, sai ciic he sdhdi (pii Bac ur
5 i=i ^Vf, 1 jt=
3.2.2.4. Phuong trinJi dudng chuixn, khoiing tuyen Ihih va gidi Iiiiii phiit hicii 12
12 -1 op G O O [iTng/ml
/////// 3.10. Dd thi bieu dien su phu thuge ndng do idl vtio tgạ
De Xiiy dung dudng chuan, chiing loi sir dung nhung dieu kien da chgn d uen, cho vao Ciic dug nghiem mil miii, Ihir tu cac dung djch: mSu chuán idl (cd ndng do 0 ; 2; 4; 6; 8; 10; 12 iig/10 m l ) ; 1ml H2SO4 lOM; 1ml CPH lÓ^M; lac deu, rdi dua cac dug (va dung dich H2O2) vao dieu nhiet d nhiet do t = 30 ± 1*'C . Sau 10 phiit them
1ml H2O2IOM, lac deu rdi do do hitp thu d budc sdng X = 525 nm, vdi khoiing each
thdi gian do la mot phiit, den phiit thu tu diing do (khi do do hap thu can tao nhiet do d phdng dat may do la 30 ± l"C). Tir kel qua do do lutp thu quang se tfnh dugc sir phu ihugc ndng do idt theo tga, ket qua thu dugc bieu dien tren hinh 3T0
Sli dung phiin mem Origin de xii If sd lieu, chiing toi tim dugc phuang trinh dudng chuiin nhu sau:
Y(lOỌtga) = 0,832(± 0,155) + 1,034(± 0,026).X
(R = 0,999; p = 0,95 ; SD = 0,214)
Bdng 3.25. Ket quii khiio sal khoang tuyen tfnh
[I] n>i/m] lOỌlga 0 1,07 2 3,18 4 5,17 6 7,32 8 9,65 10 11,14 12 11,06
Két qua thuc nghiem cho tháy dudng chuan chi tuyen tfnh trong khoang (2-10 ng/ml), khi ndng do idl > 12 ng/ml thi do háp thu quang khong dn dinh, do chfnh Xiic giiim. Su dung phuang phiip nghien ciiu tren day, Bing Liang va cong su
da tim dugc khoang tuyen ifnh (1-7 ng/ml); cdn theo Takashi Tomiyasu, lim dugc
khoang luyeii Ihili lir 0,2-10 ng/ml. Cd Ic do 6i6u kiCn moi irudng, ihicl bj cung
nhu hda chat...nen két quii nghien ciiu ciia cluing toi Idn han mgl ft so vai kel qua ciia Ciic tac giii [124], [125]
* Gidi han phai hien
Gidi han phat hien dugc tfnh iheo quy tac " 3 a " (each Inili GHPH nhu trong muc 3.3.1.3). Tii* phuang trinh dudng chuiui d tren, vti sau nhieu liin lien hanh Ihf nghiem lien miiu triuig, nhd viio cong cu phiui mem ciia may tfnh, chiing toi tim dugc GHPH ciia phuang phiip da nghien ciiu nhu sau:
Phuang irinh dudng chuan: Y (lOỌlga) = 0,832(± 0,155) + I,043(± 0,026).X
((R = 0,999 ;p = 0,95). Sb - 0,026 ; Sa = 0,155). => GHPH = 0,6 ng/ml
Tu ket quii tren, da xac dinh dirge GHPH la 0,6 ng/ml