/KeY"-F$2f$* `0)4-F 47sP)u4m$ 479)4j$+$a0 0)5 $549usKeY"0 !0C;-. !g$ZyPZ49<)P$2^4+h9)4m-F$2f,`/0C; -. -U>54mW+7)0)5 2I$547)KeY"0 40C;-. 4m7<)@‰-. 4m7)<0)5 2I M47‰8M47)0 R0)5 2I`7<+M4<=‰0 [...]...ĐỀ THI TUYỂN SINH VÀO LỚP 10 NĂM 2011 TRƯỜNG THPT CHUYÊN THOẠI NGỌC HẦU – AN GIANG MÔN TOÁN Thời gian: 120 phút (không kể thời gian phát đề) Câu I (2,0 điểm) 1 Rút gọn rồi tính giá trị biểu thức (không dùng máy tính): A = x 2 − 4x 2 + 8 + 2x 2 . = !0CD!$6+!I 4 4 J"E"FG$2H0K$H 4 LJ$4M 4 +< N( O$P 4 Q+R=G 4 Q+2K( O$01RES4H 4 LJ$-M0 )*+N,-. / 0T$3. 4 79)<+$a7P-F 4 7P$+K49)09Y$98b 4 < )8( 4 0cd<+M4<=79P<+M4<=7)P$+K479P$+K4 7)0 01-KR70 !0)5 70798707) 40 )5. / 0:#$;!.+$ 54 78 20 5 2 8− + 0 !01$234m!.+$ 54 25 49 B 0,01 16 9 = × × )*+0,P-. / ) 6U%8>V<%8X>nN0 0] 4 4 -T$34m 6U%$2^4o