11.16. Dap an dung la Ạ
So mol cac chát:
^0,1775(mol); nco = ^ = 0,145 (mol). 22,4 = 44
Dat CTPT chung cua hai este la C - H j - O j . Phucfng trlnh phan iJng chay:
C - H , - 0 , + ^ ^ 0 2 ^ n C 0 2 + n H 2 0 (1) n 2n 2 3 n - 2 , - , mol n m o l 2 0,1775 0,145 3 n - 2
n, = 3 -> CTPT cua este thii nhát la C3H6O2.
n2 = 4 ^ CTPT cua este thir hai la C4HSO2. 11.17. Dap an dung la C.
Dat CTPT cua hai este la C , H X O O C-Hr.
» y a h
Phuong t r l n h phan iJng xa phong hoa:
C,HyCOOC-H^ + NaOH ^ C.HyCOONa + C - H J ; O H 1,99 g a m x gam 2,05 gam 0,94 gam X = 2,05 + 0,94 - 1,99 = 1 gam.
S6' m o l cac chát tham gia phan iJng va tao thanh d^u bang s6' mo]
NaOH va bang: H N a O H = :;7: = 0,025 9mol). 40 T a b l e t : Mc^H,cooNa =1^-82. 12x + y + 44 + 23 = 82. 12x + y = 15 ^ X = 1, y = 3.
C6ng thiic cáu tao cua axit tao este la: C H 3 C O O H .
Tinh tucrng t u cho hai ancol c6 CTPT chung C - H^ O H, ta dirge ancol thir nhát la CH3OH va ancol t h i i hai la CzH^OH.
11.18. Dap so dung la B.
Cac phuorng t r i n h phan iJng:
H C O O C 2 H , + N a O H ^ H C O O N a + C 2 H, 0 H (1)
CH3COOCH3 + N a O H ^ C H j C O O N a + CH3OH (2)
2C2H5OH ) C2H,-0-C2H5 + H2O (3)
2CH3OH > CH3-O-CH3 + H2O (4)
H C O O C 2 H , va CH3COOCH3 la hai d6ng phan, c6 CTPT la C3H6O
S6' m o l este = = 0,9 m o l . 74
Khd'i lugrng cua HjO thu ducfc la: m = 0,45 . 18 = 8,1 (gam). m = 0,45 . 18 = 8,1 (gam).
11.19. Dap an dung la Ạ
T6ng s6 lien két n trong phan tir CioH^O, Ik: 2.10 + 2-14 .
a - = 4
Theo cac dap an, khi xa phong hoa phan tii C|„H,40, tao thanh 3 phan tir mudi chiia 3 lien ket n (C = O), con lai 1 lien két 7t (C = C). tir mudi chiia 3 lien ket n (C = O), con lai 1 lien két 7t (C = C).
Mu6'i CO kien két 7t (C = C) nhirng khdng c6 d6ng phan hinh hoc. Do
do, chi CO dap an A phu hop.
11.20. Dap ling diing la B. (adsbygoogle = window.adsbygoogle || []).push({});
100 94
S6' mol NaOH = i ^ ^ ^ = 0,6 (mol). 100.40
S6' mol NaOH = 3 s6' mol este E 06 0,2; -> Este E duoc tao thanh tiir ancol ba chiic va hai axit cacboxylic no, don churc. ancol ba chiic va hai axit cacboxylic no, don churc.
Dat c6ng thiic chung cua hai mu6'i diroc tao thknh la C-H2-^,C00Nạ
Ta c6: S6' mol mu6'i = s6' mol NaOH = 0,6 mol.
-> 14n + 45 + 23 = — - 72,67 -> n =0,6 0,3336. n, = 0 -> CTPT cua axit la HCOOH. n, = 0 -> CTPT cua axit la HCOOH.
n2 = 1 ^ CTPT cCia axit la CH3COOH.
Vay hai axit do la: HCOOH va CH3COOH. 11.21. Dap an diing la D. 11.21. Dap an diing la D.