GIỚI HẠN VÔ ĐỊNH DẠNG 0 chia 0

... (x 2) lim x→ ) + 200 4 ( 1− 2x − 200 4 x x→ x = limx.7 1− 2x + lim x→ ( x 1− 2x + 200 4 = lim x→ ) ) = lim x 1− 2x + lim 200 4( 1− 2x − ( 200 4 x→ ) = lim 200 4( 1− 2x − x x x 0 x→ ) 1− 2x − x )... lim ( 200 4 = lim t→1 ) = lim 2. 200 4( t − 1) = lim 400 8( t − 1) 1− 2x − x x→ 1− t7 1− t t→1 t →1 (1− t)(1+ t + t2 + ×××+ t7 ) − 400 8 − 400 8 = = − 501 1+ t + t + ×××+ t (x Tương tự: lim ) + 200 1 1−... (x x→1 2) lim ) + 200 4 2x − + x − x−1 ) 4x − + x→1 x 2x − + 3x − − x2 − x→1 8) lim 4x + + − 6x − x2 x→ x +x 1− 2x − 200 4 x x→ 1+ x2 − 1− 2x x 0 )( 4x − + =1 Câu 10: Tìm giới hạn sau: 1) L = lim