Vò V¨n Trµ- THCS Ph¹m Kha Ph©n lo¹i ph¬ng tr×nh Bµi 1: Gi¶i ph¬ng tr×nh. a/ x 5 3− = b/ x 10 2− = − c/ 2x 1 5− = d / 4 5x 12− = e/ x 5 9+ = f/ 1 2x 10+ = g/ 2x 3 1 2+ = + h/ 3x 2 2 3− = − k/ x 1 5 3+ = − m/ 3 x 1 8 15 7 x 5 + = − n / ( ) ( ) 7 x 8 x x 11− − = + q / ( ) ( ) 1 1 17 3 x 1 23 4 x 1 11 15 − − = − − p/ 2x 3 2 x 1 − = − u/ 2x 3 2 x 1 − = − s/ 4x 3 3 x 1 + = + t / 4x 3 3 x 1 + = + o / x 5 1 x+ = − i / x 4 2 x− = − ¬/ x 4 4 x− = − l / x 13 x 1+ = + y / 4 3 x 6 5x− + = w / 3 2x 3 x+ − = */ 2 x x 1 x 2+ + = + m* / 2 3 x 3+ + = Bµi 2: Gi¶i ph¬ng tr×nh: a/ x 1 2− = b/ 2x 1 4− = c/ 2x 5 4− = d/ 3 7x 2− = e*/ 1 x 1 2 − − = f/ ( ) 2 x 1 5− = g/ 2 x 8x 16 5− + = h/ 2 4x 20x 25 1− + = k/ 2 1 4x 4x 5− + = m/ x 15 3x 1+ = − n/ 7 x 5x 1− = + p/ 5x 4 4 5x− = − u / 2 x 5x 4 x 4− + = + v/ 2 x 10x 25 x 3− + = + s / 2 25x 30x 9 x 7− + = + t / 2 x 22x 121 2x 15− + = − r/ 2 9x 2x 1= + z/ 2 x 6x 9 3x 1+ + = − w/ 4 x 7= i/ 2 16x 3x 7= + j/ 2 1 9x 6x 2x 6+ − = + y/ ( ) 2 2 x 1 x 21 x 13 0− + + − − = Bµ 3: Gi¶i pt: a/ 2x 1 2x 1 4− + + = b/ 2 2 x x 5x 7x 1+ = + − c/ 2 2 2 3x 6 x 0− − − = d/ x 1 2 x 2 3 x 3 4− − − + − = e/ 2 2 x 1 x 4 3− + − = f/ 5 x 2 x− = g/ x x 1 2x 1 3+ − − − = h/ 2 2 x 2x 1 x 6x 9 4+ + + − + = u*/ x 3 4 x 1 x 8 6 x 1 5 + − − + + − − = v*/ x 2 x 1 x 2 x 1 2+ − + − − = Bµi 4: Gi¶i pt: a/ 5x 1 3x 2 x 1− − + = − b/ x 2 2 x 0− + − = c/ x 1 2 1 x− + = + d/ x 4 x 4 2+ − − = e/ x 7 x 1 4+ + + = f/ 3x 1 x 1 2+ − − = g/ 5 x x 3 2− + − = h/ 2x 1 x 3 4+ + − = k/ x 6 2x 5 x 1+ = − − + m/ x 4 x 1 2x 9+ + + = + n/ 6 2x 4x 3 3− + − = l/ 2x 3 x 1 1+ + + = j / x 2 x 1 2− − + = Vũ Văn Trà- THCS Phạm Kha Phân loại phơng trình s/ 2 x 9 3 x 3 0 = t/ 2 x 4 2 x 2 0 = u/ x x 1 1+ + = o/ x 4 x 1 2+ + = p/ 2x 1 x 3 4+ + = q/ x 1 5x 1 3x 2 = w/ x 3 x 4 1+ = Bài 5: Giải phơng trình: a/ 1 4x 20 x 5 9x 45 4 3 + + + + = b / 36x 36 9x 9 4x 4 16 x 1 = c / 2 3x 4 3x 27 3 3x = d/ 3 2x 5 8x 7 18x 28 + = e/ 1 4x 20 x 5 9x 45 4 3 + = f/ 16x 16 9x 9 4x 4 16 x 1+ + + + = + Bài 6*: Giải pt: a/ x 14 x 5 3 3 x 5 = + b/ ( ) ( ) x x 5 2 6 5 2 6 10 + + = c/ 2 2 3x 2x 2 x x 1 x+ = + + d/ 2 x 4x 5 2 2x 3+ + = + e/ 2 x 2 x 1 0 = g/ 2 2 1 1 2 x 1 x x 1 x + = + + + h/ 4 2 x x 1993 1993+ + = f / x 8 x 2 x 2 2 x 2 1 x 1 = + + + + + + ( Vế trái có 100 dấu phân thức) Bài 7: Giải phơng trình: a/ 2 4x 9 0 = b/ 3 x x 0 = c/ 2 8x 0,75 0,58 = d/ 2 2x 7x 0 = e/ 2 5 x 3380 0 9 = f/ 2 x x 0 = g/ 2 4x 3 0 = h/ 2 x 3x 0 = k/ 2 x 36 0 = m/ 2 3x 7x 0 + = n / 2 x 20 0 = l/ 2 2x 13x 0+ = u/ 2 2x 12 0 = v/ 2 3x 8x 0 + = t/ 2 x 1 0+ = q/ 2 3x 14x 0 + = p/ 2 5x 0 = r/ 2 x 14x 0 = s/ 2 3x 10x 0 = i/ 2 2x 3 0+ = j / 2 2x 72 0+ = w / 2 2x 1072 0 = ơ / 2 2x 3x 0 = / 2 56x 1120 0 + = z/ ( ) ( ) x x 15 3 108 5x = Bài 8: Giải pt: a/ 2 x 9x 14 0 + = b/ 2 x 4x 4 9 + = c/ 2 2 4x 4x 1 x + = d/ 2 x 4x 12 0 = e/ 2 x x 2 0 = f/ 2 4x 4x 3 0 = g/ 2 x 3x 10 0 = h/ 2 x 9x 36 0 = k/ 2 x x 20 0 = m/ 2 2x 11x 12 0 + = n/ 2 x x 1 0 + = l/ 2 3x 7x 5 0+ + = s/ 2 2x 13x 20 0+ + = t/ 2 3x 8x 4 0+ + = o/ 2 3x 14x 8 0 + = p/ 2 5x 6x 8 0 = q/ 2 x 14x 29 0 + = r/ 2 3x 10x 7 0 + = z/ 2 5x 9x 4 0+ + = y/ 2 3x 8x 4 0+ + = 1) 2 3x 14x 8 0 + = 2) 2 5x 6x 8 0 = 3) ( ) ( ) 3x 1 1 x 15 + = 4) 2 x 2x 2 1 0 + = 5) 2 2x 7x 5 0+ + = 6) 2 0,7x 2,3x 3 0 = 7) ( ) 2 x 1 2 x 2 0 + + = Vò V¨n Trµ- THCS Ph¹m Kha Ph©n lo¹i ph¬ng tr×nh 8) ( ) 2 x 2 2 3 1 x 3 2 0− − − = 9) ( ) 2 x 2m 1 x 2m 0− + + = 10) ( ) 2 x m n x mn 0− + + = 11) ( ) 2 2m 3 x 2mx 3 0− − + = 12) ( ) 2 x 2 1 2 x 4 3 2 0− + + + = 13) ( ) 2 4x 2 1 3 x 3 0− + + = 14) ( ) ( ) 2 2 5x 3 5x 3 x 3− − + = + 15) ( ) ( ) ( ) 2 2 x 2 x 3 2 x 5 − − + = − Bµi 9: Gi¶i pt: 1) 4 2 x 7x 12 0− + = 2) 4 2 x 18x 81 0− + = 3) 4 2 4x 5x 9 0− − = 4) 4 2 x x 1 0− + = 5) 4 2 2x 5x 7 0+ − = 6) 4 2 2x 5x 7 0+ − = 7/ 4 2 1 1 1 x x 0 3 2 6 − + = 8/ ( ) 4 2 3x 2 3 x 2 0− − − = 9/ 2 2 1 x 2 0 x + − = 10/ ( ) ( ) 2 2 x 1 x x 1 x 1 0+ − − + + = 11/ 4 2 2x 7x 5 0− − − = 12/ 4 2 3x 11x 14 0+ − = 13/ ( ) 4 2 x 2 3 x 2 3 0− + + = Bµi 10: Gi¶i pt: a/ ( ) 2 x 1 4 0− − = b/ ( ) 2 2x 3 16 0− − = c/ ( ) ( ) 2 2 x 1 4 x 3 0 − − + = d/ 4 2 2 x 4x 4 16x 8x 1+ + = − + e/ 3 2 x 4x 8x 8 0− + − = f/ ( ) ( ) 2 2 2 x x 4 x x 12 0+ + + − = g/ ( ) ( ) 2 2 x x 1 x x 2 12 0− + − + − = h/ 2 2 2 2 x 12 x 14 x 18 x 16 7 9 13 11 − − − − − = − k*/ 2 2 1 1 19 3 x 4 x x x 4 + = − + ÷ ÷ u/ 5 2 x x 2x 2 0+ + + = i/ ( ) ( ) x 2 x 3 0− − = Þ/ ( ) ( ) ( ) x 1 x 2 x 3 0+ + − = o/ ( ) 3 x 3 27− = p/ 3 x 8 x 1 = ÷ − w*/ ( ) 2 2 x 3 x 0 − + = z*/ ( ) ( ) 2 2 x 2y y 1 0+ + − = y*/ 2 x 2 x 1 0− − = 1) 4 3 2 x 2x 6x 2x 1 0+ − + + = 2) ( ) ( ) ( ) x x 1 x 2 x 3 3+ + + = 3) 2 x 4x 5 2 2x 3+ + = + 4) 3 2 x 3x 3x 1 0+ + + = 5) 4 2 x 4x x 2 0− + + = 6/ 4 3 x x 3x 3 0− − + = 7/ ( ) ( ) 2 2 2 2 2x 3x 4 x x 1 0− − − − = 8/ 3 2 x 3x 3x 9 0− − + = 9*/ x 3 x 4 49 3 x 4 x 12 + + + = 10*/ x x 1 2 0 x 1 x + + + = + 11/ ( ) ( ) 2 2 2 x 5x 30 x 5x 216 0− − − − = 12/ 2 1 1 x 6 x 8 0 2 2 + + + + = ÷ ÷ 13/ ( ) ( ) 2 2 9 3x 2 4 7 2x 0+ − − = 14/ ( ) ( ) 2 2 y 5y 8y y 5 84 0+ − + − = 15*/ ( ) 2 2 y 5 5 y 5 6− − − = Vò V¨n Trµ- THCS Ph¹m Kha Ph©n lo¹i ph¬ng tr×nh 16*/ x 1 x 2 x 3 x 4 58 57 56 55 + + + + + = + 17*/ ( ) ( ) 4 4 x 3 x 5 9+ + + = 18*/ [ ] 2 x 8 x 7 0− + = 19*/ 4 2 x x 1993 1993+ + = 20*/ ( ) ( ) 2 2 x x 1 x x 12 12+ + + + = Bµi 11: Gi¶i pt: a/ x 4 2x 3 2 2x 3 x 4 + − + = − + b/ ( ) ( ) 2 1 1 1 x x 2 12 x 1 − = + + c/ 2 2 1 1 0 2x 1 2x 4 − = − − d/ ( ) 3 x 1 2x 1 6 x 1 x 1 − + + = − + e/ x 4 2x 3 2 2x 3 x 4 + − + = − + f/ 1 1 1 x 1 x 9 x + = − − / 2 2 2 y 3 1 y 9 6y 2y y 3y + = − + − ¬/ ( ) ( ) 3 2 32 1 1 x 2x x 2 x 1 x 2 x 1 + = − − − − − + g/ 2x 5 x 0 2x 2x 5 + − = + h/ 2 2 3 2 2 x x 5 x x 4 + = − + − + − h/ ( ) 2 x 1 x 2 x x 1 x x 1 + + = − + + k/ 1 1 1 0 x 1 x 1 x 4 + + = − + − m*/ 3 3 1 1 x x x x + = + n*/ 3 3 8 x x 2 x x − − = − u*/ 2 2 x 1 x 1 x 1 x 1 0 x 1 x 1 x 1 x 1 + − + − + + + = ÷ ÷ − + − + s/ 2 14 4 x 7 1 x 9 3 x x 3 3 x − + = − − + + − t/ x 1 x 1 3 x 1 x 1 + − + = − + i/ 2 y 2 y 2 5 6 0 y 1 y 1 + + − + = ÷ ÷ − − j/ x 2 16x 7 0 2x x 2 + − + = + . phơng trình: a/ 1 4x 20 x 5 9x 45 4 3 + + + + = b / 36x 36 9x 9 4x 4 16 x 1 = c / 2 3x 4 3x 27 3 3x = d/ 3 2x 5 8x 7 18x 28 + = e/ 1 4x 20 x 5 9x 45 4 3 + = f/ 16x 16 9x 9 4x. 1 x + = + + + h/ 4 2 x x 199 3 199 3+ + = f / x 8 x 2 x 2 2 x 2 1 x 1 = + + + + + + ( Vế trái có 100 dấu phân thức) Bài 7: Giải phơng trình: a/ 2 4x 9 0 = b/ 3 x x 0 = c/ 2 8x. 1 x 2 x 3 x 4 58 57 56 55 + + + + + = + 17*/ ( ) ( ) 4 4 x 3 x 5 9+ + + = 18*/ [ ] 2 x 8 x 7 0− + = 19* / 4 2 x x 199 3 199 3+ + = 20*/ ( ) ( ) 2 2 x x 1 x x 12 12+ + + + = Bµi 11: Gi¶i