lý thuyết tin học a bài tập tin học a

... Email: Jackie9x.spb@gmail.com  3 a = -2x 1 A a A v222 Hay 1v a vv2max222max2 hay 2 2 2 2max a (v v )   hay 1 a avv2max22max2 ...  A) , gia tc có đ ln cc đi : a max = 2 A. Giá tr đi s: a max=2 A khi x= -A; a min=-2 A khi x =A; . -  v trí cơn bng (x = 0), gia tc bng 0. + Lc tác dng lên vt dao ... LC1 A 3 A 1 B1 A 2 B2 B3 A 3 A 1 B1 A 2 Mcăsaoăăăăăăă Mcătamăgiácătamăgiác UYN TI I C MễN VT í Email: Jackie9x.spb@gmail.com 30 in t. Trong thc t, cỏc mch dao...

... A 1 để A 2max: A 2max = 2 1sin( ) A ϕ ϕ− và A 1= 2 1tan( ) A ϕ ϕ−Chú ý: Nếu cho A 2 thì từ 2 công thức trên ta tìm được A = A min A min = A 2sin(ϕ2 - ϕ1) = A 1tan(ϕ2 ... 098633818934Tóm Tắt Lý Thuyết Và PP Giải Bài Tập Vật Lí 12 - Năm Học 2013 – 2014 – Tập 1BẢNG CHỦ CÁI HILAPKí hiệu in hoa Kí hiệu in thường Đọc Kí số A αalpha 1Bβbêta 2Γγgamma 3∆δdenta 4Eεepxilon ... c a lò xo ở VTCB (đơn vị là mét)+ Đề cho x, v, a, A: ω 2 2v A x− a x max a A maxv A 2. Cách xác định A: + A = xmax: vật ở VT biên (kéo vật khỏi VTCB 1 đoạn rồi buông x = A) .Gv...

... ngược pha: π+=ϕ∆ )1k2( thì: A = A 1 – A 2.D. Nếu hai dao động lệch pha nhau bất kì: 21AA −≤ A ≤ A 1 + A 2Gv soạn: ThS. Nguyễn Vũ Bình - Tel: 098633818923 Bài Tập Ôn Thi Đại Học Môn ... qua ma sát gi a m1 và mặt sàn nằmngang, ma sát gi a m1 và m2 là µ12 = 0,8.Biên độ dao động c a vật m1 bằng bao nhiêu để hai vật không trượt lênnhau: A. A ≤ 0,8 cm. B. A ≤ 2 cm C. A ... đúng: A. Độ lệch pha c a các dao động thành phần đóng vai trò quyết định tớibiên độ dao động tổng hợp.B. Nếu hai dao động thành phần cùng pha: π=ϕ∆ 2k thì: A = A 1 + A 2C. Nếu hai dao động...

... đang ở vị trí x =A/ 2, người ta thả nhẹ nhàng lên m một vật có cùng khối lượng và hai vật dính chặt vào nhau. Biên độ dao động mới c a con lắc? A. '72 A A =B. '22 A A =C. ' 7A ... pha có cùng biên độ A gây ra tại M sự giao thoa với biên độ 2A. Nếu tăng tần số dao động c a hai nguồn lên 2 lần thì biên độ dao động tại M khi này là A. 0 . B. A C. A 2. D. 2A Câu 13: Hai ... khoảng gi a A và B có giao thoa sóng do hai nguồn trên gây ra. Phần tử vật chất tại trung điểm O c a đoạn AB dao động với biên độ bằng: A. 2 a B. 2a C. 0 D .a Câu 2: Để khảo sát giao thoa sóng...

... 4>$)9B$'7&'&=%$'7 A. )& A 4<3 B.   A 4&'53 C. -4 A 4$3 D. -4 A 4&'53Câu ... HỎI LÝ THUYẾT ÔN THI ĐẠI HỌC MÔN VẬT LÍ - NĂM HỌC 2013 - 2014 – TẬP 3Câu 49: >$)9B&'&=%2-4%  A >$45&'HP3I*#&'53Q3I*#9)53I3M ... )"#-43Câu 15: ~4")>$ A. )9>&'3B. &')9>&'3C. )9&'&=3Gv...

... ))SD ABCD = · · ·0tan 3 60SASDA SDA SDAAD= = =Þ Þ4) SA ⊥ (ABCD) (gt) ⇒ AO là hình chiếu c a SO trên ( ABCD) ⇒ ·( ,( ))SO ABCD = · ·tan 6SASO A SO A aAO= =Þ5) BC ⊥ ( SAB) ⇒ ... (SAD))⇒ AK ⊥ ( SCD) (1)• SA⊥ ( ABCD) ⇒ SA ⊥ AD, AD⊥ AB ⇒ AD ⊥ ( SAB)(2) Từ (1) và (2) ta có ···(( ),( )) ( , )SCD SAB AD AK DAK= = và do · ··0 0tan 3 60 30SDA SDA DAK= ⇒ = ⇒ =7) Ta ... chiếu c a SA trên ( SCD) ⇒ ···( ,( )) ( , )SA SCD SAAK ASK= =·tanAKASKSK=, SK= 32 a ,AK = 32 a · ·01tan 303AKASK ASKSK= = =Þ Þ10) AH ⊥ ( SBC) ⇒ SH là hình chiếu c a SA trên...

... 22. A 23. C 24. B 25. B 26. D 27. D 28. D 29. B 30. A 31. B 32. D 33. B 34. A 35. C 36. D 37. C 38. D 39. A 40. A 41. A 42. A 43. C 44. C 45. B 46. D 47. D 48. A 49. A ... trung trc c a AB cách AB 100 m và M là đim nm trên đng thng qua O song song vi AB, gn O nht mà ti đó nhn đc âm to nht. Cho rng AB << OI (vi I là trung đim c a AB ). Khong ... mt khong NA = 1m, có mc cng đ âm là L A = 90 dB. Bit ngng nghe c a âm đó Io = 0,1 nW/m2. Cng đ âm đó ti A là A. I A = 0,1 nW/m2. B. I A = 0,1 mW/m2. C. I A = 0,1 W/m2....

... dây. C. khong cáh gi a hai nút sóng hay hai bng sóng liên tip. D. hai ln khong cách gi a hai nút sóng hay hai bng liên tip. LÝ THUYT TNG HP V SÓNG DNG (BÀI TP T LUYN) Giáo ... mt si dây mà hai đu đc gi c đnh, bc sóng bng A. đ dài c a dây. B. mt n a đ dài c a dây. C. khong cách gi a hai bng sóng liên tip. D. hai ln khong cách gi a hai bng sóng liên ... Mô t s i dây AB co chiê u da i 1 m cng ngang , đâ u A cô đi nh , đâ u B g n v i mô t nha nh cu a âm thoa dao đô ng điê u hoa v i tâ n sô 20 Hz. Trên dây AB co mô t so...

... có uAB và uAM lệch pha nhau  Ở đây 2 đoạn mạch AB và AM có cùng i và uAB chậm pha hơn uAM  AM – AB =   tan tantan1 tan tan   AM ABAM AB Nếu uAB ...  1 21 2tan tantan1 tan tan    Trường hợp đặc biệt  = /2 (vuông pha nhau) thì tan1tan2 = -1. LUYỆN THI ĐẠI HỌC MÔN VẬT LÝ Email: Jackie9x.spb@gmail.com  ... 2kA A Smg g * gim biờn sau mi chu k l: 24 4mg g A k gim biờn sau N chu k: N 0 N4NFms A = A - A =K * S dao ng thc hin c: 24 4 A Ak A N A mg g * Thi gian...

... H+ c a axit dễ bị khử hơn các ion H+ c a nước b) Khả năng phóng điện c a các anion ở anot: Ở anot xảy ra quá trình oxi h a các anion gốc axit như Cl-, S2-…hoặc ion OH- c a bazơ kiềm ... Ngược lại trên anot sẽ diễn ra sự oxi h a dạng khử c a cặp có thế oxi h a – khử nhỏ nhất trước. a) Khả năng phóng điện c a các cation ở catot: Ở catot có thể xảy ra các quá trình khử sau đây: - ... Na, K, Ba, Ca, Mg, Al Ví dụ 1: Điện phân NaCl nóng chảy có thể biểu diễn bằng sơ đồ: Catot ( – ) NaCl Anot ( + ) 2| Na+ + e → Na 2Cl- → Cl2 + 2e Phương trình điện phân là: 2NaCl 2Na...

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AAAQbAAAAAg2AAAABBsAAIBgAwAAQLABAAAINgAAAAQbAACAYAMAAECwAQAAINgAAAAEGwAAAIINAABAsAEAACDYAAAAEGwAAACCDQAAAMEGAAAg2AAAABBsAAAACDYAAADBBgAAgGADA...

... m/s. Bài 4. Ta có: eUAK = hfmax UAK =ehfmax= 26,5.103 V. Bài 5. Ta có: eUAK = hfmax fmax =heUAK= 0,483.10-19 Hz. Bài 6. Ta có: eUAK  =hc min =AKhceU = ... và Cao ng Bài 2. Ta có: eUAK  =hc UAKmax =minhce = 31.103 V. Bài 3. a) Ta có: I =UP= 0,04 A. b) Ta có:21mv2max = eU0 = eU2  vmax =meU 22= 7.107 m/s. Bài ... =26,5.103 V). Bài 5. Hiu n th gi a hai n cc c a ng Cu-lít-gi (ng tia X) là UAK = 2.104 V, b qua ng nngban u c a êlectron khi bt ra khi catt. Tính tn s ln nht c a tia X mà...

... trị c a hàm số là nghiệm đơn hay nghiệm bội ba c a a thức: f′()x = 4x3 + 24ax2 – 8()x 1 + 2a = 4x()2x + 6ax - 2 1 + 2a ⎡⎤⎣⎦ Tam thức g(x) = x2 + 6ax – 2(1 + 2a) có ... –2()2 6a + 2a + 1 x2 + 4()2 a + 2a x + 3 vì = = ff′()1x f′()2x′()3x = 0 Vậy, phương trình Parabol đi qua 3 điểm cực trị là : y = –2()2 6a + 2a + 1 x2 + 4()2 a + 2a x ... 24ax2 – 8()x 1 + 2a y′′ = 12x2 + 48ax – 8() 1 + 2a y′′ = 0 3x⇔2 + 12ax – 2()1 + 2a = 0 (9) Vì (9) có = 3 6a ′Δ2 + 6() 1 + 2a = 6()2 6a + 2a + 1 > 0 , ∀a...

... c a mắt. LUYỆN THI ĐẠI HỌC MÔN VẬT LÝ Email: Duclongtn95@gmail.com 1 HỆ THỐNG LÝ THUYẾT VÀ CÁC DẠNG BÀI TẬP VẬT LÝ 11 * Tóm tắt lý thuyết * Công thức tính nhanh * Các dạng bài ... '11dd; k = ABBA ''= - dd'= dff. ;ABkBA .''  Qui ước dấu d OA : d > 0 : vật thật ; d< 0 : vật ảo. LUYỆN THI ĐẠI HỌC MÔN VẬT LÝ ... Ir, hay rIABUE (dòng điện chạy từ A đến B, qua nguồn từ cực âm sang cực dương) - Định luật Ôm cho đoạn mạch ch a máy thu UAB = V A – VB = Ir’ + Ep, hay 'rUIpABE-...

... 2Hai dao động cùng pha 2 : Hai dao động ngược pha (2 1) : Hai dao động vuông pha (2 1) : 2Hai dao động có độ lệch pha : k A A A k A A A k A A A const A A A A A 2. Khi biết một dao động ... lớn c a li độ. - Ở vị trí biên (x =  A) , gia tốc có độ lớn cực đại : a max = 2 A. Giá trị đại số: a max=2 A khi x= -A; a min=-2 A khi x =A; . - Ở vị trí cân bằng (x = 0), gia tốc ... y A A A A      2 2x y A A A    và tanyx A A với  [Min;Max] 4. Dùng máy tính tìm phương trình ( dùng cho FX 570ES trở lên) LUYỆN THI ĐẠI HỌC MÔN VẬT LÝ Email:...