Thông tin tài liệu
Luận văn
Thiết kế quy trình công nghệ gia công
chi tiết: Ô đỡ trục
Đồ Án Công Nghệ Chế Tạo Máy GVHD: NGUYỄN PHI TRUNG
BỘ GIÁO DỤC VÀ ĐÀO TẠO CỘNG HÒA XÃ HỘI CHỦ NGHĨA VIỆT NAM
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NHIỆM VỤ ĐỒ ÁN MÔN HỌC CÔNG NGHỆ CHẾ TẠO MÁY
0123NGUYỄN CHÍ TRUNG '4 3!56!7!87
-1 3$9:;<=> -2= 36!!56!?7
2@A13<:<B>CDEFD<3Ô đỡ trục
I. GHEI3
− JHK3?!!!!!<LM
− A:E<NO3P>@QR
Nội dung thiết kế :
?R CS<FD3A:EH10ET:<UT@;V=R0R0W
6R X=@OYZJVU31:G
7R $D019=DTFHKY=NA[FD
\R <CDE3]FDT9==@[TZZ==9=R
^R <:<>2DR
− 4_Z9@`=@[a:bE@O0OT:c[TYddef0O;GgThi
9A>S@Rj:;IT@NaTYZF=>2D@F
ER
− $=>T:<UYF
− CN1>=NI3$YFkHYF010HEH1YFlTF=<@e3TZTm
FHKY=NI01;FFD9NJnNIR
− ;HKYFD>2D73F>[@P
− ;=<@e>2D73F>[@PR
8R <:<@`=>2D^3FHo∅?!3
− 4_Z9@`>2Hb@`=R$:<U@`=TCN1>>2HbH10EQF@`
=R
− ;H:cP<TH:c9U:cR
− ;ZFZGp01ZZ=0IYZFQF>2D@FE2@`=
@aR
− ;Z]NA=<OHR
II. $=NJ0_3
− *J0_<3 ?NJ#7R
− *J0_<H`D3 ?NJ#7R
− NJ0_Z9@`>2D3 \NJ#7R
− *J0_<:<@`=3k0_NCl ?NJ#?R
III. -1>FE0d3
IV. -1>11E0d3
V. j=02IYq3NGUYỄN PHI TRUNG
j=42Iq
b2
6
SVTH: NGUYỄN CHÍ TRUNG MSSV:09203063
Đồ Án Công Nghệ Chế Tạo Máy GVHD: NGUYỄN PHI TRUNG
NHẬN XÉT CỦA GIÁO VIÊN HƯỚNG DẪN
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
j=02IYq
NGUYỄN PHI TRUNG
NHẬN XÉT CỦA GIÁO VIÊN PHẢN BIỆN
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
7
SVTH: NGUYỄN CHÍ TRUNG MSSV:09203063
Đồ Án Công Nghệ Chế Tạo Máy GVHD: NGUYỄN PHI TRUNG
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
j=02JNE
MỤC LỤC
F
a@P
$9r3s;<FD 8
\
SVTH: NGUYỄN CHÍ TRUNG MSSV:09203063
Đồ Án Công Nghệ Chế Tạo Máy GVHD: NGUYỄN PHI TRUNG
$9rr3X=@OYZJVU t
$9rrr3$YD019=<D ?!
$9r43$9=FD01HB>CDE ?6
$943<:<>2D ?u
$94r3X=@OHKYFD \?
$94rr3X=@O<@e \\
$94rrr3;=01<:<@`= \t
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LỜI NÓI ĐẦU
`=D$D-E$<'=>H1DF;vK=:<
]@waH2BFIDE<=>k=D$9f$D-E$<
'=>T$D-E41<*ODT$=9=jF$DTWl@S<
@K<=>xNJ@J@K=>2P0A:01;:<
^
SVTH: NGUYỄN CHÍ TRUNG MSSV:09203063
Đồ Án Công Nghệ Chế Tạo Máy GVHD: NGUYỄN PHI TRUNG
ZJVUTgK0I@A:EDEET0IF019=FDG
W'G@@KUJ=@A2CFJ<:<@KB>CDEF
DKHbR
B=CE`=Z02Je0y=:<]0A=
9=DT=9=FDT@O0OT=@[T@HTW01N<=HF
F9=GTKHbUR'B>CDEKHbH1=Yd@K
yDET=>agK0I@A:EITFFDeT;
FDU<0q@JNJ@K:;I01YZF@0I>2P
:@[FTa=1z@=]@KPQFVw.
$=ZGHETDZGYFNJ[;=@AYF01=1HE01:E
QFP>IYqR
>2TB=CE@`=<<{>C$D-EYC@01M
H|A<2:DS=:}yZFZaB=C;=~
=ZGHER$•UP>DabT@S•NvZ:<]QF
C@K1E9R
[NET•Vs1J9P>NGUYỄN PHI TRUNGP>H1<
IYq•B=CE@`=1>R-ZIYqCQFP>
1•F@Ky><:€Ty<QFNJs:Dh0A:<
]>2D1J0A<ZGR'[Yg@`=DE<=>Y
Z02H1••aF@CNaP>R
02E
CHƯƠNG I. PHÂN TÍCH CHI TIẾT GIA CÔNG
I. Chức năng :
$<s@•dH1<[=EG9:;R
$<Yv@•da]MvN@S@O0O[y[
=dR
8
SVTH: NGUYỄN CHÍ TRUNG MSSV:09203063
Đồ Án Công Nghệ Chế Tạo Máy GVHD: NGUYỄN PHI TRUNG
− j`3Ho‚\!HevNR
− 2@<aHoƒ?!@SG@Ov@•R
II. Yêu cầu kỹ thuật :
1. Đối với lỗ Ф40: H1NA[H10E;QF2R
− )2P3oJ@OsGR
− oaU;V=:;IH1UuR
− ;IHoH1ƒ\!
„!T!6^
kNJ6tm8?m…7†lR
•kNJ6R77m58m…7†lFaU;V=:;IH1UuFF@KU;
V=0ACY=kU@=lH1UuR>F3
+ =NA[HoH1‡Fˆ?T8kNJ6R65m??7m…t†l
+ @`sQFHvH1!R!7kNJ6R7^m?!?m…7†l
+ :D0Da0I[@PH1!R!?8kNJ6R78m?!6m…7†l
+ ZF:J=6sHo•AY138!
±
!R!^kNJ67um?!7m…7†lR
2. Đối với mặt đế:
− )2P3'[@<J‰T‰T0Da0I@sQFHo‚\!R
− OZGYZF:;I1>:D>2PFŠˆ‡‹Lk^?!lŒR$‡‹ˆ6^
3. Lỗ Φ10 vuông góc mặt đế:
oYgHe€NHR$U;V=QFHo01[2HoH1U?6
+ =NA[HoH1‡
‹
ˆ6^k:Fl
+ =NA[QF2HoH1‡
‹
ˆ6^kF>l
+ ZF:J=6sHo•AY13^!
±
!R!^kNJ67um?!7m…7†lR
4. Đối với lỗ Φ10 + rãnh
oYgHe€NHR$U;V=QFHo01[2HoH1U?6
+ =NA[HoH1‡
‹
ˆ6^k:F„F>l
+ =NA[QF2HoH1‡
‹
ˆ6^kF>l
+ ZF:J=6sHo•AY138!
±
!R!^NJk67um?!7m…7†lR
+ ZF:J=6sHo•A36!
±
!R!\NJk67um?!7m…7†lR
III. Vật liệu:
− 4HE<s@•dZGH13jFX=?^76
− ]*3?8!W?5\
− jFV=H1K:Q><e0I$FN01a]FZG>2G:=
k!R^÷\R^lŒTk!R\÷!R8lŒ'T!RtŒT!R?6Œ01ZG>2G:D
@=:S3$T-T$T#HW
jFV=a@NA€FTO1|T;@GTa@NANCTY•F
Da;H1J@2@KZŽYdA1<=>R
CHƯƠNG II. XÁC ĐỊNH DẠNG SẢN XUẤT
ZJVUFFFH1NFY;3
− JVU@9<
− JVU1HFk}T0nFTHIl
u
SVTH: NGUYỄN CHÍ TRUNG MSSV:09203063
Đồ Án Công Nghệ Chế Tạo Máy GVHD: NGUYỄN PHI TRUNG
− JVU1:G
4EsNEYZJVUd01A><G01F;9@GR
I@s>H1y=sHFvN<3
Dạng sản xuất
Q
1
– Trọng lượng chi tiết
•6!!: \6!!: •\:
Sản lượng hàng năm ( chiếc/năm )
9< •^ •?! •?!!
1HF} ?!^^ ?!6!! ?!!^!!
1HF0nF ?!!7!! 6!!^!! ^!!^!!!
1HFHI 7!!?!!! ^!!?!!! ^!!!^!R!!!
1:G •?!!! •^!!! •^!R!!!
I. Trọng lượng chi tiết:
HK<@KV=@O•D]3{
?
ˆ4Rγk:lR
{
?
3HK<k:lR
43S;<kY
7
lR
γ3HK2QF0HE<<kFV=8Tt‘uT6lR
$γˆuR6:LY
7
R
SF4PAL$•FF•?R!F@K3
4ˆ?R!566??^R?!
^
7
ˆ!R?!566??^Y
7
>F{
?
ˆ!T?!566??^RuT6ˆ!Rut:R
II. Sản lượng hàng năm:
JHK1M;•D]3
t
SVTH: NGUYỄN CHÍ TRUNG MSSV:09203063
Đồ Án Công Nghệ Chế Tạo Máy GVHD: NGUYỄN PHI TRUNG
?
R k? l
?!!
N N m
β α
+
= +
-3ZG<ZJVUMR
-?3ZGZJpk<=>T=>WlZJVUMR
3ZG<ZJpR
’3ZG<@K<2@SYyk’ˆ^Œ‘uŒl
“3<pQ><=sVf@01”T
“ˆk7Œ‘8Œl
4>ZJHK1MH13-ˆ
???!!!l
?!!
^8
?Rk?R?!!!!! =
+
+=N
k<LMl
$M]01NJZGHE2CYZJVUH1ZJVU1:GR
CHƯƠNG III. CHỌN PHÔI VÀ PHƯƠNG PHÁP TẠO PHÔI
I. Chọn phôi:
$<H10E@A:E@cT:Da0F@TJc01
NCTYZJVU1:GW0HEH1FV=Ta;U10q@JNJ
@A:EH10ER'=FH1jX?^76R
Cơ tính:
Mác gang
Độ bền
Độ cứng HB
Kéo Uốn
jX?^76 ?^ 76 ?8!?5\
II. Phương pháp tạo phôi:
Phôi đúc:
5
SVTH: NGUYỄN CHÍ TRUNG MSSV:09203063
Đồ Án Công Nghệ Chế Tạo Máy GVHD: NGUYỄN PHI TRUNG
4HEH1FV=a;@Fk;J>H}FT@UTaS@y
<]Wl@A:EZJVU1:G2@:D=Tq:HR
Tra lượng dư cho phôi đúc:
+ $<@U;V=rRk?8tm…7†lTU;V=:;Ir?^r?5
NJk7R?\m?t^m…7†l
+ =NA[@‡
‹
t!NJk7R?7m?t^m…7†lR
+ ja=:DQFPd01P@<H1?
!
!!•NJk7Rum?uum…7†lR
+ ZJVUH11:G2=ƒ\!@vR
+ ZF:;I<@kNA[:DFDlNJk7R??m?t6m…7†l
Bản vẽ khuôn đúc :
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SVTH: NGUYỄN CHÍ TRUNG MSSV:09203063
[...]... Bảo đảm độ chính xác cần thiết về vị trí tương quan giữa các bề mặt không gia công với các bề mặt gia công Với yêu cầu trên ta chọn mặt bên (kích thước Ø60 mm) làm chuẩn thô để gia công ở nguyên công đầu tiên II Chọn chuẩn tinh : − Cố gắng chọn chuẩn tinh là chuẩn tinh chính − Chọn chuẩn công nghệ trùng chuẩn thiết kế để sai số chuẩn là bằng 0 − Chọn chuẩn sao cho khi gia công chi tiết không bị biến... 2,32.475 phút Thời gian thực hiện: TTC = T0 + T p + T pv + Ttn (phút) Trong đó Ttc: thời gian từng chi c (thời gian nguyên công) T0: Thời gian cơ bản biến đổi trực tiếp hình dáng chi tiết Tp:Thời gian phụ, tính gần đúng Tp = 10% T0 Tpv: Thời gian phục vụ gồm thời gian phục vụ kỹ thuật (Tpvkt = 8%T0) và thời gian phục vụ tổ chức (Tpvtc = 3%T0) Ttn: Thời gian nghĩ ngơi tự nhiên của công nhân (Ttn = 5%... 2,32.475 phút Thời gian thực hiện: TTC = T0 + T p + T pv + Ttn (phút) Trong đó Ttc: thời gian từng chi c (thời gian nguyên công) T0: Thời gian cơ bản biến đổi trực tiếp hình dáng chi tiết Tp:Thời gian phụ, tính gần đúng Tp = 10% T0 Tpv: Thời gian phục vụ gồm thời gian phục vụ kỹ thuật (Tpvkt = 8%T0) và thời gian phục vụ tổ chức (Tpvtc = 3%T0) Ttn: Thời gian nghĩ ngơi tự nhiên của công nhân (Ttn = 5%...Đồ Án Công Nghệ Chế Tạo Máy 1 A GVHD: NGUYỄN PHI TRUNG 3 2 4 5 T T D A D 6 CHƯƠNG IV CHỌN PHƯƠNG PHÁP GIA CÔNG VÀ LẬP QUY TRÌNH CÔNG NGHỆ 11 SVTH: NGUYỄN CHÍ TRUNG MSSV:09203063 Đồ Án Công Nghệ Chế Tạo Máy GVHD: NGUYỄN PHI TRUNG Chọn chuẩn là một việc làm có ý nghĩa quan trọng Mục đích của việc chọn chuẩn để đảm bảo 2 yêu cầu sau: − Chất lượng chi tiết trong quá trình gia công − Đảm bảo năng... công) 21 SVTH: NGUYỄN CHÍ TRUNG MSSV:09203063 Đồ Án Công Nghệ Chế Tạo Máy GVHD: NGUYỄN PHI TRUNG T0: Thời gian cơ bản biến đổi trực tiếp hình dáng chi tiết Tp:Thời gian phụ, tính gần đúng Tp = 10% T0 Tpv: Thời gian phục vụ gồm thời gian phục vụ kỹ thuật (Tpvkt = 8%T0) và thời gian phục vụ tổ chức (Tpvtc = 3%T0) Ttn: Thời gian nghĩ ngơi tự nhiên của công nhân (Ttn = 5% T0) TTC = T0 + 10%T0 + 8%T0 + 3%T0... III Các phương án gia công: 12 SVTH: NGUYỄN CHÍ TRUNG MSSV:09203063 Đồ Án Công Nghệ Chế Tạo Máy GVHD: NGUYỄN PHI TRUNG 7 2 6 5 10 11 3 8 4 1 12 IV.Các phương án gia công: 13 SVTH: NGUYỄN CHÍ TRUNG MSSV:09203063 9 Đồ Án Công Nghệ Chế Tạo Máy GVHD: NGUYỄN PHI TRUNG Phương Án 1 Nguyên công 1: Tiện mặt 1, 3, 4 Phương Án 2 Nguyên công 1: Tiện mặt 5, 6, 8, 2 Z Z Y X Y S o o W S S Nguyên công 2: Tiện mặt 5,... [4]) 5.Thời gian nguyên công: 5.1.Phay thô: T0 = L + L1 + L2 i S n (phút) Trong đó: L : chi u dài bề mặt gia công (mm) L1 : chi u dài ăn dao (mm) L2 : chi u dài thoát dao (mm) S : lượng chạy dao vòng (mm/vòng) n : số vòng quay hoặc hành trình kép trong một phút i : số lần cắt trong 1 nguyên công - Do phay 1 lần hết lượng dư 2 mm nên i = 1 34 SVTH: NGUYỄN CHÍ TRUNG MSSV:09203063 Đồ Án Công Nghệ Chế Tạo... [4]) 5.Thời gian nguyên công: 5.1.Phay thô: T0 = L + L1 + L2 i S n (phút) Trong đó: L : chi u dài bề mặt gia công (mm) L1 : chi u dài ăn dao (mm) L2 : chi u dài thoát dao (mm) S : lượng chạy dao vòng (mm/vòng) n : số vòng quay hoặc hành trình kép trong một phút i : số lần cắt trong 1 nguyên công - Do phay 1 lần hết lượng dư 2 mm nên i = 1 30 SVTH: NGUYỄN CHÍ TRUNG MSSV:09203063 Đồ Án Công Nghệ Chế Tạo... (vòng/phút) Đồ Án Công Nghệ Chế Tạo Máy GVHD: NGUYỄN PHI TRUNG Theo TMM: chọn n =1380 v/ph Vận tốc thực tế : V= π D.nmay π 40.1380 = = 173 1000 1000 (mm/phút) 5.Thời gian nguyên công: 5.1.Tiện thô: T0 = L + L1 + L2 i S n (phút) Trong đó: L : chi u dài bề mặt gia công (mm) L1 : chi u dài ăn dao (mm) L2 : chi u dài thoát dao (mm) S : lượng chạy dao vòng (mm/vòng) n : số vòng quay hoặc hành trình kép trong... Đồ Án Công Nghệ Chế Tạo Máy t 02 = L + L1 17 + 3 = = 0.1 S n 0.15 x1380 t 03 = L + L1 2+3 = = 0.1 S n 0.15 x1380 t 04 = GVHD: NGUYỄN PHI TRUNG L + L1 + L2 1 + 0.5 + 3 = = 0.07 S n 0.61x958 T0 = t01 + t02 + t03 + t04 =0.43 (phút) Thời gian thực hiện: TTC = T0 + T p + T pv + Ttn (phút) Trong đó Ttc: thời gian từng chi c (thời gian nguyên công) T0: Thời gian cơ bản biến đổi trực tiếp hình dáng chi tiết .
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Thiết kế quy trình công nghệ gia công
chi tiết: Ô đỡ trục
Đồ Án Công Nghệ Chế Tạo Máy GVHD: NGUYỄN PHI TRUNG
. MSSV:09203063
Đồ Án Công Nghệ Chế Tạo Máy GVHD: NGUYỄN PHI TRUNG
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CHƯƠNG IV. CHỌN PHƯƠNG PHÁP GIA CÔNG VÀ LẬP QUY TRÌNH
CÔNG NGHỆ
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