... key words -Work individually - Speak aloud the new words and elicit their meaning - Guess what topic you will listen today - Work individually - Read all statements to understand and underline ... 11.walked 12.would understand Main clause a < /b> They would give the good marks b He would be fit c I could invite many friends to my house d She would be fat IV-Consolidation: - Summarize the main points ... and remember -T may delete the English words and asks Ss to write them again -Read them carefully WHILE READING: (15ms) TASK 1: GAP-FILLING -Read the passage quickly and stop at the lines that...
... Hng dn: I PHN CHUNG ộx = Cu I: 2) y = x - 4 (m - m + 1) x ; y = ởx = m - m +1 ổ 1ử Khong cch < /b> gia cc im cc tiu: d = m - m + = ỗ m - ữ + ị Mind = m = ố 2ứ p Cu II: 1) PT sin3 ... SH ^ PD ị SH ^ ((PQCD) ị VS PQCD = SPQCD SH = 3 ãC th d ng c ng thc t s th t ch:< /b> ỡVS.PQC SP SQ 2 4 = = ị VS.PQC = VS ABC = a < /b> ù 27 10 ù VS ABC SA SB 3 ị VS PQCD = VS PQC + VS PCD = a < /b> 27 ... , D) = ù ộ a < /b> = 2, b = -1, c = -10 ộ D : x - y - 10 = Gi s (D) : ax + by + c = (c 0) T: ị a < /b> = 1, b = 2, c = -10 ị D : x + y - 10 = ở ùcos (d , D) = ợ uuu r uuu r 2) Ly B ẻ (d1 ), C ẻ (d2 ) T : AB...
... SD, Q = BM ầ AD ị P l trng t m DSCM, Q l trung im ca MB ã VMDPQ VMCNB = MD MP MQ 1 = = ị VDPQCNB = VMCNB MC MN MB 6 ãVỡDl trung im ca MC nờn d ( M ,(CNB)) = 2d (D ,(CNB)) ị VMCNB = 2VDCNB ... 2) Gi ud , uD , nP ln lt lcc VTCP ca d, D v VTPT ca (P) Gi s ud = (a;< /b> b; c ) (a2< /b> + b2 + c 0) r r ãVỡd è (P) nờn ud ^ nP ị a < /b> - b + c = b = a < /b> + c (ã ) ãd , D = 450 a < /b> + b + 2c 2 a < /b> +b +c = ... 2VDCNB = VDCSB = VS ABCD ị VDPQCNB = VSABNPQ 7 VS ABCD ị VSABNPQ = VS ABCD ị = 12 12 VDPQCNB Cu V: T gi thit x + y + z2 = ị < x , y, z < ã p dng BT C si cho s dng: x ,1 - x - x ta c: Trn S...
... VKMCAND, V2 = VKBB C MAA D N ED.SD ADN = a3< /b> 7 29 EK EM EC a < /b> = = ị V1 = VKMCAND = VEAND = a3< /b> = a3< /b> , V2 = Vhlp V1 = 8 36 36 EA EN ED ã Vhlp = a3< /b> , ã VEKMC VEAND ị VEAND = V1 = V2 29 Cu ... - ữdx = x + - ln x + x + ỷ ỗ ữ x +1 ứ ố x +1 = + ln ( + ) - ln ( + ) Cu IV: Gi E = AK ầ DC, M = IE ầ CCÂ, N = IE ầ DDÂ Mt phng (AKI) chia hỡnh lp phng thnh hai a < /b> din: KMCAND v KBB C MAA D N ... IK ^ AB AB = ị CH < /b> = 2SD ABC AB = ịIK = 1 Gi s I (a;< /b> 3a < /b> 8) ẻ dCH < /b> = a < /b> = Phng tr nh AB: x - y - = d ( I , AB) = IK - a < /b> = ị I(2; 2) hoc I(1; 5) a < /b> = ã Vi I(2; 2) ị C( 1; 1) ã Vi I(1; 5) ị C( 2;...
... v ch < /b> a < /b> = b = c = II PHN T CHN Theo chng tr nh chun Cu VI .a:< /b> 1) Gi A1< /b> , A2< /b> ln lt l im i xng ca A < /b> qua BBÂ, CCÂ ị A1< /b> , A2< /b> ẻ BC Cu V: p dng bt ng thc uuu r uuu r T m c: A1< /b> (0; 1), A2< /b> (2; 1) ị Png tr nh ... Theo chng tr nh nõng cao Cu VI .b: 1) Ch< /b> ý: d1 ^ d2 v DABC vuụng c n ti A < /b> nờn A < /b> cch < /b> u d1 , d2 ị A < /b> l giao im ca d v ng phõn gi c ca g c to bi d1 , d2 ị A(< /b> 3; 2) uuu r uuu r Gi s B( 1; b) ẻ d1 , C( c; ... 2a < /b> + b + c + - 4a < /b> - 2b - 2c 2a < /b> + b + c 2a < /b> + b2 + c + a < /b> + 2 (a < /b> - 1) + (b - 1) + (c - 1) 2 Tng t: ; 2b + c + a < /b> b + 2c + a < /b> + bc + 1 4 T ú suy ra: + + + + a+< /b> bb +c c +a < /b> a +7 b +7 c +7 ng thc...
... MN ^ A< /b> C, DBÂMN c n ti B ị MN ^ B O ị MN ^ (A< /b> B C) ãV MAÂ BC 1 a < /b> a3 a3< /b> = MO.SD A< /b> BC = ịV ÂÂ = 2VMAÂ BC = a.< /b> a = BA < /b> MCN 3 2 ã Gi j l g c gia hai mt phng (A< /b> MCN) v (ABCD), P l trung im ... chng tr nh nõng cao Cu VI .b: 1) T mc M( 3; 0) ị MI = ị AB = ị AD = 2 Phng tr nh AD: x + y - = Gi s A(< /b> a; a)< /b> (vi a < /b> < 3) Ta c AM = a < /b> = ị A(< /b> 2; 1) T ú suy ra: D( 4; 1), B( 5; 4), C( 7; 2) 2) iu ... im ca CD ị NP ^ (ABCD) SDMCN = S a2< /b> a2< /b> 6 , SDMCP = ị cos j = D MCP = 4 SDMCN x y z 1 + + = v xyz = x + y + z2 xy + yz + zx ị + + Ê yz xz xy x y z 1 ã Ch< /b> ý: Vi a,< /b> b > 0, ta c : Ê + a+< /b> ba < /b> b...
... ố 2ứ 2ố 2ứ 20 a < /b> Cu IV: Gi H, M, I ln lt l trung im ca AB, AC, AM ị SH ^ (ABC), ã = a < /b> SH = IH tan a < /b> = tan a < /b> SIH a < /b> ị VS ABC = SH SD ABC = tan a < /b> 16 1 Ê + a+< /b> ba < /b> b ổ 1 1 1 1ổ 1 ổ 1 1005 ịPÊ ỗ ... zứ Cu V: ã Ch< /b> ý: Vi a,< /b> b > 0, ta c : Du "=" xy x = y = z = 1005 Vy MinP = 670 II PHN T CHN Theo chng tr nh chun Cu VI .a:< /b> 1) Gi s: AB: x y + = , AC: x + y 21 = Suy ra: A(< /b> 0; 3) BO ^ AC ... P)) = a < /b> ữ AB = 9 ứ 3 ố 2 AB = d (A,< /b> (P)) 2a < /b> - a < /b> + = a < /b> a < /b> = ị A(< /b> 3; 0; 0) 3 Cu VII .a:< /b> Gi s s tho l: a1< /b> a2 a3< /b> a4 a5< /b> ị B Trn S Tựng a+< /b> 3 ã Nu a1< /b> = thỡ c : A7< /b> = 840 (s) 3 ã Nu a2< /b> = thỡ c : C6 A6< /b> =...
... + CO 2 a < /b> T (1) v (2) ị = = = = ị KI = SO = SO CA 2CO 2CO 3 a < /b> 3 Ta c : DADC u ị CM ^ AD v CM = ị SBCDM = ( DM + BC ).CM = a < /b> 2 Ta c : DSOC ~ DKIC ị Trn S Tựng a3< /b> KI SBCDM = x 3x2 x x Cu V: Ta c ... 117p Cu IV: Gi N = BM ầ AC ị N l trng t m ca DABD K NK // SA (K ẻ SC) K KI // SO (I ẻ AC) ị KI ^ (ABCD) Vy VK BCDM = KI SBCDM KI CK CK CN = (1), DKNC ~ DSAC ị = (2) SO CS CS CA KI CN CO + ON CO ... Theo chng tr nh nõng cao Cu VI .b: 1) Ta cA < /b> = AD ầ AM ị A(< /b> 9; 2) Gi Cl im i xng ca C qua AD ị C ẻ AB x -9 y+2 = x + 7y + = - -1 + Vit phng tr nh ng thng Cx // AB ị (Cx): x + y - 25 = Ta tỡm...
... c im tho YCBT: M1 (0; 5), M2 (0; 5) uu r uu r uur r ổ 23 13 25 2) Gi I l im tho: IA + IB + 3IC = ị I ỗ ; ; ữ ố 6 ứ uuur uuur uuur uuu uu r r uuu uu r r uuu uur r uuu r uuu r Ta c : T = MA + MB ... trung trc ca BC DABC vuụng c n ti A < /b> nờn AI cng l phõn gi c ca ã BAC ợIB = IC Do ú AB v AC hp vi AI mt g c 450 ã Gi dl ng thng qua A < /b> v hp vi AI mt g c 450 Khi ú B, Cl giao im ca d vi (C) v AB ... ứ0 1 a < /b> a2 a3< /b> Cu IV: Vỡ ABB A< /b> l hỡnh b nh hnh nờn ta c : VC ABB ' = VC AB ' A < /b> ' M VC ABB ' = A< /b> M S ABC = = 3 Vy, VC ABB ' A < /b> ' = 2VC ABB ' = a3< /b> a3< /b> = Cu V: Ta c : P = x + (2 - y)2 +...
... ) d (sin x ) = 15 p p ũ (1 + cos x ).dx = 20 p 15 Cu IV: Gi E l trung im ca AB ị BC = a < /b> Trong tam gi c BIC, k ng cao IF, ta c : IF = Ta c : SBIC = S ABCD - SABI - SCDI 2SBIC BC = 3a < /b> 3a < /b> T ... + 3uv Ê + (u + v )2 ị (u + v )2 Ê ị u + v Ê T (3) v (4) ta suy c iu cn chng minh (2) II PHN T CHN Theo chng tr nh chun uu r Cu VI .a:< /b> 1) Gi s E (a;< /b> a)< /b> ẻ D ị IE = (a < /b> - 6;3 - a)< /b> uuur Gi P l im i ... im i xng ca E qua I ị P(12 a;< /b> a < /b> 1), MP = (11 - a;< /b> a < /b> - 6) uuur uu r a < /b> = Ta c : MP.IE = (11 - a)< /b> (a < /b> - 6) + (a < /b> - 6)(3 - a)< /b> = a=< /b> 7 uu r ng thng i qua M( 1; 5) v nhn IE lm VTPT uu r ã Vi a < /b> = ị IE...
... giao im AC v BD ị SO ^ ( ABCD ) Ta c : SO = S ABCD = a < /b> ị VS ABCD = SA2 - OA2 = a < /b> - 2a < /b> a = a < /b> Gi M, N l trung im AB v CD v I l t m ng tr n < /b> ni tip tam gi c SMN Ta chng minh I cch < /b> ucc mt ca ... uuu r IM = ( -1; 0; -3) ị R = IM = 10 lb n kớnh mt cu cn t m Kt lun: PT mt cu cn t ml ( x - 1) + ( y + ) + ( z - 3) = 10 2 2 Theo chng tr nh nõng cao Cu VI .b: 1) iu kin : x > BPT ( + log3 ... dt = -2cos x sin xdx ổ + cos x 1 ổ 1ử t +1 dt = ũỗ - ữ dt = ln + C = = ln ỗ ữ +C ố cos x ứ t ũ t ( t + 1) ố t + t ứ ( ) Cu VII .a:< /b> Gi Ml hỡnh chiu ca I 1; -2;3 l n Oy, ta c : M ( 0; -2; ) uuu...
... = = ị AT P DP ị = = = M: TC AC QA AT CA VA.PQN AP AQ 1 Nờn: = = = ị VA.PQN = VABCD VA.CDN AC AD 5 10 V DDÂ // BC, ta c : DDÂ=BM ị V: VC PMN CP CM 1 = = = ị VABMNP = VABCD VC ABN CA CB 4 (1) ... ) ổ - m ử3 im un U nm tr n th hm s y = x thỡ + =ỗ ữ m= 5 27 ố ứCu VII .b: Ta c : AB = BC = CA = ị DABC u Do ú t m I ca ng tr n < /b> ngoi tip DABC l trng t m 3 ca nú ổ 8ử ố 3 3ứ Kt lun: I ỗ - ; ; ... -1 Cu III: Ta c : f ( x ) = ỗ ữ ố 2x +1 ứ ổ x - ửÂ ổ x -1 ỗ ữ ị F (x) = ỗ ữ +C ố 2x +1 ứ ố 2x +1 ứCu IV: Gi T l giao im ca MN vi CD; Q l giao im ca PT vi AD TD DD ' = = TC MC TD AP QD DP CP...
... Program block System block V memory Program block Program block System block Data block System block Data block M memory M memory (permanent area) Timer and Counter current values Forced values ... Program block System block V memory M memory Timer and Counter current values Program block System block Data block Forced values System block Data block M memory (permanent area) All other areas ... RAM S7-200 CPU Program block System block V memory M memory Timer and Counter current values Forced values Program block Program block System block Data block M memory Forced values Sets all...
... AH ^ ( A < /b> ' BC ) ị AH = 1 a < /b> = + ị AA ' = Mt kh c: 2 AH A'< /b> A < /b> AM 3a < /b> Kt lun: VABC A < /b> ' B ' C ' = 16 a2< /b> ab ab Cu V: Ta c : =aa=aab (1) a < /b> +b a+< /b> b 2 ab b2 c2 bbc (2), cca (3) b+ cc +a < /b> a2 b2 c2 Cng (1), ... -1 (loaùi ) f Â(t ) = Da vo < /b> BBT, ta kt lun m t = -3 (loaùi ) ỡ BC ^ AM Cu IV: Gi Ml trung im BC, h AH vuụng g c vi A< /b> M Ta c : ị BC ^ ( AA ' M ) ị BC ^ AH ợ BC ^ AA ' a < /b> M AH ^ A < /b> ' M ị AH ... Cng (1), (2), (3), ta c : + + + ab + bc + ca a < /b> + b + ca < /b> +b b +c c +a < /b> Tng t: ( II PHN T CHN Theo chng tr nh chun Trn S Tựng ) Cu VI .a:< /b> 1) iu kin: < x < ( ) BPT log 2 x + x > log ( - x ) x + x...
... l trung im ca AB v CD; G l trng t mD SAC G c gia mt b n (SCD) v ỏy (ABCD) lả = 60 ị DSIJ u cnh a < /b> ị G cng l trng t m DSIJ SJI IG ct SJ ti K l trung im ca SJ; M, N l trung im ca SC, SD 3a < /b> 3a2< /b> ... (pcm) abc ứa < /b> bca < /b> bc Du "=" xy a < /b> = b = c = II PHN T CHN Theo chng tr nh chun uuu r Cu VI .a:< /b> 1) Gi I l trung im ca BC Ta c AG = ổ7 1ử uur AI ị I ỗ ; ữ ố2 2ứ ng thng BC qua I vuụng g c vi AH ... C9 3 Suy s cch < /b> chn trng hp ny l C6 C9 = 1680 (c ch)< /b> ã Trng hp 2: i tuyn c Ngụ Thu Thu, khụng c V Mnh Cng S cch < /b> chn nam khụng c V Mnh Cng l C6 S cch < /b> chn n c n lil C9 Suy s cch < /b> chn trng...
... Tớnh c AH = PQ = 3a < /b> a 15 a < /b> 3a2< /b> 15 , MN = ị SBDMN = Suy ra: VA.BDMN = S BDMN AH = 16 16 Cu V: ãCch < /b> 1: Ta c ab + bc + ca - 2abc = a < /b> (b + c) + (1 - 2a < /b> )bc = a < /b> (1 - a < /b> ) + (1 - 2a < /b> )bc t t = bc ... + ca - 2abc Ê + abc 1+ 27 = Mt kh ca < /b> + b + c 3 abc ị abc Ê Do ú: ab + bc + ca - abc Ê 27 27 Du "=" xy a < /b> = b = c = II PHN T CHN Theo chng tr nh chun Cu VI .a:< /b> 1) Gi C (c; 2c + 3) v I (m; ... 1) dt = 9ln3 ỗ t - t ữ = 27 ln3 2 ln t 9ln ố ứ x + 3ln x Cu IV: Gi P,Q l trung im ca BD, MN Chng minh c: AC ^ PQ Suy AC Â ^ (BDMN) Gi H l giao ca PQ v AC Suy AH l ng cao ca hỡnh ch< /b> p A.< /b> BDMN...
... x - ln( x + 1) + C 2 Cu IV: Do B v Dcch < /b> u S, A,< /b> C nờn BD ^ (SAC) Gi O l t m ca ỏy ABCD Cc tam gi c ABD, BCD, SBD lcc tam gi c cõn bng v c ỏy BD chung nờn OA = OC = OS Do ú DASC vuụng ... VII .a:< /b> Gi s cn t m l: x= x = a1< /b> a2 a3< /b> a4< /b> a5< /b> a6< /b> Vỡ khụng c mt ch < /b> s nờn c n ch < /b> s 0, 2, 3, 4, 5, 6, 7, 8, thnh lp s cn t mVỡ phi c mt ch < /b> s v a1< /b> nờn s cch < /b> xp choch < /b> s lcch < /b> S cch < /b> xp cho v tr ... 1 Ta c : VS ABCD = 2VS ABC = BO.SA.SC = ax AB2 - OA2 = ax a2< /b> Do ú: VS ABCD = a2< /b> + x = ax 3a2< /b> - x ộx = a < /b> a3 a3< /b> ax 3a < /b> - x = 6 ởx = a < /b> 2 1 ổ 1ử 1 Cu V: Ta c : a2< /b> + b + = a2< /b> - a < /b> + + b + a < /b> +...
... BT trt thnh: -a+< /b> -b+ -c2 + + b+ cc +a < /b> a +b b +c c +a < /b> a +b a+< /b> bb +c c +a < /b> a +b b +c c +a < /b> Theo BT C si ta c : + + 33 = Du "=" xy a < /b> = b = c = b+ cc +a < /b> a +b b +c c +a < /b> a +b II PHN T CHN Theo chng tr nh chun ... hỡnh ch< /b> p B. MA C ị BH = a < /b> T gi thit ị MAÂ = a < /b> , A< /b> C = a < /b> 1 a3< /b> Do ú: VB MA ' C ' = BH SMA ' C ' = BH MAÂ A< /b> CÂ = a2< /b> + b a(< /b> 1 - b - c) + ba < /b> + b = = -a < /b> b+ c b+ c b+ c a+< /b> bb +c c +a < /b> a +b b +c c +a < /b> Tng ... Gi s a1< /b> c th bng 0: + S cch < /b> xp v trcho hai ch < /b> s l: C7 + S cch < /b> xp v trcho ba ch < /b> s l: C5 + S cch < /b> xp cho v trc n li l: 2! C8 ãB y gi ta xột a1< /b> = 0: + S cch < /b> xp v trcho hai ch < /b> s l: C6 ...