!"## "$% !"#!!$%&'!()(*!$+,!- !. / 0 ! "# ! $%&'(#)*$+(12 &,-$!./012(3"4567!$-3/,4546/!&' 89 7"):!898 3 : 3:;'74<(*!$=>?5;.!*!$<=>!$5?!? $5@+,!- : 7@$=ABC46=D=E 83/ F 98/ F F 7@$=ABC6G/H3I83J/9/3:KFJ F L 7@$=ABC1C$6G/H3I83J F M98MJ3:KFJ F Ch : -Do kim loi kim d phn ng vi oxi, nưc → ()*+,'-./01'0" Kim loi kim tác dụng vi dd muối, 23to kim loi mi. ABCDBEBFGHIJK 1. N=A JO46P7!)IH!/Q%+- JO46PR/S,T=U!4V0E4" =U/E65E!W)H 2. 7@X,(O$1C$.#) 3. YZ$545(60)'789':+*;2)82<)" CEBF= $ >?= $ @ABCDEFAAGFHIJC=K>G=K>J=KL $ >J=KL $ L 7[6!/M F !\$SM F 7[6!/MJ ]^_/H4 2 OH CO n n − `12%+M F 3MJ → 3 HCO − M F 3FMJ → 2 3 CO − 3J F M 354a:!6[ 3 HCO − BEM F =1!\$ 3 HSO − BESM F =1 354:$_!6[ 3 HCO − !\$ 3 HSO − 354F$_!6[ 2 3 CO − 354bF!6[ 2 3 CO − BEMJ =1!\$ 2 3 SO − BEMJ =1 35:a4aF7!$%F6[ 3 HCO − BE 2 3 CO − c1d eE!@4".4 )%=XBE!e=e4HA).64%f!6[ JAM F BE!MJ =1$_!6[ 2 3 CO − JAM F BE!MJ &$45g S),6MJ =1BE!&H,645ge⇒!$%F6[ 3 HCO − BE 2 3 CO − JAM F BE!1C$B"!&$45g#/h$i45gj)1C$/h$/&45ge&$X! E$%M L BEJM L F A%k6$@&BE!==l25%%&Xf%64[/1O== 71m\/EA %k6$@&n==MJ F !\$==oMJ F ) [/1O==f6 6 45g [/1O==%66 45g 6 56 45g b 2 CO m 4[/1O==%6!BC4[/1O==)> 56 45g a 2 CO m 4[/1O==f!BC4[/1O==)> =p264M F BE!)X1C$B"=1%+4[/1O==f6BE$!645gE /"$2L!M =p264M F BE!)X1C$B"%+4[/1O==%66BE$!645g!E /"$2L! qd!rO#o#R/@$=ABC1C$ MJ R/1 :KF F H n o oMJF :KF R/1 M3NO8P2&Q;'R42R5S&)T8P= $ U+'+VNWP5X)C=K>J=KL $ :J=KL $ " Tính n CO −F L = n OH − - n CO F rồi s!@ +F !\$ o +F ).;6$E!%+5).& 45g điu kiện n CO −F L ≤ n CO F Trang 1/6 !"## "$% M3NO.O= $ ,R5S&U)T+'+VJ=KL $ :J=KL $ .'P)T8P2&Q9 ','" Ta có hai kết qu : - n CO F = n kết tủa - n CO F = n OH − - n kết tủa 5(N2N!+O!$ 3%/IP/Q/R-SA$s#st/4M F )4$BE!:/==$rOoMJ F u#:F8BEMJu#uv8 S4$@$% +%&!E!E)1O$6645g w@$g6/E :x#yu FL#vs y#tt C:L#yx 3%RIP/Q/R-JrO]$4[/1OtF#L6j6/M L #/M L F #/ F BE/ H-!E!E])1O$ :L#ss/M F )4$#$z{j6/ F BE/ 7!E*{@$=AB?)gBCu#L/==$ F M L :8)1O$==$ | 1O/!|Z}/>/1O/!] `>f64[/1O/!]/E R F}#vF~ o :F#vy~ :t#:u~ ( Fx#yy~ 3%SIP/Q/R-!rO F M L BEJM L _/H6!/::BE!==$oJM L F )1O$45g]BE= =${ 7,6??==$J/u#}8BE!)544"$Q4!@5}vu6/ o5!E*{%+B?)g BCFuu6/==$MJ:8 [/1O45g]/E 3%SIP/Q/R-JA!E!Eu#LLv/4M F )4$BE!Fuu6/==$j6MJu#:8BEMJu#:8)1O$ ==$] "$!E*==$])1O$!,6$z4• R F#ss6 o F#FF6 "$>Y ) ( F#}t6 R L#xs6 o y#tt6 ::#Ft6 ( x#t}6 oE:!/M F €)4$A!E!E€F/==oMJ F u#u:}8&$:#xyoM L 7.$$@/C /ER u#uFs/ o u#vyF/ u#txv ( :#:F/ oEF!s#st/4M F )4$BE!su/==MJ F )1O$:F45gR j)* 8 $g==MJ F /ER u#uus8 o u#uuF8 u#uuv8 ( u#uut8 oELSA$F#Fs/M F )4$BE!y}u6==MJu#F8 S[66[)1O$/E R x#} o :u#t :F#} ( :s#F oEsJrO]j6BER/ !66]BE!/1O=11C$!@/4 5$•$!66]BE!==MJ=1 )1O$:#y}/4 7E>>f6;!4[/1O$g!]/E5$@$4)!€$U)Z4H R L#ty~ o yy#L:~ sx#ty~ ( Fx#ty~ oE}!:/==J/BE!==$+u#F6!//M L #/h$#45g)54[/1O4")I)1O$y#v}6$z j)* 6!/$g==J//E R u#:}!\$u#L}o u#:}!\$u#F u#F!\$u#L} ( u#F!\$u#L oEvJA!E!EF#vtt/4M F )4$BE!F#}/==$oMJ F j)*6!/K/)1O$:}#yv45g w $g/E• R u#uLF o u#ust u#uv ( u#us oEy(=$R$+MJ:8BEMJ F u#uF8#Au#}6!/4M F BE!}uu6/==$R)1O$45g$4[ /1O•R :#u o :#F F#u ( F#t oEtJA5u#L6!/M F BE!==$$+u#F}6!/MJ F 1O45g)1O$/E R Lu6 o FF}6 Fu6 ( :}6 oEx:uu6/==]$+ F SM s u#:8BE F M L u#:8@$=A5BC==oM L =1 [/1O45g)1O$/ER F#Lx 6 o L#s6 s#L6 ( F#xL6 oE:uJrO]j646/!4Z6I5!1C$!=={BE!@u#:F6!/J F 7.$==J F SM s u#:8$> ).!E=={/E R :Fu6/ o vu6/ Fsu6/ ( :#F/ oE::J!E!E!Es#vt6rO6*6[$$!$g46/!]BE{455!6‚‚RBE!==J/ )1O$:#:F/4M F )4$ 6/!]#{/E R o;#8 o 8# #S ( S#o -FLJA!E!E}#v/M F €)4$BE!Fuu6/MJj)*8#==)1O$$4%f@$=A[):uu6/== MJ:8 w$g/ER u#y}o :#} F( F#} -Fsu#Fvtt/M F €)4$A!E!E€Fuu6/==MJu#:8BEMJ F u#u:8 7I4[/1O6[)1O$ /ER :#Fvo F L#uv( s#xv -F}JA!E*u#L6!/M F BE!==$+u#F}6!/MJ F [/1O==%+f&%6!,• R f:L#Fo fFu %6:v#t( %6v#t :x JA!E*6!/M F BE!==$+u#uL6!/MJ F )1O$F45g w@$g/E A. 0,02 mol ; 0,04 molo u#uF6!/'u#u}6!/ u#u:6!/'u#uL6!/( u#uL6!/'u#us6!/ Fu JA/M F €)4$BE!MJ F )1O$:u45g h$i45gj)>==$Q/)1O$}45g e $@/E R L#Lvo F#Fs :#:FD. 4,48 oE:L(G&46/!E!)-&)Z$$@$46/!@$=A)1O$BC1C$€H)*1m R ###8 o |#o;#o# #S#o# ( ;#8#8 oE:sƒH)*$!#R/4<)1O$!46/!!!E!)-& R ; L M s o F M L 8M ( ; L M s # F M L #; F M L oE:}!==$$=!@$=ABC==J s F M L# )T#$H1OE!)-& R _$44"6U& o _$45gzH 6U4&BE$45gzH ( "$H1O oE:v !o46/!BE!==$M L F $H1OE!)-& Trang 2/6 !"## "$% R _Hh44"6E& o ]Hh44"6E&BE$45g 45gz ( 46/!)j!E oE:y1C$„B;/E==$$+ R /#/M L !1C$ o /#/M L !1C$ /#/M!1C$ ( /M#/M L !1C$ oE:t7X$H%+H"6x:#F6rOj6R/BE; M & !6"1m4"$4"4)1O$$ z]$_j6;BER/ F M L JQ]!==$J/=1)1O$:#t64J F "+$!z,/E R ;M o ; L M s ; F M L ( ; F M oE:xIPRQ/S-ƒ@$2%#$;/;$!$g&,<|::/E R : F F F F } L F o : F F F F s L : : F F F F v L F ( : F F F F v L : oEFuIPRQ/S-JrO]j6#o# F MBEoM JQ!E!EF:#x6]BE!1C$#)1O$:#:F/4J F )4$BE==${#!)$Fu#}F6oMJ F JA!E!Ev#yF/4M F )4$BE!{#)1O$6645g w@$g6/E R FL#vs o :}#yv F:#xF ( Lx#su B$5@5 • …)I]BZ 6!/lM 6!/&o 6!/ P7$6 ] 6 36 o 36 M F:#x P;3F&F6!/J F 3Fl P&6!/oMJ F u#:F ⇒ u#:s'lu#:s • 0_/H = + = − FF MM MJ &F :#Fy ⇒ %!F6[ =+ =+ ⇒ − − − MJ M F L L F 6!/M 6!/JM F ⇒ u#FF'u#ut • 6oM L u#ut :xy:}#yv oEF: 66rO]j6F6[$$!$gF46/!BE8)Z$F S6*m )1O$L#Lv/M F )Z4H,$kBE$Q/rOz{ !{@$=A5BC==$J/=1,6)1O$L#Lv /M F )Z4H,$k `>==$);6$"$)1O$LF#}66[4 [/1O6$grO])>/E R FF#x o Fx#F L}#t ( Lt#} oEFFIPRQ/S-JO$]$E>j6#J#M$+BQ;l; !v#x6]BE!Lvu6/==$MJ u#}8=1Fu~!BC/1O$>%+)5%+!E!E#)1O$==${ "${)1O$66$z 4 8\4@$#)[$@&!E!Ev#x6]$>B?)gy#ts/M F )4$#)1O$:}#s6M F o5]$$"+$-< UBC$"+$)2% w@$g6/E R :L#F o :F#L ::#: ( ::#s B$5@5 • 4[/1O6]36M F 6M F 36J F M ⇒ 6J F MF#y • JM J M :v 6 :t 6F ss 6 M MJM FF u#L}u#Lu#:}yvL ⇒ 7`7]/E y J v M L • ∆ } F Fvy F = +− Q;l; π 3Bs3 π 0&]$./EJMP v J s PMMJ!\$JMP v J s PMMJ • 6!/]6!/MJ1 L::}#uu}#u:uu :Fu }#u Lv#u :Lt x#v == ⇒ ]/EJMP v J s PMMJ • `+JM v J s MMJ3LMJ → M v J s M3JMM3FJ F M ⇒ 6]36MJ/&=1Fu~6z36J F M ⇒ 6z:F#L oEFL]$$@$$@$=A1C$!==$4Z6#==$4Z6E&$4%f!45gBC F M L ]%+BC!6[ 0&]/E R o M oM ( %R#o# 3%SQIPRQ/S-Q!E!E666r46/!BE!1C$=1#?46/!E!)-&)1O$.$4J F $U)Z4HH)*BE@/Ei• R o T ( M càng lớn thì số mol càng bé → hoặc C hoặc B Chọn 39 gam → nH 2 = 39: 39 : 2 = 0,5 mol (theo K); còn n H2 (theo Ca) = 39 : 40 = 0,975 mol. Vậy K là ít nhất. Trang 3/6 !"## "$% 3%S/IPRQ/S-!Fuu6/==$oMJ F u#:8BE!Luu6/==$JM L u#:8#)1O$==$]BE 45g{ !??==$J/u#F}8BE!])54z)>$456/ o5$@$%+)Z%&!E !E w@$g/E UQ o :vu vu ( su Có nCO 3 2- = nHCO 3 - = 0,03 mol > nBa 2+ = 0,02 mol (có 0,02 mol BaCO 3 ) dung dịch X có 0,01 mol CO 3 2- Và nOH - dư = 0,04 – 0,03 = 0,01 mol, để vừa bắt đầu xuất hiện bọt khí thì nH + = nOH - + n CO 3 2- = 0,01 + 0,01 =0,02 =0,25V →V =80 ml 3%SRIPRQ/S-JrO]j646/!4Z6BE6*46/!4Z6I JQ!E!E:#ytt6]BE!1C$# )1O$==${BE}Ly#v6/4J F )4$ (=$|j6J F SM s BEJ/#!)[6!/$gJ//>[6!/$g J F SM s 7Q==${n==$|!66rO6[ w@$g6/E R s#v}v o s#svu F#yxu CSVWXR Có nH 2 SO 4 = x mol; n HCl = 2x mol 4x = 0,024.2 → x = 0,012 mol → m muối = 1,788 + 0,024.35,5 + 0,012.96 = 3,792 gam 3%SWIPRQ/S-JrJA!E!EF#Fs/4M F )4$BE!y}u6/==$oMJ F u#F8#)1O$6645 g w@$g6/E R Fx#}} o x#t} /XVWQ ( Lx#su Có n OH - : n CO 2 = 3 → n BaCO 3 = nCO 2 = 0,1 mol → m = 19,7 gam. oEF}!ss6==MJ:u~@$=ABC:u6==!!$Lx#F~ S%+)1O$6[E!• R F J`M s o L `M s J F `M s ( F J`M s BE L `M s oEFv!66rO8#R/BE!F}u6/==$]$+rOJ/:8BEJ F SM s u#}8#)1O$}#LF/4 J F )4$BE==${$!.$==$4")I (=${$J/E R : o v y ( FĐ thi tuyển sinh Đi học - Cao đẳng Khối A năm 2007 oEFy!u#:6!/` F M } BE!==$+u#L}6!/MJ#(=$)1O$$$@$$ R J L `M s J F `M s o L `M s #MJ F J`M s BE L `M s ( F J`M s BEJ F `M s Đ thi tuyển sinh Đi học - Cao đẳng Khối A năm 2008 oEFt!:#x6rO6[$$!BE=!$$!$g46/!4Z68@$=ABC==$J/=1u#sst /4)4$ 6/!8/E R o ( Đ thi tuyển sinh Đi học - Cao đẳng Khối B năm 2008 oEFx!/==$MJu#F8BE!==$$+u#:}6!/R// L )1O$x#Lv645g w@$g/E R :#tBEF#F/ o :#tBEF#s/ :#FBEF#s/ ( :#sBEF#F/ oELu!==$R// L BE!==$ F M L $=1 JH1OE!)-&)q• R 45gzZo 45gBE 45gzf=>)5$X$)j=>)55( 45gzBE$gh4 oEL:J!E}#xs6rO6[$/!$g46/!]#{)Z*$6‚‚RBE!1C$)1O$:uu6/==$† Y./E645g5!/ $!==$†?!$!@$=ABC==$RM L )1O$:y#FF645g h$i 45g)1O$==$| "$==$|)1O$66rO6[4#6$@/E R v#Lvo vL#v x#:F ( x:#F oELF!==$$+6!/JM L F BE!==$6!/JSM s F JH1O%&/E R Sgh4o k)A$ Sgh4BEBk)A$( k)A$)![€/ oELL_=U!@$E!!$@$!@$=1C)-&).05)1O$rO$@$46/!#o#R/BER R J F Mo (=$MJ (=$J F SM s /!G( (=$J L oELs!/4SM F )4$@$=A5BC==$!6=1 7,6==$o/ F =1BE!rO,)1O$F#LL 645g 0@E!![$@$12@• R u#::F/ o u#FFs/ :#:Fu/ ( F#Fsu/ oEL}!rOj6BER/$_/H6!/12+/E:FBE!1C$=1 S4$@$%+%&!E!E)1O$t#xv /4J F )4$BE66$z4" w$g6/E R :u#to }#s y#t ( sL#FĐ thi tuyển sinh Đi học Khối A năm 2008 oELvi??Fuu6/==] F M L :8'JM L u}8BE!Fuu6/==J/F8.$M F )1O$€)4$/E R s#st/ o :#vt/ F#Fs/ ( L#Lv/ oELySA$::#F/M F )4$BE!==rO$+u#F6!/MJ F BEu#}6!/MJ [/1O45g)1O$4% +%&!E!E/E R }6 o Lu6 :u6 ( Y@@4@$ oELt!:/==J/BE!==$+u#F6!/R/M F /h$45g)54[/1O4")I)XO$y#v}6$z#j)* 6!/$g==$J//E R u#:}8BEu#L}8o u#:}8BEu#F8 u#F8BEu#L}8( u#F8BEu#L}8 oELxSA$s#st/M F )4$BE!==$+u#L6!/MJ F [/1O==%+5)I5E!!BC==)>• R w%6::#F6 o 7ft#t6 w%6Fu6 ( "&)I oEsuSA$6!/4M F BE!==MJ F )1O$L645g Y==%+&,6F645ge w@$g/E R u#u}6!/ o u#uy6!/ u#:6!/ ( u#ut6!/ oEs:SA$/4M F )4$BE!F}u6/==oMJ F :8)1O$:x#y645g w@$g/E R F#Fs/!\$s#st o s#st/!\$t#xv/ s#st/!\$v#yF/ ( F#Fs/!\$t#xv/ oEsFSA$4M F BE!Fuu6==oMJ F :y#:~)1O$645gBE==] !MJ F =1BE!==])1O$6 45g 7I4[/1O45g)1O$/>/Esx#s6 S[6!/4M F /E Trang 4/6 !"## "$% R u#F6!/ o u#sxs6!/ u#L6!/ ( u#s6!/ 3%/IPRQQW-:L#s6rOF6[$$!$gF46/!‚‚)1O$v#t$zBE4] 1O4 ]$!ABE!y}6/==$MJ:8#4[/1O6[4)1O$%+/E• R }#t o v#} s#F D. 6,3g 3%YIPRQQU-JA5/M F )4$BE!Luu6/==$MJ6!/K/)1O$:u#v6 F M L BEt#s6 JM L w#/>/1O/E• A. 4,48lít và 1M o s#st/BE:#}8 v#yF/BE:8 ( }#v/BEF8 3%ZJA5M F BE!==$MJ=1O$==$R R/E6F>n !==$o/ F =1BE!>:)1O$645g !==$oMJ F =1BE!>F)1O$645g !5a (=$R$+ R F M L o JM L MJBEJM L D. NaHCO 3 , Na 2 CO 3 3%[Y[$@&!E!Eu#:6!/;jA!E*%k6$@&BE!$+Luu6/==MJ:8 [/1O6[ )1O$%+ A. 8,4g và 10,6g o tsBE:uv u#tsBE:#uv ( s#FBE}#L 3%WY[$@&!E!E:&=!$$!R€.4!)Z4H1m%k6$@&)1O$A5BE!)X== MJ=1&4[/1OfFL6 7,65o/ F =1BE!&H,6yt#t645g ]@$)7`7R• R F J s o L J s C. C 4 H 6 ( L J v 3%UY[$@&!E!EF#v6&=!$$!RjA!E*%k6$@&BE!)X}uu6/==$MJ#,6 o/ F =1BE!==$%+&H:x#y645g h$i45gj,6oMJ F =1BE!>1C$/h$& H:x#y645ge ]@$)7`7R5xua8 R a::u Lx':F'J:'M:v'o:Ly R F J F o s J s v J v D. C 8 H 8 3%XY[$@&!E!E:u6O$e$2R#J#M JA!E*%k6$@&BE!vuu6/MJ:8&4[ /1O==$fFx#F6 7,6/ F=1 BE!==$%+&$:u645gH ]@$)7`7R 57`7UBC7Yw FL':F'J:'M:v'su A. C 5 H 8 O 2 o } J :u M F } J v M s ( } J :F M 3%/QY[$@&!E!E6!/$=e$2{)1O$F6!/M F 8\4@$).Q6!/{$>B?)gF6!/MJ "+$$!h$g{/E• R JMMJ F J F MMJ o F J } MMJ J L MMJ D. HOOC-COOH 3%//]/ErOzj68M L 'M L !L:#t6]@$=ABCu#t/==$J/:8 _@.)q R ]$Q=1%+ B. acid còn dư sau phn ng ]%+B?)gBC$= ( t#xv/M F )4$& 3%/IPRQQW-!??==$+6!/J/BE!==$$+6!/ F M L )jm4&)Z)1O$/4)4$BE ==$] $!=11C$B"!BE!==$]$H45g o.+$/,HeBC#/E• A. V=22,4(a-b) o ::#F ::#F3 ( FF#s3 3%SIPRQQW-JA!E!EF#vtt/M F )4$BE!F#}/==$oMJ F j)*6!/K/#)1O$:}#yv6 45g w$g/E• R u#uLF o u#ust u#uv D. 0,04 3%YIPRQQW-!66*/,6;E$!/;&/$BCHt:~ 7!E*/1OM F )1O$A !E!EBE!==$MJ F #)1O$}}u645gBE==$] Y4‡==$],6)1O$:uu645g w$g6/E• R }}u o t:u v}u D. 750 3%Z(p/M F )4$BE!Luu6/==MJ F u#}8 S%+)1O$:u45g 0&n RK F#Fs/ oK L#Lv/ K s#st/ D/. C A, C đu đng 3%[Y[$@&!E!Eu#:6!/ F J } ˆJjA!E*%k6$@&BE!$+y}6/==oMJ F F8 7I4[ /1O6[)1O$%+/EA. 32,65g o :x#y :F#x} ( L}#y} 3%WA!E*u#txv/M F BE!L/==$MJ F u#u:8)1O$ R :45g B. 2g kết tủa L45g ( s45g 3%UJA!E*u#L6!/M F BE!==$$+u#F}6!/MJ F 4[/1O==$%+f&%6! ,6•:F'J:'M:v'su R 7f:L#F6 o 7fFu6 w%6:v#t6 D Gim 6,8gam 3%XJA!E*6!/M F BE!==$$+u#uL6!/MJ F )1O$F645g _• :F'J:'M:v'su A. 0,02mol và 0,04 mol o u#uF6!/BEu#u}6!/ u#u:6!/BEu#uL6!/ ( u#uL6!/BEu#us6!/ 3%/QY[$@&u#FF}6!/1O)2$+$Rn!B?)g JA5%k6$@&BE!:uu6/==oMJ F :#}8)1O$ :s#yy}45g 1OR$$"+$E!=1C)-&•:F'J:'M:v'o:Ly A. CH 3 OH o F J } MJ L J y MJ ( s J y MJ 3%//JA!E!EF#Fs/M F )4$BE!==$1C$B"!$$+u#uy}6!/MJ F S%k6)1O$ %+j6 R _$M L o _$JM L F M L BEJM L F ( JM L F BEM F 3%/RJA!E!Eu#FFs/M F )4$BE!F/MJ F u#u:8)1O$6645g w$g6/E• R : o :#} F ( F#} 3%/SSA$/4M F )4$BE!:#}/oMJ F u#:8)1O$:x#y645g w/C$g/E• Trang 5/6 !"## "$% R :#:F o F#Fs s#st ( v#yF 3%/YJA5u#vyF/M F )4$BE!$+F/==$MJ F u#u:8 7,65u#s6MJBE!E& [/1O45g)1O$%+/E• R :#} o F F#} ( L 3%/ZJA!E!EF#vtt/4M F )4$BE!F#}/==$oMJ F j)*6!/K/)1O$:}#yv45g w $g/E• R u#uLF o u#ust u#uv ( u#us 3%/[(=$R$+MJ:8BEMJ F u#uF8#Au#}6!/4M F BE!}uu6/==$R)1O$45g$ 4[/1O• R :u o :F Fu ( Ft 3%/WJA5u#F6!/M F BE!:/==$$+MJu#F8BEMJ F u#u}8)1O$45g\• R } o :} :u ( : 3%/U(=$]$+MJu#F8BEMJ F u#:8 JAy#ts/4M F )4$BE!:/==$]4[/1O45 g)1O$/E• R :} o } :u ( : 3%/X!u#:s6!/M F A5BE!==$$+u#::6!/MJ F 70&4[/1OM L !/C24[ /1OM F )G=U,4[/1O==$$Q/%6!,• A. 1,84gam o :ts6 :t#s6 ( u#:ts6 3%RQ!u#:s6!/M F A5BE!==$$+u#ut6!/MJ F 70&4[/1OM L !i24[ /1OM F )G=U,4[/1O==$$Q/f/E!,• R s:v6 o s:#v6 C. 4,16gam ( u#s:v6 3%R/7_4[2$grO]j6M F BESM F !BC4 F nF !u#::F/)4$$g]/*$06W}uu6/== oMJ F SH6%=UF}6/J/u#F8).Q/1OoMJ F ? ~;![6!/6r4!rO]/E• R }uBE}u B. 40 và 60 LuBEyu ( FuBEtu 3%RR!}#v/]j6 F BEM F )4$)$06W}/==$MJ F u#uF8).%+%&!E!E)1O$} 645g 7_4[2$grO]!BCJ F A. 18,8 o :#tt Ly#v ( F: 3%RS(p}#v/M F )4$BE!$+Fuu6/==$MJj)*8'==$)1O$$4%f@$=A[ ):uu6/==$MJ:8 w@$g/E• R u#y} o :#} C. 2 ( F#} 3%RY!u#Fvtt/M F )4$A!E!E€Fuu6/==$MJu#:8BEMJ F u#u:8 7I4[/1O6[ )1O$/E• R :#Fv6 o F6 L#uv6 D. 4,96gam 3%RZY[$@&!E!E}#F6:&=!$$!R %k6$@&)1O$A5BE!==oMJ F &$Lx#s645g 7,6MJBE!>1C$/h$/&$:x#y645ge ]@$)7`7$gR 5xva8 R a::} :F'J:'M:v'o:Ly A. C 8 H 8 o v J v y J t M ( "@$) 3%R[Y[$@&!E!E:/1O6Rn!B?)g)1O$M F #J F MBE F $!!E*%k6$@&W)X 1C$B"!=1&$Fu45g 4[/1O==$%6)!BC)>/Es#x6 !@4i$.$/E :#:F/)4$ ]@$)7`7R58 R ayu :F'J:'M:v':s'su R L J y B. C 2 H 7 N ‰ L J x ( s J :: 3%RWY[$@&!E!ErORj6F&=!$$!/,5!=G&)j)Š JA!E*%k6$@&BE!L /==MJ F u#u:8)1O$45gBE4[/1O==$fF#sv !==oMJ F BE!/&$45ge 7I4[ /1O45gF/>/Ev#xs 764[/1O6r&=!$$!)G=U• A. 0,3g và 0,44g o LBEs#s u#LBEss ( LuBEss 3%RUY[$@&!E!E:j61O6;&/$BE1O;&/$jA!E*%k6$@&BE!:}u6/==oMJ F :8 &$45gBE4[/1O==$%6s#v 7,6==oMJ F =1BE!/&$:x#y45ge ~4[/1O6r1O !rO/E• R suBEvu o FuBEtu Lu#yBEvx#L D. 58,18 và 41,82 3%RX75E%+O1C$!E!EF4;)1O$F1O/,5 !rO1OE&@$=ABC=1 )1O$F#vtt/J F )4$ 8\4@$)[$@&!E!ErO,jA%k6$@&BE!1C$B"!)1O$Lu645 g#5A$$!MJ=1BE!&$:L645ge ]@$)7`7F4;•FL':F'J:'M:v'su A. C 2 H 4 và C 3 H 6 o L J v BE s J t s J t BE } J :u ( 4"@$))1O$ 3%SQJ5M F BE!==$MJ)1O$==$R o5n $!??==$J/BE!==$R%6}u6/==J/:86C&z)>$4!@ !==oMJ F =1BE!==$R)1O$y#tt645g ==$R$+•FL':F'J:'M:v'o:Ly R F M L o JM L C. NaOH và Na 2 CO 3 ( JM L # F M L Trang 6/6 . YZ$545(60)'789':+*;2)82<)" CEBF= $ >?= $ @ABCDEFAAGFHIJC=K>G=K>J=KL $ >J=KL $ L 7[6!/M F !$SM F 7[6!/MJ ]^_/H4 2 OH CO n n − `12%+M F 3MJ → 3 HCO − M F 3FMJ → 2 3 CO − 3J F M 354a:!6[ 3 HCO − BEM F =1!$ 3 HSO − BESM F =1 354:$_!6[ 3 HCO − !$ 3 HSO − 354F$_!6[ 2 3 CO − 354bF!6[ 2 3 CO − BEMJ =1!$ 2 3 SO − BEMJ =1 35:a4aF7!$%F6[ 3 HCO − BE 2 3 CO − c1d eE!@4".4. qd!rO#o#R/@$=ABC1C$ MJ R/1 :KF F H n o oMJF :KF R/1 M3NO8P2&Q;'R42R5S&)T8P= $ U+'+VNWP5X)C=K>J=KL $ :J=KL $ " Tính n CO −F L = n OH − - n CO F rồi s!@ +F !$ o +F ).;6$E!%+5).& 45g điu kiện n CO −F L ≤ n CO F Trang 1/6 . w@$g/E UQ o :vu vu ( su Có nCO 3 2- = nHCO 3 - = 0,03 mol > nBa 2+ = 0,02 mol (có 0,02 mol BaCO 3 ) dung dịch X có 0,01 mol CO 3 2- Và nOH - dư = 0,04 – 0,03 = 0,01