Daj thi HK2 L t2 CO BAN NEm hqc 20122013 Hg vit6n: .....,..... .................. Ldp : I 2 J,t 4 ) 6 7 8 9 l0 1l t2 13 l l5 l6 t7 l8 l9 2A A o G) 6) (E o G) : 6) .to o fi) O ( G) (D o ti (D (s G) B €) o iliJ G) (} (.il lril i o o (D () e} 6) C e 0) ;. :i () u o 6l :, o €) o c) o e G: h, \ c o A i, o o D (, o o) o G) (} (D (, o (, €i) G} (D (} o o o 2l 22 23 24 zs 26 27 28 29 30 Da4 Di6m A o o o 6t o B o () (rl €) c r, t,, (? fr v () e) D ril U o 0 C.f,u li Gie su mQt chdt ph6ng xp c6 khiSi luqng.mo ve chu ki bi,rrdlil2} gid. Sau 60 gie thi ti sii luqng ch6t ph6ng xp cdn lpi so vdi lugng ch6t ph6ng x4 cl6 phdn rS ld A. 18 B.l7 c.ll3 D. u6 Cia 2t Cho phan img hpt nhan lct + p + i.er+ , , khtii lugng c:iua cdc hpt nh6n ld m(Ar) : 36,956889u, m(Cl) :36,956563u , m(n) : 1,008670u , r.n(p) : 1,007276u , lu = 93lMeVcz. NEng luqng md phan img niy tohrahoflc thu vdo ld bao nhi6u ? A. Toi ru l,60l32MeV B. Toi ra2,562ll2J}te C. Thu vito 2,562112.10tel D. Thu vio 1,60132MeV Cf,u 3: Cfrlu 2: Nguli ta quan t6m dtin phan rmg nhiQt hpch li vi : A.Ce3Hdokia B. Phan rmg nhi€t h4ch spch hon phan tmg phan hpch C. Phan tmg nhiQt hach t6a ndng luqmg D. Nhi6n liSu nhiQt hpch hdu nhu v6 6n Ciu 4: Sti nguy6n tu c6 trong 29laold ( Na: 6,OZJ02 A. L2O4JO20 nguy6n trr 8.2,951020 nguyCn tu C.4,05.1023 nguy6n t D.6,02.1023 nguy6n tu Cfiu 5: Chgn cdu ft6 liti drtng. Trong mQt phan img hpt frfo, t6ng kh6i luong c;ira cdc hqt nhdn tham gia A. TIng. B. Tang hopc gifurntuj,theo phan rmg. C. dugc b6o toan. D. Giem Ciu 6: Chu ki birrrderia mQt ch6t ph6ng xp ld thoi gian sau d6 A. HiQn tugng ph6ng x.? Ep lpi.nhu cfi B.D0 ph6ng x4 tdng gdp mQt 16n C. Kh6i lugmg chSt ph6ng xp tdng l6n g6p hai Hn tchOi tuqng ban t> " ,*r: 2.10 cos (2000r - t>fo> ta Y-dng,hai khel6ch n:Or tl} hai khe c'6n uran qi.Ian s6t ld m lltong hq vdn tr0n I