C 26 02 phan ung cong cua hidrocacbon khong no

www.tuhoc.edu.vn k 2, k Br2 —C VD1: 2H2 C2H2 Br2 CH CHBr=CHBr Br2 CHBr2–CHBr2 Ni (a) CH2=CH2 + H2 (b) CH (c) CH to Ni to + H2 Ni to (d) CH (e) CH + Br2 (f) (CH3)2C=CH–CH3 + Br2 2–metylbut–2–en + H2 A) trans–2–metylbut–2–en C) 2,2 Ni to B) 2–metylbutan D) pentan htttp://tuhoc.edu.vn/blog www.tuhoc.edu.vn VD2: H2 không +H2 +H2 CH3–CH=CH2 Ni, to CH3–CH2–CH3 Ni, to CH3–C +H2 Pd/PbCO3, to CH3–CH=CH2 +H2 Không Pd/PbCO3, to không A) B) C) D) A) C) B) D) 1, 2SO4 A2, A3, A4 4H8 1, A2 A3 tác A2 A4 A) cis–but–2–en trans–but–2–en B) trans–but–2–en cis–but–2–en C) 2–metylpropen but–1–en D) but–1–en 2–metylpropen htttp://tuhoc.edu.vn/blog www.tuhoc.edu.vn A C5H10 1500 oC +H2 C2H2 B Pd/PbCO3, to to, xt, p to , TÁCH C +H2 D Ni, to p xt, E CH TÁ A) CH4 B) C2H4 C) C4H4 D) C2H6 A) C2H4 C4H10 C) C4H4 C3H6 B) C2H2 C4H8 D) C2H4 C4H8 A) axetilen etan C) butan etan B) etilen butan D) etan etilen o 2, A) pen–2–in C) 3–metylbut–1–in A Pd/PbCO3 B) pent–1–in D) pent–1–in – A) 2–metylpent–1–in C) 4–metylpent–2–in B) 2–metylpen–2–in D) 4–metylpent–1–in B PbCO3 A) C2H4 B) C2H2 C) C3H4 (xúc tác Pd/ D) C3H6 htttp://tuhoc.edu.vn/blog www.tuhoc.edu.vn nH2n H2 Ni CnH2n + H2 nX MX nY MY mX mY X nY nX C2H4 H2 dX MX MY – nY VD3: 2H4 CnH2n+2 to nX = x + y = (mol) 3, 75 He MX 15 C2H4 (M = 28) x y MX = 15 H2 (M = 2) | 28 15 | | 15 | nY nX x = 0,5; y = 0,5 C2H4 + H2 Ta có: 1 MX MY 15 20 nY Ni to C2H6 0, 75 (mol) 2H4 H2 – 0,75 = 0,25 (mol) 2H4 hay H2 htttp://tuhoc.edu.vn/blog h% 0, 25 0,5 100% 50 (%) www.tuhoc.edu.vn C C2H4 2 A) 70 % TOPPER Chú ý aA + bB a C) 60 % D) 50 % D cC + dD nA B) 80 % A) 26,22 % C) 50,02 % nB b B) 52,16 % D) 57,14 % E C3H6 A) 26,00 % C) 33,33 % B) 90,90 % D) 30,00 % h% MX MY 100% MX, MY F nH2n A) 40 % B) 60 % H2 C) 65 % D) 75 % G hóa anken htttp://tuhoc.edu.vn/blog A) d2 d1 100% B) d1 d2 100% C) d2 d1 100% D) d2 d1 100% www.tuhoc.edu.vn nH2n–2 H2 qua CnH2n–2 + H2 CnH2n–2 + 2H2 CnH2n CnH2n+2 T X, mY, mZ CnH2n–2 H2 T CnH2n+2 H2 CnH2n+2 CnH2n CnH2n– H2 xt to Br2 CnH2n CnH2n–2 = mY mY = mZ + mT X, mY, mZ, mT X VD4: 2H2 A) 1,04 gam C) 1,64 gam 0,04 mol H2 B) 1,32 gam D) 1,20 gam 2H2; xt H2 ) (C2H2; C2H4; C2H6; H2) to mY mX mC2H2 2H6 mH2 1, 64 (gam) H2 C2H4 C2H2 dZ 0,5 O2 nZ htttp://tuhoc.edu.vn/blog Mà mY = mZ + mT 0, 02 MZ 16 mZ 0,32 (gam) mT = 1,64 – 0,32 = 1,32 (gam) www.tuhoc.edu.vn H 2H2 0,2 mol H2 A) 3,00 B) 2,60 C) 2,16 I D) 0,84 2H2 A) 1,4 gam C) 1,04 gam H2 B) 1,3 gam D) 0,92 gam J 2H2 A) 0,252 gam C) 0,580 gam K 0,03 mol H2 B) 0,328 gam D) 0,520 gam 2H2 H2 2H2 H2 A) 13 gam gam C) 11,5 gam 0,88 gam L 2H2 B) 0,88 gam 11,5 gam D) gam 13 gam H2 C2H4, C2H6, C2H2 H2 A) 1,30 gam C) 2,60 gam 2H2 B) 2,18 gam D) 0,52 gam htttp://tuhoc.edu.vn/blog www.tuhoc.edu.vn k phân 2, k VD5: CH HBr CHBr=CH2 HBr CHBr2–CH3 VD6: CH2Br–CH2–CH3 (A) CH3–CHBr–CH3 (B) CH2=CH—CH3 + HBr • • VD7: B A • Anken + H2O • Ankin + H2O VD: CH Ancol: CnH2n + H2O HgSO 2O H CH2=CH–OH CnH2n+1OH CH3CH=O M (a) CH2=CH2 + HBr (b) CH2=CH2 + H2O (c) CH3–CH=CH2 + H2O (e) CH 2O HgSO4 H H to H to (d) (CH3)2C=CH2 + HBr (f) CH htttp://tuhoc.edu.vn/blog www.tuhoc.edu.vn VD8: xHy x Hy + HCl CxHy+1Cl 35,5 12x (y 1) 35,5 %Cl 12x y 100% 45, 223% 42 x 42 12 y 3H6 N A) but–1–en C) but–2–en B) xiclopropan D) propilen O A) but–1–en C) pent–1–en Y2 B) but–2–en D) pent–2–en P A) pent–1–en C) but–2–en B) pent–2–en D) pent–2–in Q htttp://tuhoc.edu.vn/blog www.tuhoc.edu.vn – C4 VD9: nCH2=CH2 xt to ,p cao —CH2—CH2— n etilen polietilen xt (–A–)n to ,p cao • • • –A– R (a) propilen (hay propen) (b) stiren, CTCT C6H5CH=CH2 (c) vinyl clorua, CTCT CH2=CH–Cl S A) 1000 B) 2000 C) 965 D) 4000 T A) 672000 C) 504000 TOPPER Chú ý B) 336000 D) 33600 U CH2 (M = 14) htttp://tuhoc.edu.vn/blog 10 www.tuhoc.edu.vn PdCl2 ,Cu2Cl2 2CH CH to vinylaxetilen C 3CH to benzen V H2O, H+ Cl2 askt A C2H5Cl HCl C Br2 B D H2SO4 E W 1500 oC lµm l¹nh nhanh CH4 C4H10 A cracking B H2O H C H2SO4 (®Æc) H2O D X F Vinylaxetilen PdCl2, CuCl2, to CH4 1500 oC lµm l¹nh nhanh A H2O/HgSO4, H+ B H2 Pd/PbCO3 C Br2 D H2O, H+ E htttp://tuhoc.edu.vn/blog 11 www.tuhoc.edu.vn k liên k Y A) 2,24 B) 4,48 C) 1,12 D) 11,2 Z Nung nóng A) gam C) gam B) 24 gam D) 16 gam a A) 16,0 B) 3,2 C) 8,0 D) 32,0 C) 0,60 D) 0,48 b C4H10, C4H8, C4H6 H2 A) 0,24 B) 0,36 c A) gam C) gam B) 12 gam D) 16 gam htttp://tuhoc.edu.vn/blog 12 www.tuhoc.edu.vn Câu Câu E D Câu R S A B F B A G B T A B H C U D I D A J B D K A C L C V W X Y A A Z B A C M N A a A B B O C b B C B P B c B D D Q (a) CH2=CH2 + H2 (b) CH CH3CH3 CH3CH3 CH3CH2CH2CH3 + 3H2 (d) CH CHBr2–CHBr2 CHBr2–CBr2–CHBr–CH2Br + 3Br2 (f) (CH3)2C=CH–CH3 + Br2 (CH3)2CBr–CHBr–CH3 M (a) CH2=CH2 + HBr CH3CHBr (b) CH2=CH2 + H2O CH3CH2OH (c) CH3–CH=CH2 + H2O CH3–CHOH–CH3 (d) (CH3)2C=CH2 + H2O (CH3)3COH (e) CH CH3CHO 2O CH3CHBr2 Q but–1–en htttp://tuhoc.edu.vn/blog 13 www.tuhoc.edu.vn R (a) nCH2=CH xt to ,p CH3 —CH2–CH— CH3 n (b) nCH2=CH xt to ,p C6H5 —CH2–CH—– C6H5 n (c) nCH2=CH xt to ,p Cl —CH2–CH—– Cl n U MP = 448.000 V A: C2H6; B: C2H4; C: C2H5OH; D: C2H4Br2; E: C2H5OSO3H W A: C2H2; B: CH2=CH–CH2–CH3; C: CH3–CH(OH)–CH2–CH3 D: CH3–CH=CH–CH3 X A: C2H2; B: CH3CHO; C: C2H4; D: C2H4Br2; E: C2H5OH; F: PE htttp://tuhoc.edu.vn/blog 14 [...]... 2 CH3CH3 CH3CH3 CH3CH2CH2CH3 2 + 3H2 (d) CH CHBr2–CHBr2 2 CHBr2–CBr2–CHBr–CH2Br 2 + 3Br2 (f) (CH3) 2C= CH–CH3 + Br2 (CH3)2CBr–CHBr–CH3 M (a) CH2=CH2 + HBr CH3CHBr (b) CH2=CH2 + H2O CH3CH2OH (c) CH3–CH=CH2 + H2O CH3–CHOH–CH3 (d) (CH3) 2C= CH2 + H2O (CH3)3COH (e) CH CH3CHO 2O CH3CHBr2 Q but–1–en htttp://tuhoc.edu.vn/blog 13 www.tuhoc.edu.vn R (a) nCH2=CH xt to ,p CH3 —CH2–CH— CH3 n (b) nCH2=CH xt to ,p C6 H5... (a) nCH2=CH xt to ,p CH3 —CH2–CH— CH3 n (b) nCH2=CH xt to ,p C6 H5 —CH2–CH—– C6 H5 n (c) nCH2=CH xt to ,p Cl —CH2–CH—– Cl n U MP = 448.000 V A: C2 H6; B: C2 H4; C: C2 H5OH; D: C2 H4Br2; E: C2 H5OSO3H W A: C2 H2; B: CH2=CH–CH2–CH3; C: CH3–CH(OH)–CH2–CH3 D: CH3–CH=CH–CH3 X A: C2 H2; B: CH3CHO; C: C2 H4; D: C2 H4Br2; E: C2 H5OH; F: PE htttp://tuhoc.edu.vn/blog 14 ...www.tuhoc.edu.vn PdCl2 ,Cu2Cl2 2CH CH to 2 vinylaxetilen C 3CH to benzen V H2O, H+ Cl2 askt A C2 H5Cl HCl C Br2 B D H2SO4 E W 1500 oC lµm l¹nh nhanh CH4 C4 H10 A cracking B H2O H C H2SO4 (® c) H2O D X F Vinylaxetilen PdCl2, CuCl2, to CH4 1500 oC lµm l¹nh nhanh A H2O/HgSO4, H+ B H2 Pd/PbCO3 C Br2 D H2O, H+ E htttp://tuhoc.edu.vn/blog 11 www.tuhoc.edu.vn 6 k liên 2 k 2 Y 2 A) 2,24 B) 4,48 C) 1,12 D)... Nung nóng 2 A) 0 gam C) 8 gam B) 24 gam D) 16 gam a 2 A) 16,0 B) 3,2 C) 8,0 D) 32,0 C) 0,60 D) 0,48 b C4 H10, C4 H8, C4 H6 và H2 A) 0,24 B) 0,36 c 2 A) 8 gam C) 6 gam B) 12 gam D) 16 gam htttp://tuhoc.edu.vn/blog 12 www.tuhoc.edu.vn C u 1 2 C u E D C u R S A B F B 3 A G B T A 4 B H C U 5 D I D 6 A J B 7 D K A 8 C L C V W X Y A 9 A Z B A C M N A a A B B O C b B C B P B c B D D Q 1 (a) CH2=CH2 + H2 (b) CH