comparison of methods for calculating serum osmolality form chemical concentrations and the prognostic value of such calculations clin chem 1975 feb 21 2 190 4
... −0.67 −0.69 12 −0. 12 −0.18 29 8 −0 .25 −0 .20 125 −0.13 −0. 14 48 −0.09 −0.05 Sum −6.9 2. 0 −0.5 22 .1 −17.9 −5.3 2.42. 9 2. 6 QTL variance HH BB BU 25 0 90 91 129 327 89 83 89 87 22 3 99 100 QTL ... none ofthe markers are informative (NI); (b) only informative markers on the left side ofthe position (IL); (c) only informative markers on the right side ofthe position (IR); and (d) informative ... biases the estimate ofthe average coefficient of inbreeding, since the sum ofthe Eigenvalues equals the trace ofthe matrix [22 ], and their average is equal to one plus the average coefficient of...
... 1.35 4. 05 1.8 1.9 10 7.15 2. 35 2. 35 12 5.65 2. 05 2. 7 14 1.85 2. 1 16 4. 6 1.55 1.75 18 2. 1 0. 62 0.76 Isochrysis galbana H5 grew the better in f /2 than in the ESM media and ASW media The growth of ... Acid (DHA) 4. 16 14. 69 2. 09 1 .22 5. 42 2.71 3. 52 18.9 0 . 24 15.89 5.53 The total fatty acids in Isochrysis galbana H5 are 74. 37 g/mg fresh weight Isochrysis galbana H5 has a great variety of fatty ... from 14C to 22 C, among C16:0, C18:4n-3 and C 22: 0 are the most abundant fatty acids The compossition is different from previous report [10] but major variations in the fatty acid compositions of...
... (2. 40 ) for Re = and α = 90◦ 47 2. 18 The flow with conditions (2. 40 ) for Re = and α = 115◦ 47 2. 19 The flow with conditions (2. 40 ) for Re = and α = 135◦ 47 2. 20 The ... (2. 38) for Re = and α = 90◦ 44 2. 10 The flow with initial regime (2. 38) for Re = and α = 115◦ 44 2. 11 The flow with initial regime (2. 38) for Re = and α = 135◦ 44 2. 12 ... CHAPTER THE NUMERICAL METHOD FOR FLOWS IN SECTORS ∂ϕ ∂ζ = 0, ζ=ζl 2 ∂ζ = (2. 28 ) ζ=ζl Now instead ofthe boundary -value problem (2 .21 ) – (2. 24) we will solve the approximate problem (2 .21 ) , (2. 23),...
... arrival in the ED was 27 (10) minutes Before pre-hospital treatment (T1) Ofthe 1 24 patients who were included in the study on arrival ofthe ambulance at the scene, 92 survived and 32 died Compared ... 1 24 Non-survivors: n = 32 Survivors: n = 92 Age (years, ± SD) 62 ± 19 68 ± 14 * 59 ± 20 * Sex (n, % male) 73 (59%) 22 (69%) 51 (55%) Intensive care unit admission (n, %) 57 (46 %) 15 (47 %) 42 ... 82% ), specificity of 74% (95% CI = 65 to 84% ), PPV of 47 % (95% CI = 31 to 63%) and a NPV of 85% (95% CI = 77 to 94% ) In the high lactate group, 47 % (95% CI = 31 to 63%) ofthe patients died,...
... as basis The receiver in the EURASIP Journal on Advances in Signal Processing Tmpe-fec = 0. 847 8 0.1 522 0. 42 2 7 0.5773 0.99 0.01 0.01 0.99 80 25 % 23 % 66% 56% 60 40 75% 77% 44 % 20 34% (2) The state ... each cell ofthe matrix hosts one byte of information and N denotes the number of rows in the matrix The standard defines thevalueof N to be one of Miska M Hannuksela et al IP header (20 B) Payload ... enclosed in a stand that left only the screen and buttons ofthe device visible The device andthe front ofthe stand were vertically aligned andthe viewing distance was set to 44 cm The headphones...
... normal PCR reaction of 50 µl volume (25 µl of master mix, Comparisonof Diagnostic Methodsforthe Detection of Parasites in Fish 2 l of each primer, or µl of template and 18 or 20 µl of water) - Polymerase ... Comparisonof Diagnostic Methodsforthe Detection of Parasites in Fish and disadvantages, depending on the purpose and target of study For parasitological investigation, the classical methods ... 0.76 15 .23 ± 2. 36 1/3 Roach Rutilus rutilus 15.30± 3.89 49 .11± 4. 12 2/8 Total 18 13.13 2. 11 28 .68 4. 71 27 .8% Name of fish species Three fish species with a total of samples were tested by the compression...
... one-way forwarding using Matthew’s formula of 2, 7 84 m and 1,969 m respectively Sundberg’s formula Considering Cnet ofand p of 0 .25 as average valueand input, the other variables in the formula for ... J FOR SCI., 55, 20 09 (9): 42 3 43 1 Loading and unloading time Fig Scatter of loading and unloading time with forwarding distance y 3. 645 2Ln(x 9 .22 84 y = = 3. 645 2Ln(x))++ 9 .22 84 60 R2 = 0 .26 54 ... prediction model Slope of J FOR SCI., 55, 20 09 (9): 42 3 43 1 Table Summary statistics ofthe parameters Parameter Max Mean Min Loading (min) 42 . 24 17 .23 2. 78 Loaded travel (min) 10. 72 4 .22 0.35 Unloading...