THIẾT kế cầu THÉP 22TTC272 05, tải TRỌNG THIẾT kế HL93, CHIỀU dài TOÀN dầm 34,6m, bề RROONGJ PHẦN XE CHẠY 7m,bề RỘNG lề bộ HÀNH 2x1,5m

54 1.3K 0
THIẾT kế cầu THÉP 22TTC272 05, tải TRỌNG THIẾT kế HL93, CHIỀU dài TOÀN dầm 34,6m, bề RROONGJ PHẦN XE CHẠY 7m,bề RỘNG lề bộ HÀNH 2x1,5m

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OKkM[SKVlSQrna`VNzMQO|ZN†hNbMgS"5mkWnQ]VlSQNbMgSB/mhQ NhQxy[\Q]aKŽMa`VO•Z]K‘hghQNhQtVtRSghQNhQgkrnOSQO…VW’5[bmNO†gS [bmVO}ZgKLQO•ZrLVtQ]N…VVO}Z[jNVOplNbMR“KaOliQ]NYNOOhK[bmgKLQVK`ZgS ?mOKkMNhlVlSQ[bmgKLQO•ZgS/muNOKkMNhl[bmVO}ZgSm ]!^_!JI TURR#  Đ n môn hc thit k cu thp  XQO+…VW’NOMQ]msVN”VQ]hQ]NbM CHƯƠNG 2 : THIẾT KẾ LAN CAN – LỀ BỘ HÀNH    ! XQO+OKVK`VghQNhQ!gkrnOSQO      '()*+)*',-'.,-/,-  ‹{•V’QO!ViKVWjQ] Ž{‹Q]KiQux‹{–V’QONOlm—KQO|ZVOhQOghQNhQgSx‹{•[bm]KiQ{‹Q O|ZV’QOVlYQgSaOliQ]NYNO]K‘hOhKNnVghQNhQgKkQak„BBBmm ]!^_!JI TURR# " Đ n môn hc thit k cu thp  XQO+‹{•V’QORSViKVWjQ]VYN[\Q]gLQVOhQOghQNhQ iKVWjQ]VYN[\Q]gLQVOhQOghQNhQQOvOXQOHurhl]•m+ ^WjQ]gv•Q]riQVOŒQghQNhQVWLQmmNOKkM[SK+   / •#B 5 ‚ #?/€B €" " U − − = •'„BB5/˜mm ^lqVViKVOK`Va`+ iKZOŒQr…VWLQNOKkM[SKVOhQOghQNhQŠ„B#˜mmRSViKVeZVWMQ]-„?;B VOplKkM?  nKg™NVWlQ]VOhQOghQNhQ ^)tmpQ[lViKVWjQ]riQVOŒQ]ŒUWhVqKmsVN”VNO’QO]K‘hQO|Z+   BB5/€BBB /BB • ‚ ? ? U h iY T ]>>= = = ^)tmpQ[lOlqVViK]ŒUWhVqKmsVN”VNO’QO]K‘hQO|Z+   š š š B#€BBB ?/BBB • ‚ ? ? h ^ T T ]>>= = = = - - - ?;B€BBB ""/BBB • ‚ " " h ^ T T ]>>= = = = ^–O•ZViKVWjQ]›VWqQ]VOYK]K“KOqQNvwQ]{n+ )tmpQVqKmsVN”VNO’QO]K‘hQO|ZVWlQ]VWqQ]VOYK]K“KOqQNvwQ]{ngS+ š  š  € œ  • • ‚ž œ • • ‚ž U   U h Y h h Y ^ ^ T T T T T T η γ γ γ = + + WlQ]{f+ ˆx…{KkMNOŸQOViKVWjQ] € €   j k η η η η = = VOplNYNKkM  "RS / ˆx…ViKVWjQ]R“KOlqVViKgS #/ Y γ = Oˆx…ViKVWjQ]NOlV¡QOViK / Y γ = VOpl KkM"uiQ]"HRS"H •   œ/€/BB #/€•?/BBB•""/BBB‚ž œ#/€•?/BBB•""/BBB‚žT = + + •0%11%$•mm‚  OiQ‡Q]NO|Mg™NN†hghQNhQ ^)tmpQTMYQV’QON†hVK`V[KˆQ+  " " " " " " " 5 BB/ • ‚ BB/€#B • ‚ "55? • ‚ #B A j  >>  = − = − =  ^¢NaOYQ]M…Q[hQO{|QON†hVK`V[KˆQ+ ]!^_!JI TURR# / Đ n môn hc thit k cu thp  "55? € €"B B/€ B/€#B  ^ j T c  = = • - 0$%11•mm‚ " KŽmVlYQ tQ]VO¢NaKŽmVlYQVWqQ]VOYK]K“KOqQNvwQ]{n+   T T φ ≥ ˆx…x¢NaOYQ]  φ = {…KR“KM…QVOplKkM5/" •€5/??•mm‚£/??/5•mm‚•Đảm bảo chịu lực  '()*+)/2*.,-/,-3/45-672  ‹{•V’QO!ViKVWjQ] ¤TMhg™NVO¥Q]{¢Q]VYN[\Q]RSlNnVghQNhQzUNnVghQNhQ›]K‘hNbM{ŽV’QO iKVWjQ]VYN[\Q]gLQNnVNOŸNOŸrhl]•mNYNg™NVOplZOv‹Q]Q]hQ]NbMVqKNYNR|VW’ gKLQa`VVOhQOghQNhQurhl]•m+ ^lqVViKZOŒQr…Š„B#˜mmVWLQQyhQO|ZVOhQOghQNhQ{vwQ]VWMUkQRk NnVVOSQOg™NVeZNOMQ]-¦„Š€„B#€BBB„#"B•‚ ^lqVVqKVeZVWMQ]-„?;BVWLQVOhQOghQNhQQhU{v•N[KNOMUŽQR|{sVQ]hUR| VW’]KhlR“KNnV •eUV–Q]O•Zg™NVYN[\Q]gLQNnVVOplZOv‹Q]Q]hQ]NbMVqKm—KR|VW’]KhlR“K VOhQOghQNhQgS+ ƒ„-•-¦„#"B•?;B•80$9•‚ ‹{•V’QORSNYNa’NOVOv“NOXQOOjNN†hNnVQOvXQOH[v“K{ŒU+ XQO"+‹{•V’QONnVghQNhQ  nKg™NVWlQ]NnVghQNhQ )tmpQVqKmsVN”VH+ €•"B /5B #?B‚ 5B€5?B   T l − = + + = •01199mm )tmpQaKŽmVlYQVqKVWqQ]VOYK]K“KOqQNvwQ]{n+ € #/€?"?BB YY   T T γ − = = •0::199•mm‚ •ˆx…ViKVWjQ]R“KOlqVViKgS #/ YY γ = ‚  OiQ‡Q]NO|Mg™NN†hNnVghQNhQ ‹{•V’QONnVghQNhQgS[bmNlQ]olg•aOKr¤TMhg™NVO¥Q]{¢Q][jNVW\N‚ )tmpQTMYQV’QON†hVK`V[KˆQNnVghQNhQVqKmsVN”VH{v•Nxy[\Q] MVlh[ BB#V’QO{v•Na`VTMigS+ "#$%&'(' )#"*+#,#"%&-&&(.& /012*134/5%6%'''''77.'''''' 8%'''''77'''''' #1,"/*2%6%&&&9' 8%.&:9.( ]!^_!JI TURR# 5 Đ n môn hc thit k cu thp  ;/+#1,</=*1#",*$%6%-'.:- '-:( 8%9&:9:&' )"/20>,/=*1#",*$%68%-9.9.'& &. $2**/=3?"$,*/1%6%:.:' 8%-( )"*1>*@$A+/+#1,<$126782*"#>,*/1<$4/0,>#1,"/*2% %&':-:'999$A/13B'''''''''C D%-.:'9- $A/13B'''''''''C • & „/"5B#mm "  H¢NaOYQ]M…Q[hQO{|QON†hNnVghQNhQ+   € € /"5B#€"B€ u#u/u#B •  ‚ BB 7 h ^ T j c ] >>  = = = " KŽmVlYQNnVghQNhQ H WqQ]VOYK]K“KOqQNvwQ]{n+    €u#u/u#B €#/€?"?BB ;;?"BB•  ‚ 7 YY   T T ] >> φ η γ − ≥ = ≥ =  •O¤h§    '()*+);<-;=*>-6.?;2'@-'  ‹{•V’QORSViKVWjQ] ‹{•V’QOgS[bm]KiQ{‹QuN”VBBBmm[SKVOplZOv‹Q][jNNbM{ŽV’QOuVK`V[KˆQ V’QOgSOXQONO‘QOeVr€O„BBBoBBmmuNOKkM[SKQO|ZV’QOVlYQgS„BBmm XQO/+‹{•V’QOgkrnOSQO iKVWjQ]VYN[\Q]]•mV¡QOViKriQVOŒQ•'‚uOlqVViKQ]vwK•-‚ / /€B €BBB€BB /• ˜ ‚U ] >> − = =  €B €BBB • ˜ ‚Y ] >> − = =  ’QOVlYQQnKg™N )tmpQVWqQ]VOYK]K“KOqQNvwQ]{n+ ( ) ( ) ( )     € /€/ #/€ €BB € € #5;;  ? ? U Y  U Y Y T ] >> γ γ η + + = = = )tmpQVWqQ]VOYK]K“KOqQxy[\Q]+ ( ) ( ) ( )   € /  €BB € € 5?#/  ? ?  U Y Y T ] >> η + + = = =  ’QOVlYQRSr…VW’N…VVO}Z OjQ[ x „#Bmm OKkMNhlR‰Q]Q}Q+   ~  €#5;; #B #B €B?/€ € B;€B?/€B€BBB  S S  T  A A c % φ = − − = − − •h„mm ]!^_!JI TURR# # Đ n môn hc thit k cu thp  &}VV¨x…   BB B"  B?"€#B S S   A A β = = = ≤ WlQ]{f ( ) ( ) ~  BB/ BB/ B?/  ? B?/ € B ? 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Đ n môn hc thit k cu thp  H1Q]xMzVVWlQ]N…VVO}ZVqKVWjQ]VŒmN…VVO}ZgS+ ( ) ( ) ( ) 5?#/ BBBBB   € #B ;# €  ; /;#" ;""B  S S S S 7  g T c A h c T j g = − = − = ≤ = HeU{KkMaKˆQRkQ¢VVO¤hm¬Q  '()*+);ABC,37D/;(E*  ‹{•V’QORSViKVWjQ] H’QOrfRŸhgkrnOSQOVWlQ]{sNrKˆVuR“KNzZQ]‡QNOsQ H™NVOK`Va`ghQNhQgzUVOpl #+ -Ov‹Q]VYN[\Q] ™N•‚ OKkM[SKg™NVYN[\Q] ]hQ] ƒ V „"B  V „B#Bmm O¥Q]{¢Q] ƒ R „?B  R „//BBmm 'jN ƒ  „?B   „B#Bmm H…VVO}ZVWlQ]rfRŸhNOjQx‹rngS / " φ VWLQm[SKrfRŸh XQO5+‹{•V’QOrfRŸh  OiQ‡Q]NO|Mg™N H…KR“KNYNRhotVWlQ]mnVZObQ{lqQVvwQ]+    ? ?     n % n   T Y k T T  Y Y      = + +  ÷  ÷ −     OKkM[SKVvwQ]V“KOqQ N VWLQ{foiUWhN‹NzM{vwQ]NOiUZOiKgzUr-Q]+ ( )  ?   % n      T T  Y Y Y T +   = + +  ÷   H“KNYNRhNOqmVqK{bMVvwQ]OlsNVqKm…KQ…K+        n % n   T Y k T T  Y Y      = + +  ÷  ÷ −     ( )    % n      T T  Y Y Y T +   = + +  ÷   H'laOtQ]NfVvwQ]{ŸQOQLQ) r „BuNYNa®OKˆMxy[\Q]VO…Q]QOzVQOv #" ]!^_!JI TURR# ; Đ n môn hc thit k cu thp  H&YN{|QOaOiQ‡Q]NO|MmtmpQN†hVvwQ]VWLQmnV{‹QR|NOKkM[SK{…KR“KVW\N Q]hQ]•) N ‚ K`V[KˆQV’QOVlYQroO„oBB•mm‚uV’QOVOplVK`V[KˆQ{sVN…V{‹QuN…VVO}Zr…VW’ gS+   "€" B#5; • ‚ "€BB S b >>= = OKkMNhlR‰Q]Q}QTMU{–KN†hrLVtQ]+ ~  B#5;€5/ B• ‚ B?/€ € B?/€B€ S ^  b c  >> c % = = = ( ) ( ) ~  BB/ BB/ B?/  ? B?/ € B ? B?" # #  c β = − − = − − = •R“K ~ B ?  c T T= ≥ ‚ OjQ[ x „/Bmm  B BB; B"  B?"€/B S S   A A β = = = ≤ •VO¤h{KkMaKˆQZOYOlqK[¯l • B  • ‚ B#5;€5/€•/B ‚    S ^ S  T b c A= − = − • "B/#  ˜  T ] >> >>= H&YN{|QOaOiQ‡Q]NO|MmtmpQN†hVvwQ]VWLQmnV{‹QR|NOKkM[SK{…KR“KVW\N {¢Q]•) š ‚ K`V[KˆQV’QOVlYQroO„oBB•mm‚uV’QOVOplVK`V[KˆQ{sVN…V{‹QuN…VVO}Zr…VW’ gS+   €"€ B" • ‚ "€BB S b >>= = OKkMNhlR‰Q]Q}QTMU{–KN†hrLVtQ]+ ~  B"€5/ 5?• ‚ B?/€ € B?/€B€ S ^  b c  >> c % = = = ( ) ( ) ~  BB/ BB/ B?/  ? B?/ € B ? B?" # #  c β = − − = − − = •R“K ~ B ?  c T T= ≥ ‚ OjQ[ x „/Bmm  5? B B"  B?"€/B S S   A A β = = = ≤ •VO¤h{KkMaKˆQZOYOlqK[¯l • 5?  • ‚ B"€5/€•/B ‚   n S ^ S  T b c A= − = − • /?//  ˜ n T ] >> >>= H …KR“KNYNRhotVWlQ]mnVZObQ{lqQVvwQ]+ ( ) ( )  ?€BB€ B /?//€BB B#B B#B 5?5   "B/#  Y >> +   = + + =  ÷   ( )   "B/#€5?5 ?€B ?€/?//€BB "/5B;5 €5?5 B#B BB n k ]     = + + =  ÷  ÷ −     H“KNYNRhNOqmVqK{bMVvwQ]OlsNVqKm…KQ…K+ ]!^_!JI TURR# B [...]... và được lựa chọn sơ bộ như sau: Cánh trên: Bề rộng: bc = 300 mm Bề dày: tc = 20 mm Vách dầm (bản sườn): Chiều cao: Dw = 1140 mm Bề dày: tw = 20 mm Cánh dưới dầm: Bề rộng: bf = 300 mm Bề dày: tf = 20 mm Bản táp cánh dưới: Bể rộng: b 'f = 400mm ' Bề dày: t f = 20mm Chiều cao dầm: d = 1200 mm 1200 1140 20 300 20 20 yo = 497.85 20 300 400 Hình 9 : Tiết diện ngang dầm chủ (phần dầm thép) 4.2 XÁC ĐỊNH ĐẶC... cắt với tải trọng xe 1 SE (m.g Xe )V , M = 1.2* *0.111 2 SE → (m.g Xe )V , M = 0.1 (một làn chất tải) SVTH : Nguyễn Quang Đại MSSV: CD04016 24 Đồ án môn học thiết kế cầu thép GVHD: ThS Phan Quốc Bảo 4.5.3 Bảng tổng hợp hệ số phân bố ngang (mg) lớn nhất cho hoạt tải Tải trọng Dầm, nội lực Mômen Dầm trong Lực cắt Mômen Dầm biên Lực cắt Số làn chất tải 2 1 1 1 Xe tải 0.5 0.6 0.1 0.1 Xe hai... Lực cắt cho tải trọng xe: VXe 3truc = 145*0.32 + 145*0.26 + 35*0.2 → VXe 3truc = 91 kN Lực cắt cho tải trọng xe 2 trục: VXe 2truc = 110*(0.32 + 0.303) → VXe 2truc = 69 kN Lực cắt cho tải trọng làn: 0.32* 23000 *10−3 2 = 34.224 kN Vlan = 9.3* → Vlan Lực cắt do tải trọng người: 0.32* 23000 2 = 16.56 kN VPL = 4.5*10−3 * → VPL - Tổng hợp lực cắt do hoạt tải gây ra trong trường hợp này là: V = VXe3truc +... trường hợp xếp tải TH2 chưa kể hệ số: Lực cắt cho tải trọng xe: VXe 3truc = 145*0.25 + 145*0.21 + 35*0.16 → VXe 3truc = 72.3 kN Lực cắt cho tải trọng xe 2 trục: VXe 2truc = 110*(0.25 + 0.24) → VXe 2truc = 54 kN Lực cắt cho tải trọng làn: 0.25* 25500 2 = 29.644 kN Vlan = 9.3*10−3 * → Vlan Lực cắt do tải trọng người: 0.25* 25500 2 = 14.344 kN VPL = 4.5*10−3 * → VPL - Tổng hợp lực cắt do hoạt tải gây ra trong... cốt thép thiết kế: As = 0.85* f c' * a * b 0.85*30*9.3*1000 = = 650(mm 2 ) fy 365 Lượng cốt thép tối thiểu: As ,min = 0.03* b * h * f c' 30 = 0.03*1000*100* = 247 mm 2 fy 365 ( ) → chọn lượng cốt thép bố trí: 2 As = 650 mm2 → chọn φ12a150 ( As = 791mm ) bố trí cho 1 m dài bản mặt cầu theo phương dọc cầu 3.4.2 Thiết kế cốt thép chịu mômen dương u Mô men thiết kế thép: M 1/2 = 22356( N mm) , tiết diện thiết. .. xếp tải TH1 chưa kể hệ số: Lực cắt cho tải trọng xe: VXe 3truc = 145*0.6 + 145*0.41 + 35*0.22 → VXe3truc = 154.15 kN Lực cắt cho tải trọng xe 2 trục: VXe 2truc = 110*(0.6 + 0.55) → VXe 2truc = 127 kN Lực cắt cho tải trọng làn: Vlan = 9.3*10−3 * 0.6*13600 2 SVTH : Nguyễn Quang Đại MSSV: CD04016 32 Đồ án môn học thiết kế cầu thép GVHD: ThS Phan Quốc Bảo → Vlan = 37.944 kN Lực cắt do tải trọng. .. Mômen do hoạt tải người chưa nhân hệ số:  7441*11000   7441* 23000   M PL = 4.5*10−3 *  ÷+  ÷ 2 2     → M PL = 569236.5 kNmm ● Tính lực cắt cho trường hợp xếp tải TH1 chưa kể hệ số: Lực cắt cho tải trọng xe 3 trục: VXe 3truc = 145*0.68 + 145*0.42 + 35*0.15 → VXe 3truc = 165 kN Lực cắt cho tải trọng xe 2 trục: VXe 2truc = 110*(0.68 + 0.606) → VXe 2truc = 142 kN Lực cắt cho tải trọng làn:... cắt do hoạt tải gây ra trong trường hợp này là: V = VXe3truc + Vlan + VPL = 154.15 + 37.944 + 18.360 = 210.454 ( KN ) - Vậy trường hợp xếp tải này gây ra lực cắt lớn hơn so với TH2 ● Tính lực cắt cho trường hợp xếp tải TH2 chưa kể hệ số: Lực cắt cho tải trọng xe: VXe 3truc = 145*0.4 + 145*0.32 + 35*0.23 → VXe3truc = 112.45 kN Lực cắt cho tải trọng xe 2 trục: VXe 2truc = 110*(0.4 + 0.38) → VXe 2truc =... ( ) - Ứng suất trong cốt thép tại trọng tâm cốt thép là: fs = E 13202*1000 Mn 200000 ( ds − x ) s = * ( 150 − 30.3) * = 167 ≤ f sa = 219 ( MPa ) I cr Ec 64268435 29440 - Vậy điều kiện về nứt thỏa mãn CHƯƠNG 4 : THIẾT KẾ DẦM CHỦ 4.1 LỰA CHỌN SƠ BỘ TIẾT DIỆN DẦM CHỦ Chọn tiết diện ngang dầm thép hình chữ I, được tổ hợp từ thép tấm bằng các mối hàn rãnh liên tục ngấu hoàn toàn .Thép sử dụng là M270 cấp... 0.5 0.6 0.1 0.1 Tải trọng làn 0.5 0.6 0.1 0.1 Tải trọng người 0.5 0.5 1.04 1.04 4.6 XÁC ĐỊNH TĨNH TẢI – TÍNH NỘI LỰC DO TĨNH TẢI TÁC DỤNG Trọng lượng bản thân kết cấu lấy theo Bảng 3.5.1-1 22TCN 272-05 Để đơn giản khi tính toán, tĩnh tải coi như phân bố đều trên các dầm chủ không phân biệt dầm trong hay dầm ngoài ● Lớp phủ: DW = [7000*75]*[2.25*10-5] / 6 → DW = 1.97 N/mm ● Bản mặt cầu (bao gồm cả vùng . cu thp  XQO+…VW’NOMQ]msVN”VQ]hQ]NbM CHƯƠNG 2 : THIẾT KẾ LAN CAN – LỀ BỘ HÀNH    ! XQO+OKVK`VghQNhQ!gkrnOSQO . l≥ • #‚ • ( ) ( ) ;; "BBBB] ]≥ •O¤h§ CHƯƠNG 3 : THIẾT KẾ BẢN MẶT CẦU  E LVtQ]riQmsVNbM+BNfª N ¦„B)-hRS@ N „;""B)-h …VVO}Z. ;""B  S S S S 7  g T c A h c T j g = − = − = ≤ = HeU{KkMaKˆQRkQ¢VVO¤hm¬Q CHƯƠNG 4 : THIẾT KẾ DẦM CHỦ . N OGGH;P OjQVK`V[KˆQQ]hQ][bmVO}ZOXQONO‘u{v•NV–O•ZV•VO}ZVzmr-Q]NYNm…K OSQW¬QOgKLQVNQ]zMOlSQVlSQO}Zxy[Q]gS)#BNzZ"/ŠVOpl

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Mục lục

  • CHƯƠNG 1 : SỐ LIỆU THIẾT KẾ

    • 1.1. CÁC SỐ LIỆU ĐỀ BÀI

    • 1.2. VẬT LIỆU THIẾT KẾ

    • 1.3. BỐ TRÍ SƠ BỘ CÔNG TRÌNH

    • CHƯƠNG 2 : THIẾT KẾ LAN CAN – LỀ BỘ HÀNH

      • 2.1. BỐ TRÍ CHUNG LAN CAN – LỀ BỘ HÀNH

      • 2.2. THIẾT KẾ LAN CAN

        • 2.2.1 Thiết kế thanh lan can

          • 2.2.1.1 Sơ đồ tính – tải trọng

          • 2.2.1.2 Nội lực trong thanh lan can

          • 2.2.1.3 Khả năng chịu lực của lan can

          • 2.2.1.4 Kiểm toán

          • 2.2.2 Thiết kế cột lan can ở THGH cường độ

            • 2.2.2.1 Sơ đồ tính – tải trọng

            • 2.2.2.2 Nội lực trong cột lan can

            • 2.2.2.3 Khả năng chịu lực của cột lan can

            • 2.2.2.4 Kiểm toán cột lan can

            • 2.3. THIẾT KẾ LỀ BỘ HÀNH

              • 2.3.1 Thiết kế bản bê tông lề bộ hành

                • 2.3.1.1 Sơ đồ tính và tải trọng

                • 2.3.1.2 Tính toán nội lực

                • 2.3.1.3 Tính toán và bố trí cốt thép

                • 2.3.1.4 Kiểm tra nứt

                • 2.3.2 Thiết kế bó vỉa ở TTGH đặc biệt

                  • 2.3.2.1 Sơ đồ tính và tải trọng

                  • 2.3.2.2 Khả năng chịu lực

                  • 2.3.2.3 Kiểm toán

                  • CHƯƠNG 3 : THIẾT KẾ BẢN MẶT CẦU

                    • 3.1. SỐ LIỆU TÍNH TOÁN

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