nhung bai tap vat ly hay lop 6

... 80 6 cos(ωt + π 6 ) V, u C = 40 2 cos(ωt – 2π 3 )V, điện áp hiệu dụng ở hai đầu điện trở là U R = 60 3 V. Hệ số công suất của đoạn mạch trên là A. 0, 862 . B. 0,908. C. 0,753. D. 0 ,66 4. ...  1 π u=3cos(40πt + )cm 6 ; 2 5π u=3cos(40πt - )cm 6 . Vn tc truyn sóng 60 cm/s. Tìm s ng v n O 1 O 2 ? A. 16 B. 8 C. 9 D. 18 Câu 48:  AB ... C. 126W D. 96W Câu 34. Cho mạch điện RLC mắc nối tiếp, trong đó RC 2 < 2L. Đặt vào hai đầu đoạn mạch điện áp xoay chiều u = U 2 cos 2ft, trong đóng U có giá trị không đổi, f có thể thay...

Ngày tải lên: 30/05/2014, 11:49

... 0 1 73,8 tan 1, 4 76 55,9 55 54' 50 x h α α = = = ⇒ = = + H ng th 2, ch y xi t vào trong đo n AH, h p v i MH góc ướ ứ ạ ế ạ ợ ớ β v i:ớ 0 0 2 25, 4 tan 0,508 26, 93 26 56 ' 50 x h β ... = Vì v 1 = 3v 2 => S 1 = 3S 2 hay a + x = 2 2 h x+ 2 2 2 2 2 2 ( ) 9( ) 8 2ax+9h 0a x h x x a⇔ + = + ⇔ − − = thay s vào ta có:ố 8x 2 -100 15 -6. 50 2 = 0 ph ng trình có 2 nghi m: xươ ... n t c ta có:ứ ộ ậ ố 13 12 23 v v v= + r r r V i: vớ 12 = 1000 0,9( / ) 15 .60 AB m s t = = v 23 = 500 5 ( / ) 15 .60 9 BC m s t = = Vì phà luôn chuy n đ ng vuông góc v i b sôngể ộ ớ ờ nên 12 v r ...

Ngày tải lên: 07/07/2014, 10:45

Ngày tải lên: 12/09/2013, 02:49

... A. 6 10 6  s B. 6 10 3  s C. 6 10 2  s D. 6 10 12  s Câu 21: Mắc vào hai đầu đoạn mạch RLC nối tiếp gồm một nguồn điện xoay chiều có tần số f thay đổi đượC. Khi tần số f 1 = 60 Hz, hệ ... 80 6 cos(ωt + π 6 ) V, u C = 40 2 cos(ωt – 2π 3 )V, điện áp hiệu dụng ở hai đầu điện trở là U R = 60 3 V. Hệ số công suất của đoạn mạch trên là A. 0, 862 . B. 0,908. C. 0,753. D. 0 ,66 4. ... max T t = 0,1= T = 0,6s S = 2A +A = 60 cm 6  Câu 6: Vật có tốc độ cực đại khi gia tốc bằng 0; tức là lúc hl dh ms F = F +F = 0 lần đầu tiên tại N Là lạ & kho khó 1.0 | 16 Xét đoạn chứa...

Ngày tải lên: 03/01/2014, 20:17

... 139:MộtnhàmáyđiệnnguyêntửcócôngsuấtP= 6. 10 5 kW,hiệusuất20%.NhiênliệulàUđượclàm giàu25%.Muốnchonhàmáyhoạtđộngliêntụctrong1nămcầnphảicungcấpchonókhốilượngquạngcầnlà baonhiêu,biếtnănglượngtrungbìnhtỏaracủamộtphânhạchlà200MeV.1nămcó 365 ngày. A.1154kg. B. 461 6kg. C. 461 6tấn. D.185kg. ChọnB.   27 A P.t P.t H N 2,9 565 .10 E.N H. E N m M 1153540 ,6 g N          *Khốilượngquặngcầndùng:  ... 32:NguồnsóngởOdaođộngvớitầnsố10Hz,daođộngtruyềnđivớivậntốc0,4m/strêndâydài.Trên phươngnàycó2điểmPvàQtheothứtựđóPQ=15cm.Chobiênđộa=10mmvàbiênđộkhôngđổitrong quátrìnhtruyềnsóng.NếutạithờiđiểmnàođóPcóliđộ0,5cmdichuyểntheochiềudươngthìliđộtạiQlà: A.-1cm. B.-0,5cm. C.8 ,66 cm. D 8 ,66 mm. ChọnC. *λ=4cm. 2 .15 7,5 4       *QtrễphahơnPmộtlượng=π+π/2 *Dựavàohìnhvẽthìu Q =10cos30=8 ,66 mm. Câu 33:M,NlàhaiđiểmtrêncùngmộtphươngtruyềnsóngcủasóngmặtnướcMN=5,75λ.Tạimộtthời điểmnàođóMvàNđangcóliđộlàu M =3mm,u N =-4mm,mặtthoángởNđangđilêntheochiềudương.Coi biênđộlàkhôngđổi.BiênđộsóngtạiMvàchiềutruyềnsónglà: M ...  ,nướctrong tựnhiêncólẫn0,015%D 2 O,vớikhốilượngriêngcủanướclà1000kg/m 3 ,1u=931,5MeV/c 2 ,N A =6, 022.10 23  mol -1 .Nếutoànbộ 2 1 D đượctáchratừ1m 3 nướclàmnhiênliệuchophảnứngtrênthìnănglượngtỏaralà: A. 1, 863 .10 26 MeV. B. 1,0812.10 26 MeV. C. 1, 061 4.10 26 MeV....

Ngày tải lên: 28/04/2014, 11:48

... > d = (k + 2 1 ) = 1,6k + 0,8 d 2 = AO 2 + x 2 = 6 2 + x 2 > (1,6k +0,8) 2 = 36 + x 2 > 0  x 2 = (1,6k +0,8) 2 – 36  64 O C N B A NGUOITHAY.VN 10 4 72 4 AB AB ... tan 3 2  t = 3 = tan 6  > 3 2  t = 6  + k > t = 4 1 + 2 3k x = 6cos( 3 2  t - 6  ) = x = 6cos[ 3 2  ( 4 1 + 2 3k ) - 3  ] x = 6cos(k - 6  ) = ± 3 3 cm = ± 5,19 ... +1,5k ≤ 20 > - 6 ≤ k ≤ 6 > Trên đng tròn có 26 đim dao đng vi biên đ cc đi im gn đng thng AB nht ng vi k = 6 im M thuc cc đi th 6 d 1 – d 2 = 6 = 18 cm; d 2 ...

Ngày tải lên: 13/05/2014, 13:33

... 2(T/12+T/4)=2T/3=2.0.02/3=1/75s. 2phut =60 00T.vậy đáp số là 60 00.1/75=80s. AS6:Chiếu sáng hai khe Yang đồng thời 2 bức xạ đơn sắc có lamda1 = 0.45 micromet và lamda2 (từ 0 .64 đến 0. 76 micromet ). O và M là ... là ? A.n1=240 (vòng/phút) và n2= 960 (vòng/phút) B.n1= 360 (vòng/phút) và n2 =64 0 (vòng/phút) C.n1=120 (vòng/phút) và n2=1920 (vòng/phút) D.n1=300(vòng/phút) và n2= 768 ( vòng/phút ) Bài này giải tà ... điện năng là 60 %. Để hiệu suất truyền tải tăng đến 90% mà công suất truyền đến nơi tiêu thụ vẫn không thay đổi thì điện áp hiệu dụng đưa lên 2 đầu đường dây bằng bao nhiêu? D.1 46, 67V nhờ giúp...

Ngày tải lên: 23/05/2014, 20:08

... 4 10cos(20 ) 10 6 i x t x e π π π = + ↔ = Bấm: 10 6 3 4 3 10 6 2 6 π π π ∠ − + ∠ − − + ∠ , SHIFT, 2, 3 máy s ẽ hi ệ n 6 6 4 π ∠ − Kết quả: 6 6 cos(20 )( ) 4 x t cm π π ⇒ = − Ví dụ 7: Hai ... máy FX570ES : 6 1 1 10cos(20 ) 10 6 i x t x e π π π − = − ↔ = , 2 2 2 6 3 cos(20 ) 6 3 2 i x t x e π π π − = − ↔ = 3 1 4 3cos(20 ) 4 3 x t x π = − ↔ = − , 6 4 4 10cos(20 ) 10 6 i x t x e π π π = ... - 09 068 48238 Trang 16 Email: doanvluong@yahoo.com ; doanvluong@gmail.com Trang 16 C L A B R M A. AB u 15 6 cos(200 t / 6) (V) = π − π B. ( ) AB u 15 6 cos 200 t / 6 (V) = π + π C....

Ngày tải lên: 12/06/2014, 16:48

... đến Anot: 1 2 mv 2 2 = eU AK =⇒ v 2 = 0 .66 .10 6 m/s Vậy 0, 66 .10 6 ≤ v 2 ≤ 0, 97.10 6 19 Cho dây AB cố định cố thể thay đổi l bằng ròng rọc. f = 20 Hz, khi thay đổi l ta thấy giữa 2 lần có sóng ... anot là v thõa mãn: A. 0m/s ≤ v ≤ 0, 97.10 6 m/s B. 0, 66 .10 6 m/s ≤ v ≤ 0, 97.10 6 m/s C. 0, 71.10 6 m/s ≤ v ≤ 0, 97.10 6 m/s D. 0m/s ≤ v ≤ 0, 71.10 6 m/s Hướng Dẫn http.//boxmath.vn/ TUYỂN TẬP ... = m.v 2 2 => v =  13, 92.1, 6. 10 −13 .24, 0015.1, 66 .10 −27 =  6, 7.10 14 Ta có: q.v.B = m.v 2 r => r = m.v q.B ⇐⇒ 4, 0015.1, 66 .10 −27 .  6, 7.10 14 2.1, 66 .10 −19 .0, 5 = 1, 07m 21 Một sợi dây căng...

Ngày tải lên: 21/06/2014, 06:20

... 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Ngày tải lên: 18/07/2014, 18:22

... x x + + 3 6, 32,4 I = BD R U = x x + + 3 6, 32,4 6 = 6, 32,4 )3 (6 + + x x U 13 = I. R 13 = 6, 32,4 )3 (6 + + x x .1,2 = 6, 32,4 )3(2,7 + + x x I 1 = 1 13 R U = 3 6, 32,4 )3(2,7 + + x x = 6, 32,4 )3(4,2 + + x x U 24 ... I 2 - I 1 = 6, 32,4 .6 +x x - 6, 32,4 )3(4,2 + + x x = 6, 32,4 2, 76, 3 + − x x I A = x x 6, 3 2,4 2,7 6, 3 + − (2) Biện luận : + Khi x tăng từ 2 ( Ω ) trở lên thì x 2,7 và x 6, 3 đều giảm ... = I 1 - I 2 = 6, 32,4 )3(4,2 + + x x - 6, 32,4 .6 +x x = 6, 32,4 6, 32,7 + − x x (1) Biện luận : Khi x = 0 → I A = 2 (A) Khi x tăng thì (7,2 - 3 ,6. x) giảm ; (4,2.x + 3 ,6) tăng do đó I A ...

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