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... in.) = P = 8 .045 0 lb or P = 8.05 lb (b) From Equation (2) 8 .045 0 lb − (80 lb ) + B = B = 75.9775 lb or B = 76.0 lb Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P Beer, E Russell... 0: Ay = −87. 504 N and: A= Ax2 + Ay2 = θ = tan −1 Ay Ax (237.50)2 + (−87. 504) 2 = 253.11 N = tan −1 87. 504 = 20.226° 237.50 ∴ A = 253 N Vector Mechanics for Engineers: Statics and Dynamics, 8/e,... −10.7376 )2 + ( 2.5981)2 θ = tan −1 = 11 .047 5 lb, and 2.5981 = 13.6020° 10.7376 Therefore: Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P Beer, E Russell Johnston, Jr., Elliot