Tyre Vehicle Dynamics 2011 Part 5 pptx

Tyre Vehicle Dynamics 2011 Part 5 pptx

Tyre Vehicle Dynamics 2011 Part 5 pptx

... camber: α -60 0 60 κ 1 0. 05 0.1 0.2 0.4 0.8 1.6 κ 0, κ -1 -0 .5 0 0 .5 1 1 0,2, 5 10 20 40 80 α α α -60 0 60 0. 05 1 0.1 0.2 0.4 0.8 1.6 κ 0 α κ κ -1 -0 .5 0 0 .5 1 10 1 25 20 40 80 α 0 200 80 κ κ 0 0 .5 1 0 κ α γ α -60 0 60 4 0. 05 0.1 0.2 0.4 0.8 1.6 κ 0 [kN] 4 0 0 .5 1 [ - ] κ 10 20 40 80 α o [ ] 0, 2, 5 [kN] κ -1 ... class="bi x0 y 65 w1 h4d" alt="" 2 β cos β arctan( )...

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Tyre Vehicle Dynamics 2011 Part 6 docx

Tyre Vehicle Dynamics 2011 Part 6 docx

... 1 ψ o 0 1 .5 [m] 1.00 .50 -60 0 -20 -40 step in side slip step in yaw angle = 1 α o = 1 ψ o [Nm] 1 .5 [m] 1.00 .50 0 [N] 20 10 1 .5 [m] 1.00 .50 step in turn slip = 1/1 15 [1/m] ϕ o = 1 15 [m] o 1 .5 [m] 1.00 .50 [Nm] step ... [m] o 1 .5 [m] 1.00 .50 [Nm] step in turn slip = 1/1 15 [1/m] ϕ o = 1 15 [m] o 0 1 .5 1.0 0 .5 2.0 0 0 .5 -0 .5 [kNm] 0.4 0.8 [m] = -2 α o 0 o 2...

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Tyre Vehicle Dynamics 2011 Part 14 ppt

Tyre Vehicle Dynamics 2011 Part 14 ppt

... 160 [km/h] 0 5 -5 -10 real part eigenvalues [1/s] wobble weave capsize lean mode = 0 baseline + rider lean 040 80 120 160 [km/h] 0 5 -5 -10 real part eigenvalues [1/s] wobble weave capsize = 0 = - 150 0N = ... y126 w5 h1a" alt="" 01 2 5 34 0.01 -0.04 0 response to step lean torque =1Nm [s] time δ ϕ ϕϕ ϕ 10 δ 10 [rad] = 35 km/h = 0 012 53 4 [s] time ϕ ϕϕ ϕ 10 δ 10 [rad]...

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Tyre Vehicle Dynamics 2011 Part 15 pot

Tyre Vehicle Dynamics 2011 Part 15 pot

... lines tan ϕ -0.1 -0. 05 0 0. 05 0.1 -1 .5 -1 -0 .5 0 0 .5 1 1 .5 -0.1 -0. 05 0 0. 05 0.1 -1 .5 -1 -0 .5 0 0 .5 1 1 .5 [rad] α 1 [rad] α 2 1 1 2 2 0 o = 55 o γ 1 = 55 o γ 2 0 o = 1732 N 1 = 2094 N 2 equilibrium curve equilibrium ... 0. 05 δ 30 40 50 20 10 m/s = α 2 α α 21 0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 α α 12 α 1 α α 21 equilibrium curves handling curve speed li...

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