1. Trang chủ
  2. » Tất cả

Chuong 5a drilling hydraulics hydrostatics

27 0 0

Đang tải... (xem toàn văn)

Tài liệu hạn chế xem trước, để xem đầy đủ mời bạn chọn Tải xuống

THÔNG TIN TÀI LIỆU

Thông tin cơ bản

Định dạng
Số trang 27
Dung lượng 613,5 KB

Nội dung

Petroleum Engineering 405 Drilling Engineering * Well Drilling Engineering Drilling Hydraulics Hydrostatics Dr DO QUANG KHANH * Drilling Hydraulics Hydrostatics Hydrostatic Pressure in Liquid Columns[.]

Well Drilling Engineering Drilling Hydraulics - Hydrostatics Dr DO QUANG KHANH Drilling Hydraulics - Hydrostatics  Hydrostatic Pressure in Liquid Columns  Hydrostatic Pressure in Gas Columns  Hydrostatic Pressure in Complex Columns  Forces on Submerged Body  Effective (buoyed) Weight of Submerged Body  Axial Tension in Drill String A = FA/A Read: Applied Drilling Engineering, Ch.4 (Drilling Hydraulics) HW #4 ADE # 4.3, 4.4, 4.5, 4.6 WHY? Drilling Hydraulics Applications  Calculation of subsurface hydrostatic pressures that may tend to burst or collapse well tubulars or fracture exposed formations  Several aspects of blowout prevention  Displacement of cement slurries and resulting stresses in the drillstring Drilling Hydraulics Applications cont’d Bit nozzle size selection for optimum hydraulics Surge or swab pressures due to vertical pipe movement Carrying capacity of drilling fluids Well Control ppore < pmud < pfrac Fig 4-2 The Well Fluid System Forces Acting on a Fluid Element F1 = FWV = specific wt of the fluid pA dp D ) A F2 = ( p  dD F A  D w v F3 = Pressures in a fluid column  At equilibrium, F=0 = F1 + F2 + F3 dp  F 0 pA  ( p  dD D )A  Fw v AD  dp  Fw v dD (p = gh) Incompressible Fluids dp  Fw v dD Integrating, p  Fw v D  p [ p  p when D  ] Incompressible Fluids In field units, Fw v 62   * 144 33  0.433 * 8.33 Fw v  052  1’ x 1’ x 1’ cube 10 Compressible Fluids p = pressure of gas, psia o T = temperature, R V = gas volume, gal  = density, lbm/gal Z = gas deviation factor M = gas molecular wt n = moles of gas m = mass of gas, lbm R = universal gas constant, o = 80.3 psi.gal/lb-mole R 13 Compressible Fluids From Eqs (2) and (4): 052 p M  dp  dD 80.3 Z T  p  p0 Integrating,  Assumptions? dp M  p 1544 Z T [ln p ] p p0 D  D0 dD M D  [D] D 1544 Z T M (D  D ) p p exp [ ] 1544 Z T 14 Example M (D  D ) p p exp [ ] 1544 Z T Column of Methane (M = 16) Pressure at surface = 1,000 psia Z=1, T=140 F (i) What is pressure at 10,000 ft? (ii) What is density at surface? (iii) What is density at 10,000 ft? (iv) What is psurf if p10,000 = 8,000 psia? 15 Fig 4-3 A Complex Liquid Column p 0.052  D  p0 p 0.052  D n p  p  0.052   i ( D i  D i  ) i 1 16 Pa = ? Fig 4-4 Viewing the Well as a Manometer 17 Buoyancy Force = weight of fluid displaced (Archimedes, 250 BC) Figure 4-9 Hydraulic forces acting on a foreign 18 Effective (buoyed) Weight We  W  Fb W - f V W W - f s   We  W    f s    Buoyancy Factor Valid for a solid body or an open-ended pipe! 19 Example For steel,  s  65 lbm / gal immersed in mud, (  f 15 lbm / gal ) the buoyancy factor is:  f   15.0         0.771 s   65.5   A drillstring weighs 100,000 lbs in air Buoyed weight = 100,000 * 0.771 = 77,100 lbs 20

Ngày đăng: 02/04/2023, 11:04

w