Đề tài máy bào ngang loại 2

tu« kd ad an man h9C nguyen If; may la mot khdu rat quan trong nhdm muc dich giup cho sinh vien tong kit lai nhiing kien thuc ail duoc trinh bay trong khi h9C If; thuyet, mat khac thidt

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D6 an May bao loai 2 se man: N guyen Ly - Chi TiSt May

LaI NOI Diu

Man h9C n uyen If; may la man h9C co' so' khong thi thidu duac a6i voi nganh co' khi,

n anh chd tao may noi rieng va cac n anh cong n hiep khac noi chung Day la man h9C a u tien a¢t n~n mong cho nhiing kidn thuc v ~ may, la co' so' an thidt cho cac man

h9C khac nhu chi tidt may, may cdt

tu« kd ad an man h9C nguyen If; may la mot khdu rat quan trong nhdm muc dich giup cho sinh vien tong kit lai nhiing kien thuc ail duoc trinh bay trong khi h9C If; thuyet, mat khac thidt kd ad an giup cho sinh vien cung c 6 va me rong them kidn thtrc v~ If; thuyet va thuc tiin.

Dd lam quen voi cong viec thidt kd email duac giao a~ bai thidt kd "May bao

n ang loai 2" phuong an 2 Trong thai gian lam ad an email duoc su giup ao' cua cdc thdy giao hua g d n va su tim toi h9C h i ban be Email hoan thanh ad an man h9C ng y n If; may.

Lan aau lam quen vo cong viec thidt kd nen em con c o nhi~u sai sot, thidu kinh

n hiem thuc tiin Vqy nen em kinh mong cac thdy, co giao giup ao' va chi bao them

ai em nam viing va hidu mot each thau dao hon cac kidn thuc

Em xin ch n thanh cam on su' chi bao tdn tinh cua th dy giao huang dan T r an Va n

La m trong su t qua trinh hua g d n ad an man h9C nay.

Sinh vien thidt kd

Trinh van vinh

Sinh vien Nguyen Hiru Tinh - Lap K39MB

Sinh vien .Ng yen Hiru Tinh - Lap K39MB

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-1-D6 an May bao loai 2 se mon : N guyen Ly - Chi TiSt May

Phdn I

PH AN ticn DO N G HOC CO c i u CHi N H

A GiOi thi e u nguy n Lv L m viec:

May bao ngang loai 2 la mot trong cac loai may dt got tho g dung nhat, Gay la loai may cong taco CO"c~u chinh g6m 5 khau 7 khop, n uyen I;' l am viec so b 9 nhir sau: khi khau dftn (1) quay G~U(dftn dong bang dong co dien) nho co ca u cu l it (3) chuyen dong l~c qua l~c lai trong pham vi g6c l~c \If nao do Qua khau (4) chuyen dong vim quay quanh khop B vira chuyen do g tinh tien, Khau (5) mang GAubao chuyen dong

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B Phan tich dong hoc cO'ca :

I Tinh b(ic tl;l'do c ua co cau va xi p loqi co cau.

1 Tinh bdc {'If ' do cua co' du:

Theo cong thirc : W=3n-(2ps+P4)-S-Wd

Trong do: n =5 : s6 khau dong cua co c~u

Nhom 2: gom khau (2) va khau (3) loai 2 khau 3 khop, nhom loai 2

V~y co c~u loai 2 Cac nhom duoc bieu dien nhu hinh ve

/7T7777

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D6 an May bao loai 2 se mon : N guyen Ly - Chi TiSt May

II Tinh todn d{jng hoc ca cau - vi hoq db chuyen vi:

De ve duoc hoa d6 chuyen vi thea cac sf>lieu dfl cho ta phai tinh duoc cac kich thuoc chua biet

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Vay ta c6 t h @ dung co cAu tren ban ve Ao D~u tien lay diem 01 bfrt ky, l~p h~ true

phan bang nhau Qua d6 ta xac dinh duoc 8 vi tri cong voi hai vi tri O,05H va mot vi

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tri bi e n phai N hir va y ta co 11 vi tri va ta ve hoa d6 cho 11 vi tri do ta danh s6 sao cho

dAu tien la diem x at phat cua qua trinh lam viec Tren duong tiep tuyen ta lc1ydean

0 B=258,53 (rnmj.Tir each ve tren ta co co cc1umay bao ngang 10c;t12 hoan toan xa

dinh voi 11 vi tri

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D 6 an May bao loai 2 se man: N guyen Ly - Chi TiSt May

P c

P H A N II

~

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D6 an May bao loai 2 se man : N guyen Ly - Chi TiS t May

tr i

Tron g d 6 V A l c 6: - Plnro g vuong g6c voi O IA

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D6 an May bao loai 2 se mon : Nguyen Ly - Chi TiSt May

Tir P ke duong thang ~3 vuong g6c voi phuong tnrot 02B Hai duong thang d6 citt

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D6 a n May b ao lo a i 2 se man: N guyen Ly - Chi TiSt May

HOA DO vAN TOC

3 Tinh v~n t6c g6c cua cac khau quay

Vi khau 2 va 3 n6i voi nhau bang khop tinh tien nen: {J) 2 = {J) 3

Mat khac khau 3va 4 n6i voi nhau bang khop tinh tien nen (J)4 = {J) 3

Do do ta c6

Chieu xac dinh bang each d~t P i a 3 vao di€m A va so voi O2

Bang hoa d6 v~n t6c ta xac dinh duoc van t6c cua tftt d cac diem thuoc cac khau dong thoi

ta cling tinh duoc van t6c g6c cua cac khau

10

-Sinh vien Nguyen Hiru Tinh - Lap K39MB

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-D6 an May bao loai 2 se man: N guyen Ly - Chi TiSt May

Sau khi v e hoa d 6 va n t6c ta x ac dinh duoc Van t 6 c cac di @ m tren cac khau.chun g duoc bieu di ~ n trong b a ng 1 , 2

Bang 1: Biiu diJn v(in lac cdc iliim tren cdc khdu (mm)

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D 6 an May bao loai 2 se mon : N guyen Ly - Chi TiSt May

tri s6 6 may dang a che de>lam viec va vi tri s6 11 ling voi hanh trinh chay khong,

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D6 a n May b a o lo a i 2 se man: N guyen Ly - Chi TiSt May

+ a kA3 2 - A c6 chieu la chieu cua vee to' va• n t6c V A A 3 2 quay di mot g6c 90° thuan theo

+ a B 4 c6 phuong ngang, tri s6 chua biet,

+ a ~ B 3 c6 chieu la chieu cua vee to' van t6c VB 4 B 3 q ay di mot g6c 90° thuan theo

2 Xa c dinh cac d oan b ie n di €n

13

-Sinh vie n .Ng yen Hiru Tinh - Lap

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Ch n ty xich gia t6c la ~ a

14

-Sinh vie n .Ng yen Hiru Tinh - Lap

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Db an May bao loai 2 se man: N guyen Ly - Chi TiSt May

=> 7tn =

- 2

A ) 0 A

3 Cach dung boa db gia t6c

7ta~ (a~ == a;) nr mut a~ dung a;k vuong g6c voi phuo g tnrot 02B Tir g6c 7tdung

Tt b

0 A

bieu thi v~n t6c a 64 == a 6 5 .

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a i = a 2

4.Gia t6c g6c cac khau

Vi khau 2 va 3 n6i voi nhau bang khop tinh tien nen: e2 = e3

Mat khac khau 3va 4 n6i voi nhau bang khop tinh tien nen e3 = e4

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D6 a n May bao lo a i 2 se man : N guye n Ly - C h i TiS t M ay

N Qi dung c u a b ai toan ph an tic h do n g h oc co cftu chin h l a di xac d i nh a p l ire tai cac

k op do n g va ti nh rn a men ca n b a n g tren k h au d ~ n Co sa d~ giai l a n u ye n l y

Da l am b e, K hi ta t h em cac l uc qua n ti nh ta se l ~ p d oc cac p h uong t ri nh can b ang l uc cua cac kha u , c u a co cau va cua may D ua vao cac ph u ong trinh can b ang hrc nay ,

b ang phuong p hap ve da giac hr c ta giai ra cac luc c hu a b iet d6 I a a p hr c t ai cac k h p

dong, Cuoi cling con l a i khau d~ n ta se ti n h duoc rna m en can b a n

Ta tien hanh p han tich ap lire khop dong cho co cft u tai 2 vi tri lam viec d6 l a vi t ri 6

va vi tri chay khong 11 Dong thai xac dinh momen can b ang d~ t vao khau d~n Viec tien h anh phan tich ap lire khop dong d6i voi 2 vi tri tuong t1,1n'ha u nen ta chi tien hanh cho mo t vi tr i 6 ( rieng vi t ri 11 k h n g c 6 hr c can Pc)

Luc can c6 ic h c h i t ac do n g t ren k h au 5 a cac vi tri 2 -;- 6 va a t~ t ca v i t ri d6 d~ u

b ang hang s6 Tri s6 c u a lire nay b ang: P ci = P , = 29 00 N.

- Dff cho : G = ql ; q = 30 (Kg / m); G2 = G4 = 0; G S = 4G 3 ; J s = (m.L 2 )11 2 ; Trong tam cua khau n~m a tru n g diem kic h t huoc do n g .

1 :Tf nh kho i hrong va tro n g lu ong cac khau :

-Sinh vien Ngu en Hiru Tinh - Lap

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D6 a n May b ao lo a i 2 se man: N guyen Ly - Chi TiSt May

q: Trong luang phan b6 theo e h i@u d ai

Do khau 5 chuyen d9ng tinh tien nen b == s

=> Fqts co phuong ngang e6 chien nguoc chieu voi chieu 1lSs ' co gia tri

Vi tri s6 6: Fq t s =69,96.11,86.0,1 986 = 1 4,34 (N)

Vi tri s6 11: Fqts =69,96.0,1 986.222,34 = 2331,058 (N )

* Khau I

Do khau Jchuyen dong quay quanh true e6 dinh qua ° nen hrc quan tinh co diem d~t tai

tam va d~p k co phuong chieu ngiroc chieu 1lS 3' co gia tri

Vi tri s6 6: Fq t 3 =17,4 0,1 986.18,65 = 4 ,88 (N)

Vi tri s6 11: Fqt 3 =17,49.0,1 986.204,33 = 535,55 (N )

* Xac dinh trong tam khau (3) :

Trong tam khau 3 d~t (y trung diem cua kich thuoc dong cua khau 3

* Xac dinh tam va d~p K:

Khoang ea h nr O2 dSn KIa:

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D6 a n May b a a l oai 2 se man: N guyen Ly - Chi TiSt May

Ros c phuong vuong g6c voi phuong tnrot R34 chua xac dinh Ta tach rieng

khau 4: Cac luc tac dung la : (R34 ,R4S ) ~ 0 ta thay rang R34 ,R4S co phuongvuong g6c voi can tnrot va ta co : RS4 + R34 = 0 (2)

.Vay h~ phuong trinh (1) (2) giai duoc bang phuong phap ve hoa d6 luc va ta se xac

dinh duoc R34 va Ros nho vao hoa d6

Ta ch n ty 1~xich J l p = 10 N / m m.

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D 6 an May bao loai 2 se man : N guyen Ly - Chi TiS t May

-

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-21-~ R 4 5 = R 3

Sinh vien Ng yen Hiru Tinh - Lap K39MB

-20 Sinh vien Nguyen Hiru Tinh - Lap K39MB

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-22-D6 a n May b ao lo a i 2 se man: N guyen Ly - Chi TiSt May

Tach nhom axua (2-3) cd c l(I' c dijt l e n nhom la :

Phuong trinh can bang luc :

Trong p uong trinh tren c6 :

G 3 dft xac dinh hoan toan

Pqt3c6 diem d~t tai K3, phuong song song voi nS' 3 , chien nguoc

lai, Tach rieng khau 2, cac luc d~t len la : (R32 ,R'2) ~ 0

Do do R 32 , R 12 tao thanh h~ hrc can bang nen chung phai true d6i :

R32 = - R12 , c6 phuong vuong g6c voi p uong tnrot

Tach rieng khau 3 va lAyMomen voi diem O2 ,ta c6 :

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D6 an May bao loai 2 Bo ma n : N g u ye n Ly - C h i T i ~ May

Xet kh a u d ~ n : T a l~y Mornen voi die m O [

Sin h vi e n Nguy e n Hiru Tinh - Lap K39MB

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-22-D6 a n May b ao lo a i 2 se man: N guyen Ly - Chi TiSt May

ta ducc :

MeB =( R21.h- G1.h ).J.!L

thay s6 vao ta c6 :

MeB = ( 3656,2.5 ,92 43,029.3 ,31 ) 0,00205 = 393,972 (N.m)

b, Xac dinh Momen can bang khau dftn bang p uong phap don Jucopski

Dua vao phirong phap di chuyen kha di

{ Trong 1 h~ lire can bang , t6ng cong sufrt nrc thai cua tfrt ca cac lire =0 trong moi

b , Xac dinh Momen can bang khau dftn bang phuong phap don Jucopski

Xoay hoa d6 v~n t6c di 90° thea chien UJ I va d~t tfrt ca cac hrc nrong img

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-D6 a n May b ao lo a i 2 se mon : N guyen Ly - Chi TiSt May

cua khau dfin thuc tS khong phai la hang s6 rna co su thay d6i trong mot pham vi nao

do? Day la d i @ u k hong th€ tranh k oi Tuy nhien ta k o g th€ eho phep van t6e dao

dong voi mot bien d9 vuot qua gioi han nao do vi khi do nhfrng d i @u k i en lam viec va

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Db a n May b ao l oai 2 se man: N guyen Ly - Chi TiSt May

yeu celu cong nghe khong duoc dam bao nira d~n toi do chinh xac cua may bi

Ta dung phirong phap db thi duong cong Vittenbao

1) Vi biiu dB mo men can thay thi :

a) V i biiu dB mi) men thay thi:

Mctt = I (Pk.Vk + M, ffik) - = (Pcih c + G3.h + G1.hl).IlL

k col

Tinh rna men can thay thS thea phuong phap don Jucopky Cach lam nhu sau

xoay 11 v tri hoa db van t6c cua co cftu thea chieu ffil mot gee 90° , sau do d~t trong hrong cua cac khau GI , G3, G4,G5 vao trong Him cac dean tren hoa db van t6c ,d~t

lire can ky thuat Pe tai C sau do lfty rna men voi g6c hoa db P Nlnrng hrc nao gay ra rna men chong lai chien xoay hoa db v~n t6c ta Ifty dau (+), hrc nao gay ra momen cung chieu xoay van t6c ta Ifty dftu (-)

C hit Y :_T~ihai vi tri 0,05H ta tinh momen can cho hai tnrong hop la co lire can Pc va

+ Mte3 = - 0,00205 (2900.66,3+ 4 ,029.33,81 + 174,9 1 ,06) =- 402,17 (N.m)

+Mtte4 = - 0,00205 (2900.74,07 +43,02.17,5 + 1 4,9.7,89) = - 444,71(N.m)

1

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D 6 an May bao loai 2 se mon : N guyen Ly - Chi TiSt May

Ve d6 thi Mett,Ur cac gia tri ta tim diroc Lap h~ true vuong g6c trong d6 :

True tung bieu thi Mjt voi ty l~ xich :

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D b an May bao loai 2 se man: N guyen Ly - Chi TiSt May

b) Vi da th] cong A c , Ad va mi) men phtit drng Md

:

mm Phuong phdp tich phiin :

cua c c dean d6ng song song voi true tung eli t duong cong tai cac diem al,a2 , tren

Tren db thi ve Ac cling chia true hoanh nhu bieu db Mctt

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Db a n May b ao l oai 2 se mon : N guyen Ly - Chi TiSt

May

N6i diem d.lu va diem cuoi cua db thi cong can ~=f( <p ) ta duoc db thi co g phat do g

Ae =f(<p) vi rang mo men dong thay thS la hang s6 : M, = const (chua biet tri s6 mo

men dong ) Nhung cong cua mo men k o g d6i va ban

Nghia la cong cua luc phat dong Ae ty I~ voi goc <p va tren true toa d9 Aegoc

<p phai duoc bieu thi bang duong thang

Ngoai ra, sau toan b9 chu ky lam viec cua may, cong d ng bang cong can : Ae=Ac

Vi vay diro g thang Ad = f(qi) se n6i diem d.lu va diem cuoi diro g cong Ac = f(rp)(6 d u va 6 cuoi elm ky Ae=Ac

Tri s6 cua mo men phat dong xac dinh bang each v p an db thi : Ad=f(rp)

Muon the nr diem P cua db thi M = f(rp) ta ke tia song song voi duong thang Ae= f(rp)toi c~t true M Tung d9 se bieu thi me men phat dong M, voi ty I~ xich 11M

c) X ay dun g db thi 1E = j( tp) :

a) Xac dinh mornen quan tinh thay the va ve bieu db Jt g

Mornen quan tinh xac dinh thea cong thirc :

J = '"./ Vsk 2 +Js oik 2 +J

I1 L mk-{ ) K-( - 0 )

K col col

= J01+ (ms.vss2 + +m3.vs/+ + JS3.(I)/)

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-D6 a n May b ao l oai 2 se man: N guyen Ly - Chi TiSt May

f(rp) va !-lJ cua d6 thi Jtt = f(<p) Duong eong tron d6 ta goi la dirong eong Vitten bao c) Xac dinh rna men quan tinh banh da :

1

Theo d~u bai ra thi h~ s6 khong d~u eho phep la : [ 6 ] = 30

Ta tinh v~n t6e g6e eho phep 16"nnhat va nh o nhat cua khau mot

(J) tb = (0 1 = 8,55 (rad/s)

(J)J max = (J)tb [ 1+ [~]] = 8,5 [1+ 3~.2]= 8,69 (rad/s)

(J)l min = (Ot b [ 1_[~] ]=8,5 [1 - 3~.2] = 8,4 (rad/s)

Tinh cac g6e nghieng \V max va \V min hop voi tiSp tuyen cua d6 thi

~E = f(Itt) voi true Jtt :

_ ~J 2 _ 0 , 1 8 55 2 (1 _ 1 ) _tg( \V m ax ) - (Ot b .(1+[6]) - 266895·' + 30 - 0,5

2·~E ,

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D6 an May bao loai 2 se mon : N guyen Ly - Chi TiSt May

DVa vao cac g6c do , ta ke cac tiep tuyen nrong irng voi dirong cong L1E

= f(Jtt) voi cac g6c \lfmax=29,5 ° ; \j!m i n = 2 ,87° toi c~t true L1Eva do doan ab gioi han boi hai giao diem cua 2 tiep tuyen voi true tung (L1E) ta duoc : ab=

t g if/ max - t g if/ m in 0 , 6 - 0 , 2 ' g

Chon duong kinh banh da la D = 0,7 (m) ~ khoi hrong cua banh da la:

momen ngoai lire, lam viec c~n dam bao cac ch tieu an khop Vi vay ta c6 thS chia ra

lam hai buoc: Buoc mot la tinh toan thiet kS sire ben banh rang Qua buoc nay ta c6 thS

sa bO dinh ra kich thuoc banh fang va cac thong s6 kich thuoc nhu moduyn, khoangeach true A, s6 rang Zl , Z 2 Buoc tiSp thea la can cir vao cac thong s6 nhu ty s6

Sinh vien Ngu en Hir u Tinh - Lap K39MB

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-36-truyen, s6 rang moduyn khoang each true ta tinh to an va thiet kS banh rang v @mat

hinh hoc (hay con goi la to g hop hinh hoc) cap banh rang

Sinh vien Ngu en Hir u Tinh - Lap K39MB

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-37-D6 an May bao loai 2 se mon : N guyen Ly - Chi TiSt May

V~y nhiem vu cua viec tong h p hinh hoc cap banh ding la xac dinh c c thong 86 kichthuoc va xac dinh cac ch tieu Chl1thro g cua cap banh din , ve cap banh ding do

1 Tinh toan cac thong 86 cua banh din

Tir 86li~u dff ch : ZJ = 13; Z2 = 4 ; m = 10 bQ truyen banh rang khong co yeu cftu gi v€ khoang each true Nen ta ch n cap banh ding dich chinh

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-D6 an May bao loai 2 se mon : N guyen Ly - Chi TiSt May

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