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phần 3 những so sánh giữa lý luận thực tiễn và một số kiến nghị cho công tác huy động vốn tại ngân hàng tmcp công thương việt nam pgd phú nhuận

PERFECTIONNEMENT DE COMMUNICATIONS SECURISEES AGT EN UTILISANT LA CRYPTOGRAPHIE QUANTIQUE

PERFECTIONNEMENT DE COMMUNICATIONS SECURISEES AGT EN UTILISANT LA CRYPTOGRAPHIE QUANTIQUE

Luận văn báo cáo - ngoại ngữ

... Corriger la terre Corriger la terre 1800 km (a) 16 bits/s (b) 33 0 bits/s (c) 33 00 bits/s 33 00 km (a) 16 bits/s (b) 33 0 bits/s (c) 33 00 bits/s Stabilitộ de pointage du systốme optique sur satellite ... 24 3. 1.2 Authentification quantique 27 3. 2 Protocole dauthentification quantique 27 3. 3 Protocole de communication 29 Chapitre Conclusion 31 Acronymes 32 ... formule (3) , on a besoin denviron 43 satellites pour couvrir une surface de largeur de 1040 km Le photon est envoyộ de la station au sol au systốme optique de 30 cm de satellite On a: d = 30 00 km...
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Bài giảng Chapter 7 The Quantum-Mechanical Model of the Atom

Bài giảng Chapter 7 The Quantum-Mechanical Model of the Atom

Hóa học

... 10 -3 J, Epulse/Ephoton = # photons Solve: −9 3. 37 × 10 nm × E photon = hc = λ ( 10 m = 3. 37 ×10 −7 m nm 6.626 ×10 34 J • s 3. 00 ×108 m • s -1 )( 3. 37 × 10 3 10 J 3. 83 mJ × = 3. 83 × 10 3 J ... Calculate the number of photons in a laser pulse with wavelength 33 7 nm and total energy 3. 83 mJ Given: λ = 33 7 nm, Epulse = 3. 83 mJ Find: number of photons Concept Plan: λ(nm) −9 Ephoton λ (m) ... Chemistry: A Molecular Approach −7 m ) = 5.8985 ×10 −19 J number of photons = 3. 83 ×10 3 J 5.8985 × 10 3 J = 6.49 × 1015 photons 32 Practice – What is the frequency of radiation required to supply 1.0...
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Tài liệu THE QUANTUM IN CHEMISTRY: An Experimentalist’s View pptx

Tài liệu THE QUANTUM IN CHEMISTRY: An Experimentalist’s View pptx

Hóa học - Dầu khí

... Constant 30 4 7.2 Reactions Involving Gases and Pure Solids or Liquids 31 0 7 .3 Chemical Equilibrium in Solutions 31 5 7.4 Equilibria in Solutions of Strong Electrolytes 32 8 7.5 Buffer Solutions 33 1 7.6 ... independent variables 7 P 1.1 Introduction 105 105 3 105 P/Nm22 T 1000 K T 500 K 2 73 3 105 T 37 3 K T 2 73 K 105 37 3 500 T 1000 0.05 (a) 0.1 0.1 m 0.05 Vm/m3 mol21 V (b) Figure 1.1 (a) The pressure of ... Thermodynamics of Solutions 237 6.1 Ideal Solutions 238 6.2 Henry’s Law and Dilute Nonelectrolyte Solutions 6 .3 Activity and Activity Coefficients 258 6.4 The Activities of Nonvolatile Solutes...
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Tài liệu Đề tài

Tài liệu Đề tài " Asymptotic faithfulness of the quantum SU(n) representations of the mapping class groups " pdf

Thạc sĩ - Cao học

... 1998), 137 – 139 , Contemp Math 233 , A M S., Providence, RI, 1999 [M2] ——— , Quantum representations of mapping class groups, in Groupes et G´om´trie (Journ´e annuelle 20 03 de la SMF), 19 36 , 20 03 e ... (1989), 53 94 e [Fal] G Faltings, Stable G-bundles and projective connections, J Algebraic Geom (19 93) , 507–568 [Fr] D S Freed, Classical Chern-Simons theory, Part 1, Adv Math 1 13 (1995), 237 – 30 3 [FWW] ... The Poisson structure on the moduli space of flat connections and chord diagrams, Topology 35 (1996), 1069– 10 83 ASYMPTOTIC FAITHFULNESS 36 7 [AMR2] ——— , Quantization of the algebra of chord diagrams,...
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The Quantum-Mechanical Model of the Atom pdf

The Quantum-Mechanical Model of the Atom pdf

Kĩ thuật Viễn thông

... 7 .3) SOLUTION l = 33 7 nm * 10-9 m = 3. 37 * 10-7 m nm m b (6.626 * 10 -34 J # s )a 3. 00 * 108 s hc Ephoton = = l 3. 37 * 10-7 m -19 = 5.8985 * 10 J 10 -3 J 3. 83 mJ * = 3. 83 * 10 -3 J mJ E pulse 3. 83 ... Photon Energy A nitrogen gas laser pulse with a wavelength of 33 7 nm contains 3. 83 mJ of energy How many photons does it contain? SORT You are given the wavelength and total energy of a light ... Practice 7.2 Example 7 .3 For Practice 7 .3 Exercises 3, Example 7.4 For Practice 7.4 Exercises 15–18 Examples 7.5, 7.6 For Practice 7.5, 7.6 Example 7.7 For Practice 7.7 Exercises 35 38 Exercises 21–28...
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Báo cáo

Báo cáo "Quantum kinetic equation in the quantum hadrondynamics (QHD-I) model " pptx

Báo cáo khoa học

... defined by ++ > < So (k, t, t′) =So (k, t, t′ )θ(t − t′ ) + So (k, t, t′)θ(t′ − t), −− So (k, t, t′) −+ So (k, t, t′) +− So (k, t, t′) > =So (k, t, t′ )θ(t′ > =So (k, t, t′ ), < =So (k, t, t′ ), ... 3 ), iSφ = δΦ jφ = (32 ) (33 ) and δL µ µ µ = Zω + (m2 + δm2 )ω µ = Jω = −jω + iSω , ω ω δωµ (34 ) where δLCT , δW µ µ jω =W µ (m2 + δm2 ) = W W (35 ) δLL ¯ = gω Zgω Ψγµ Ψ δW µ µ Eqs. (31 ) and (34 ) ... approximate Φ2 and W2 by their thermal equilibrium values d3 k nB (ωk ), (2π )3 k d3 k nµν (ωk ) =δµν 3 (2π) k B Φ2 = W = δµν W µ W ν ( 73) (74) To two - loop order, the Feynman diagrams that contribute...
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Đề tài

Đề tài " On the distribution of matrix elements for the quantum cat map " pptx

Thạc sĩ - Cao học

... and 3 : µ4 = µ2 − 3 N2 − µ2 3 µ2 = 3 , 3 − µ2 N3 − µ2 3 which in turn gives that µ2 − 3 µ2 − 3 3 − µ2 µ2 − 3 µ2 − 3 µ2 3 − N3 µ2 − 3 ( 3 − µ2 ) + µ2 = 3 = µ2 = 3 − µ2 3 − µ2 3 ... µ2 = 3 , µ1 = µ4 or µ4 = µ2 − 3 N2 − µ2 3 µ2 = 3 , 3 − µ2 N3 − µ2 3 µ1 = µ2 − 3 µ2 3 − N3 3 = µ2 3 − µ2 µ2 3 − N2 We note that the first case can only happen if N1 = N2 and N3 = N4 ... families µ2 = 3 , µ1 = µ4 and µ4 = N2 − µ2 3 3 = 3 , N3 − µ2 3 µ1 = µ2 3 − N3 µ2 = µ2 µ2 3 − N2 If C = and N1 = N4 = N2 = N3 then K = and there is a family of solutions given by µ2 = 3 , µ1...
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the quantum physics of black holes and string theory

the quantum physics of black holes and string theory

Vật lý

... 33 35 39 ABSORPTION BY THREE-BRANES 39 Classical Solution and Classical Absorption Absorption in the Microscopic Model ... Bekenstein JD Phys Rev D 7: 233 3 (19 73) ; Bekenstein JD Phys Rev D 9 :32 92 (1974) Pelath MA, Wald RM gr-qc/9901 032 (1999) Hawking S Commun Math Phys 43: 199 (1975) Hawking S Phys Rev D 13: 191 (1976) Hawking ... Phys Lett B375:1 03 (1996) 30 Maldacena J, Susskind L Nucl Phys B475:679 (1996) 31 Callan C, Maldacena J Nucl Phys B472:591 (1996) 32 Horowitz G, Strominger A Phys Rev Lett 77: 236 8 (1996) 33 Das SR,...
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scientific american   -  1993 04  -  controlling the quantum jitters of atoms

scientific american - 1993 04 - controlling the quantum jitters of atoms

Toán học

... April 19 93 49 1900 1990 2050 AGE 85+ 80–84 75–79 70–74 65–69 60–64 55–59 50–54 45–49 40–44 35 39 30 34 25–29 20–24 15–19 10–14 5–9 0–4 400 30 0 200 100 MALE POPULATION (MILLIONS) 0 100 200 30 0 400 ... PREDICTION 50 40 30 OBSERVED 20 PREDICTION AS OF 1 935 10 1 935 1945 1955 1965 1975 SOURCE: Social Security Administration 1985 YEAR 1995 2005 2015 2025 STRAINS ON SOCIAL PROGRAMS, such as Social Security ... Director, New Business Development CHICAGO: 33 3 N Michigan Avenue, Chicago, IL 60601; Patrick Bachler, Advertising Manager DETROIT: 30 00 Town Center, Suite 1 435 , SouthÞeld, MI 48075; Edward A Bartley,...
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squires, the mystery of the quantum world (second edition)

squires, the mystery of the quantum world (second edition)

Vật lý

... about a system, as in 53. 2, but as something that really exists, something that is, indeed, part of the external reality which we observe There are at least three good reasons why we should want ... me, and to react in similar ways, so, from the existence of my conscious mind, I can reasonably infer the existence of real people, distinct from myself, also with conscious minds Finally, these ... barrier, at which stage it makes a ‘choice’, either through a hidden variable procedure or with some degree of randomness, as to whether to pass through or not Such a choice would be made regardless...
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Báo cáo hóa học:

Báo cáo hóa học: " Effects of Shape and Strain Distribution of Quantum Dots on Optical Transition in the Quantum Dot Infrared " doc

Hóa học - Dầu khí

... C11(GPa) C12 (GPa) 83. 29 45.26 C44 (GPa) ˚ Kr (GPaA) 39 .59 60.0 170. 13 215.09 9.59 15.41 59 .31 5 74.85 ˚ KX (GPaA) ˚ Krr (GPaA) 122.1 56.6 Nanoscale Res Lett (2008) 3: 534 – 539 537 has effect on the ... pyramid QD 1.8 1.6 1.4 1.4 633 eV 1 .34 25 eV Energy (EV) 0.8 0.6 1.29 03 eV 1.2 1.0 0.8 0.8 0.6 CB HH LH 1.2 1.0 1.0884 eV 0.6 0.4 0.0978 eV 0.2 0.0 -0.2 -30 -20 -10 10 20 1. 133 9 eV 0.4 0.0809 eV 0.09247 ... 0.0809 eV 0.09247 eV 0.2 0.0 lens QD 1.4 1 .30 83 eV 0.4 0.2 1.8 1.6 1.4 1.2 1.0 Truncated pyramid QD 1.6 0.0 -0.2 30 -30 -20 -10 10 20 -0.2 30 -30 -20 -10 10 20 30 Z Axis (nm) difference of electron...
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The Quantum Mechanics Solver 28 docx

The Quantum Mechanics Solver 28 docx

Khoa học xã hội

... 29, 32 cesium atom, 2 83 cesium atoms, 279 • CH3 (methyl), 239 CH3 −• COH−COO− , 240 chain of coupled spins, 2 03 chain of molecules, 204 coherence properties, 1 93 collision, 12 condensate, 1 93 conductor, ... pigments, 231 polyethylene, 231 positive muon, 245 positron, 73, 2 53 positronium, 73 potential well, 231 precession, 65 satellite, 32 scalar product, scattering, 12 scattering amplitude, 13 scattering ... matter, 87 isotope, 69 atom, 73, 81 interaction, 29, 237 , 238 splitting, 73 structure, 237 transition, 74 Jacobi variables, 187, 190 joint probability, 165 KamLAND, 19 ket, G.P.S., 29, 32 gravitational...
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The Quantum Mechanics Solver 1 ppsx

The Quantum Mechanics Solver 1 ppsx

Khoa học xã hội

... 32 32 33 Neutron Interferometry 3. 1 Neutron Interferences 3. 2 The Gravitational Effect 3. 3 ... 235 23 Hyperfine Structure in Electron Spin Resonance 237 23. 1 Hyperfine Interaction with One Nucleus 238 23. 2 Hyperfine Structure with ... 231 22.2 Nitrogenous Ions 232 22 .3 Solutions 233 22.4 Comments ...
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The Quantum Mechanics Solver 2 docx

The Quantum Mechanics Solver 2 docx

Khoa học xã hội

... Fourier transform ϕ(p): ϕ(p) = (2π¯ )3/ 2 h h e−ip·r/¯ ψ(r) d3 r is the probability amplitude to find that the particle has a momentum p Operators Among the operators associated to usual physical quantities, ... and so on (with ues {a1,α }), N2 measurements of A p i=1 Ni = N ), we can determine the probability distribution of the ai,α , ˆ ˆ and therefore the Pi,α |ψ If the p operators Ai are well chosen, ... of the system at time t If we consider an isolated system, whose Hamiltonian is time-independent, the energy eigenstates of the Hamiltonian |φn are the solution of the time independent Schr¨dinger...
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The Quantum Mechanics Solver 3 docx

The Quantum Mechanics Solver 3 docx

Vật lý

... c 23 s 23 ⎠ ⎝ iδ −s 23 c 23 0 −s 13 e c 13 where cij = cos θij and sij = sin θij The complete experimental solution of the problem would consist in measuring the three mixing angles θ12 , θ 23 , θ 13 ... U , ⎞ ⎛ Ue1 Ue2 Ue3 ⎟ ˆ ⎜ Uαi |νi , U = ⎝ Uµ1 Uµ2 U 3 ⎠ |να = (1.8) i=1 Uτ Uτ Uτ ∗ This matrix is unitary ( i Uβi Uαi = δαβ ) and it can be written as: ⎞ ⎞⎛ ⎞⎛ ⎛ s 13 e−iδ c 13 c12 s12 0 ˆ ⎠ ⎝ ... bj The form factor Fj is defined by: Fj (q) = h eiq·rj /¯ |ψ0 (r , , r j , , r n )|2 d3 r1 d3 rj d3 rn In general, interference effects can be observed between the various q contributing...
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