Tài liệu Circuits & Electronics P13 docx

6.002 Fall 2000 Lecture 1 13 6.002 CIRCUITS AND ELECTRONICS Digital Circuit 6.002 Fall 2000 Lecture 2 13 C + – C v I v + – R t C v O V I V () RC t IOIC eVVVv − −+= 1 () OC Vv =0 t I V I v 0 Review time constant RC RC 6.002 Fall 2000 Lecture 3 13 Let’s apply the result to an inverter. A B V S V S X C GS t A v V5 0 1 Æ 0 at A A B X First, rising delay t r at B 6.002 Fall 2000 Lecture 4 13 A B V S V S X C GS ideal t A v V5 0 1 Æ 0 at A First, rising delay t r at B observed t B v V5 0 6.002 Fall 2000 Lecture 5 13 A B V S V S X C GS t A v V5 0 1 Æ 0 at A OH V r t rising delay of X First, rising delay t r at B t B v V5 0 6.002 Fall 2000 Lecture 6 13 Equivalent circuit for 0Æ1 at B + – B v SI Vv = + – L R GS C () GSL CR t SSB eVVv − −+= 0 1 From Now, we need to find t for which v B = V OH . SI Vv = for t ≥ 0 () 00 = B v 6.002 Fall 2000 Lecture 7 13 GSL CR t SSOH eVVv − −= Or Find t r : OHS CR t S VVeV GSL r −= − S OHS G SL r V VV CR t − = − ln S OHS GSLr V VV CRt − −= ln 6.002 Fall 2000 Lecture 8 13 GSL CR t SSOH eVVv − −= Or Find t r : OHS CR t S VVeV GSL r −= − S OHS G SL r V VV CR t − = − ln S OHS GSLr V VV CRt − −= ln e.g. KR L 1= pFC GS 1.0= VV S 5= VV OH 4= 5 45 ln101.0101t 123 r − ×××−= − ns16.0= !1.0 nsRC = 6.002 Fall 2000 Lecture 9 13 Falling Delay t f S V + – L R + – B v GS C ON R () () V Vv SB 5 0 = X Falling delay t f is the t for which v B falls to V OL Equivalent circuit for 1 Æ 0 at B 6.002 Fall 2000 Lecture 10 13 Falling Delay t f Equivalent circuit for 1 Æ 0 at B ONLTH RRR ||= LON ON STH RR R VV + = Thévenin replacement … + – B v TH V TH R GS C + – S V + – L R + – B v GS C ON R () () V Vv SB 5 0 = X . 6.002 Fall 2000 Lecture 1 13 6.002 CIRCUITS AND ELECTRONICS Digital Circuit 6.002 Fall 2000 Lecture 2 13 C + – C v I