Đang tải... (xem toàn văn)
MDIJl]GB0CRUH0I BfllTnPPHHnH0[1TR0nGDn!/HpCII10nT0fln CHO HOC SINH TRUNG HOC PHO THONG PHAM THI M O N G T I / O N G NGUY§N THUY PHUONG T R A M " Trong qua trinh day hge, mdi hge sinh (HS) cd mgt nang[.]
MDIJl]GB0CRUH0I.BfllTnPPHHnH0[1TR0nGDn!/HpCII10nT0fln CHO HOC SINH TRUNG HOC PHO THONG PHAM THI M O N G T I / O N G - - NGUY§N THUY P H U O N G T R A M " T rong qua trinh day hge, mdi hge sinh (HS) cd mgt nang tuc liep nhan thdng tin va xuli van de khac nhau,Thuc tidn day hge dcac trudng trung hge phd thdng (THPT) hign cho thay, da sdcac gid day van duge lien hanh ddng logt, ap dyng nhu cho mgi ddi luong HS, Giao vien (GV) eung cap kien thii'c, HS giai cac bai lap (BT) loan Iheo trinh lud saeh giao khoa (SGK), thieu suphan hda Do dd, viee tochucday hgc phan hda nham lao ddng Iyc thue day ddng ea hgc tap eho mgi ddi tugng HS, phat huy tdi da nang luc ea nhan, tinh tich cyc, chu ddng, sang lao cua HS, Baiviet de cap tdi quy trinh xay dyng bgcau hdi (CH), BT phan hda day hoe mdn Toan a THPT Cau hoi, bai tap phan hda day hgc toan d THPT Helhd'ng CH, BT phan hda phaidam bao dugc su phat then loan dien cae matve kien thirc, kTnang, thai ddcua HS.Dodd, cae chuan kien thuc, kTnang quy dmh chuang trinh deu cd bgCH, BT phan hda tren co sd dam bao tinh khoa hgc, chinh xac, phat huy tlnh tich cyc, sang lao, cd linh he thd'ng va gan lien vdi thue tidn Bg C H, BT phan hda thudng duoc phan theo ehu de, ednhieu CH, dukien tinh hudng vacd suphan bac de phii hgp vdi timg ddi tugng HS Trong dd, can du vd so luang BT cung nhu npidung kien thtic cho timg nhdm HS phan hda Bd CH, BT phan hda dugc sip xep lang dan theo mifc nhan thuc, chifa nhieu yeu iddan dat denang dan kha nang kham pha van dd, ren luyen cac kT nang hgc lap cho HS (dae biel ddi vdi HS yeu, kem}, Mdi CH, BT phan hda can hudng de'n vigc Ihue hien cae mye dich day hgc, dat d mdt tinh hudng cy the deu chua dyng mgl each tudng minh hay tilm an nhung dyng y su phgm khae NghTa la phai dam bao ehiic nang day hgc, chu'c nang giao due, chirc nang phatlrien, chu'c nang kiem tra; nhien, cac chi/e nang khong tach rdi Vigc nhan manh chuc nang hay chuc nang khae phy Ihudc 46 Tap chi Giao due so 314 vao viec khai thac bg CH, BT phan hda va nSng kfc su pham cua GV nh^m siidung cdhigu quachotilng 6St tugng HS, Do do, dd'i vdl* he thdng CH, B"Pphan hda cang "min" se cang phu hop vdi vigc sis dyng cho nhieu ddi tugng HS khac va dat hieu qua cao day hgc Vidu 7; Tim m dedd thi ham so: y = x= - 2x^ + (1 -m)x -I- m c3t Injc Ox tai die'm phan biet cd hoanh dg X , Xj, Xj thda man dieu kien x,' + x^' + X3^ ' = /« 0,^ i.d)10y Kha 2x'-i-6x'+2-m = +i + 2m = Q • hTjro C^) Tim cac gia trj cua m d£ phiUfig Irinh sau c6 - ~ 2nshiem: !L + x^+2-m = 0i*) - Khflng can nfiu tSl ca c Jc Inrflng hijp nhi/ bi6n luan ma ch? nau tri/Ong hijp PT C j ) Tim cac gia Ir; cua m sS phi/dng trinh sau cd c6 nghidm phan biet +2 + m = nghl?m - x ' ~ix^ d) Tim cac gia Ir in de phi/dng Gioi Cl » X ^ J - ' - ] = -ix^ - GV can giup HS phat hl^n 6\H)c Mu bl£n a6i phUdng trirh 66 vk Vii nuii til$n (C) ia rjt quan vao dA lh| cA kk luan (3 Iti/dng hdP), c) Tim cac gid In cua m OS- Bian d6i: phin blOl: l>j) :-x' ( c = j t ' + j r ' - l = 2m + 2) U = y-H3.t'-l(C) phi/Ong trinh sau cd rghiim di/dfig thing (d) - Bian ddi - Lam iLftJngtu nhi/trgn f / , ) Tim cac gia Iri cua m de phutfng trinh sau trinh sau cO nghiem Icin han 1: (chuy nhQng gia tri x>1) x'+3x'+5-m = OC) cd diJng x'+3x^'3 nghiem Are ( - , ) : + m = SUMMARY Phan hda day hgc la dudng nang cao hieu qua giao dye Viec xay dung va sudyng cd hieu qua bd CH va BT phan hda se gdp phan tac ddng tn/c tiep den lung HS De xay dung va sudung hieu qua bd CH va BT phan hda, ddi hdi GV phai la ngudi yeu nghe, tan tam voi cdng viec vi thdi gian dau luldn.Tudac diem, yeu cau su pham va quy trinh xay dung bgCH, BT phan hda bd mdn Toan, GV can van dyng mdt each linh hoat nham gdp phan nang eao hieu qua day hgc loan d phdthdng ndi chung va oTHPT ndi rieng Tai liCu Iham khao Nguyfin Bi Kim Phmmg phap day hoc mOn Todn NXB DaihQcauplnun H 2004 Phan Trgng Ngy Day hcjc va phinrag phap dgy hoc nh^ truiVng NXB D^i h(ic sit phgm H 2005 Dio Tam - Trfln Trung T6' chiic hoat d^ng nh^n thih: day h9c mOn Todn * truwng trung hoc pha' thflng NXB Dqi hpc supham, H 2010 Nguyin Thfi' Th^ch Huwng d&a thuc hi^n chuSn kign thifc kl nSng mfln Toan If^ 12 NXB Gida due, H 2009 481 Tap chi Giao due so 314 In the study, each student has a capacity to rer ceive and handle the issue differently Thus the need In organize teaching distinction to create a force for all students in one classroom In this article we wlB present some problems about process buUdlngque^ tions assignments differentiation In teachingmath to high school students -^ THONG BAO Tap chi Giao due thang \d, d|t mua thuan tign tai cac bifu cyc dia phUdng (Ma so C192) hoac dat mua true tiep tai Tea soan (so luong Idn) tlieo dja chl: TAP CHI GIAO DyC, "Mnh Hodi Diic, quan Bong Da, Ha N6i.^ Kinh mdi b^n dgc cac ddn vj gi^o ^Cj trudng hoc tiep tuc dSt mua Tsip chi Giao d^^ ndm 2013 Mol lien hg xin giJi ve dja chi tr|n hoac lien lac qua so dign thoai: 04.3734536^ Fax: 04.37345363 , ".,'J Xin Iran trgng cam On %\ TAP CHf GIAO DgC^ -(ki2-7/2013% ... HS Dua vao budc nay, G V ed the phat hien va dieu cao cho HS kha gidi vh Hvin cua IC) h e s g i l c c i J a ( d | i a i ehinh bude 4^, budc cho phu hop hon u i t ring tiip tuyin - GV giup HS lt)jy... SGK, GV sexac djnh mue ti&u, ren day du cae kTnang hoc tap cho HS;khidd,GV ehl yeu cau cua bai hge ve ehuan kien thtic, kTnang, ttiai nen cho HS giai den cau b) va dat cac CH b,) bj),c), cua HS... dgy hoc nh^ truiVng NXB D^i h(ic sit phgm H 2005 Dio Tam - Trfln Trung T6'' chiic hoat d^ng nh^n thih: day h9c mOn Todn * truwng trung hoc pha'' thflng NXB Dqi hpc supham, H 2010 Nguyin Thfi'' Th^ch