3 paragraphs 3 and 4 activities
Báo cáo khóa học: Human PABP binds AU-rich RNA via RNA-binding domains 3 and 4 pdf
... for AU4 (nM) Kd for M8 (nM) PABP PABP1 2 34 PABP12 PABP 34 0.67 (0.61–0. 74) 0. 74 (0.61–0.81) 1.8 (1.6–1.9) 1.5 (1 .3 1.6) 3. 9 (3. 7 4. 1) 1 .3 (1.2–1 .4) 1 13 (82–157) 2.9 (2.8 3. 1) 7.7 (6.5–9.1) 2 .4 (2.2–2.6) ... proteins PABP1 2 34 contains the four RRM domains but not the large C-terminal domain, while PABP12 and PABP 34 contain RRM domains and 2, and RRM domains and 4, respectively (Fig 3) The Fig Detection ... nickel chromatography and poly(U) affinity column Lane 1, PABP; lane 2, PABP1 2 34 ; lane 3, PABP12; lane 4, PABP 34 Ó FEBS 20 03 45 4 R T Sladic et al (Eur J Biochem 271) Fig Measurement of apparent Kd values...
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báo cáo hóa học: " Similar promotion of Aβ1-42 fibrillogenesis by native apolipoprotein E ε3 and ε4 isoforms" pptx
... Y: Visualization of Aβ 42 ( 43 ) and A 40 in senile plaques with endspecific Af3 monoclonals: Evidence that an initially deposited species is A 42 ( 43 ) Neuron 19 94, 13: 45 - 53 Naslund J, Thyberg J, ... amyloid J Biol Chem 19 94, 269: 2 34 03- 2 34 06 Zhou Z, Smith JD, Greengard P, Gandy S: Alzheimer amyloid-β peptide forms denaturant-resistant complex with type 3 but not type 4 isoform of native apolipoprotein ... apolipoprotein E 3 CHO apolipoprotein E 4 CHO apolipoprotein E 3 CHO apolipoprotein E 4 CHO apolipoprotein E 3 CHO apolipoprotein E 4 CHO apolipoprotein E 3 CHO apolipoprotein E 4 Aβ1 -40 1.0 ±...
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Báo cáo toán học: "Goldberg-Coxeter Construction for 3- and 4-valent Plane Graphs" pdf
... 2, 53 0, 3, 2, 588 [CC] 43 34 26 34 43 43 43 34 43 34 26 26 34 26 34 43 43 43 43 34 34 43 26 43 43 26 34 43 26 34 43 34 34 26 43 43 34 26 43 43 34 34 43 34 43 26 43 43 34 26 GCk,l (Octahedron) ... 14 4, 10 32 , 42 , 4, 10 4, 10 32 , 22 , 10 14 12 , 12 6, 14 14 22 , 10 22 , 10 14 [CC] 43 34 26 34 43 43 43 34 43 34 26 26 34 26 34 43 43 43 43 34 34 43 26 43 43 26 34 43 26 34 43 34 34 26 43 ... 4 8, 9, 7, 10, 1∗ 7, 8, 5∗ 9, 11, 10, 11, 2∗ 9, 12, 11, 8, 11, 13, 1∗ 9, 13, [z] 34 26 34 34 34 26 34 34 26 34 34 26 34 34 34 34 34 34 26 34 34 34 26 34 26 34 34 34 26 34 34 34 34 34 26 34 34 ...
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Báo cáo khoa học: " Profile of time-dependent VEGF upregulation in human pulmonary endothelial cells, HPMEC-ST1.6R infected with DENV-1, -2, -3, and -4 viruses" pps
... ± 5.7 ± 0 .4 ± 1 .4 0±0 1, 244 .0 ± 1 .4 14, 997.5 ± 50.2 14, 2 23. 8 ± 46 0 .3 21,275.6 ± 550.5 9,0 94. 5 ± 220.6 24 600.1 ± 59 .4 10,167.1 ± 38 4 .3 11, 039 .2 ± 969 .4 15,529.7 ± 238 .3 11,782.0 ± 53. 7 96 876.0 ... ± 730 .1 10 , 34 9 .4 ± 189.9 13, 541 .0 ± 5 23. 6 4, 610.1 ± 207.9 192 3, 247 .7 ± 39 8.5 25, 948 .5 ± 43 2 .0 29,889.6 ± 828 .4 41,560 .4 ± 131 .2 20,281.7 ± 706.1 Samples were taken at time points 0, 8, 24, 96, ... 0.167950 0.057191 0.000089 0.0080 74 0.006 035 0.0 04 2 34 24 0.008879 0. 045 426 0.001775 0.000297 96 0.07 931 6 0.002276 0.0105 24 0.0 135 08 192 0.006617 0.012808 0.0016 83 0.0188 74 Competing interests The authors...
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FCE Speaking Part 3 and 4 teacher handbook 08
... learned and serious audience 2.What is the key difference between classical music and romantic music ? Classical music has beauty in itself, whereas romantic music arouses people’s emotions 3. Why ... with a strong beat people ? and simple tunes, which are easy to remember Mus ic Classical De s cript E xam p ♪ F le ionarne d and s e rious leor a SYMPHONY NO .4 audience, dependend ... icpe ople our m inds and m ake s us bring calm s toge the r feallthelaxe d Be autiful ss oul hetm ilulate e re s orrow in one ’s ongs s art e lps to he noble fe e lings and ofte n s tre ngthe...
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Báo cáo khoa học: Fowlicidin-3 is an a-helical cationic host defense peptide with potent antibacterial and lipopolysaccharideneutralizing activities ppt
... Disallowed 205 68 86 51 7.6 18. 64 2.82 18.58 ) 14. 67 11.27 ± ± ± ± ± 5 .30 0.17 0.69 5.00 0.65 3. 03 ± 0.82 4. 44 ± 0.87 0 .36 ± 0. 14 0.90 ± 0. 24 0 . 34 ± 0. 13 1. 54 ± 0 .39 64. 8% 33 .4% 1.8% 0.0% lowest-energy ... using ATCC No Fowl -3 (lM) Fowl-1 (lM) 25922 140 28 130 76 138 83 70 040 8 2 2 2 2 19115 259 23 43 3 00 BAA -39 1 2 fowlicidin-1 as a reference peptide As shown in Table 2, fowlicidin -3 was active against ... Bommineni et al A Structure and functions of fowlicidin -3 30 100 60 15 40 10 Fowl -3 Fowl -3 + FBS Fowl-1 Fowl-1 + FBS 20 0 10 20 30 40 50 Peptide (µM) B 100 Hemolysis (%) CCL3/MIP-1α 20 Relative Fold...
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Chapter 3: Financial Audit Receivables and Payables Activities between funds that are ppt
... 4 73, 43 6 ,888 11,650 ,44 1 6 ,44 9,596 6,661 ,30 3 6 34 ,37 3 33 0,8 14 46,805 — 49 ,082 — — — — 11,650 ,44 1 6 ,49 8,678 6,661 ,30 3 6 34 ,37 3 33 0,8 14 46,805 25,7 73, 332 49 ,082 25,822 ,41 4 11, 842 ,31 6 — 11, 842 ,31 6 37 ,615, 648 ... 14, 220 ,41 0 14, 220 ,41 0 97 ,36 9,5 14 (40 7 ,37 2,266) 14, 220 ,41 0 (39 3,151,856) 31 7 ,48 5 ,33 5 30 , 535 ,685 1,562,115 2,091, 733 3, 066,777 43 , 5 23, 519 94, 837 (21, 839 ,779) — — — — — — — 3, 645 ,000 31 7 ,48 5 ,33 5 ... 3) 14, 741 ,227 122,805, 238 Total current assets 2 ,30 9,277 3, 4 13, 46 9 — 11, 233 ,0 23 2,2 14, 542 Total receivables 2,261,687 851,517 39 5,000 11, 233 ,0 23 277 , 34 1 ,32 3 — — — — 277 , 34 1 ,32 3 27,277,052 1 ,40 6,017...
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current conditions and assessment on the effects of the caring, supporting and treating activities for aids patients at adult outpatient clinics in 3 provinces of vietnam, 2009 - 2010
... n=6 83) (%) - Without Test result 91 9,6 41 8 54, 5 36 5 53, 4 - With Test result 809 90 ,4 34 9 45 ,5 31 8 46 ,6 * ** *** Normal
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Dimensioning and Tolerancing Handbook Episode 3 Part 4 potx
... Temperature range (oC) X 0.00 042 0.00 048 0. 042 11 Y 0.00 038 0.00 046 0. 041 82 Z 0.00 049 0.00050 0. 04 132 X 0.00 045 0.00050 0. 037 23 Y 0.00 040 0.00 042 0. 041 23 Z 0.00050 0.000 54 0. 039 98 TVE Test # 7: Coordinate ... Coordinate range (mm), (temp comp off) Temperature range (oC) X 0.00 047 0.00052 0. 039 28 Y 0.00 042 0.00 047 0.0 43 3 2 Z 0.00052 0.00051 0. 041 11 Based on these results, test #5 was replicated two more times ... Test # 4: Coordinate range (mm), (temp comp on) Coordinate range (mm), (temp comp off) Temperature range (oC) X 0.00092 0.00092 0.0 833 6 Y 0.00051 0.00 048 0.09782 Z 0.00 133 0.001 13 0.1 647 6 In...
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Data Analysis Machine Learning and Applications Episode 3 Part 4 potx
... Equation and Figure 4: ∗ Pn×m = Un×c · Sc×c ·Vc×m 2.69 0.57 2.22 4. 25 0.78 3. 93 2.21 0. 04 3. 17 1 .38 2.92 4. 78 -0.61 0.28 -0.29 -0.95 -0. 74 0. 14 ∗ Pn×i (3) 8.87 -0 .47 -0.28 -0 .47 -0.69 4. 01 0.11 ... 0.20 54 Portal 0. 142 5 0.2050 Portal 0.0058 0. 245 5 MNI (0 .33 ) e f f (0. 83) e f c (0.17) 0.2815 0 .35 18 0.1 836 0.2079 0.02 54 0. 245 9 MNINE (0 .33 ) U SAW e f f (0. 83) e f c (0.17) 0. 640 8 0.7685 0 .36 0.1965 ... ACTOR 35 30 precision precision 40 25 20 15 10 10 20 30 40 50 (a) k 60 70 80 90 100 DIRECTOR GENRE FRUM-70 KEYWORD FRUM -30 FRUM-10 70 20 18 16 14 12 10 68 Precision 45 66 64 62 60 58 10 20 30 40 ...
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Advanced Mathematical Methods for Scientists and Engineers Episode 3 Part 4 pot
... 4x3 To check the theorem, d x x2 d ∆[A(x)] = dx dx x2 x4 2x x x2 = + 2x 4x3 x x = x4 − 2x3 + 4x4 − 2x3 = 5x4 − 4x3 16 .4. 2 The Wronskian of a Set of Functions A set of functions {y1 , y2 , ... Example 16 .4. 1 Consider the the matrix A(x) = x x2 x2 x4 The determinant is x5 − x4 thus the derivative of the determinant is 5x4 − 4x3 To check the theorem, d x x2 d ∆[A(x)] = dx dx x2 x4 2x x ... (J3 ) J 0 0 f (J4 ) 0 J4 We want to compute eJt so we consider the function f (λ) = we see that 2t e t e2t eJt = e2t 0 8 94 eλt , which has the derivative f (λ) = t eλt Thus 0 e3t...
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Giáo án Anh văn lớp 6 : Tên bài dạy : UNIT 12. SPORTS AND PASTIMES Lesson 3 B1-4 (P127-128) docx
... fishing and I play football (Thuy writes): I watch T.V, I go to the park and I play badminton (Chinh writes): I listen to music, I play football and I watch T.V Group writing (poster): San, Thuy and ... and Chinh play football San goes fishing Thuy goes to the park and plays badminton Chinh listens to music III HOME WORK: - Learn by heart vocabulary - Do B1 (workbook) - Prepare U12 lesson B4-5 ... S2: No, I don’t S3: Do you watch TV? S2: No, I don’t Pre writing Pre teach Free time = spare time (to) go fishing...
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Design and Optimization of Thermal Systems Episode 3 Part 4 ppsx
... degree of difficulty D – (3 1) Therefore, the optimum value of the cost is given by U* 150 w1 w1 30 0 w2 w2 30 0 w3 w3 1, 000 w4 w4 with w2 w3 w4 w1 w2 w4 w2 w3 w4 w1 w1 w3 w4 The last three equations ... from the expression for U* This gives w1 10 /3, w2 –1, and w3 4 /3 Therefore, U* 10.5 10 /3 10 / 12 1 0.15 4 /3 4 /3 70 .30 The independent variables H and T may be obtained from the expressions for ... C* 3. 5 w1 w1 14. 8 w2 w2 5 64 Design and Optimization of Thermal Systems with w2 w1 and 1.4w1 2.2w2 From these equations, w1 0.611 and w2 0 .38 9 Therefore, C* (3. 5/0.611)0.611 ( 14. 8/0 .38 9)0 .38 9...
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Giáo án Anh văn lớp 7 : Tên bài dạy : At home and away. Lesson 3: (A3- 4) pdf
... _ Introduce the listening , and ask the Ss to work in pairs to choose the sentence which contains the similar information to the tape - Play the tape tree times , and ask the Ss to share the ... Introduce the reading, and ask some questions : -Do you write diary ? - What you always write in your diary ? C.While- reading -Ask the Ss to read the reading in silence and answer the question ... Liz and her parents arrrive in Hanoi ? - What does Mr Robinson ? -How old is Liz ? - What does Ba collect ? - Ask the Ss to the exercise in the book (P: 90) - Work in pairs to the exercise., and...
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Gear Geometry and Applied Theory Episode 3 Part 4 pptx
... gears and is ω − ωc (c) = m41 −ωc ( 23. 2 .4) where (c) (c) (c) m41 = m 43 · m21 = (−1) N3 N4 · (−1) (N3 )(N ) N1 = N2 (N )(N ) ( 23. 2.5) Equations ( 23. 2 .4) and ( 23. 2.5) yield 4 (c) = − m41 ωc ( 23. 2.6) ... (22 .4. 2) = [sin γ2 cos θ2 − cos γ2 sin γ2 sin θ2 ]T (22 .4 .3) ∂u (2) ∂r f τ (2) = O2P |O2P | = ∂u (2) ∂r f ∂u Using Eqs (22 .4. 1), (22 .4. 2), and (22 .4 .3) , we obtain cos η = tan γ1 tan γ2 (22 .4. 4) ... determined as follows: (c) (c) (c) m41 = m 43 · m21 = (+1) N3 N4 · (+1) N1 (N3 )(N ) = N2 (N )(N ) ( 23. 2.8) Then we obtain (N3 )(N ) 4 =1− ωc (N )(N ) ( 23. 2.9) Large reduction of angular velocity...
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C# in Depth what you need to master c2 and 3 phần 4 pdf
... queue.Dequeue()); } The output of listing 3. 14 is as follows: Stack:9 Stack:8 Stack:7 Stack:6 Stack:5 Stack :4 Stack :3 Stack:2 Stack:1 Stack:0 Queue:0 Queue:1 Queue:2 Queue :3 Queue :4 Queue:5 Queue:6 Queue:7 Queue:8 ... section 4. 2 would still be relevant and the feature would still work and be useful However, C# provides extra syntactic sugar to make it even better—that’s the subject of section 4 .3 4. 2 System.Nullable ... or the other and use it consistently Listing 4 .3 is exactly equivalent to listing 4. 2 but uses the ? modifier Listing 4 .3 The same code as listing 4. 2 but using the ? modifier int? nullable =...
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Synthesis and characterisation of electrical conducting polymers co polymers based on omega functionalised 3 alkylthiophenes 4
... (1H, m), 6. 93 (2H, m) and 7. 23 (1H, m) 13 C NMR of 11-Thiophen -3- yl-undec-1-en -3- ol 1 43 . 2; 141 .3; 128.2; 1 24. 9; 119.7; 1 14. 5; 73. 2; 37 .0; 30 .5; 30 .3; 29 .4 29 .3; 29.2; 25.2 Found (C, 71 .37 ; H, 9.58; ... (%) unit (%) C15.5H21.8O1.4S C15H20OS 32 .1 33 .9 C92H126O16S10 C96H111O19S10 46 .6 44 .6 C112H152O17S10 C 132 H182O19S10 40 .3 35.2 10 C202H305O25S10 C204H 344 O19S10 24. 4 24. 8 11 a The formulae were ... (30 60. 14 w, 2997.67 s, 2 945 .89 s, 1727 .30 s, 144 7 .47 m, 138 8.09 w, 11 43 . 65 s, 927.12 m, 785 m) 10 (Found: C 64 .37 %, H 7.28%, S 15 .32 %) IR/cm-1 (30 60. 14 w, 2925.67 s, 2856.89 s, 1728 .30 s, 145 2.74...
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Tìm thêm: xác định các nguyên tắc biên soạn khảo sát các chuẩn giảng dạy tiếng nhật từ góc độ lí thuyết và thực tiễn khảo sát chương trình đào tạo gắn với các giáo trình cụ thể tiến hành xây dựng chương trình đào tạo dành cho đối tượng không chuyên ngữ tại việt nam điều tra đối với đối tượng giảng viên và đối tượng quản lí điều tra với đối tượng sinh viên học tiếng nhật không chuyên ngữ1 khảo sát thực tế giảng dạy tiếng nhật không chuyên ngữ tại việt nam nội dung cụ thể cho từng kĩ năng ở từng cấp độ xác định mức độ đáp ứng về văn hoá và chuyên môn trong ct phát huy những thành tựu công nghệ mới nhất được áp dụng vào công tác dạy và học ngoại ngữ mở máy động cơ lồng sóc mở máy động cơ rôto dây quấn hệ số công suất cosp fi p2 đặc tuyến mômen quay m fi p2 đặc tuyến tốc độ rôto n fi p2 sự cần thiết phải đầu tư xây dựng nhà máy phần 3 giới thiệu nguyên liệu từ bảng 3 1 ta thấy ngoài hai thành phần chủ yếu và chiếm tỷ lệ cao nhất là tinh bột và cacbonhydrat trong hạt gạo tẻ còn chứa đường cellulose hemicellulose chỉ tiêu chất lượng theo chất lượng phẩm chất sản phẩm khô từ gạo của bộ y tế năm 2008 chỉ tiêu chất lượng 9 tr 25